The inner diameter of a cylindrical wooden -Maths 9th

The inner diameter of a cylindrical wooden -Maths 9th
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Answer :

Inner radius of the cylindrical pipe (r) = 24/2 cm = 12 cm Outer radius of the cylindrical pipe (R) = 28/2  cm = 14 cm Length of the cylindrical pipe (h) = 35 cm  Volume of the wood used in making the cylindrical pipe = πR2h - πr2h = πh(R2 - r2)  = 22/7 x 35(142 - 122) = 22/7 x 35(14 +12) (14 – 12) = 22/7 x 35 x 26 x 2 = 5720 cm3  Mass of 1 cm3 of wood = 0.6 g  ∴ Mass of 5720 cm3 of wood = (5720 x 0.6) g = 3432 g =  3432/1000 kg = 3.432 kg Thus, the mass of pipe = 3.43 kg
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