The diagonals AC and BD of parallelogram ABCD intersect at the point O. -Maths 9th

The diagonals AC and BD of parallelogram ABCD intersect at the point O. -Maths 9th
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ABCD is a parallelogram . ∴ AD | | BC ⇒  ∠ACB = ∠DAC = 34° Now, ∠AOB is an exterior angle of △BOC   ∴ ∠OBC + OCB =  ∠AOB [∵ ext  ∠ = sum of two int. opp. ∠S] ⇒ ∠OBC + 34° = 75°  ⇒  ∠OBC  = 75° - 34° = 41°   or ∠DBC = 41°       
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