In old age I'm lost, in trauma I'm tossed. What am I? -Riddles

In old age I'm lost, in trauma I'm tossed. What am I? -Riddles
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1 Answer

Answer :

Memories.
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Some will use me, while others will not, some have remembered, while others have forgot. For profit or gain, I'm used expertly, I can't be picked off the ground or tossed into the sea. Only gained from patience and time, can you unravel my rhyme? What am I? -Riddles

Description : Some will use me, while others will not, some have remembered, while others have forgot. For profit or gain, I'm used expertly, I can't be picked off the ground or tossed into the sea. Only gained from patience and time, can you unravel my rhyme? What am I? -Riddles

Last Answer : I'm Knowledge.

.Which of the following is true: A. Antibiotics are useful in the treatment of periodontitis B. Trauma from occlusion causes thickening of the marginal gingivae C. Periodontitis is the primary cause of teeth lost after the age of 35. D. All periodontal pockets can be identified by x-ray E. Periodontitis is the most common disease in the oral cavity

Description : .Which of the following is true:  A. Antibiotics are useful in the treatment of periodontitis   B. Trauma from occlusion causes thickening of the marginal gingivae  C. Periodontitis is the ... can be identified by x-ray  E. Periodontitis is the most common disease in the oral cavity

Last Answer : E. Periodontitis is the most common disease in the oral cavity

I am a thing of eternal paradox. My courage is fueled by righteous anger, but I am blinded by consuming rage, fed from my grudges. My empathy makes me vulnerable to others grief, but in the end, it is my own connection to similar trauma that breeds these sympathetic tears. Despite knowing that my entire world will one day fade into dust, I am overwhelmed with joy. Who am I? -Riddles

Description : I am a thing of eternal paradox. My courage is fueled by righteous anger, but I am blinded by consuming rage, fed from my grudges. My empathy makes me vulnerable to others grief, but in the end, it is ... that my entire world will one day fade into dust, I am overwhelmed with joy. Who am I? -Riddles

Last Answer : This answer was deleted by moderators

A rubber ball is tossed off the top of a 90 foot building. Every time it bounces, it goes back up half way. How many bounces will the ball take before it stops? -Riddles

Description : A rubber ball is tossed off the top of a 90 foot building. Every time it bounces, it goes back up half way. How many bounces will the ball take before it stops? -Riddles

Last Answer : The answer is infinite, in a gravity free world. But of course gravity will eventually stop it.

I can easily get lost or stolen, I am highly noticeable, I'm bigger than an iPhone, I can only fit in a backpack and I'm only allowed to stay at home for safety. -Riddles

Description : I can easily get lost or stolen, I am highly noticeable, I'm bigger than an iPhone, I can only fit in a backpack and I'm only allowed to stay at home for safety. -Riddles

Last Answer : An iPad.

I hurt the most when lost, yet also when not had at all. I'm sometimes the hardest to express, but the easiest to ignore. I can be given to many, or just one. What am I? -Riddles

Description : I hurt the most when lost, yet also when not had at all. I'm sometimes the hardest to express, but the easiest to ignore. I can be given to many, or just one. What am I? -Riddles

Last Answer : Love.

The king dies and two men, the true heir and an impostor, both claim to be his long-lost son. Both fit the description of the rightful heir: about the right age, height, coloring and general appearance. Finally, one of the elders proposes a test to identify the true heir. One man agrees to the test while the other flatly re-fuses. The one who agreed is immediately sent on his way, and the one who re-fused is correctly identified as the rightful heir. Can you figure out why? -Riddles

Description : The king dies and two men, the true heir and an impostor, both claim to be his long-lost son. Both fit the description of the rightful heir: about the right age, height, coloring and general ... the one who re-fused is correctly identified as the rightful heir. Can you figure out why? -Riddles

Last Answer : The test was a blood test. The elder remembered that the true prince was a hemophiliac.

My age today is three times what it will be three years from now minus three times what my age was three years ago. How old am I? -Riddles

Description : My age today is three times what it will be three years from now minus three times what my age was three years ago. How old am I? -Riddles

Last Answer : Don't be too confused, the answer is 18 years old.

I can be old or new, big or small, thick or thin. I contain information about all that is present in the entire world. I contain links to countless minds, worlds, adventures, universes, mysteries, and even mystical things. I am a place where things are out of the world and where imaginations are realities. People fill me with their thoughts, opinions, and life stories. Most children tend to think I'm boring, but there are only a few truly talented, out of this world, beautiful-minds who wait for me enthusiastically and when done with me, waits for my descendants. What am I? -Riddles

Description : I can be old or new, big or small, thick or thin. I contain information about all that is present in the entire world. I contain links to countless minds, worlds, adventures, universes, mysteries, ... wait for me enthusiastically and when done with me, waits for my descendants. What am I? -Riddles

Last Answer : Books! Come on, who doesn't love to curl up with a good book beside the fireplace?!

When I'm new, I'm worthless. After I'm old and used, I'm worth hundreds, thousands and millions. What am I? -Riddles

Description : When I'm new, I'm worthless. After I'm old and used, I'm worth hundreds, thousands and millions. What am I? -Riddles

Last Answer : A canvas. A blank canvas is worthless until it becomes a painting!

I'm from the Old World, and my name from Latin; I can be cured, or served with au gratin. What am I? -Riddles

Description : I'm from the Old World, and my name from Latin; I can be cured, or served with au gratin. What am I? -Riddles

Last Answer : Beef.

I have three colors, each with a different meaning. When I'm old they become dull, but when I'm new they are gleaming. I help keep people safe, but sometimes they hate me. You won't see me in a forest, but you will in a big city. Some of me have short lengths, and some of me have long. And in the time that the longest of me take, you could sing a very long song. When my colors change, people get happy or sad, and when you guess what I am, you will be very glad. What am I? -Riddles

Description : I have three colors, each with a different meaning. When I'm old they become dull, but when I'm new they are gleaming. I help keep people safe, but sometimes they hate me. You won't see me in a forest, ... get happy or sad, and when you guess what I am, you will be very glad. What am I? -Riddles

Last Answer : A Stoplight.

It's true I am hot and cold, and I'm always with the old. Youth requires what life does not see, and the heart of groups requires me. I stand alone within all holes, never to see the light of day. Let my turmoil bring you joy since I don't ever make you pay. What am I? -Riddles

Description : It's true I am hot and cold, and I'm always with the old. Youth requires what life does not see, and the heart of groups requires me. I stand alone within all holes, never to see the light of day. Let my turmoil bring you joy since I don't ever make you pay. What am I? -Riddles

Last Answer : The letter O.

I was a stage critic in the days of old. Some thought I was poisonous, others knew better. I'm often thought to be something I'm not, and I'm usually round and never bitter. What am I? -Riddles

Description : I was a stage critic in the days of old. Some thought I was poisonous, others knew better. I'm often thought to be something I'm not, and I'm usually round and never bitter. What am I? -Riddles

Last Answer : A tomato.

I'm tall when I'm young and I'm short when I'm old. What am I? -Riddles

Description : I'm tall when I'm young and I'm short when I'm old. What am I? -Riddles

Last Answer : Candle or Pencil.

I sound a color,But that's the old me;I grow near the water;I'm what your doing.What am I? -Riddles

Description : I sound a color,But that's the old me;I grow near the water;I'm what your doing.What am I? -Riddles

Last Answer : Read/Reed

I’m tall when I’m young and I’m short when I’m old. What am I? -Riddles

Description : I’m tall when I’m young and I’m short when I’m old. What am I? -Riddles

Last Answer : One of the four things which came to my mind :A burning candle.A mountain/hill. The process is called denudation , under which mountains/hills lose their height as those become older, due to natural ... which is being eaten or a food item which is similar in external structure.A pencil or a chalk.

’m tall when I’m young, and I’m short when I’m old, what am I -Riddles

Description : ’m tall when I’m young, and I’m short when I’m old, what am I -Riddles

Last Answer : answer:

I have legs, but won't walk A mouth that will not talk Woodland home, lost to me Stabled now, in nursery Made to move, but must stay You won't hear me say nay. What am I? -Riddles

Description : I have legs, but won't walk A mouth that will not talk Woodland home, lost to me Stabled now, in nursery Made to move, but must stay You won't hear me say nay. What am I? -Riddles

Last Answer : Rocking horse.

I am said to be strong and unbreakable yet gental and kind. I may be suppressed but not ignored. I can be lost but may be found. I can die yet still live on. What am I? -Riddles

Description : I am said to be strong and unbreakable yet gental and kind. I may be suppressed but not ignored. I can be lost but may be found. I can die yet still live on. What am I? -Riddles

Last Answer : The sun.

I am free, yet priceless.You can't own me, but you can use me.You can't keep me, but you can spend me.Once you have lost me, you can never retrieve me.What am I? -Riddles

Description : I am free, yet priceless.You can't own me, but you can use me.You can't keep me, but you can spend me.Once you have lost me, you can never retrieve me.What am I? -Riddles

Last Answer : Time.

I am free yet priceless, you can't own me but you can use me, you can't keep me but you can spend me. Once you lost me you can never have me back. What am I? -Riddles

Description : I am free yet priceless, you can't own me but you can use me, you can't keep me but you can spend me. Once you lost me you can never have me back. What am I? -Riddles

Last Answer : Time.

A 59-year-old trauma patient has suffered multiple septic complications including severe pneumonia, intraabdominal abscess, and major wound infection. He has now developed signs of multisystem organ failure. Which of the following statement(s) is/are true concerning necessary changes to be made in his nutritional management? a. Carbohydrate load should be reduced in the face of respiratory failure b. In patients with renal failure, protein intake should be diminished c. During hemodialysis protein intake should be limited to the same extent d. In patients with hepatic failure, carbohydrate load should be increased

Description : A 59-year-old trauma patient has suffered multiple septic complications including severe pneumonia, intraabdominal abscess, and major wound infection. He has now developed signs of multisystem organ ... the same extent d. In patients with hepatic failure, carbohydrate load should be increased

Last Answer : Answer: a, b The most severe complication of sepsis is multiple system organ dysfunction syndrome, which may result in death. The development of organ failure requires changes in the ... should be provided as fat emulsion. If encephalopathy develops, protein load should also be reduced0

-yr old sustained trauma to the chest present with severe short of breath with cyanosis, his rt lung is silent with hyperresonance. The FIRST step to treat this pt: a. O2 mask b. Tube thoracostomy c. CXR _______________

Description : -yr old sustained trauma to the chest present with severe short of breath with cyanosis, his rt lung is silent with hyperresonance. The FIRST step to treat this pt: a. O2 mask b. Tube thoracostomy c. CXR _______________

Last Answer : a. O2 mask

Patient reported to you 30 min after trauma to central incisor. Patient is 10 yrs old and there is traumatic exposure of pulp. What will be the line of treatment— 1) coronal pulpotomy and Ca-hydr. Base and then permanent filling 2) Ca-hydroxide base and permanent filling 3) 1-2 mm. of coronal pulp extirpated and Ca hydroxide and then permanent filling 4) Pulpectomy

Description : Patient reported to you 30 min after trauma to central incisor. Patient is 10 yrs old and there is traumatic exposure of pulp. What will be the line of treatment- 1) coronal pulpotomy and Ca-hydr. ... 3) 1-2 mm. of coronal pulp extirpated and Ca hydroxide and then permanent filling 4) Pulpectomy

Last Answer : 3) 1-2 mm. of coronal pulp extirpated and Ca hydroxide and then permanent filling

A 9 years-old boy has a small white discolouration on his maxillary central incisor. The lesion is most probably, A. Hypocalcification due to trauma of the primary predecessor B. Hypoplasia due to acute systemic infection when 6-12 months old C. Defect during the histo differentiation stage of development D. Defect during the morho differentiation stage of development

Description : A 9 years-old boy has a small white discolouration on his maxillary central incisor. The lesion is most probably, A. Hypocalcification due to trauma of the primary predecessor B ... the histo differentiation stage of development D. Defect during the morho differentiation stage of development

Last Answer : A. Hypocalcification due to trauma of the primary predecessor

The most likely cause of abnormal uterine bleeding in 13 years old girl is: a) Uterine cancer. b) Ectopic pregnancy. c) Anovulation. d) Systemic bleeding diatheses. e) Trauma.

Description : The most likely cause of abnormal uterine bleeding in 13 years old girl is: a) Uterine cancer. b) Ectopic pregnancy. c) Anovulation. d) Systemic bleeding diatheses. e) Trauma.

Last Answer : The correct answer to the question is (c) because a 13 year old girl experiencing abnormal uterine bleeding is likely not ovulating, hence the irregular bleeding pattern, which is common ... release during the cycle. Young girls who experience very heavy bleeding warrant urgent medical treatment

A beggar found a leather purse that someone had dropped in the marketplace. Opening it, he discovered that it contained 100 pieces of gold. Then he heard a merchant shout, 'A reward! A reward to the one who finds my leather purse!' Being an honest man, the beggar came forward and handed the purse to the merchant saying, 'Here is your purse. May I have the reward now?' 'Reward?' scoffed the merchant, greedily counting his gold. 'Why the purse I dropped had 200 pieces of gold in it. You've already stolen more than the reward! Go away or I'll tell the police.' 'I'm an honest man,' said the beggar defiantly. 'Let us take this matter to the court.' In court, the judge patiently listened to both sides of the story of a leather bag lost and a leather bag found. He counted the coins; 100 gold coin

Description : A beggar found a leather purse that someone had dropped in the marketplace. Opening it, he discovered that it contained 100 pieces of gold. Then he heard a merchant shout, 'A reward! A reward to the one ... of a leather bag lost and a leather bag found. He counted the coins; 100 gold coin -Riddles

Last Answer : The judge said 'Merchant, you said that the purse you lost contained 200 peices of gold. The purse this beggar found only contained 100 peices of gold. Therefore it cannot be the same purse'. With that the judge gave the purse to the beggar.

What can I do with bags of fresh cranberries I tossed in the freezer for preservation?

Description : What can I do with bags of fresh cranberries I tossed in the freezer for preservation?

Last Answer : answer:You can make my delicious cranberry apple relish that goes great with pork, poultry. If you pour it into sealed jars it will last for at least a year, in or out of the fridge. 4 ... pink foam develops. About 20 minutes, stirring frequently. Keeps in fridge for weeks in covered container. :-)

What item should be tossed onto your coffin (details inside)?

Description : What item should be tossed onto your coffin (details inside)?

Last Answer : answer:I used to do military funerals, and this one veteran had a bunch of his favorite stuff in his coffin: a DVD, a Bud Light, and other various trinkets. So I think that'd be a cool idea ... a video game console, women's underwear, some of my favorite beers, and some of my favorite books. Lol.

A coin is tossed 500 times and we get Heads : 285 and tails : 215 times. When a coin is tossed at random, what is the probability of getting a. head? b. tail? -Maths 9th

Description : A coin is tossed 500 times and we get Heads : 285 and tails : 215 times. When a coin is tossed at random, what is the probability of getting a. head? b. tail? -Maths 9th

Last Answer : Given, Total number of events = 500 No. of times heads occur = 285 Probability of getting head when coin is tossed at random = 285/500 = 57/100 No. of times tails occur = 215 Probability of getting tails when coin is tossed at random = 215/500 = 43/100

Two coin are tossed 400 times and we get a. Two Heads : 112 times b. One Head : 160 times c. No Head : 128 times. When two coins are tossed at random, what is the probability of getting a. Two Heads b. One Head c. No Head -Maths 9th

Description : Two coin are tossed 400 times and we get a. Two Heads : 112 times b. One Head : 160 times c. No Head : 128 times. When two coins are tossed at random, what is the probability of getting a. Two Heads b. One Head c. No Head -Maths 9th

Last Answer : Given, Total number of events = 400 (a) No. of times two heads occur = 112 Probability of getting two heads = 112/400 = 7/25 (b) No. of times one heads occur = 160 Probability of getting one heads = 160/400 = 2/5 (c) No. of times no heads occur = 128 Probability of getting no heads = 128/400 = 8/25

Two coins are tossed 1000 times and the outcomes are recorded as below : -Maths 9th

Description : Two coins are tossed 1000 times and the outcomes are recorded as below : -Maths 9th

Last Answer : Required probability = P(0 heads) + P(1 head) = 250/1000 + 550 / 1000 = 800/ 1000 =4 / 5 =0.8

Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes ; -Maths 9th

Description : Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes ; -Maths 9th

Last Answer : Total number of chances = 23 + 72 + 77 + 28 = 200 Number of chances of coming 2 heads = 72 therefore P( coming 2 heads)= 514 / 642 = 9 / 25

Two coins are tossed simultaneously for 360 times. The number of times ‘2 Tails’ appeared was three times ‘No Tail’ appeared and number of times ‘1 tail’ appeared is double the number of times ‘No Tail’ appeared. -Maths 9th

Description : Two coins are tossed simultaneously for 360 times. The number of times ‘2 Tails’ appeared was three times ‘No Tail’ appeared and number of times ‘1 tail’ appeared is double the number of times ‘No Tail’ appeared. -Maths 9th

Last Answer : Total number of outcomes = 360 Let the number of times ‘No Tail’ appeared be x Then, number of times ‘2 Tails’ appeared =3x Number of times ‘1 Tail’ appeared =2x Now, x + 2x + 3x =360 ⇒ 6x =360 ⇒ x= 60 P(of getting two tails)=(3 x 60) / 360 =1 / 2

Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes -Maths 9th

Description : Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes -Maths 9th

Last Answer : It is given that coin is tossed 200 times Total number of trials = 200 Number of events for getting less than three tails = 68 + 82 + 30 = 180 Probability of getting less than 3 tails =180 / 200 =9 / 10

A coin is tossed 500 times and we get Heads : 285 and tails : 215 times. When a coin is tossed at random, what is the probability of getting a. head? b. tail? -Maths 9th

Description : A coin is tossed 500 times and we get Heads : 285 and tails : 215 times. When a coin is tossed at random, what is the probability of getting a. head? b. tail? -Maths 9th

Last Answer : Given, Total number of events = 500 No. of times heads occur = 285 Probability of getting head when coin is tossed at random = 285/500 = 57/100 No. of times tails occur = 215 Probability of getting tails when coin is tossed at random = 215/500 = 43/100

Two coin are tossed 400 times and we get a. Two Heads : 112 times b. One Head : 160 times c. No Head : 128 times. When two coins are tossed at random, what is the probability of getting a. Two Heads b. One Head c. No Head -Maths 9th

Description : Two coin are tossed 400 times and we get a. Two Heads : 112 times b. One Head : 160 times c. No Head : 128 times. When two coins are tossed at random, what is the probability of getting a. Two Heads b. One Head c. No Head -Maths 9th

Last Answer : Given, Total number of events = 400 (a) No. of times two heads occur = 112 Probability of getting two heads = 112/400 = 7/25 (b) No. of times one heads occur = 160 Probability of getting one heads = 160/400 = 2/5 (c) No. of times no heads occur = 128 Probability of getting no heads = 128/400 = 8/25

Two coins are tossed 1000 times and the outcomes are recorded as below : -Maths 9th

Description : Two coins are tossed 1000 times and the outcomes are recorded as below : -Maths 9th

Last Answer : Required probability = P(0 heads) + P(1 head) = 250/1000 + 550 / 1000 = 800/ 1000 =4 / 5 =0.8

Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes ; -Maths 9th

Description : Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes ; -Maths 9th

Last Answer : Total number of chances = 23 + 72 + 77 + 28 = 200 Number of chances of coming 2 heads = 72 therefore P( coming 2 heads)= 514 / 642 = 9 / 25

Two coins are tossed simultaneously for 360 times. The number of times ‘2 Tails’ appeared was three times ‘No Tail’ appeared and number of times ‘1 tail’ appeared is double the number of times ‘No Tail’ appeared. -Maths 9th

Description : Two coins are tossed simultaneously for 360 times. The number of times ‘2 Tails’ appeared was three times ‘No Tail’ appeared and number of times ‘1 tail’ appeared is double the number of times ‘No Tail’ appeared. -Maths 9th

Last Answer : Total number of outcomes = 360 Let the number of times ‘No Tail’ appeared be x Then, number of times ‘2 Tails’ appeared =3x Number of times ‘1 Tail’ appeared =2x Now, x + 2x + 3x =360 ⇒ 6x =360 ⇒ x= 60 P(of getting two tails)=(3 x 60) / 360 =1 / 2

Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes -Maths 9th

Description : Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes -Maths 9th

Last Answer : It is given that coin is tossed 200 times Total number of trials = 200 Number of events for getting less than three tails = 68 + 82 + 30 = 180 Probability of getting less than 3 tails =180 / 200 =9 / 10

Three coins were tossed 30 times simultaneously. -Maths 9th

Description : Three coins were tossed 30 times simultaneously. -Maths 9th

Last Answer : Frequency disribution of above data in tabular form is given as:

Two coins are tossed 1000 times and the outcomes are recorded as below: -Maths 9th

Description : Two coins are tossed 1000 times and the outcomes are recorded as below: -Maths 9th

Last Answer : P (at most one head) = P (0 head) + P (1 head) = 250/1000 + 550/1000 = 800/1000 = 4/5

Two coins are tossed simultaneously 500 times. -Maths 9th

Description : Two coins are tossed simultaneously 500 times. -Maths 9th

Last Answer : Since, frequency of one or more than one head = 100 + 270 = 370 Therefore, P (one or more heads) = 370/500 = 37/50

Three coins are tossed simultaneously -Maths 9th

Description : Three coins are tossed simultaneously -Maths 9th

Last Answer : Frequency of more than one tail = 135 + 85 = 220 ∴ P (more than one tail) = 220/500 = 11/25

A coin is tossed thrice and all eight outcomes are assumed equally likely. Find whether the events E -Maths 9th

Description : A coin is tossed thrice and all eight outcomes are assumed equally likely. Find whether the events E -Maths 9th

Last Answer : When a coin is tossed three times, the sample space is given by S = [HHH, HHT, HTH, THT, THH, HTT, TTH, TTT] E = {HHH, HTT, THT, TTH}, F = {TTT, HTH, THH, HHT}E ∩ F = ϕP(E) = \(rac{4}{8}\) = \(rac{1}{2}\ ... rac{1}{2}\) x \(rac{1}{2}\) x \(rac{1}{4}\) ≠ P(E ∩ F) ∴ E and F are not independent events.

A fair coin is tossed three times. Let A, B and C be defined as follows: -Maths 9th

Description : A fair coin is tossed three times. Let A, B and C be defined as follows: -Maths 9th

Last Answer : The sample space is S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} A = {HHH, HHT, HTH, HTT}, B = {HHH, HHT, THH, THT} and C = {HHT, THH} Also, A ∩ B = {HHH, HHT}, B ∩ C = {HHT, THH}, C ∩ A = {HHT}P (A ... (C), i.e., if the events are pairwise independent and (ii) P (A ∩ B ∩ C) = P (A) . P (B) . P (C)

Let a pair of fair coins be tossed. Here S = {HH, HT, TH, TT}. Consider the events A = {heads on the first coin} = {HH, HT}, -Maths 9th

Description : Let a pair of fair coins be tossed. Here S = {HH, HT, TH, TT}. Consider the events A = {heads on the first coin} = {HH, HT}, -Maths 9th

Last Answer : ThenP (A) = P (B) = P (C) = \(rac{2}{4}\) = \(rac{1}{2}\) andP (A ∩ B) = P ({HH}) = \(rac{1}{4}\), P (A ∩ C) = P ({HT}) = \(rac{1}{4}\)P ( ... C)Thus condition (i) is satisfied, i.e., the events are pairwise independent. But condition (ii) is not satisfied and so the three events are not independent

If two coins are tossed once, what is the probability of getting at least one head ? -Maths 9th

Description : If two coins are tossed once, what is the probability of getting at least one head ? -Maths 9th

Last Answer : When two coins are tossed once, there are four possible outcomes, i.e., S = {HH, HT, TH, TT} ∴ Total number of outcomes = n(S) = 4 Let A : Event of getting at least one head ⇒ A = {HH, HT, TH} ⇒ n(A) = 3∴ P(A) = \(rac{n(A)}{n(S)}\) = \(rac{3}{4}.\)