A spherical metal of radius 10 cm is melted and made into 1000 smaller spheres of equal sizes. In this process the surface area of the -Maths 9th

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Answer :

Option (C) is correct. Solution: Let the radius of the small spheres be ‘r’ cm.  Volume of metal remains the same in both cases.  So, vol of the spherical metal of radius 10 cm = total vol of the 1000 smaller spheres of radius ‘r’ cm. 4/3π103 = 1000*4/3πr3 Therefore, r = 1cm. Surface area of Spherical metal of radius 10 cm: 4π102 = 400π Total Surface area of 1000 smaller spheres: 1000*4π12 = 4000π  Hence, the surface area increased by 10 times.

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Last Answer : since curved surface of half of the spherical ball = 56.57 cm2 ∴ 2πr2 = 56.57 ⇒ r2 = 56.57 / 2 × 3.14 = 9 ⇒ r = 3 cm Now, volume of spherical ball = 4 / 3 πr3 = 4 / 3 × 3.14 × 3 × 3 × 3 = 113.04 cm3

Description : A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Last Answer : since curved surface of half of the spherical ball = 56.57 cm2 ∴ 2πr2 = 56.57 ⇒ r2 = 56.57 / 2 × 3.14 = 9 ⇒ r = 3 cm Now, volume of spherical ball = 4 / 3 πr3 = 4 / 3 × 3.14 × 3 × 3 × 3 = 113.04 cm3

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