In △ABC and △PQR, BC = QR (Given) ⇒ 1/2BC = 1/2QR ⇒ BM = QN In triangles ABM and PQN, we have AB = PQ (Given) BM = QN (Proved above) AM = PN (Given) ∴ △ABM ≅ △PQN (SSS congruence criterion) ⇒ ∠B = ∠Q (CPCT) Now, in triangles ABC and PQR, we have AB = PQ (Given) ∠B = ∠Q (Proved above) BC = QR (Given) ∴ ΔΑΒC ≅ ΔPOR (SAS congruence criterion) Participation, beauty, hardworking.