Find the range of values of x which satisfy x^2 + 6x – 27 > 0, –x^2 + 3x + 4 > 0 simultaneously. -Maths 9th

Find the range of values of x which satisfy x^2 + 6x – 27 > 0, –x^2 + 3x + 4 > 0 simultaneously. -Maths 9th
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Last Answer : Solving for first solution: 3x-8y=27 put the value of y=0 3x-8(0)=27 3x=27 x=27/3 therefore,x=9 so, first solution=(9,0). Solving for second solution: 3x-8y=27 put the value of x=1 3(1)-8y=27 3-8y=27 -8y=27-3 -8y=24 y= -24/8 y= -3 therefore, second solution=(1,-3). [answer].

find 2 different solutions for 3x-8y=27 -Maths 9th

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Last Answer : Solving for first solution: 3x-8y=27 put the value of y=0 3x-8(0)=27 3x=27 x=27/3 therefore,x=9 so, first solution=(9,0). Solving for second solution: 3x-8y=27 put the value of x=1 3(1)-8y=27 3-8y=27 -8y=27-3 -8y=24 y= -24/8 y= -3 therefore, second solution=(1,-3). [answer].

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6x^+17xy+5y^ -Maths 9th

Description : 6x^+17xy+5y^ -Maths 9th

Last Answer : what we have to do to this question??? we have to factorise or do something else?

6x^+17xy+5y^ -Maths 9th

Description : 6x^+17xy+5y^ -Maths 9th

Last Answer : what we have to do to this question??? we have to factorise or do something else?

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Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`

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Description : Let f and g be the functions from the set of integers to the set integers defined by f(x) = 2x + 3 and g(x) = 3x + 2 Then the composition of f and g and g and f is given as (A) 6x + 7, 6x + 11 (B) 6x + 11, 6x + 7 (C) 5x + 5, 5x + 5 (D) None of the above

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Description : Out of the following linear equations in two variables, the two representing a pair of parallel lines graphically are: 3x - 4y = 6 3x + 4y = 6 6x + 8y = 12 6x - 8y + 6 = 0 (a) 3x - 4y = 6 and 6x + 8y = 12 (b) 3x - 4y = 6 ... 6 = 0 (c) 6x + 8y = 12 and 3x + 4y = 6 (d) 6x - 8y + 6 = 0 and 3x + 4y = 6

Last Answer : (b) 3x - 4y = 6 and 6x - 8y + 6 = 0

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If – x^2 + 3x + 4 > 0, then which of the following is correct? -Maths 9th

Description : If – x^2 + 3x + 4 > 0, then which of the following is correct? -Maths 9th

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If x is real and x^2 + 3x + 2 > 0, x^2 – 3x – 4 < 0, then which of the following is correct? -Maths 9th

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The equation whose roots are the negatives of the roots of the equation x^7 + 3x^5 + x^3 – x^2 + 7x + 2 = 0 is : -Maths 9th

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The equation whose roots are twice the roots of the equation x^2 – 3x + 3 = 0 is -Maths 9th

Description : The equation whose roots are twice the roots of the equation x^2 – 3x + 3 = 0 is -Maths 9th

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Last Answer : (c) (8, 6)Let AB be the given line 4x + 3y = 25 Let O′(a, b) be the image of O in the given line AB. Let O O′ cut AB in point P. Also OP ⊥ AB and P is the mid-point of OO′. ∴ Co-ordinates of P are \(\bigg( ... 4 imes6}{3}\) = 8∴ The image of the point O(0, 0) in the line 4x + 3y - 25 = 0 is (8, 6).

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Last Answer : Let p(x) = 2x4 - 5x3 + 2x2 - x+ 2 firstly, factorise x2-3x+2. Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term] = x(x-2)-1 (x-2)= (x-1)(x-2) Hence, 0 of x2-3x+2 are land 2. We have to prove that, 2x4 ... )2 - 2 + 2 = 2x16-5x8+2x4+ 0 = 32 - 40 + 8 = 40 - 40 =0 Hence, p(x) is divisible by x2-3x+2.

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Description : Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Last Answer : Let p(x) = 2x4 - 5x3 + 2x2 - x+ 2 firstly, factorise x2-3x+2. Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term] = x(x-2)-1 (x-2)= (x-1)(x-2) Hence, 0 of x2-3x+2 are land 2. We have to prove that, 2x4 ... )2 - 2 + 2 = 2x16-5x8+2x4+ 0 = 32 - 40 + 8 = 40 - 40 =0 Hence, p(x) is divisible by x2-3x+2.

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What must be added to 2x(square) - 5x + 6 to get x(cube) - 3x(square) + 3x - 5? -Maths 9th

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