A sender uses the Stop-and-Wait ARQ protocol for reliable transmission of frames. Frames are of size 1000 bytes and the transmission rate at the sender is 80 Kbps (1Kbps = 1000 bits/second). Size of an acknowledgement is 100 bytes and the transmission rate at the receiver is 8 Kbps. The one-way propagation delay is 100 milliseconds. Assuming no frame is lost, the sender throughput is __________ bytes/second. a. 2500 b. 2000 c. 1500 d. 500

A sender uses the Stop-and-Wait ARQ
protocol for reliable transmission of frames.
Frames are of size 1000 bytes and the
transmission rate at the sender is 80 Kbps
(1Kbps = 1000 bits/second). Size of an
acknowledgement is 100 bytes and the
transmission rate at the receiver is 8 Kbps.
The one-way propagation delay is 100
milliseconds. Assuming no frame is lost, the
sender throughput is __________
bytes/second.
a. 2500
b. 2000
c. 1500
d. 500
by

1 Answer

Answer :

a. 2500
by

Related questions

The distance between two stations M and N is L kilometers. All frames are K bits long. The propagation delay per kilometer is t seconds. Let R bits/second be the channelcapacity. Assuming that processing delay is negligible, the minimum number of bits for the sequence number field in a frame for maximum utilization, when the sliding window protocol used is: a. A b. B c. C d. D

Description : The distance between two stations M and N is L kilometers. All frames are K bits long. The propagation delay per kilometer is t seconds. Let R bits/second be the channel capacity. Assuming that processing ... maximum utilization, when the sliding window protocol used is: a. A b. B c. C d. D

Last Answer : c. C

Inthe _____ Protocol, the sender sends its frames oneafter another with noregard to the receiver. A) Stop-and-Wait B) Simplest C) Go-Back-N ARQ D) Selective-Repeat ARQ

Description : Inthe _____ Protocol, the sender sends its frames oneafter another with noregard to the receiver. A) Stop-and-Wait B) Simplest C) Go-Back-N ARQ D) Selective-Repeat ARQ

Last Answer : Stop-and-Wait B) Simplest

Station A uses 32 byte packets to transmit messages to Station B using a sliding window protocol. The round trip delay between A and B is 80 milliseconds and the bottleneck bandwidth on the path between A and B is 128 kbps. What is the optimal window size that A should use? a. 20 b. 40 c. 160 d. 320

Description : Station A uses 32 byte packets to transmit messages to Station B using a sliding window protocol. The round trip delay between A and B is 80 milliseconds and the bottleneck bandwidth on the path between A and B ... What is the optimal window size that A should use? a. 20 b. 40 c. 160 d. 320

Last Answer : b. 40

Inthe _____ Protocol, the sender sends one frame, stops until it receives confirmation from the receiver, and then sends the next frame. A) Stop-and-Wait B) Simplest C) Go-Back-N ARQ D) Selective-Repeat ARQ

Description : Inthe _____ Protocol, the sender sends one frame, stops until it receives confirmation from the receiver, and then sends the next frame. A) Stop-and-Wait B) Simplest C) Go-Back-N ARQ D) Selective-Repeat ARQ

Last Answer : Stop-and-Wait

Which consequences are more likely to occur during the frame transmission in StopandWait ARQ mechanism? a. Loss of frame or an acknowledgementb. Delay in an acknowledgement c. Normal operation d. All of the above

Description : Which consequences are more likely to occur during the frame transmission in StopandWait ARQ mechanism? a. Loss of frame or an acknowledgement b. Delay in an acknowledgement c. Normal operation d. All of the above

Last Answer : d. All of the above

A pure ALOHA Network transmits 200 bit frames using a shared channel with 200 Kbps bandwidth. If the system (all stations put together) produces 500 frames per second, then the throughput of the system is ______. a. 0.384 b. 0.184 c. 0.286 d. 0.58

Description : A pure ALOHA Network transmits 200 bit frames using a shared channel with 200 Kbps bandwidth. If the system (all stations put together) produces 500 frames per second, then the throughput of the system is ______. a. 0.384 b. 0.184 c. 0.286 d. 0.58

Last Answer : b. 0.184

When does the station B send a positive acknowledgement (ACK) to station A in Stop and Wait protocol? a. only when no error occurs at the transmission level b. when retransmission of old packet in a novel frame is necessary c. only when station B receives frame with errorsd. all of the above

Description : When does the station B send a positive acknowledgement (ACK) to station A in Stop and Wait protocol? a. only when no error occurs at the transmission level b. when retransmission of old packet in a novel frame is necessary c. only when station B receives frame with errors d. all of the above

Last Answer : only when no error occurs at the transmission level

When does the station B send a positive acknowledgement (ACK) to station A in Stop and Wait protocol? a. only when no error occurs at the transmission level b. when retransmission of old packet in a novel frame is necessary c. only when station B receives frame with errors d. all of the above

Description : When does the station B send a positive acknowledgement (ACK) to station A in Stop and Wait protocol? a. only when no error occurs at the transmission level b. when retransmission of old packet in a novel frame is necessary c. only when station B receives frame with errors d. all of the above

Last Answer : only when no error occurs at the transmission level

If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ______. a. 64 Kbps b. 32 Mbps c. 32 Kbps d. 64 MbpS

Description : If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ______. a. 64 Kbps b. 32 Mbps c. 32 Kbps d. 64 MbpS

Last Answer : c. 32 Kbps

Inthe _________ protocol weavoid unnecessary transmissionby sending only frames that are corrupted. A) Stop-and-Wait ARQ B) Go-Back-N ARQ C) Selective-Repeat ARQ D) none of the above

Description : Inthe _________ protocol weavoid unnecessary transmissionby sending only frames that are corrupted. A) Stop-and-Wait ARQ B) Go-Back-N ARQ C) Selective-Repeat ARQ D) none of the above

Last Answer : Selective-Repeat ARQ

Which provision can resolve / overcome the shortcomings associated with duplication or failure condition of Stop and Wait Automatic Repeat Request protocol especially due to loss of data frames or non reception of acknowledgement? a. Provision of sequence number in the header of message b. Provision of checksum computation c. Both a & b d. None of the above

Description : Which provision can resolve / overcome the shortcomings associated with duplication or failure condition of Stop and Wait Automatic Repeat Request protocol especially due to loss of data frames or non reception ... message b. Provision of checksum computation c. Both a & b d. None of the above

Last Answer : Provision of sequence number in the header of message

Which feature of Go Back N ARQ mechanism possesses an ability to assign the sliding window in the forward direction? a. Control Variables b. Sender Sliding Window c. Receiver Sliding Window d. Resending of frames

Description : Which feature of Go Back N ARQ mechanism possesses an ability to assign the sliding window in the forward direction? a. Control Variables b. Sender Sliding Window c. Receiver Sliding Window d. Resending of frames

Last Answer : b. Sender Sliding Window

Which feature of Go-Back-N ARQ mechanism possesses an ability to assign the sliding window in the forward diretion? A. Control Variables B. Sender Sliding Window C. Receiver Sliding Window D. Resending of frames

Description : Which feature of Go-Back-N ARQ mechanism possesses an ability to assign the sliding window in the forward diretion? A. Control Variables B. Sender Sliding Window C. Receiver Sliding Window D. Resending of frames

Last Answer : B. Sender Sliding Window

A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network? a. 2 Mbps b. 60 Mbps c. 120 Mbps

Description : A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network? a. 2 Mbps b. 60 Mbps c. 120 Mbps

Last Answer : a. 2 Mbps

Suppose transmission rate of a channel is 32 kbps. If there are ‘8’ routes from source to destination and each packet p contains 8000 bits. Total end to end delay in sending packet P is _____. a. 2 sec b. 3 sec c. 4 sec d. 1 sec

Description : Suppose transmission rate of a channel is 32 kbps. If there are ‘8’ routes from source to destination and each packet p contains 8000 bits. Total end to end delay in sending packet P is _____. a. 2 sec b. 3 sec c. 4 sec d. 1 sec

Last Answer : a. 2 sec

Suppose that the one-way propagation delay for a 100 Mbps Ethernet having 48-bit jamming signal is 1.04 micro-seconds. The minimum frame size in bits is: a. 112 b. 160 c. 208 d. 256

Description : Suppose that the one-way propagation delay for a 100 Mbps Ethernet having 48-bit jamming signal is 1.04 micro-seconds. The minimum frame size in bits is: a. 112 b. 160 c. 208 d. 256

Last Answer : d. 256

In a digital transmission, the receiver clock is 0.1 percent faster than the sender clock. How many extra bits per second does the receiver receive if the data rate is 1 Mbps ? (A) 10 bps (B) 100 bps (C) 1000 bps (D) 10000 bps

Description : In a digital transmission, the receiver clock is 0.1 percent faster than the sender clock. How many extra bits per second does the receiver receive if the data rate is 1 Mbps ? (A) 10 bps (B) 100 bps (C) 1000 bps (D) 10000 bps

Last Answer : (C) 1000 bps 

Consider a CSMA/CD network that transmits data at a rate of 100 Mbps (108 bits per second) over a 1 km (kilometre) cable with no repeaters. If the minimum frame size required for this network is 1250 bytes, what is the signal speed (km/sec) in the cable? a. 8000 b. 10000 c. 16000 d. 20000

Description : Consider a CSMA/CD network that transmits data at a rate of 100 Mbps (108 bits per second) over a 1 km (kilometre) cable with no repeaters. If the minimum frame size required for this network is 1250 bytes, what is the signal speed (km/sec) in the cable? a. 8000 b. 10000 c. 16000 d. 20000

Last Answer : d. 20000

What will be the efficiency of a Stop and Wait protocol, if the transmission time for a frame is 20ns and the propagation time is 30ns? a. 20% b. 25% c. 40% d. 66%

Description : What will be the efficiency of a Stop and Wait protocol, if the transmission time for a frame is 20ns and the propagation time is 30ns? a. 20% b. 25% c. 40% d. 66%

Last Answer : b. 25%

A pure ALOHA Network transmit 200 bit frames using a shared channel with 200 Kbps bandwidth. If the system (all stations put together) produces 500 frames per second, then the throughput of the system is .............. (A) 0.384 (B) 0.184 (C) 0.286 (D) 0.586

Description : A pure ALOHA Network transmit 200 bit frames using a shared channel with 200 Kbps bandwidth. If the system (all stations put together) produces 500 frames per second, then the throughput of the system is .............. (A) 0.384 (B) 0.184 (C) 0.286 (D) 0.586

Last Answer : (B) 0.184

A network with bandwidth of 10 Mbps can pass only an average of 12,000 frames per minute with each frame carrying an average of 10,000 bits. What is the throughput of this network ? a. 1 Mbps b. 2 Mbps c. 10 Mbps d. 12 Mbps

Description : A network with bandwidth of 10 Mbps can pass only an average of 12,000 frames per minute with each frame carrying an average of 10,000 bits. What is the throughput of this network ? a. 1 Mbps b. 2 Mbps c. 10 Mbps d. 12 Mbps

Last Answer : b. 2 Mbps

If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ............... (A) 64 Kbps (B) 32 Mbps (C) 32 Kbps (D) 64 Mbps

Description : If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ............... (A) 64 Kbps (B) 32 Mbps (C) 32 Kbps (D) 64 Mbps

Last Answer : (C) 32 Kbps

In Stop-and-Wait ARQ, we use sequence numbers to number the frames. The sequence numbers are based on __________arithmetic. A) modulo-2 B) modulo-4 C) modulo-m D) none of the above

Description : In Stop-and-Wait ARQ, we use sequence numbers to number the frames. The sequence numbers are based on __________arithmetic. A) modulo-2 B) modulo-4 C) modulo-m D) none of the above

Last Answer : modulo-2

Inthe _________Protocol, ifno acknowledgment for aframe has arrived, we resend all outstanding frames. A) Stop-and-Wait ARQ B) Go-Back-N ARQ C) Selective-Repeat ARQ D) none of the above

Description : Inthe _________Protocol, ifno acknowledgment for aframe has arrived, we resend all outstanding frames. A) Stop-and-Wait ARQ B) Go-Back-N ARQ C) Selective-Repeat ARQ D) none of the above

Last Answer : Go-Back-N ARQ

Which ARQ mechanism deals with the transmission of only damaged or lost frames despite the other multiple frames by increasing the efficiency & its utility in noisy channels? a. GoBackN ARQ b. Selective Repeat ARQ c. StopandWait ARQ d. All of the above

Description : Which ARQ mechanism deals with the transmission of only damaged or lost frames despite the other multiple frames by increasing the efficiency & its utility in noisy channels? a. GoBackN ARQ b. Selective Repeat ARQ c. StopandWait ARQ d. All of the above

Last Answer : b. Selective Repeat ARQ

If delaysare recorded as 10 bit numbers in a 50 router network, and delay vectorsare exchanged twicea second,how muchbandwidth per fill duplex line is occupied by the distributedrouting algorithm? A. 500 bps B. 1500 bps C. 5 bps D. 1000 bps

Description : If delaysare recorded as 10 bit numbers in a 50 router network, and delay vectorsare exchanged twicea second,how muchbandwidth per fill duplex line is occupied by the distributedrouting algorithm? A. 500 bps B. 1500 bps C. 5 bps D. 1000 bps

Last Answer : 1000 bps

A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network ? (A) 2 Mbps (B) 60 Mbps (C) 120 Mbps (D) 10 Mbps

Description : A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network ? (A) 2 Mbps (B) 60 Mbps (C) 120 Mbps (D) 10 Mbps

Last Answer : (A) 2 Mbps Explanation: In data transmission, throughput is the amount of data moved successfully from one place to another in a given period of time, and typically measured in bits per second (bps), ... second (Mbps) or gigabits per second (Gbps). Here, Throughput = 15000 x 8000/60 = 2 Mbps 

In a token ring network the transmission speed is 10^7 bps and the propagation speed is 200 metres/micro second. The 1- bit delay in this network is equivalent to: a. 500 metres of cable. b. 200 metres of cable. c. 20 metres of cable. d. 50 metres of cable

Description : In a token ring network the transmission speed is 10^7 bps and the propagation speed is 200 metres/micro second. The 1- bit delay in this network is equivalent to: a. 500 metres of cable. b. 200 metres of cable. c. 20 metres of cable. d. 50 metres of cable

Last Answer : c. 20 metres of cable.

How many bytes of data can be sent in 15 seconds over a serial link with baud rate of 9600 in asynchronous mode with odd parity and two stop bits in the frame? a. 10,000 bytes b. 12,000 bytes c. 15,000 bytes d. 27,000 bytes

Description : How many bytes of data can be sent in 15 seconds over a serial link with baud rate of 9600 in asynchronous mode with odd parity and two stop bits in the frame? a. 10,000 bytes b. 12,000 bytes c. 15,000 bytes d. 27,000 bytes

Last Answer : b. 12,000 bytes

A network with bandwidth of 10 Mbps can pass only an average of 12,000 frames per minute with each frame carrying an average of 10,000 bits. What is the throughput of this network ? (A) 1 Mbps (B) 2 Mbps (C) 10 Mbps (D) 12 Mbps

Description : A network with bandwidth of 10 Mbps can pass only an average of 12,000 frames per minute with each frame carrying an average of 10,000 bits. What is the throughput of this network ? (A) 1 Mbps (B) 2 Mbps (C) 10 Mbps (D) 12 Mbps

Last Answer : (B) 2 Mbps

The network layer is concerned with __________ of data. a. bits b. frames c. packets d. bytes

Description : The network layer is concerned with __________ of data. a. bits b. frames c. packets d. bytes

Last Answer : c. packets

The network layer is concerned with __________ of data. a) bits b) frames c) packets d) bytes

Description : The network layer is concerned with __________ of data. a) bits b) frames c) packets d) bytes

Last Answer : c) packets

The maximum temperature in the I.C engine cylinder is of the order of a. 500 – 1000 C b. 1000 – 1500 C c. 1500 – 2000 C d. 2000 – 2500 C

Description : The maximum temperature in the I.C engine cylinder is of the order of a. 500 – 1000 C b. 1000 – 1500 C c. 1500 – 2000 C d. 2000 – 2500 C

Last Answer : ANSWER d. 2000 – 2500 C

A sum of money is to be distributed among A, B, C, D in the proportion of 5:2:4:3. If C gets Rs. 1000 more than D, what is B's share? A) Rs. 500 B) Rs. 1500 C) Rs. 2000 D) Rs.2500 E) NONE

Description : A sum of money is to be distributed among A, B, C, D in the proportion of 5:2:4:3. If C gets Rs. 1000 more than D, what is B's share? A) Rs. 500 B) Rs. 1500 C) Rs. 2000 D) Rs.2500 E) NONE

Last Answer : Answer: C Let the shares of A, B, C, D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively. Then, 4x−3x=1000 ⇒x=1000. B's share =Rs.2x=Rs.(2×1000)= Rs. 2000

Station A uses 32 byte packets to transmit messages to station B using sliding window protocol. The round trip delay between A and B is 40 milli seconds and the bottleneck bandwidth on the path between A and B is 64 kbps. The optimal window size of A is (1) 20 (2) 10 (3) 30 (4) 40

Description : Station A uses 32 byte packets to transmit messages to station B using sliding window protocol. The round trip delay between A and B is 40 milli seconds and the bottleneck bandwidth on the path between A and B is 64 kbps. The optimal window size of A is (1) 20 (2) 10 (3) 30 (4) 40

Last Answer : (2) 10

Determine the maximum length of the cable (in km) for transmitting data at a rate of 500 Mbps in an Ethernet LAN with frames of size 10,000 bits. Assume the signal speed in the cable to be 2,00,000 km/s.b. 2 c. 2.5 d. 5

Description : Determine the maximum length of the cable (in km) for transmitting data at a rate of 500 Mbps in an Ethernet LAN with frames of size 10,000 bits. Assume the signal speed in the cable to be 2,00,000 km/s. b. 2 c. 2.5 d. 5

Last Answer : b. 2

Which of the following statement is False about the efficiency of the given channel? a. If we want to send big packets on the channel, then Stop and Wait is good choice. b. If length of packet increases, efficiency of channel also increases. c. Distance between sender and receiver is directly proportional to efficiency of channel. d. Efficient might be less if capacity of channel is high

Description : Which of the following statement is False about the efficiency of the given channel? a. If we want to send big packets on the channel, then Stop and Wait is good choice. b. If length ... is directly proportional to efficiency of channel. d. Efficient might be less if capacity of channel is high

Last Answer : Distance between sender and receiver is directly proportional to efficiency of channel.

At what distance is VHF propagation normally limited? A. Around 500 miles B. Around 1500 miles C. Around 2000 miles D. Around 1000 miles

Description : At what distance is VHF propagation normally limited? A. Around 500 miles B. Around 1500 miles C. Around 2000 miles D. Around 1000 miles

Last Answer : A. Around 500 miles

At what distance is VHF propagation normally limited? A. Around 500 miles B. Around 1500 miles C. Around 2000 miles D. Around 1000 miles

Description : At what distance is VHF propagation normally limited? A. Around 500 miles B. Around 1500 miles C. Around 2000 miles D. Around 1000 miles

Last Answer : A. Around 500 miles

Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is ................ (A) 1.636 Kbps (B) 1.636 Mbps (C) 2.272 Mbps (D) 3.272 Kbps

Description : Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is ... ...... (A) 1.636 Kbps (B) 1.636 Mbps (C) 2.272 Mbps (D) 3.272 Kbps

Last Answer : Answer: Marks given to all

Commercial available medium size machines have a speed range of ______ . (a) 200 to 400 r.p.m. (b) 600 to 1000 r.p.m. (c) 1000 to 1500 r.p.m. (d) 2000 to 2500 r.p.m.

Description : Commercial available medium size machines have a speed range of ______ . (a) 200 to 400 r.p.m. (b) 600 to 1000 r.p.m. (c) 1000 to 1500 r.p.m. (d) 2000 to 2500 r.p.m.

Last Answer : (d) 2000 to 2500 r.p.m.

Suppose the round trip propagation delay for a 10 Mbps Ethernet having 48-bit jamming signal is 46.4 ms. The minimum frame size is a. 94 b. 416 c. 464

Description : Suppose the round trip propagation delay for a 10 Mbps Ethernet having 48-bit jamming signal is 46.4 ms. The minimum frame size is a. 94 b. 416 c. 464

Last Answer : c. 464

An IP datagram of size 1000 bytes arrives at a router. The router has to forward this packet on a link whose MTU (maximum transmission unit) is 100 bytes. Assume that the size of the IP header is 20 bytes. The number of fragments that the IP datagram will be divided into for transmission is : a. 10 b. 50 c. 12 d. 13

Description : An IP datagram of size 1000 bytes arrives at a router. The router has to forward this packet on a link whose MTU (maximum transmission unit) is 100 bytes. Assume that the size of the IP header is 20 bytes ... the IP datagram will be divided into for transmission is : a. 10 b. 50 c. 12 d. 13

Last Answer : d. 13

The network layer encapsulates the data into _______of data. A. bits B. frames C. packets D. bytes

Description : The network layer encapsulates the data into _______of data. A. bits B. frames C. packets D. bytes

Last Answer : C. packets

Out of all the elastomers, natural rubber has the longest elongation range & flexibility of the order of __________ percent. (A) 1-1000 (B) 1000-1500 (C) 1500-2000 (D) 2000-2500

Description : Out of all the elastomers, natural rubber has the longest elongation range & flexibility of the order of __________ percent. (A) 1-1000 (B) 1000-1500 (C) 1500-2000 (D) 2000-2500

Last Answer : (A) 1-1000

Hydrogen content in petroleum products varies from 12 to 15% (by weight). As a result the difference between gross and net heating value of petroleum fuels varies in the range of __________ kcal/kg. (A) 600-750 (B) 250-350 (C) 1000-1500 (D) 2000-2500

Description : Hydrogen content in petroleum products varies from 12 to 15% (by weight). As a result the difference between gross and net heating value of petroleum fuels varies in the range of __________ kcal/kg. (A) 600-750 (B) 250-350 (C) 1000-1500 (D) 2000-2500

Last Answer : (A) 600-750

International parcel box rate is a) 1000,1500 & 2500 b) 2000,3000 & 5000 c) 750,1500&2500 d) None of these

Description : International parcel box rate is a) 1000,1500 & 2500 b) 2000,3000 & 5000 c) 750,1500&2500 d) None of these

Last Answer : a) 1000,1500 & 2500

International parcel box rate is a) 1000,1500 & 2500 b) 2000,3000 & 5000 c) 750,1500&2500 d) None of these

Description : International parcel box rate is a) 1000,1500 & 2500 b) 2000,3000 & 5000 c) 750,1500&2500 d) None of these

Last Answer : a) 1000,1500 & 2500