Description : The mean of 25 observations is 36. Out of these observations, if the mean of first 13 observations is 32 and that of the last 13 observations is 40, the 13th observation is -Maths 9th
Last Answer : (b) Given, mean of 25 observations = 36 ∴ Sum of 25 observations = 36 x 25 = 900 Now, the mean of first 13 observations = 32 ∴ Sum of first 13 observations = 13 x 32 = 416 and the mean of last 13 ... - (Sum of 25 observations) = (520 + 416)-900 = 936 - 900 = 36 Hence, the 13th observation is 36.
Description : Mean of 36 observations is 12. One observation 47 was misread as 74. Find the correct mean. -Maths 9th
Last Answer : Mean of 36 observations = 12 Total of 36 observations = 36 x 12 = 432 Correct sum of 36 observations = 432 – 74 + 47 = 405 Correct mean of 36 observations = 405/ 36 =11.25
Description : Mean of 20 observations is 17. If in the observations, observation 40 is replaced by 12, find the new mean. -Maths 9th
Last Answer : Since mean of 20 observations is 17 Sum of the 20 observations = 17 x 20 = 340 New sum of 20 observations = 340 – 40 + 12 = 312 New mean=312 / 20 =15.6
Description : The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th
Last Answer : Let the 8 observations are x1, x2, x3, x4, x5, x6, x7, x8 ∴ x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = 40 × 8 = 320 New mean = 320 + 5 × 8 = 360 / 8 = 45
Description : Ten observations 6, 14, 15, 17, x + 1, 2x – 13, 30, 32, 34, 43 are written in ascending order. -Maths 9th
Last Answer : Here, the arranged data is 6, 14, 15, 17, x + 1, 2x - 13, 30, 32, 34, 43 Total number of observations = 10 Here, 10 is an even number , therefore median will be the mean of (10 / 2)th and (10 / 2 + 1)th observation. ... ⇒ 3x + 12 / 2 = 24 ⇒ 3x - 12 = 48 ⇒ 3x = 60 ⇒ x = 20 ∴ The value of x = 20
Description : The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150, the resulting mean will be -Maths 9th
Last Answer : NEED ANSWER
Last Answer : Solution of this question
Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles
Last Answer : 22
Description : Ten observations 6, 14, 15, 17, x+1, 2x -13, -Maths 9th
Last Answer : 6, 14, 15, 17, x + 1, 2x -13, 30, 32, 34, 43, Here, n = 10 Since the number of observations is 10 (an even number), therefore, the median = (10/2)th observation + (10/2 + 1)th observation/2 = 5th observation + 6th ... = x + 1 + 2x - 13/2 ⇒ 48 = 3x - 12 ⇒ 3x = 48 + 12 = 60 ⇒ x = 20
Description : If the mean of the observations x, x + 3, x + 5, x + 7and x + 10 is 9, then mean of the last three observations is -Maths 9th
Last Answer : According to question find the mean of the last three observations
Description : If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th
Last Answer : x + x + 2 + x + 4 + x + 6 + x + 8 / 5 = 11 5x + 20 = 55 5x = 35 ⇒ x = 7
Description : Mean of 50 observations was found to be 80.4. -Maths 9th
Last Answer : Here, n = 50, x̅ = 80.4 So, x̅ = ∑ xi/n ⇒ 80.4 = ∑ xi/50 ⇒ ∑ xi = 80.4 x 50 = 4020 Correct value of ∑ xi = 4020 - 69 + 96 = 4047 Correct mean = Correct value of ∑ xi/n = 4047/50 = 80.94
Description : The line L is given by x/5 + y/b = 1 passes through the point (13, 32). The line K is parallel to L and has the equation -Maths 9th
Last Answer : (a) 45º The equations of the given lines are: A\(x\) + By = A + B ⇒ By = -A\(x\) + (A + B) ⇒ y = \(-rac{A}{B}x\) + \(rac{(A+B)}{B}\) ....(i)and A(\(x\) - y) + B(\(x\) ... (ii) = m2 = \(rac{(A+B)}{B-A}\)Let θ be the angle between both the lines, then∴ tan θ = 1 ⇒ θ = tan-1 (1) = 45°.
Description : The mean of the data set comprising of 16 observation is 16. If one of the observation valued 16 is deleted and three new observations 3, 4, & 5 are a
Last Answer : The mean of the data set comprising of 16 observation is 16. If one of the observation valued 16 is deleted and three ... B. 16.8 C. `14.0` D. `16.0`
Description : The spacing between the discs in the gang bolt ranges cm for lighy duty and cm heavy -duty harrows i. 15-25 and 25-30 c) 40-45 and 45-50 ii. 20-30 and 30-40. d) 15-25 and 32-36
Last Answer : 15-25 and 25-30
Description : If each observation of the data is increased by 5, then their mean -Maths 9th
Last Answer : Simplify the question
Description : Pick up the correct statement from the following (A) The first man-made satellite, Sputnik-l' was launched on 4th October, 1957 (B) The United State's Explorer 6 transmitted the first picture ... observations, started systematic earth observations from space from 1, April, 1960 (D) All of these
Last Answer : Answer: Option D
Description : Find the median of the following observations: 46,64,87,41,58,77,35,90,55,92,33. If 92 is replaced by 99 and 41 by 43. find the new median -Maths 9th
Last Answer : Here's ur answer Hope it has helped u..
Description : The range of 12 observations is 60. If the least observation is 90, then find the greatest observation.
Last Answer : The range of 12 observations is 60. If the least observation is 90, then find the greatest observation. A. 130 B. 140 C. 150 D. 160
Description : Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th
Last Answer : Here, the minimum and maximum values of given data are 6 and 32 respectively. Range = 32 – 6 = 26
Description : Find the median of the values 37, 31, 42, 43, 46, 25, 39, 45, 32. -Maths 9th
Last Answer : Arranging the data in ascending order, we have 25, 31, 32, 37, 39, 42, 43, 45, 46 Here, number of observations = 9 (odd) Median = value of (9+1 / 2)th Observation = Value of 5th Observation = 39
Description : The range of the data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11 and 20 is -Maths 9th
Last Answer : In conclusion, the range of data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, and 20 is 26.
Last Answer : (d) In a given data, maximum value = 32 and minimum value = 6 We know, range of the data = maximum value – minimum value = 32 – 6 = 26 Hence, the range of the given data is 26.
Description : A field is in the shape of a trapezium whose parallel sides are 25 m and 10 m. The non-parallel sides are 14 m and 13 m. Find the area of the field. -Maths 9th
Last Answer : Let the given field is in the form of a trapezium ABCD such that parallel sides are AB = 10 m and DC = 25 m Non-parallel sides are AD = 13 m and BC = 14 m. We draw BE || AD, such that BE = 13 m. ... = 112 m2 So, area of the field = area of ∆BCE + area of parallelogram ABED = 84 m2 + 112 m2 = 196 m2
Description : Find the area of a trapezium whose parallel sides are 25 cm and 13 cm long and the distance between them is 8 cm. -Maths 9th
Last Answer : Area of a trapezium = 1/2(sum of parallel sides) x (perpendicular diatance between them) = 1/2(25 + 13) x 8 = 152cm2
Description : If the average of 4 observations x, x+1, x+2, x+3 is 12 then the average of last 2 observations is A) 10 B) 11 C) 12 D) 13
Last Answer : D) We have (x+x+1+x+2x+3/40=12 4x+6=48 4x=42 x=10.5 so the numbers are 10.5,11.5, 12.5, 13.5 required average = 12.5+13.5/2 =26/2 =13.
Description : BMR of healthy adult women is about (A) 32 kcal/hour/square metre (B) 36 kcal/hour/square metre (C) 40 kcal/hour/square metre (D) 44 kcal/hour/square metre
Last Answer : Answer : B
Description : 40 39 32 37 16 ? -8 a) 35 b) 36 c) 33 d) 32 e) 40
Last Answer : The series is + (1^2 - 2), – (2^2 + 3), + (3^2 - 4), –(4^2 + 5), ..... Answer: a)
Description : One writes all numbers from 50 to 99 without the digits 2 and 7. How many numbers have been written? (A) 32 (B) 36 (C) 40 (D) 38
Last Answer : Answer: A
Description : The average age of K and L is 48 years. If M replaced K, the average age would be 40 and if M replaced L, the average would be 44. What are the ages of K,L,M repectively? A) 58, 46, 22 B) 32, 44, 36 C) 52,44,36 D) 56, 22,38
Last Answer : Answer: C) Total age of K& L = 48*2 = 96 yrs----->1 Total age of L& M = 40*2 = 80yrs----->2 Total age of K& M = 44*2 = 88 yrs----->3 from 1, 2, 3 K+L+M =132---->4 from 1 & 4, M= 36 from 2 & 4, K=52 from 3 & 4, L=44 Hence the required answer is 52,44,36
Description : I was curious if anyone out there knew how to change Peachtree accounting from a 13 month period (where 13th month is Dec 31-Dec31) to a 12 Month period (where each month is a period)
Last Answer : You can setup a new Company defining a 12 period year. Make sure to UNCHECK the line referencing ACCOUNTING PERIODS, and then you will have the opportunity to select your starting Month and ... Company shell. Check the Peachtree HELP and search on Rebuild or Rebuilding Company for more information.
Description : A man was found dead next to a 13 story building. The police say it was a suicide, but you say it was a homicide (someone killed him). To prove this, you go to each floor on the building, open ... 13th floor, open the window, and toss a penny out. How does this prove it wasn't a suicide? -Riddles
Last Answer : If the man committed suicide, he would've left the window open and you wouldn't have had to open it.
Description : A metallic sheet is of rectangular shape with dimensions 48 cm x 36 cm. From each of its corners, a square of 8 cm is cut-off and an open box is made of the remaining sheet. Find the volume of the box. -Maths 9th
Last Answer : When squares of 8 cm is cutt-off from rectangulare sheet then, Length of box (l) = (98 - 8 - 8) = 32 cm Breadth of box (b) = (36 - 8 - 8) = 20 cm Height of box (h) = 8cm ∴ Volume of box = lbh = 32 x 20 x 8 = 5120 cm3
Description : In a survey of 364 children aged 19-36 months, it was found that 91 liked to eat potato chips. -Maths 9th
Last Answer : Total children = 364 Number of children like potato chips = 91 Number of children do not like potato chips = 364 – 91 = 273 273 Required probability = 273 / 364 =0.75
Description : (36)^7/2 - (36)^5/2 ÷ (36)^3/2 -Maths 9th
Last Answer : (c) Total number of survey children's age from 19-36 months, n(S) = 364 In those of them 91 out of them liked to eat potato chips. ∴ Number of children who do not like to eat potato chips, n(E) = ... S) = 273/364 = 0.75 Hence, the probability that he/she does not like to eat potato chips is 0.75.
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