Description : What is the product of the perpendiculars from the two points -Maths 9th
Last Answer : (a) a2 Given, ax cos ϕ + by sin ϕ - ab = 0. ∴ Perpendicular distance of the given line from \(\big(+\sqrt{b^2-a^2},0\big)\)d1 = \(\bigg|rac{a\sqrt{b^2-a^2}\, ext{cos}\,\phi\,-ab}{\sqrt{a^2 ... , ext{sin}^2\,\phi}}\bigg|\)∴ Perpendicular distance of the given line from \(\big(-\sqrt{b^2-a^2},0\big)\)