(b) Let us consider a linear equation ax + by + c = 0 … (i) Since, (-2,2), (0, 0) and (2, -2) are the solutions of linear equation therefore it satisfies the Eq. (i), we get At point(-2,2), -2a + 2b + c = 0 …(ii) At point (0, 0), 0+0 + c = 0 ⇒ c = 0 …(iii) and at point (2, – 2), 2a-2b + c = 0 …(iv) From Eqs. (ii) and (iii), c = 0 and – 2a + 2b + 0 = 0, – 2a = -2b,a = 2b/2 ⇒a = b On putting a = b and c = 0 in Eq. (i), bx + by + 0= 0 ⇒ bx + by = 0 ⇒ – b(x + y)= 0 ⇒ x + y = 0, b ≠ 0 Hence, x + y= 0 is the required form of the linear equation.