The value of 6 + log(3/2) -Maths 9th

The value of 6 + log(3/2) -Maths 9th
by

1 Answer

Answer :

(d) 4Let A  = 6 + \( ext{log}_{rac{3}{2}}\)\(\bigg[rac{1}{3\sqrt2}\sqrt{4-rac{1}{3\sqrt2}\sqrt{4-rac{1}{3\sqrt2}\sqrt{4-rac{1}{3\sqrt2}\sqrt{4-rac{1}{3\sqrt2}}}}}...\) Let P = \(\sqrt{4-rac{1}{3\sqrt2}\sqrt{4-rac{1}{3\sqrt2}\sqrt{4-rac{1}{3\sqrt2}\sqrt{4-rac{1}{3\sqrt2}}}}}...\)P = \(\sqrt{4-rac{1}{3\sqrt2}P}\) ⇒ P2 = 4 - \(rac{1}{3\sqrt2}\)P ⇒ P2 + \(rac{1}{3\sqrt2}\)P - 4 = 0⇒ P = \(rac{-rac{1}{3\sqrt2}±\sqrt{rac{1}{18}+16}}{2}\) = \(rac{-rac{1}{3\sqrt2}±rac{17}{3\sqrt2}}{2}\)(Applying the formula for roots of Q.E.)⇒ P = \(rac{16}{3 imes2\sqrt2}\) or \(rac{-18}{3 imes2\sqrt2}\) = \(rac{8}{3\sqrt2}\) or \(-rac{3}{\sqrt2}\)Neglecting p = \(rac{-3}{\sqrt2}\) as p > 0, we have p = \(rac{8}{3\sqrt2}\)∴ A = 6 + \( ext{log}_{rac{3}{2}}\)\(\bigg(rac{1}{3\sqrt2} imesrac{8}{3\sqrt2}\bigg)\) = 6 + \( ext{log}_{rac{3}{2}}\) \(\big(rac{4}{9}\big)\)= 6 + \( ext{log}_{rac{3}{2}}\) \(\big(rac{3}{2}\big)^{-2}\) = 6 - 2 \( ext{log}_{rac{3}{2}}\) \(rac{3}{2}\) = 6 - 2 = 4.
by

Related questions

If a, b, c be the p^th, q^th, r^th terms of a GP, then the value of (q – r) log a + (r – p) -Maths 9th

Description : If a, b, c be the p^th, q^th, r^th terms of a GP, then the value of (q – r) log a + (r – p) -Maths 9th

Last Answer : (a) 0Let h be the first term and k be the common ratio of a GP, then a = hkp - 1, b = hkq - 1, c = hkr - 1∴ (q - r) log a + (r - p) log b + (p - q) log c = log [hkp -1]q - r + log [hkq -1]r - p + log[hkr -1]p - ... r + r - p + p - q) (kp - 1)q - r (kq -1)r - p (kr -1)p - q = log(ho ko) = log 1 = 0.

Find the minimum value of log n m + log m n, where m > 1 and n > 1. -Maths 9th

Description : Find the minimum value of log n m + log m n, where m > 1 and n > 1. -Maths 9th

Last Answer : answer:

Find the value of logxx + logxx^3 + logxx^5 + ........ + log xx^(2n-1). -Maths 9th

Description : Find the value of logxx + logxx^3 + logxx^5 + ........ + log xx^(2n-1). -Maths 9th

Last Answer : answer:

If log32, log3 (2^x – 5) and log^3 (2^x – 7/2) are in A.P., then what is the value of x ? -Maths 9th

Description : If log32, log3 (2^x – 5) and log^3 (2^x – 7/2) are in A.P., then what is the value of x ? -Maths 9th

Last Answer : answer:

If (log x)/(l + m - 2n) = (log y)/(m + n - 2l) = (log z)/(n + l - 2m), then xyz is equal to : -Maths 9th

Description : If (log x)/(l + m - 2n) = (log y)/(m + n - 2l) = (log z)/(n + l - 2m), then xyz is equal to : -Maths 9th

Last Answer : Let l+m−2nlogx​=m+n−2llogy​=n+l−2mlogz​=k(say) So, we get logx=k(l+m−2n) ....... (i) logy=k(m+n−2l) ....... (ii) logz=k(n+l−2m) ....... (iii) ∴logx+logy+logz=k(l+m−2n)+k(m+n−2l)+k(n+l−2m) ⇒logx+logy+logz=kl+km−2kn+km+kn−2kl+kn+kl−2km ⇒log(xyz)=0 ⇒logxyz=log1 ⇒xyz=1

If 1/3 log3 M + 3 log3 N = 1 + log 0.008 5, then -Maths 9th

Description : If 1/3 log3 M + 3 log3 N = 1 + log 0.008 5, then -Maths 9th

Last Answer : (b) \(N^9=rac{9}{M}\)\(rac{1}{3}\) log3 M + 3 log3 N = 1 + log0.008 5⇒ log3 M1/3 + log3N3 = 1 + log0.0085 ⇒ log3 M1/3 N3 = 1 + log0.0085 ⇒ M1/3 N3 = 3(1 + log0.0085) ⇒ M1/3 N3 = 31 . 3log0.0085⇒ \(N^9=rac{27 ... ^9=rac{27}{M}\big(3^{log_{rac{1}{5}}5}\big)\) = \(rac{1}{M}\) (27)(3-1) = \(rac{9}{M}.\)

If (log x)/(a^2+ab+b^2) = (log y)/(b^2+bc+c^2) = (log z)/(c^2+ca+a^2), then x^(a-b). y^(b-c). z^(c-a) = -Maths 9th

Description : If (log x)/(a^2+ab+b^2) = (log y)/(b^2+bc+c^2) = (log z)/(c^2+ca+a^2), then x^(a-b). y^(b-c). z^(c-a) = -Maths 9th

Last Answer : (c) 1Let each ratio = k and base = e ⇒ loge x = k(a2 + ab + b2) ⇒ (a - b) loge x = k (a - b) (a2 + ab + b2) ⇒ loge xa - b = k(a3 - b3) ⇒ xa - b = \(e^{k(a^3-b^3)}\) Similarly, yb-c = \(e^{k(b^3-c^3)}\), zc-a = \ ... (e^{k(b^3-c^3)}\) . \(e^{k(c^3-a^3)}\)= \(e^{k[a^3-b^3+b^3-c^3+c^3-a^3]}\) = e0 = 1.

What is the sum, of 'n' terms in the series : log m + log -Maths 9th

Description : What is the sum, of 'n' terms in the series : log m + log -Maths 9th

Last Answer : (d) log \(\bigg[rac{m^{(1+n)}}{n^{(n-1)}}\bigg]^{rac{n}{2}}\) S = log m + log \(rac{m^2}{n}\) + log \(rac{m^3}{n^2}\) + ...........n terms= log \(\bigg[\)m.\(rac{m^2}{n}\).\(rac{m^3}{n^2}\)........ ... 2}}}{n^{rac{n(n-1)}{2}}}\)\(\bigg]\) = log \(\bigg[rac{m^{(1+n)}}{n^{(n-1)}}\bigg]^{rac{n}{2}}\)

If log (a + c) + log (a – 2b + c) = 2 log (a – c), then a, b, c are in -Maths 9th

Description : If log (a + c) + log (a – 2b + c) = 2 log (a – c), then a, b, c are in -Maths 9th

Last Answer : (c) H.P.Given, log (a + c) + log (a – 2b + c) = 2 log (a – c) ⇒ log (a + c) (a – 2b + c) = log (a – c)2 ⇒ (a + c) (a – 2b + c) = (a – c)2⇒ 4ac = 2ba + 2bc ⇒ 2ac = b(a + c)∴ b = \(rac{2ac}{a+c}\) ⇒ a, b, c are in H.P.

If x, y, z are in G.P. and (log x – log 2y), (log 2y – log 3z) and (log 3z – log x) are in A.P., -Maths 9th

Description : If x, y, z are in G.P. and (log x – log 2y), (log 2y – log 3z) and (log 3z – log x) are in A.P., -Maths 9th

Last Answer : (d) obtuse angledx, y, z are in G.P. ⇒ y2 = xz ...(i) (log x - log 2y), (log 2y - log 3z) and (log 3z - log x) are in A.P. ⇒ 2(log 2y - log 3z) = (log x ... x is the length of the side opposite ∠A.∵ cos A is less than 0, i.e, negative, ∠A is obtused and the triangle is obtuse angled.

If (log x)/(l + m - 2n) = (log y)/(m + n - 2l) = (log z)/(n + l - 2m), then xyz is equal to : -Maths 9th

Description : If (log x)/(l + m - 2n) = (log y)/(m + n - 2l) = (log z)/(n + l - 2m), then xyz is equal to : -Maths 9th

Last Answer : (b) 1Let \(rac{ ext{log}\,x}{l+m-2n}\) = \(rac{ ext{log}\,y}{m+n-2l}\) = \(rac{ ext{log}\,z}{n+l-2m}\) = k. Thenlog x = k(l + m – 2n), log y = k(m + n – 2l); log z = k(n + l – 2m) ⇒ log x + log y + log z = k(l + m – 2n) + k(m + n – 2l) + k(n + l – 2m)⇒ log(xyz) = 0 ⇒ log(xyz) = log 1 ⇒ xyz = 1.

If f(x) = log ((1+x)/(1-x)), show that f (2x/(1+x^2)) = 2 f(x). -Maths 9th

Description : If f(x) = log ((1+x)/(1-x)), show that f (2x/(1+x^2)) = 2 f(x). -Maths 9th

Last Answer : answer:

2 . If the mean of the following distribution is 6 . Find the value of p ? x 2 4 6 10 P + 5 f 3 2 3 1 2 -Maths 9th

Description : 2 . If the mean of the following distribution is 6 . Find the value of p ? x 2 4 6 10 P + 5 f 3 2 3 1 2 -Maths 9th

Last Answer : Here's ur answer...

If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Description : If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Last Answer : x + x + 2 + x + 4 + x + 6 + x + 8 / 5 = 11 5x + 20 = 55 5x = 35 ⇒ x = 7

2 . If the mean of the following distribution is 6 . Find the value of p ? x 2 4 6 10 P + 5 f 3 2 3 1 2 -Maths 9th

Description : 2 . If the mean of the following distribution is 6 . Find the value of p ? x 2 4 6 10 P + 5 f 3 2 3 1 2 -Maths 9th

Last Answer : Here's ur answer...

If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Description : If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Last Answer : x + x + 2 + x + 4 + x + 6 + x + 8 / 5 = 11 5x + 20 = 55 5x = 35 ⇒ x = 7

In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is -Maths 9th

Description : In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is -Maths 9th

Last Answer : NEED ANSWER

In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is -Maths 9th

Description : In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is -Maths 9th

Last Answer : (b) Let x and y be the upper and lower class limit in a frequency distribution. Now, mid value of a class (x + y )/2=10 [given] ⇒ x + y = 20 (i) Also, given that, width of class x- y = 6 (ii) On ... putting x = 13 in Eq. (i), we get 13+y = 20 ⇒ y = 7 Hence, the lower limit of the class is 7.

Find the value of x, if(6/5)to the power x ,(5/6) to the power 2x = 125/216. -Maths 9th

Description : Find the value of x, if(6/5)to the power x ,(5/6) to the power 2x = 125/216. -Maths 9th

Last Answer : Solution :-

Find the value of k,if y+3 is a factor of 3y(to the power square) + ky + 6. -Maths 9th

Description : Find the value of k,if y+3 is a factor of 3y(to the power square) + ky + 6. -Maths 9th

Last Answer : Solution :-

Find the value of x3-8y3-36xy-216 when x = 2y+6. -Maths 9th

Description : Find the value of x3-8y3-36xy-216 when x = 2y+6. -Maths 9th

Last Answer : Solution :-

For what value of x+y in fig.6.4 will ABC be a line? -Maths 9th

Description : For what value of x+y in fig.6.4 will ABC be a line? -Maths 9th

Last Answer : Solution :- For ABC to be a line, the sum of two adjacent angles must be 180°, i.e., x + y must be equal to 180°.

In Fig.6.6, find the value of x for which the lines l and m are parallel. -Maths 9th

Description : In Fig.6.6, find the value of x for which the lines l and m are parallel. -Maths 9th

Last Answer : Solution :-

In Fig. 6.7, if l||m, then find the value of x. -Maths 9th

Description : In Fig. 6.7, if l||m, then find the value of x. -Maths 9th

Last Answer : Solution :-

In Fig. 6.9, find the value of x. -Maths 9th

Description : In Fig. 6.9, find the value of x. -Maths 9th

Last Answer : Solution :-

In Fig. 6.10, if m|n, then find the value of x. -Maths 9th

Description : In Fig. 6.10, if m|n, then find the value of x. -Maths 9th

Last Answer : Solution :-

In Fig. 6.17, AB| |CD. Find the value of x. -Maths 9th

Description : In Fig. 6.17, AB| |CD. Find the value of x. -Maths 9th

Last Answer : Solution :-

If the mean of 8,5,2,x,6,5 is 6 , then find the mean of the value of x -Maths 9th

Description : If the mean of 8,5,2,x,6,5 is 6 , then find the mean of the value of x -Maths 9th

Last Answer : (8+5+2+x+6+5)/6=6 (26+x)=6×6 26+x=36 X=36-26 X=10

Find the value of the polynomial p(x) = x^3-3x^2-2x+6 at x = underroot 2 -Maths 9th

Description : Find the value of the polynomial p(x) = x^3-3x^2-2x+6 at x = underroot 2 -Maths 9th

Last Answer : In this chapter, we shall proceed with recalling some of the constructions already learnt in the earlier classes and deal with some more. Here in this section, we will construct some of these ... be done? 2. Always explain the construction. Write the sequence of steps that are actually taken.

Two students A and B solve an equation of the form x^2 + px + q = 0. A starts with a wrong value of p and obtains the roots as 2 and 6. -Maths 9th

Description : Two students A and B solve an equation of the form x^2 + px + q = 0. A starts with a wrong value of p and obtains the roots as 2 and 6. -Maths 9th

Last Answer : Let αα and ββ be the roots of the quadratic equation x2+px+q=0x2+px+q=0 Given that, A starts with a wrong value of p and obtains the roots as 2 and 6. But this time q is correct. i.e., a product of roots ... 1 Now, from Eqs. (ii) and (iii), we get α=−3 and β=−4α=−3 and β=−4 which are correct roots.

For what value of k will the roots of the equation kx^2 – 5x + 6 = 0 be in the ratio 2 : 3 ? -Maths 9th

Description : For what value of k will the roots of the equation kx^2 – 5x + 6 = 0 be in the ratio 2 : 3 ? -Maths 9th

Last Answer : (b) 1 Let the roots of the equation kx2 - 5x + 6 = 0 be α and β. Then, α + β = \(\frac{5}{k}\) ...(i) αβ = \(\frac{6}{k}\) ...(ii) Given \(\ ... frac{9}{k}\) ⇒ 9k2 - 9k = 0 k(k - 1) = 0 ⇒ k = 0 or 1 But k = 0 does not satisfy the condition, so k = 1.

If the polynomial x^6 + px^5 + qx^4 – x^2 – x – 3 is divisible by x^4 – 1, then the value of p^2 + q^2 is : -Maths 9th

Description : If the polynomial x^6 + px^5 + qx^4 – x^2 – x – 3 is divisible by x^4 – 1, then the value of p^2 + q^2 is : -Maths 9th

Last Answer : The divisor is x4−1=(x−1)(x+1)(x2+1) By factor theorem, f(1)=f(−1)=0 Thus, 1+p+q−1−1−3=0 and 1+q−1−3=p−1 i.e., p+q=4 and p−q=−2 Adding the two, 2p=2 i.e. p=1 and ∴ q=3. ∴ p2+q2=1+9=10

If ax^3 + bx^2 + x – 6 has (x + 2) as a factor and leaves a remainder 4, when divided by (x – 2), the value of a and b respectively are : -Maths 9th

Description : If ax^3 + bx^2 + x – 6 has (x + 2) as a factor and leaves a remainder 4, when divided by (x – 2), the value of a and b respectively are : -Maths 9th

Last Answer : Let p(x) = ax³ + bx² + x - 6 A/C to question, (x + 2) is the factor of p(x) , and we know this is possible only when p(-2) = 0 So, p(2) = a(-2)³ + b(-2)² - 2 - 6 = 0 ⇒ ... --(2) solve equations (1) and (2), 4a = 0 ⇒a = 0 and b = 2 Then, equation will be 2x² + x - 6

Find the value of a, if the line passing through (–5, –8) and (3, 0) is parallel to the line passing through (6, 3) and (4, a). -Maths 9th

Description : Find the value of a, if the line passing through (–5, –8) and (3, 0) is parallel to the line passing through (6, 3) and (4, a). -Maths 9th

Last Answer : Let C(x, y) be the centre of the circle passing through the points P(6, -6), Q(3, -7) and R(3, 3) Then, PC = QC = RC(Being radius of the same circle) PC2 = QC2 ⇒ (x - 6)2 + (y + 6)2 = (x - 3)2 + (y + 7)2 ⇒ x2 - ... i), we get 3\(x\) + (-2) - 7 = 0 ⇒ 3\(x\) = 9 ⇒ \(x\) = 3 ∴ The centre is (3, -2).

Determine the ratio in which the point P(m, 6) divides the join of A(– 4, 3) and B(2, 8). Also find the value of m. -Maths 9th

Description : Determine the ratio in which the point P(m, 6) divides the join of A(– 4, 3) and B(2, 8). Also find the value of m. -Maths 9th

Last Answer : (b) 1 : 2Any point on the x-axis is (a, 0).Let the point (a, 0) divide the join of A(2, -3) and B(5, 6) in the ratio k : 1. Then the co-ordinates of the point of division are \(\bigg(rac{5k+2}{k+1},rac{6k-3}{k+1}\ ... 6k - 3 = 0 ⇒ k = \(rac{1}{2}\)Required ratio is k : 1 ⇒ \(rac{1}{2}\) : 1 = 1 : 2.

If the sum of zeroes of the quadratic polynomial 3x2 – kx + 6 is 3, then find the value of k. -Maths 9th

Description : If the sum of zeroes of the quadratic polynomial 3x2 – kx + 6 is 3, then find the value of k. -Maths 9th

Last Answer : Here a = 3, b = -k, c = 6 Sum of the zeroes, (α + β) = − = 3 …..(given) ⇒ −(−)3 = 3 ⇒ k = 9

If 2x + 3y = 13 and xy = 6, find the value of 8x3 + 21y3. -Maths 9th

Description : If 2x + 3y = 13 and xy = 6, find the value of 8x3 + 21y3. -Maths 9th

Last Answer : 2x +3y = 13-----(1) xy =6-----(2) 8x³ +27y³ = (2x)³ +(3y)³ = (2x+3y)³ - 3*2x*3y(2x+3y) [using (a+b)³ = a³+b³+3ab(a+b)] = (13)³- 18 * 6 *13 [ using (1) and (2)] = 2197 - 1404 =793

If 9x2 + 25y2 = 181 and xy = -6, find the value of 3x + 5y. -Maths 9th

Description : If 9x2 + 25y2 = 181 and xy = -6, find the value of 3x + 5y. -Maths 9th

Last Answer : answer:

Compute the value of 9x2 + 4y2 if xy = 6 and 3x + 2y = 12. -Maths 9th

Description : Compute the value of 9x2 + 4y2 if xy = 6 and 3x + 2y = 12. -Maths 9th

Last Answer : Consider the equation 3x + 2y = 12 Now, square both sides: (3x + 2y)2 = 122 => 9x2 + 12xy + 4y2 = 144 =>9x2 + 4y2 = 144 – 12xy From the questions, xy = 6 So, 9x2 + 4y2 = 144 – 72 Thus, the value of 9x2 + 4y2 = 72

Find the value of x and y if l is parallel to m -Maths 9th

Description : Find the value of x and y if l is parallel to m -Maths 9th

Last Answer : the value should be zero...according to me as I think!!

Find the decimal expansion of 7/22 .Explain why it is taken as the approximate value of pi -Maths 9th

Description : Find the decimal expansion of 7/22 .Explain why it is taken as the approximate value of pi -Maths 9th

Last Answer : 3.1564267467648582474747477647908765434567896542345678765431222245775583585.................................. or 22/7 is the value f pi

What's pie's value -Maths 9th

Description : What's pie's value -Maths 9th

Last Answer : The number π is a mathematical constant, the ratio of a circle's circumference to its diameter, commonly approximated as 3.14159. It has been represented by the Greek letter 'π' since the mid-18th century, though it is also sometimes spelled

If l parallel to m, find the value of x. -Maths 9th

Description : If l parallel to m, find the value of x. -Maths 9th

Last Answer : Pls provide diagram, how can we know where is x

Find the value of k for 5x +2ky =3k, if x =1 and y =1 is its solution. -Maths 9th

Description : Find the value of k for 5x +2ky =3k, if x =1 and y =1 is its solution. -Maths 9th

Last Answer : Given, equation is 5x + 2ky = 3k. On putting x =1 and y =1 in this equation, we get 5(1) + 2k(1) =3k ⇒ 5 + 2k =3k ⇒ 5 = 3k - 2k ⇒ k = 5 Hence, required value of k is 5.

The point (2,3) lies on the graph of the linear equation 3x - (a -1)y =2a -1. If the same point also lies on the graph of the linear equation 5x + (1-2a)y = 3b, then find the value of b. -Maths 9th

Description : The point (2,3) lies on the graph of the linear equation 3x - (a -1)y =2a -1. If the same point also lies on the graph of the linear equation 5x + (1-2a)y = 3b, then find the value of b. -Maths 9th

Last Answer : Given, point (2,3) lies on the line. So, the point (2, 3) is the solution of 3x - (a -1) y = 2a - 1 On putting x = 2 and y = 3 in given solution. ∴ 3 2 - (a-1) 3 = 2a - 1 ⇒ 6 - 3a + 3 = 2a - 1 ⇒ - 3a ... 2 2) 3 = 3b ⇒ 10 - 9 = 3b ⇒ 1 = 3b ⇒ 1 / 3 = b Hence, the value of b is 1 / 3.

Using identities , find the value of -Maths 9th

Description : Using identities , find the value of -Maths 9th

Last Answer : (i) 1012 = (100 + 1)2 = 1002 + 2 100 1 + 12 = 10000 + 200 + 1 = 10201 (ii) 982 = (100 - 2)2 = 1002 - 2 100 2 + 22 = 10000 - 400 + 4 = 9604 (iii) 0.982 = (1- 0.02)2 = 12 - 2 1 0 ... 102 - 12 = 99 (v) 190 190 - 10 10 = 1902 - 102 = (190 + 10 ) (190 - 10) = 200 180 = 36000

In the following equations , verify whether the given value of the variable is a solution of the equation : -Maths 9th

Description : In the following equations , verify whether the given value of the variable is a solution of the equation : -Maths 9th

Last Answer : (i) If we substitute x = 4, we get L.H.S = x + 4 = 4 + 4 = 8 and R.H.S = 2x = 2 x 4 = 8 ∴ L.H.S = R.H.S. Hence, 4 is a solution of x + 4 = 2x. (ii) If we substitute y = 3, we get L.H.S = y - 7 = 3 - ... S = 2u + 7 = 2(5) + 7 = 10 + 7 = 17 ∴ L.H.S = R.H.S. Hence , 5 is a solution of 3u + 2 = 2u + 7

In the following equations , verify whether the given value of the variable is a solution of the equation : -Maths 9th

Description : In the following equations , verify whether the given value of the variable is a solution of the equation : -Maths 9th

Last Answer : (i) f we substitute x = √2, we get L.H.S. = 2x - 3 = 2(√2) - 3 = 2√2 - 3 and R.H.S = x / 2 - 2 = √2 / 2 - 2 ∴ L.H.S. ≠ R.H.S . Hence, √2 is not a solution of 2x - 3 = x / 2 - 2 (ii) If we substitute ... = 7 ∴ L.H.S. ≠ R.H.S . Hence , -1 is not a solution of 24 - 3 (u - 2) = u + 8

If the median of data (arranged in ascending order) 31, 33, 35, x, x+10, 48, 48, 50 is 40, then find value of x. -Maths 9th

Description : If the median of data (arranged in ascending order) 31, 33, 35, x, x+10, 48, 48, 50 is 40, then find value of x. -Maths 9th

Last Answer : Given data is 31, 33, 35, x, x+10, 48, 48, 50 Number of observation = 8 (even) Median = Value of (8/2)th observation + Value of (8/2+1)th observation / 2 Value of 4th observation + Value of 5th observation / 2 = x + x + 10 / 2 = x + 5 ∴ x + 5 = 40 ⇒ x = 35

The value of 1.999… in the form of p/q, where p and q are integers and -Maths 9th

Description : The value of 1.999… in the form of p/q, where p and q are integers and -Maths 9th

Last Answer : Value of 1.999 is given below .