Description : The total sulphur content of the body is (A) 25–50 gm (B) 50–75 gm (C) 100–125 gm (D) 150–200 gm
Last Answer : Answer : D
Description : Each gm of protein on complete oxidation yields (A) 0.21 gm water (B) 0.31 gm water (C) 0.41 gm water (D) 0.51 gm water
Last Answer : Answer : C
Description : One gram of fat on complete oxidation in the body yields about (A) 4 Kcal (B) 6 Kcal (C) 9 Kcal (D) 12 Kcal
Description : Dust content in raw blast furnace gas is about __________ gm/Nm3 ; hence it is cleaned to the dust level of about < 10 mg /Nm3 before use. (A) 15-30 (B) 1-2 (C) 70-100 (D) 150-200
Last Answer : (A) 15-30
Description : Potassium content of muscle tissue in mg/100 ml is about (A) 50–100 (B) 100–150 (C) 250–400 (D) 150–200
Description : The normal concentration of potassium in whole blood is (A) 50 mg/100 ml (B) 100 mg/100 ml (C) 150 mg/100 ml (D) 200 mg/100 ml
Description : The insulin content of pancreas is about (A) 50–70 units (B) 100–150 units (C) 150–180 units (D) 200–250 units
Description : For an adult male daily requirement of iodine is (A) 25–50 µg (B) 50–100 µg (C) 100–150 µg (D) 200–250 µg
Last Answer : Answer : A
Description : The amount of coproporphyrins excreted per day in feces is about (A) 10–50 µgs (B) 100–150 µgs (C) 200–250 µgs (D) 300–1000 µgs
Description : After accounting for SDA, the net gain of energy from 100 gm of fat is about (A) 600 kcal (B) 780 kcal (C) 900 kcal (D) 1020 kcal
Last Answer : Answer : B
Description : After accounting for SDA, the net gain of energy from 25 gm of proteins is about (A) 70 kcal (B) 100 kcal (C) 130 kcal (D) 200 kcal
Description : In slow sand filters, the turbidity of raw water can be removed only up to (A) 60 mg/litre (B) 75 mg/litre (C) 100 gm/litre (D) 150 mg/litre
Last Answer : (A) 60 mg/litre
Description : The prescribed hardness limit of potable water ranges between (A) 50 to 75 P.P.M. (B) 75 to 115 P.P.M. (C) 100 to 150 P.P.M. (D) 150 to 200 P.P.M.
Last Answer : (B) 75 to 115 P.P.M.
Description : One gram of protein on complete oxidation in the body yields about (A) 2 Kcal (B) 4 Kcal (C) 8 Kcal (D) 12 Kcal
Description : One gram of carbohydrate on complete oxidation in the body yields about (A) 1 Kcal (B) 4 Kcal (C) 6 Kcal (D) 9 Kcal
Description : Complete oxidation of one molecule of glucose into CO2 and H2O yields (A) 8 ATP equivalents (B) 15 ATP equivalents (C) 30 ATP equivalents (D) 38 ATP equivalents
Description : Oxidation of one molecule of glucose yields (A) 12 ATP (B) 24 ATP (C) 38 ATP (D) 38 ATP
Description : Which of the following statement regarding β-oxidation is true? (A) Requires β-ketoacyl CoA as a substrate (B) Forms CoA thioesters (C) Requires GTP for its activity (D) Yields acetyl CoA as a product
Description : Oxidation of galactose with conc HNO3 yields (A) Mucic acid (B) Glucuronic acid (C) Saccharic acid (D) Gluconic acid
Last Answer : A
Description : Oxidation of which substance in the body yields the most calories (A) Glucose (B) Glycogen (C) Protein (D) Lipids
Last Answer : D
Description : A screw jack has 4 threads per inch. The mean radius of the thread is 2.338 inches. The mean diameter of the bearing surface under the cap is 3.25 inches. What is the turning moment required to raise the bload of 150 kg ( a.5.61 kg-inch b.50.6 kg-inch c.107 dynes d.30.3 kg-inch e.23.6 kg-inch
Last Answer : b. 50.6 kg-inch
Description : The State Bank of India has created how much crores fund for investing in IT or Fintech startups? A) 200 B) 50 C) 100 D) 150 E) 300
Last Answer : A) 200 Explanation: India s largest public sector lender State Bank of India has created IT innovations and startup fund and have allotted Rs 200 crore for investment in promising ... for any India registered entity for their business promotion in India using information technology for banking.
Description : In case of failed ATM transactions, if the amount is not credited to customer‟s account within 7 working days from the date of receipt of the complaint. Banks have to pay compensation at the rate of Rs.________ per day. A. 150 B. 200 C. 100 D. 10 E. 50
Last Answer : C. 100 Explanation: Reconciliation of failed transactions at ATMs – For any failure to re-credit the customer‘s account within 7 working days from the date of receipt of the complaint, the bank will pay compensation of Rs.100/-, per day, to the aggrieved customer.
Description : If the depletion of oxygen is found to be 5 ppm after incubating a 2.5% solution of sewage sample for 5 days at 21°C, B.O.D. of the sewage is A. 50 ppm B. 100 ppm C. 150 ppm D. 200 ppm
Last Answer : ANS: D
Description : Lifetime of ILD’s A. 150,000 h B. 100,000 h C. 50,000 h D. 200,000 h
Last Answer : C. 50,000 h
Description : Flat Rate parcel price 1Kg, 2 Kg & 5 Kg are a) 125,200 & 400 b) 100,150 & 200 c) 50,100 &150 d) None of these
Last Answer : a) 125,200 & 400
Description : Fee for availing business reply service a) Apr to Jun -100, Jul to Sep-75, Oct to Dec-50, Jan to Mar -25 b) Apr to Jun -200, Jul to Sep-150, Oct to Dec-100, Jan to Mar -50 c) Apr to Jun -250, Jul to Sep-150, Oct to Dec-75, Jan to Mar -50 d) Free of cost
Last Answer : b) Apr to Jun -200, Jul to Sep-150, Oct to Dec-100, Jan to Mar -50
Description : Each serving machine is responsible for about _____ tablets in BigTable. a) 150 b) 100 c) 50 d) 200
Last Answer : 100
Description : The horizontal deflection of a parabolic curved beam of span 10 m and rise 3 m when loaded with a uniformly distributed load l t per horizontal length is (where Ic is the M.I. at the crown, which varies as the slope ... arch). (A) 50/EIc (B) 100/EIc (C) 150/EIc (D) 200/E
Last Answer : (D) 200/E
Description : A thin, flat & square plate measuring 2 m 2 m is freely hanging in ambient air at 25°C. It is exposed to the solar radiation falling on one side of the plate at the rate of 500 W/m2. The plate temperature will ... heat transfer co-efficient is __________ W/m2 °C. (A) 50 (B) 100 (C) 150 (D) 200
Last Answer : (B) 100
Description : If the maximum shear stress at the end of a simply supported R.C.C. beam of 6 m effective span is 10 kg/cm2 , the share stirrups are provided for a distance from either end where, is (A) 50 cm (B) 100 cm (C) 150 cm (D) 200 cm
Last Answer : Answer: Option C
Description : If depth of slab is 10 cm, width of web 30 cm, depth of web 50 cm, centre to centre distance of beams 3 m, effective span of beams 6 m, the effective flange width of the beam, is (A) 200 cm (B) 300 cm (C) 150 cm (D) 100 cm
Description : Indian Meteorological department uses the standard gauges whose collectors have apertures of (A) 50 or 100 sq. cm area (B) 100 or 150 sq. cm area (C) 100 or 200 sq. cm area (D) 250 or 500 sq. cm area
Description : Minimum thickness of load bearing RCC wall should be (A) 50 mm (B) 100 mm (C) 150 mm (D) 200 mm
Last Answer : (B) 100 mm
Description : Crushing strength of a good building stone should be more than (A) 50 MPa (B) 100 MPa (C) 150 MPa (D) 200 MPa
Last Answer : Answer: Option B
Description : The minimum strength of the mortar used in load bearing brick masonry, is (A) 50 N/cm2 (B) 100 N/cm2 (C) 150 N/cm2 (D) 200 N/cm2
Last Answer : : Option B
Description : A trader wants to sell a watch at 25% profit. If its cost price was Rs.x more, an extra profit of Rs.50 would be made on it. find x(in Rs.) a)100 b)125 c)150 d)200
Last Answer : d)200
Description : Calculate the value of closing stock from the following according to Weighted Average method: 1st January, 2014: Opening balance: 50 units @ Rs. 4 Receipts: 5th January, 2014: 100 units @ Rs. 5 12th January, 2014: 200 units ... 2014: 150 units (a) Rs. 765 (b) Rs. 805 (c) Rs. 786 (d) Rs. 700
Last Answer : (c) Rs. 786
Description : Calculate the value of closing stock from the following according to LIFO method: 1st January, 2014: Opening balance: 50 units @ Rs. 4 Receipts: 5th January, 2014: 100 units @ Rs. 5 12th January, 2014: 200 units @ Rs. 4.50 ... , 2014: 150 units (a) Rs. 765 (b) Rs. 805 (c) Rs. 786 (d) Rs. 700
Last Answer : (b) Rs. 805
Description : Calculate the value of closing stock from the following according to FIFO method: 1st January, 2014: Opening balance: 50 units @ Rs. 4 Receipts: 5th January, 2014: 100 units @ Rs. 5 12th January, 2014: 200 units @ Rs. 4.50 ... , 2014: 150 units (a) Rs. 765 (b) Rs. 805 (c) Rs. 786 (d) Rs. 700
Last Answer : (a) Rs. 765
Description : Maximum number of members in case of public company is: A. 50 B. 100 C. 150 D. 200
Last Answer : D. 200
Description : Water derived in gm from complete oxidation of each gm of carbohydrate is about (A) 0.15 (B) 0.25 (C) 0.35 (D) 0.55
Description : The total calcium of the human body is about (A) 100–150 g (B) 200–300 g (C) 1–1.5 kg (D) 2–3 kg
Description : Which of the following could be the unit of rotational inertia of a body in CGS system? a.cm4 b.gm-cm2 c.107 dynes d.kg-cm2 e.gm-cm4
Last Answer : b. gm-cm2
Description : Pick out the wrong statement. Iodine value of an oil or fat is (A) The number of grams of iodine taken up by 100 gm of oil or fat (B) A measure of its unsaturation (C) Helpful in findings ... & its suitability for making soap (D) Independent of the type of oil, whether it is drying or non-drying
Last Answer : (D) Independent of the type of oil, whether it is drying or non-drying
Description : The brain of human adult weighs about-----? A. 1200 – 1300 gm (Answer) B. 1600 – 2000 gm C. 500 – 800 gm D. 100 – 200 gm
Last Answer : A. 1200 – 1300 gm (Answer)
Description : The brain of human adult weighs about (1) 1200 – 1300 gm (2) 1600 – 2000 gm (3) 500 – 800 gm (4) 100 – 200 gm
Last Answer : 1200 – 1300 gm
Description : A flywheel 200 cm in diameter is rotating at 100 rpm. A point on the rim of the flywheel will not have a.angular velocity b.centripental acceleration c.tangential acceleration d.all of the above e.107 dynes
Last Answer : c. tangential acceleration
Description : A flywheel 200 cm in diameter is rotating at 100 rpm. A point one the rim of the flywheel will not have a.angular velocity b.centripetal acceleration c.tangential acceleration d.all of the above e.107 dynes
Last Answer : a. angular velocity
Description : Saponification number is (A) mg of KOH required to saponify one gm of fat or oil (B) mg of KOH required to neutralize free fatty acids of one gms of fat (C) mg of KOH required to neutralize the acetic acid obtained by saponification of one gm of fat after it has been acetylated (D) None of these