A triangle and a parallelogram have the same base and the same area. -Maths 9th

A triangle and a parallelogram have the same base and the same area. -Maths 9th
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Answer :

Let   a = 26 cm,    b  = 28 cm,   c = 30 cm  ∴  s = (a + b + c)/2  = (26 + 28 + 30)/2  =  84/2 = 42  ∴  Area of triangle = root under (√s(s - a )(s - b)(s - c)   = root under (√42(42 - 26)(42 - 28)(42 - 30)) = root under (√42 x 16 x 14 x 12) = root under (√2 x 3 x 7 x 2 x 2 x 2 x 2 x 2 x 7 x 2 x 2 x 3) = 2 x 2 x 2 x 2 x 3 x 7   =  336 cm2 Now, Area of  parallelogram = Area of triangle  ⇒ Base x height = 336 ⇒ 28 x height = 336  ⇒   height  =  336/28 = 12 cm
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A triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 26 cm, 28 cm and 30 cm, -Maths 9th

Description : A triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 26 cm, 28 cm and 30 cm, -Maths 9th

Last Answer : For the given triangle, we have a = 28 cm, b = 30 cm, c = 26 cm Area of the given parallelogram = Area of the given triangle ∴ Area of the parallelogram = 336 cm2 ⇒ base x height = 336 ⇒ ... be the height of the parallelogram. ⇒ h = 33628 = 12 Thus, the required height of the parallelogram = 12 cm

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In the figure, the area of parallelogram ABCD is -Maths 9th

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In figure, if parallelogram ABCD and rectangle ABEM are of equal area, then -Maths 9th

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The area of the parallelogram ABCD is 90 cm2. -Maths 9th

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Find the area of a parallelogram given in the figure. Also, find the length of the altitude from vertex A on the side DC. -Maths 9th

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