In an equilateral triangle ABC, the side BC is trisected at D. Then AD^2 is equal to -Maths 9th

In an equilateral triangle ABC, the side BC is trisected at D. Then AD^2 is equal to -Maths 9th
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Last Answer : Since the segment joining the mid points of any two sides of a triangle is half the third side and parallel to it. DE = 1 / 2 AC ⇒ DE = AF = CF EF = 1 / 2 AB ⇒ EF = AD = BD DF = 1 ... △DEF ≅ △AFD Thus, △DEF ≅ △CFE ≅ △BDE ≅ △AFD Hence, △ABC is divided into four congruent triangles.

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