Description : 95 students each from 102 schools participated -Maths 9th
Last Answer : 95 x 102 = (100 - 5)(100 + 2) 1002 + (- 5 + 2) x 100 + (- 5 x 2) = 10,000 - 300 – 10 = 9,690 Fraternity, patriotism.
Description : The number of members of society A who participated -Maths 9th
Last Answer : The number of participants from society A and C is equal. Things which are double of the same thing are equal to one another. Social service, helpfulness, cooperation, environmental concern.
Description : For spreading the message 'Save Environment Save Future' -Maths 9th
Last Answer : In △ABC, we have ∠A + ∠B + ∠C = 180° (Since, sum of the angles of a △ is 180°) ⇒ 1/2∠A + 1/2∠B + 1/2∠C = 180°/2 ⇒ 1/2∠A + ∠1 + ∠2 = 90° ∴ ∠1 + ∠2 = 90° - 1/2∠A .. ... using (i) ] ⇒ ∠BOC = 180° - 90° + 1/2∠A ∴ ∠BOC = 90° + 1/2∠A Environmental care, social, futuristic.
Description : In 1954, the Public Health Service organized an experiment in which nearly 2 million children in grades 1, 2 and 3 participated. The experiment was to test a vaccine. Name the disease the children were vaccinated against, and identify the individual who developed the vaccine.
Last Answer : ANSWER: POLIO; VACCINE DEVELOPED BY JONAS SALK
Description : A school provides milk to the students daily in cylindrical glasses of diameter 7 cm. -Maths 9th
Last Answer : Diameter d = 7 cm Radius r = 7 / 2 cm and h = 12 cm ∴ V = πr2h = 22 / 7 × 7 / 2 × 7 / 2 × 12 = 462 Total milk for 1600 students = 462 × 1600 = 739200 cm3 = 739200 / 1000 litres = 739.2 litres .
Description : A school provides milk to the students daily in a cylindrical glasses of diameter 7 cm. -Maths 9th
Last Answer : Volume of milk in 1 glass =πr2h =π×(3.5)2×12=461.58cm2for 1600 students milk needed is =1600×461.58=738258litre
Last Answer : According to question find the litres of milk is needed to serve 1600 students.
Description : In a survey, it was found that 9 out of every 11 households -Maths 9th
Last Answer : 2/11 = 0.18(recurring), Non terminating repeating. People are becoming more social, helpful, cooperative and caring.
Description : In how many ways can a committee of five persons be formed out of 8 members when a particular member is taken every time? -Maths 9th
Last Answer : ∴Required number of ways = 7C4 = 7!
Description : Have any of you participated in any of the 7 or 21 day "clean eating" challenges?
Last Answer : answer:What I learned from my own weight loss and change in eating habits is that it was what worked for me and is not something I can tell someone else to do. Before a lifestyle change over two ... some orange juice in the morning. So we are like the sugar version of Jack Sprat and his wife.
Description : Is every rational number a whole number?Justify your answer. -Maths 9th
Last Answer : No, for example 1/5 is a rational number but not a whole number.
Description : Prove that every line segment has one and only one mid-point. -Maths 9th
Last Answer : Solution :-
Description : In how many ways can 6 gentlemen and 3 ladies be seated round a table so that every gentleman may have a lady by his side? -Maths 9th
Last Answer : If each gentleman has to have a lady by his side, the seating arrangement can be done as shown below: This can be done in 5! (Gentlemen) × 3! (Ladies) = 720 ways.
Description : An amusement fair was organised in a circular park for the children of slum clusters. Free food was supplied to them at 4 stalls situated at A, B, C and D as shown in the given figure. -Maths 9th
Last Answer : (i) From figure , it is clear that angle between the lines joining stalls C,D and stalls C, B is ∠BCD . Given, ∠DBC = 60° and ∠BAC = 40° CD is a chord of circle. Here, ∠CBD and ... for society. (iii) Other social issues for which such compaigns are required, are old age home, orphanages, etc.
Description : Thirty children were asked about the number of hours they watched TV programmes in the previous week. The results were found as follows : -Maths 9th
Last Answer : (i) Frequency distribution table (ii) From the above frequency distribution table, we observe that number of children in the class - interval 15 - 20 is 2. So, 2 children view television for 15 hours or more than 15 hours a week .
Description : The following table gives the pocket money (in Rs) given to children per day by their parents : Represent the data in the form of a histogram. -Maths 9th
Last Answer : The required histogram is as below :
Description : In a survey of 364 children aged 19-36 months, it was found that 91 liked to eat potato chips. -Maths 9th
Last Answer : Total children = 364 Number of children like potato chips = 91 Number of children do not like potato chips = 364 – 91 = 273 273 Required probability = 273 / 364 =0.75
Description : 750 families with 3 children were selected randomly and the following data recorded If a family member is chosen at random, compute the probability that it has : -Maths 9th
Last Answer : (i) P(no boy child) =100 / 750 = 2 / 15 (ii) P (no girl child) = 120 /750 =4 / 25
Last Answer : NEED ANSWER
Last Answer : (c) Total number of survey children's age from 19-36 months, n(S) = 364 In those of them 91 out of them liked to eat potato chips. ∴ Number of children who do not like to eat potato chips, n(E) = ... S) = 273/364 = 0.75 Hence, the probability that he/she does not like to eat potato chips is 0.75.
Description : 30 children were asked about the number of hours -Maths 9th
Last Answer : No, the number of children who watched TV for 10 or more hours a week is 4 + 2, i.e., 6 .
Description : Thirty children were asked about the number -Maths 9th
Last Answer : The frequency distribution of above data in tabular form is given as: (ii) Two children watched television for 15 or more hours a week.
Description : In a survey of 364 children aged 19-36 months, -Maths 9th
Last Answer : Children who do not like potato chips = 364 - 91 = 273 P (a child does not like potato chips) = 273/364 = 0.75
Description : In a survey of 364 children aged 20-40 months, -Maths 9th
Last Answer : Number of children = 364 Number of children not like to eat potato chips = 364 - 91 = 273. The required probability = 273/364 = 0.75
Description : 1500 families with 2 children were selected -Maths 9th
Last Answer : (i) P (a family having 2 girls) = Number of families having 2 girls/Total number of families = 475/1500 = 19/60 (ii) P (a family having 1 girl) = Number of families having 1 girl/Total number of ... families = 211/1500 Sum of probabilities = 475/1500 + 814/1500 + 211/1500 = 1500/1500 = 1
Description : Children of a society planned to plant trees in their area. -Maths 9th
Last Answer : Environmental care, beauty, conservation.
Description : A group of children prepared some decorative pieces -Maths 9th
Last Answer : In △AEC, ∠A + ∠E + ∠C = 180° ...(i) (Angle sum property of a triangle) Similarly, in △BDF, ∠B + ∠D + ∠F = 180° ...(ii) Adding (i) and (ii), we get ∠A + ∠B + ∠C + ∠D + ∠E + ∠F = 360° Social, caring, cooperative, hardworking.
Description : In the 86th amendment to the Constitution in 2002, which of the following was added as a fundamental duty of every citizen of India? a) A parent or guardian to provide opportunities for ... the natural environment including forests, rivers and wild life, and to have compassion for living creatures
Last Answer : a) A parent or guardian to provide opportunities for education to his child or, as the case may be, ward between the age of six and fourteen years
Description : The paint in a certain container is sufficient to paint an area equal to 9.375 m2. How many bricks of dimensions 22.5 cm×10 cm×7.5 cm can be painted out of this container? -Maths 9th
Last Answer : Total surface area of one brick = 2(lb +bh+lb) = [2(22.5 10+10 7.5+22.5 7.5)] cm2 = 2(225+75+168.75) cm2 = (2 468.75) cm2 = 937.5 cm2 Let n bricks can be painted out by the ... 93750 cm2 So, we have, 93750 = 937.5n n = 100 Therefore, 100 bricks can be painted out by the paint of the container.
Description : A bag contains 5 green and 7 red balls, out of which two balls are drawn at random. What is the probability that they are of the same colour ? -Maths 9th
Last Answer : (d) \(rac{31}{66}\)Total number of balls in the bag = 12 (5 Green + 7 Red) Let S be the sample space of drawing 2 balls out of 12 balls.Thenn(S) = 12C2 = \(rac{12 imes11}{2}\) = 66∴ Let A : Event of drawing two red balls⇒ ... \(rac{n(B)}{n(S)}\) = \(rac{21}{66}\) + \(rac{10}{66}\) = \(rac{31}{66}\).
Description : A traffic signal board, indicating ‘SCHOOL AHEAD’, is an equilateral triangle with side a. Find the area of the signal board, using Heron’s formula. -Maths 9th
Last Answer : Let each side of the equilateral triangle be a. Semi-perimeter of the triangle,
Description : For a particular year, following is the distribution of ages (in years) of primary school teachers in a district: -Maths 9th
Last Answer : 1.First class interval is 15 - 20 and its lower limit is 15. 2.Fourth class interval is 30 - 35 Lower limit is 30 and upper limit is 35. 3.Class mark of the class 45 - 50 =( 45+50 )/ 2 ... = Upper limit of each class interval - Lower limit of each class interval ∴ Here, class size = 20 - 15 = 5
Description : In a school marks obtained by 80 students are given in the table. Draw a histogram. Also, make frequency polygon. -Maths 9th
Last Answer : Here, class size = 135 - 305 = 10 ∴ Lower limit of first class interval is 305 - 10 / 2 = 300 Upper limit of first class interval is 305 + 10 / 2 = 310 Thus, first class interval is 300 - 310 Required histogram and frequency polygon is given on the graph paper .
Description : In a sample study of 642 people, it was found that 514 people have a high school certificate. -Maths 9th
Last Answer : Total number of persons = 642 Number of persons with high school certificate = 514 therefore Required probability=514 / 642 =0.80
Description : The given table shows the month of birth of 40 students of class IX of a particular section in a school. -Maths 9th
Last Answer : (a) P (later half of the year) = 23 / 40 (b) P (month having 31 days) = 26 / 40 = 13 / 20 (c) P(month having 30 days) = 10 / 40 = 1 / 4
Last Answer : (d) The total number of people in sample study, n(S) = 642. The number of people who have high school certificate, n(E) = 514. So, the probability that the person selected has a high school certificate ... S)=514/642 = 0.8 Hence, the probability that the person has a high school certificate is 0.8.
Description : A traffic signal board indicating ‘SCHOOL AHEAD’ -Maths 9th
Last Answer : Perimeter of the signal board, 2s = a + a + a ⇒ s = 3/2.a Area of triangle = under root (√s(s - a)(s - b)(s - c)) = under root (√3a/2(3/2.a - a)(3/2.a - a)(3/2.a - a) = under root (√3a/2 x ... = 180 cm 3a = 180 ⇒ a = 60 cm ∴ Area of signal board √3/4.a2 = √3/4 x (60)2 = 900√3 cm2
Description : Some students of a school started a campaign against -Maths 9th
Last Answer : Area of rectangle ABCD = 5 x 3 = 15 cm2 Cost incurred on one banner = ₹3 x 15 = ₹45 Cost incurred on 5 banners = 5 x ₹45 = ₹225 Social awareness, caring, cooperative.
Description : Why is the author deeply embarrassed the next day in school? Which words show his fear and insecurity? -Maths 9th
Last Answer : The author was full of remorse as he was left with nothing. He didn’t have proper dress and study material. He had no backpack. He had the feeling of insecurity. All things appeared strange to him ... going to be this way. I just wanted to curl up and die” reveal his fear and insecurity.