The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150, the resulting mean will be -Maths 9th

The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150, the resulting mean will be -Maths 9th
by

1 Answer

Answer :

Solution of this question
by

Related questions

The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150, the resulting mean will be -Maths 9th

Description : The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150, the resulting mean will be -Maths 9th

Last Answer : NEED ANSWER

Mean of 20 observations is 17. If in the observations, observation 40 is replaced by 12, find the new mean. -Maths 9th

Description : Mean of 20 observations is 17. If in the observations, observation 40 is replaced by 12, find the new mean. -Maths 9th

Last Answer : Since mean of 20 observations is 17 Sum of the 20 observations = 17 x 20 = 340 New sum of 20 observations = 340 – 40 + 12 = 312 New mean=312 / 20 =15.6

Mean of 20 observations is 17. If in the observations, observation 40 is replaced by 12, find the new mean. -Maths 9th

Description : Mean of 20 observations is 17. If in the observations, observation 40 is replaced by 12, find the new mean. -Maths 9th

Last Answer : Since mean of 20 observations is 17 Sum of the 20 observations = 17 x 20 = 340 New sum of 20 observations = 340 – 40 + 12 = 312 New mean=312 / 20 =15.6

Mean of 36 observations is 12. One observation 47 was misread as 74. Find the correct mean. -Maths 9th

Description : Mean of 36 observations is 12. One observation 47 was misread as 74. Find the correct mean. -Maths 9th

Last Answer : Mean of 36 observations = 12 Total of 36 observations = 36 x 12 = 432 Correct sum of 36 observations = 432 – 74 + 47 = 405 Correct mean of 36 observations = 405/ 36 =11.25

The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th

Description : The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th

Last Answer : Let the 8 observations are x1, x2, x3, x4, x5, x6, x7, x8 ∴ x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = 40 × 8 = 320 New mean = 320 + 5 × 8 = 360 / 8 = 45

Mean of 36 observations is 12. One observation 47 was misread as 74. Find the correct mean. -Maths 9th

Description : Mean of 36 observations is 12. One observation 47 was misread as 74. Find the correct mean. -Maths 9th

Last Answer : Mean of 36 observations = 12 Total of 36 observations = 36 x 12 = 432 Correct sum of 36 observations = 432 – 74 + 47 = 405 Correct mean of 36 observations = 405/ 36 =11.25

The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th

Description : The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th

Last Answer : Let the 8 observations are x1, x2, x3, x4, x5, x6, x7, x8 ∴ x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = 40 × 8 = 320 New mean = 320 + 5 × 8 = 360 / 8 = 45

The mean of 25 observations is 36. Out of these observations, if the mean of first 13 observations is 32 and that of the last 13 observations is 40, the 13th observation is -Maths 9th

Description : The mean of 25 observations is 36. Out of these observations, if the mean of first 13 observations is 32 and that of the last 13 observations is 40, the 13th observation is -Maths 9th

Last Answer : NEED ANSWER

The mean of 25 observations is 36. Out of these observations, if the mean of first 13 observations is 32 and that of the last 13 observations is 40, the 13th observation is -Maths 9th

Description : The mean of 25 observations is 36. Out of these observations, if the mean of first 13 observations is 32 and that of the last 13 observations is 40, the 13th observation is -Maths 9th

Last Answer : (b) Given, mean of 25 observations = 36 ∴ Sum of 25 observations = 36 x 25 = 900 Now, the mean of first 13 observations = 32 ∴ Sum of first 13 observations = 13 x 32 = 416 and the mean of last 13 ... - (Sum of 25 observations) = (520 + 416)-900 = 936 - 900 = 36 Hence, the 13th observation is 36.

Find the median of the following observations: 46,64,87,41,58,77,35,90,55,92,33. If 92 is replaced by 99 and 41 by 43. find the new median -Maths 9th

Description : Find the median of the following observations: 46,64,87,41,58,77,35,90,55,92,33. If 92 is replaced by 99 and 41 by 43. find the new median -Maths 9th

Last Answer : Here's ur answer Hope it has helped u..

Find the median of the following observations: 46,64,87,41,58,77,35,90,55,92,33. If 92 is replaced by 99 and 41 by 43. find the new median -Maths 9th

Description : Find the median of the following observations: 46,64,87,41,58,77,35,90,55,92,33. If 92 is replaced by 99 and 41 by 43. find the new median -Maths 9th

Last Answer : Here's ur answer Hope it has helped u..

Mean of 50 observations was found to be 80.4. -Maths 9th

Description : Mean of 50 observations was found to be 80.4. -Maths 9th

Last Answer : Here, n = 50, x̅ = 80.4 So, x̅ = ∑ xi/n ⇒ 80.4 = ∑ xi/50 ⇒ ∑ xi = 80.4 x 50 = 4020 Correct value of ∑ xi = 4020 - 69 + 96 = 4047 Correct mean = Correct value of ∑ xi/n = 4047/50 = 80.94

If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Description : If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Last Answer : x + x + 2 + x + 4 + x + 6 + x + 8 / 5 = 11 5x + 20 = 55 5x = 35 ⇒ x = 7

If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Description : If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Last Answer : x + x + 2 + x + 4 + x + 6 + x + 8 / 5 = 11 5x + 20 = 55 5x = 35 ⇒ x = 7

If the mean of the observations x, x + 3, x + 5, x + 7and x + 10 is 9, then mean of the last three observations is -Maths 9th

Description : If the mean of the observations x, x + 3, x + 5, x + 7and x + 10 is 9, then mean of the last three observations is -Maths 9th

Last Answer : NEED ANSWER

If the mean of the observations x, x + 3, x + 5, x + 7and x + 10 is 9, then mean of the last three observations is -Maths 9th

Description : If the mean of the observations x, x + 3, x + 5, x + 7and x + 10 is 9, then mean of the last three observations is -Maths 9th

Last Answer : According to question find the mean of the last three observations

The mean of the data set comprising of 16 observation is 16. If one of the observation valued 16 is deleted and three new observations 3, 4, & 5 are a

Description : The mean of the data set comprising of 16 observation is 16. If one of the observation valued 16 is deleted and three new observations 3, 4, & 5 are a

Last Answer : The mean of the data set comprising of 16 observation is 16. If one of the observation valued 16 is deleted and three ... B. 16.8 C. `14.0` D. `16.0`

If each observation of the data is increased by 5, then their mean -Maths 9th

Description : If each observation of the data is increased by 5, then their mean -Maths 9th

Last Answer : NEED ANSWER

If each observation of the data is increased by 5, then their mean -Maths 9th

Description : If each observation of the data is increased by 5, then their mean -Maths 9th

Last Answer : Simplify the question

A box contains 50 bolts and 150 nuts. On checking the box, it was found that half of the bolts and half of the nuts are rusted. -Maths 9th

Description : A box contains 50 bolts and 150 nuts. On checking the box, it was found that half of the bolts and half of the nuts are rusted. -Maths 9th

Last Answer : Total number of nuts and bolts in the box = 150 + 50 = 200 Number of nuts and bolts rusted = 1 / 2 × 200 = 100 P(a rusted nut or bolt) = 100 / 200 = 1 / 2

A box contains 50 bolts and 150 nuts. On checking the box, it was found that half of the bolts and half of the nuts are rusted. -Maths 9th

Description : A box contains 50 bolts and 150 nuts. On checking the box, it was found that half of the bolts and half of the nuts are rusted. -Maths 9th

Last Answer : Total number of nuts and bolts in the box = 150 + 50 = 200 Number of nuts and bolts rusted = 1 / 2 × 200 = 100 P(a rusted nut or bolt) = 100 / 200 = 1 / 2

Ten observations 6, 14, 15, 17, x + 1, 2x – 13, 30, 32, 34, 43 are written in ascending order. -Maths 9th

Description : Ten observations 6, 14, 15, 17, x + 1, 2x – 13, 30, 32, 34, 43 are written in ascending order. -Maths 9th

Last Answer : Here, the arranged data is 6, 14, 15, 17, x + 1, 2x - 13, 30, 32, 34, 43 Total number of observations = 10 Here, 10 is an even number , therefore median will be the mean of (10 / 2)th and (10 / 2 + 1)th observation. ... ⇒ 3x + 12 / 2 = 24 ⇒ 3x - 12 = 48 ⇒ 3x = 60 ⇒ x = 20 ∴ The value of x = 20

Ten observations 6, 14, 15, 17, x + 1, 2x – 13, 30, 32, 34, 43 are written in ascending order. -Maths 9th

Description : Ten observations 6, 14, 15, 17, x + 1, 2x – 13, 30, 32, 34, 43 are written in ascending order. -Maths 9th

Last Answer : Here, the arranged data is 6, 14, 15, 17, x + 1, 2x - 13, 30, 32, 34, 43 Total number of observations = 10 Here, 10 is an even number , therefore median will be the mean of (10 / 2)th and (10 / 2 + 1)th observation. ... ⇒ 3x + 12 / 2 = 24 ⇒ 3x - 12 = 48 ⇒ 3x = 60 ⇒ x = 20 ∴ The value of x = 20

Ten observations 6, 14, 15, 17, x+1, 2x -13, -Maths 9th

Description : Ten observations 6, 14, 15, 17, x+1, 2x -13, -Maths 9th

Last Answer : 6, 14, 15, 17, x + 1, 2x -13, 30, 32, 34, 43, Here, n = 10 Since the number of observations is 10 (an even number), therefore, the median = (10/2)th observation + (10/2 + 1)th observation/2 = 5th observation + 6th ... = x + 1 + 2x - 13/2 ⇒ 48 = 3x - 12 ⇒ 3x = 48 + 12 = 60 ⇒ x = 20

Water flows in a tank 150 m × 100 m at the base, through a pipe whose cross-section is 2 dm by 1.5 dm, at a speed of 15 km per hour. -Maths 9th

Description : Water flows in a tank 150 m × 100 m at the base, through a pipe whose cross-section is 2 dm by 1.5 dm, at a speed of 15 km per hour. -Maths 9th

Last Answer : Volume of water discharged through the pipe = Volume increase of the tank First, consider the pipe. Volume discharge through pipe = length breadth speed time Let the time taken to fill the tank to 3 m depth be t. ... the tank V=150 100 3 cu. m ⇒ V=450 100 Therefore, 450t=450 100 ⇒ t=100 hours

A tank internally measuring 150 cm × 120 cm × 100 cm has 1281600 cm^3 of water in it. Porous bricks are placed in the water until the tank -Maths 9th

Description : A tank internally measuring 150 cm × 120 cm × 100 cm has 1281600 cm^3 of water in it. Porous bricks are placed in the water until the tank -Maths 9th

Last Answer : Volume of a brick = 20 cm 6 cm 4 cm = 480 cm3. Water absorbed by one brick = (110 480)(110 480) cm3 = 48 cm3. Let x bricks be placed in the water. Then, x bricks absorb 48x cm3 of water. ... tank ⇒ 1281600 + 480xx - 48xx = 150 x 120 x 100 ⇒ 432xx = 1800000 - 1281600 = 518400 ⇒ xx = 1200.

The range of 12 observations is 60. If the least observation is 90, then find the greatest observation.

Description : The range of 12 observations is 60. If the least observation is 90, then find the greatest observation.

Last Answer : The range of 12 observations is 60. If the least observation is 90, then find the greatest observation. A. 130 B. 140 C. 150 D. 160

Pick up the correct statement from the following(A) The first man-made satellite, Sputnik-l' was launched on 4th October, 1957 (B) The United State's Explorer 6 transmitted the first picture of the earth in August 1959 (C) Television Infrared Observation Satellite (TIROS) designed for meteorological observations, started systematic earth observations from space from 1, April, 1960 (D) All of these

Description : Pick up the correct statement from the following (A) The first man-made satellite, Sputnik-l' was launched on 4th October, 1957 (B) The United State's Explorer 6 transmitted the first picture ... observations, started systematic earth observations from space from 1, April, 1960 (D) All of these

Last Answer : Answer: Option D

Pick up the correct statement from the following: (A) An observation or the resulting reading with the level on a levelling staff is called sight (B) A back sight is the first sight taken after setting up the instrument in any position (C) The first sight on each change point is a fore sight (D) All the above

Description : Pick up the correct statement from the following: (A) An observation or the resulting reading with the level on a levelling staff is called sight (B) A back sight is the first sight taken after setting up ... position (C) The first sight on each change point is a fore sight (D) All the above

Last Answer : (D) All the above

The median of the data 26,56,32,33,60,17,34,29,45 is 33. If 26 is replaced by 62, then find the new median. -Maths 9th

Description : The median of the data 26,56,32,33,60,17,34,29,45 is 33. If 26 is replaced by 62, then find the new median. -Maths 9th

Last Answer : Here, the given data in ascending order is 17, 29, 32, 33, 34, 45, 56, 60, 62 Now median is (9 + 1 / 2)th term i.e. , 5th term Hence, new median is 34.

The median of the data 26,56,32,33,60,17,34,29,45 is 33. If 26 is replaced by 62, then find the new median. -Maths 9th

Description : The median of the data 26,56,32,33,60,17,34,29,45 is 33. If 26 is replaced by 62, then find the new median. -Maths 9th

Last Answer : Here, the given data in ascending order is 17, 29, 32, 33, 34, 45, 56, 60, 62 Now median is (9 + 1 / 2)th term i.e. , 5th term Hence, new median is 34.

Counters marked 1, 2, 3 are placed in a bag and one is drawn and replaced. -Maths 9th

Description : Counters marked 1, 2, 3 are placed in a bag and one is drawn and replaced. -Maths 9th

Last Answer : (b) \(rac{7}{27}.\)Let S be the sample space of drawing a counter three times and replacing it each time. Then, n(S) = 3 3 3 = 27 Let A : Event of obtaining a total of 6 in the three draws of counters. Then, A = {(1, 2, 3), ... (2, 2, 2)} ⇒ n(A) = 7 ∴ P(A) = \(rac{n(A)}{n(S)}\) = \(rac{7}{27}.\)

Four healthy people in their twenties got involved in injuries resulting in damage and death of few cells of the following. Which of the cells are least likely to be replaced by new cells? (a) Liver cells (b) Neurons (c) Malpighian layer of the skin (d) Osteocytes

Description : Four healthy people in their twenties got involved in injuries resulting in damage and death of few cells of the following. Which of the cells are least likely to be replaced by new cells? (a) Liver cells (b) Neurons (c) Malpighian layer of the skin (d) Osteocytes

Last Answer : (b) Neurons

Write a story in about 150 words on the basis of following inputs. -Maths 9th

Description : Write a story in about 150 words on the basis of following inputs. -Maths 9th

Last Answer : answer:

The mean of 200 items was 50. Later on, it was discovered that the two items were misread as 92 and 8 instead of 192 and 88.find the correct mean. -Maths 9th

Description : The mean of 200 items was 50. Later on, it was discovered that the two items were misread as 92 and 8 instead of 192 and 88.find the correct mean. -Maths 9th

Last Answer : Here's ur answer..

There are 50 numbers. Each number is subtracted from 53 and the mean of the numbers so obtained is found to be – 3.5. Find the mean of the given numbers. -Maths 9th

Description : There are 50 numbers. Each number is subtracted from 53 and the mean of the numbers so obtained is found to be – 3.5. Find the mean of the given numbers. -Maths 9th

Last Answer : Let x be the mean of 50 numbers. ∴ sum of 50 numbers = 50x Since each number is subtracted from 53. According to question, we have 53 × 50 - 50x / 50 = - 3.5 ⇒ 2650 - 50x = -175 ⇒ 50x = 2825 ⇒ x = 2825 / 50 = 56.5

The mean of 200 items was 50. Later on, it was discovered that the two items were misread as 92 and 8 instead of 192 and 88.find the correct mean. -Maths 9th

Description : The mean of 200 items was 50. Later on, it was discovered that the two items were misread as 92 and 8 instead of 192 and 88.find the correct mean. -Maths 9th

Last Answer : Here's ur answer..

There are 50 numbers. Each number is subtracted from 53 and the mean of the numbers so obtained is found to be – 3.5. Find the mean of the given numbers. -Maths 9th

Description : There are 50 numbers. Each number is subtracted from 53 and the mean of the numbers so obtained is found to be – 3.5. Find the mean of the given numbers. -Maths 9th

Last Answer : Let x be the mean of 50 numbers. ∴ sum of 50 numbers = 50x Since each number is subtracted from 53. According to question, we have 53 × 50 - 50x / 50 = - 3.5 ⇒ 2650 - 50x = -175 ⇒ 50x = 2825 ⇒ x = 2825 / 50 = 56.5

There are 50 numbers. Each number is subtracted from 53 and the mean of the number so obtained is found to be – 3.5. -Maths 9th

Description : There are 50 numbers. Each number is subtracted from 53 and the mean of the number so obtained is found to be – 3.5. -Maths 9th

Last Answer : NEED ANSWER

There are 50 numbers. Each number is subtracted from 53 and the mean of the number so obtained is found to be – 3.5. -Maths 9th

Description : There are 50 numbers. Each number is subtracted from 53 and the mean of the number so obtained is found to be – 3.5. -Maths 9th

Last Answer : Find the mean of the given number is

Mean of the following is 50 find p -Maths 9th

Description : Mean of the following is 50 find p -Maths 9th

Last Answer : This answer was deleted by our moderators...

Match the following : Crops Annual Rainfall A. Rice 1. 100 to 150 cm B. Wheat 2. 50 to 75 cm C. Ragi 3. 40 to 50 cm D. Bajra 4. 50 to 100 cm A B C D (a) 1 2 4 3 (b) 4 3 2 1 (c) 3 2 1 4 (d) 2 1 3 4

Description : Match the following : Crops Annual Rainfall A. Rice 1. 100 to 150 cm B. Wheat 2. 50 to 75 cm C. Ragi 3. 40 to 50 cm D. Bajra 4. 50 to 100 cm A B C D (a) 1 2 4 3 (b) 4 3 2 1 (c) 3 2 1 4 (d) 2 1 3 4

Last Answer : Ans: (a)

Potassium content of muscle tissue in mg/100 ml is about (A) 50–100 (B) 100–150 (C) 250–400 (D) 150–200

Description : Potassium content of muscle tissue in mg/100 ml is about (A) 50–100 (B) 100–150 (C) 250–400 (D) 150–200

Last Answer : Answer : C

The normal concentration of potassium in whole blood is (A) 50 mg/100 ml (B) 100 mg/100 ml (C) 150 mg/100 ml (D) 200 mg/100 ml

Description : The normal concentration of potassium in whole blood is (A) 50 mg/100 ml (B) 100 mg/100 ml (C) 150 mg/100 ml (D) 200 mg/100 ml

Last Answer : Answer : D

The oxidation of 100 gm of fat yields (A) 50 gm water (B) 107 gm water (C) 150 gm water (D) 200 gm water

Description : The oxidation of 100 gm of fat yields (A) 50 gm water (B) 107 gm water (C) 150 gm water (D) 200 gm water

Last Answer : Answer : B

The total serum testosterone in adult men is (A) 50–100 ng/100 ml (B) 150–250 ng/100 ml (C) 300–1000 ng/100 ml (D) 1000–3000 ng/100 ml

Description : The total serum testosterone in adult men is (A) 50–100 ng/100 ml (B) 150–250 ng/100 ml (C) 300–1000 ng/100 ml (D) 1000–3000 ng/100 ml

Last Answer : Answer : C

The insulin content of pancreas is about (A) 50–70 units (B) 100–150 units (C) 150–180 units (D) 200–250 units

Description : The insulin content of pancreas is about (A) 50–70 units (B) 100–150 units (C) 150–180 units (D) 200–250 units

Last Answer : Answer : D

Quantity of copper present in the body of an adult is (A) 0–50 mg (B) 50–100 mg (C) 100–150 mg (D) 150–250 mg

Description : Quantity of copper present in the body of an adult is (A) 0–50 mg (B) 50–100 mg (C) 100–150 mg (D) 150–250 mg

Last Answer : Answer : C

Daily iodine requirement of an adult is about (A) 50 µg (B) 100 µg (C) 150 µg (D) 1 mg

Description : Daily iodine requirement of an adult is about (A) 50 µg (B) 100 µg (C) 150 µg (D) 1 mg

Last Answer : Answer : C

For an adult male daily requirement of iodine is (A) 25–50 µg (B) 50–100 µg (C) 100–150 µg (D) 200–250 µg

Description : For an adult male daily requirement of iodine is (A) 25–50 µg (B) 50–100 µg (C) 100–150 µg (D) 200–250 µg

Last Answer : Answer : A