Description : The word length of a computer is measured in A) Bytes B) Millimeters C) Meters D) Bits
Last Answer : Answer : D
Description : The word length of a computer is measured in a. Bytes b. Millimeters c. Meters d. Bits
Last Answer : d. Bits
Description : a computer which CPU speed around 100 million instruction per second and with the word length of around 64 bits is known as a. Super computer b. Mini computer c. Micro computer d. Macro computer
Last Answer : a. Super computer
Description : The Width of a processor’s data path is measured in bits. Which of the following are common data paths? a. 8 bits b. 12 bits c. 16 bits d. 32 bits
Last Answer : a. 8 bits
Description : Can you tell what passes into and out from the computer via its ports? a. Data b. Bytes c. Graphics d. Pictures
Last Answer : a. Data
Description : Speed of processor chip is measured in (1) Mbps (2) MHz (2) Bits/second (4) Bytes/second
Last Answer : MHz
Description : The term gigabyte refers to a. 1024 bytes b. 1024 kilobytes c. 1024 megabytes d. 1024 gigabyte
Last Answer : c. 1024 megabytes
Description : Most bacterial cells are measured using what metric system of length? a. Millimeters (mm) b. Micrometers (µm) c. Nanometers (nm) d. Centimeters (cm)
Last Answer : b. Micrometers (µm)
Description : If in a computer, 16 bits are used to specify address in a RAM, the number of addresses will be a. 216 b. 65,536 c. 64K d. Any of the above
Last Answer : b. 65,536
Description : The original ASCII code used…bits of each byte, reserving that last bit for error checking a. 5 b. 6 c. 7 d. 8
Last Answer : c. 7
Description : the storage capacity of a disk system depends on the bits per inch of track and the tracks per inch of a. Cylinder b. Hum c. Cluster d. Surface
Last Answer : d. Surface
Description : A byte consists of a. One bit b. Four bits c. Eight bits d. Sixteen bits
Last Answer : c. Eight bits
Description : Consider a source computer(S) transmitting a file of size 106 bits to a destination computer (D)over a network of two routers (R1 and R2) and three links(L1, L2, and L3). L1connects S to R1; L2 connects R1 to ... file from S to D? a. 1005 ms b. 1010 ms c. 3000 ms d. 3003 ms Answer: Option(a)
Last Answer : a. 1005 ms
Description : How many millimeters are in .5 meters?
Last Answer : 500
Description : What is a disk of matter that circles a planet and consist of numerous particles in orbit that range in size from a few millimeters to several hundred meters?
Last Answer : Planetary ring
Description : What is ten meters times ten meters times sixty millimeters in volume?
Last Answer : 6 cubic meters
Description : What measure is the best estimate for the average height of a middle school students 1.5 meters 1.5 centimeters 1.5 kilometers 1.5 millimeters?
Last Answer : 1.5 centimeters
Description : X-rays can penetrate several ____ into a solid matter. a) millimeters b) meters c) centimeters d) kilometers
Last Answer : c) centimeters
Description : What is the wavelength in millimeters of a sound wave whose frequency is 35 KILOHERTZ. Assume the speed of sound is 350 METERS PER SECOND? w) 100 millimeters x) 1,000 millimeters y) 10 millimeters z) 1/10 millimeters
Last Answer : ANSWER: Y -- 10 MILLIMETERS
Description : The tectonic plates on which India and the adjacen portion of Asia ride are colliding at a rate of: w) 1-10 millimeters per year x) 1-10 centimeters per year y) 1-10 meters per year z) 1-10 decimeters per year
Last Answer : ANSWER: X -- 1-10 CENTIMETERS PER YEAR
Description : A memory unit stores 2^16 bytes in 32-bit words. How many address bits are necessary in order to retrieve a single word from this memory unit?
Last Answer : Each word is 4 bytes, which occupies 4 consecutive addresses at 16 bits each. The first 14 bits of these addresses will be the same, differing only in the two least significant bits. You only need to specify the first 14 bits, because there are only 2^14 words occupying those 2^16 bytes.
Description : The message in pub/sub is an opaque blob of ________ a) Bits b) Bytes c) Word d) Nibble
Last Answer : Bytes
Description : Plotter accuracy is measured in terms of repeatability and a. Buffer size b. Resolution c. Vertical dimensions d. Intelligence
Last Answer : b. Resolution
Description : The output quality of a printer is measured by a. Dot per inch b. Dot per sq. inch c. Dots printed per unit time d. All of above
Last Answer : b. Dot per sq. inch
Description : The number of characters that can be stored in given physical space is a. Word length b. Byte c. Data density d. Field
Last Answer : c. Data density
Description : A 32 bit microprocessor has the word length equal to a. 2 byte b. 32 byte c. 4 byte d. 8 byte
Last Answer : c. 4 byte
Last Answer : 8 bits = 1 byte.
Description : One megabyte equals approximately 1) 1,000 bits 2) 1,000 bytes 3) 1 million bytes 4) 1 million bits 5) 2,000 bytes
Last Answer : Answer :3
Description : Which of the following are the best units of data on an external storage device? A) Bits B) Bytes C) Hertz D) Clock cycles
Last Answer : Answer : B
Description : Voltage signal generated by a microphone is A. digital in nature B. analogue in nature C. consists of bits and bytes D. hybrid in nature
Last Answer : analogue in nature
Description : A binary number with 8 bits is called asa___ a. Bytes b. Bits c. Nibble d. __ Allof these
Last Answer : a. Bytes
Description : What is the commonly used unit for measuring the speed of data transmission? A) Bytes per second B) Baud C) Bits per second D) Both B and C
Last Answer : B) Baud
Description : The network layer is concerned with __________ of data. a. bits b. frames c. packets d. bytes
Last Answer : c. packets
Description : How many bytes of data can be sent in 15 seconds over a serial link with baud rate of 9600 in asynchronous mode with odd parity and two stop bits in the frame? a. 10,000 bytes b. 12,000 bytes c. 15,000 bytes d. 27,000 bytes
Last Answer : b. 12,000 bytes
Description : A sender uses the Stop-and-Wait ARQ protocol for reliable transmission of frames. Frames are of size 1000 bytes and the transmission rate at the sender is 80 Kbps (1Kbps = 1000 bits/second). Size of ... is lost, the sender throughput is __________ bytes/second. a. 2500 b. 2000 c. 1500 d. 500
Last Answer : a. 2500
Description : Consider a CSMA/CD network that transmits data at a rate of 100 Mbps (108 bits per second) over a 1 km (kilometre) cable with no repeaters. If the minimum frame size required for this network is 1250 bytes, what is the signal speed (km/sec) in the cable? a. 8000 b. 10000 c. 16000 d. 20000
Last Answer : d. 20000
Description : The network layer encapsulates the data into _______of data. A. bits B. frames C. packets D. bytes
Last Answer : C. packets
Description : The network layer is concerned with __________ of data. a) bits b) frames c) packets d) bytes
Last Answer : c) packets
Description : 1 Kilobyte (KB) is _______: a) 1000 bits b) 1 Kilo KB c) Both (a) and (b) d) 1024 Bytes e) None of The Above
Last Answer : d) 1024 Bytes
Description : Which of the following are the best units of data on an external storage device? 1) Bits 2) Bytes 3) Hertz 4) Clock cycles
Last Answer : 2) Bytes
Description : Which of the following are the best units of data on an external storage device? 1 Bits 2 Bytes 3 Hertz 4 Clock cycles
Last Answer : 2 Bytes
Description : What is the commonly used unit for measuring the speed of data transmission? A) Bytes per second B) Baud C) Bits per second
Description : The network layer is considered as the _______? A. Backbone B. packets C. Bytes D. bits
Last Answer : A. Backbone
Description : Data in network layer is transferred in the form of ____________ A. Layers B. Packets C. Bytes D. Bits
Last Answer : B. Packets
Description : A memory management system has 64 pages with 512 bytes page size. Physical memory consists of 32 page frames. Number of bits required in logical and physical address are respectively: (1) 14 and 15 (2) 14 and 29 (3) 15 and 14 (4) 16 and 32
Last Answer : (3) 15 and 14
Description : What is the width of a rectangle who has 222 millimeters as the perimeter and a length of 60 millimeters?
Last Answer : ForP = perimeterL = lengthW = width2L + 2W = PFor the given information this means2x60 + 2W = 222120 + 2W = 2222W = 222W = 51So the Width would be 51 millimeters
Description : Your Minolta camera has a 50 millimeter lens. The 50 millimeters is the lens' w) diameter x) focal length y) magnification z) aperture
Last Answer : ANSWER: X -- FOCAL LENGTH
Description : All modern computer operate on a. Information b. Floppies c. Data d. Word
Last Answer : c. Data
Description : A computer which CPU speed around 100 million instruction per second and with the word length of around 64 bits is known as A) Super computer B) Mini computer C) Micro computer D) Macro computer
Last Answer : Answer : A