There are two sets of five numbers each – set P and set Q. P is a set of consecutive even numbers and Q is a set of consecutive numbers. The sum of the numbers of P is 230. The second least number in Q is 33 less than twice the least number in P. Find the sum of the numbers in Q. 1 : 260 2 : 250 3 : 240 4 : 270 5 : None of these

There are two sets of five numbers each – set P and set Q. P is a set
of consecutive even numbers and Q is a set of consecutive numbers.
The sum of the numbers of P is 230. The second least number in Q is 33
less than twice the least number in P. Find the sum of the numbers in Q.
1 : 260
2 : 250
3 : 240
4 : 270
5 : None of these
by

1 Answer

Answer :

image

1 : 260

by

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A boat takes 4hours for traveling downstream from point P to point Q and coming back to point P upstream. If the velocity of the stream is 2km ph and the speed of the boat in still water is 4kmph, what is the distance between P and Q? A.9 km B.7 km C.5 km D.6km

Description : A boat takes 4hours for traveling downstream from point P to point Q and coming back to point P upstream. If the velocity of the stream is 2km ph and the speed of the boat in still water is 4kmph, what is the distance between P and Q? A.9 km B.7 km C.5 km D.6km

Last Answer : Answer- D Basic Formula: Speed of stream = ½ (a-b) km/hr Speed of still water = ½ (a+b) km/hr Explanation: Time taken by boat to travel upstream and downstream = 4 hours Velocity of the stream, ½ (a-b) = 2km/hr a ... + x / 6 = 4 3x + x / 6 = 4 4x = 24 so,x = 6 distance between P and Q = 6km

A man distributed 43 chocolates to his children. How many of his children are more than five years old? I. A child older than five years gets 5 chocolates II. A child 5 years or younger in age gets 6 chocolates. If the question can be answered with the help of statement I alone, If the question can be answered with the help of statement II alone, If both,statement I and statement II are needed to answer the question If the question cannot be answered even with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Description : A man distributed 43 chocolates to his children. How many of his children are more than five years old? I. A child older than five years gets 5 chocolates II. A child 5 years or younger ... the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Last Answer : From both statement I and II: Let the number of chocolates received by child older than 5 years be x and that of for child than 5 years or younger be y Therefore, 5x + 6 y = 43 Since x and y has to ... for the above equation will be x=5 and y=3 Hence, 5 children are older than 5 years Answer : c

The allowable tensile stress in mild steel stirrups, reinforced cement concrete, is(A) 1400 kg/cm2(B) 190 kg/cm2(C) 260 kg/cm2(D) 230 kg/cm

Description : The allowable tensile stress in mild steel stirrups, reinforced cement concrete, is (A) 1400 kg/cm2 (B) 190 kg/cm2 (C) 260 kg/cm2 (D) 230 kg/cm

Last Answer : Answer: Option A

256 128 ? 192 96 240 80 a) 64 b) 156 c) 96 d) 128 e) 176

Description : 256 128 ? 192 96 240 80 a) 64 b) 156 c) 96 d) 128 e) 176

Last Answer : The series is ×0.5, ÷1, ×1.5, ÷2, ×2.5.... Answer: d)

185% of 400 + 35% of 240 = ?% of 1648 a) 85 b) 75 c) 125 d) 50 e) None of these

Description : 185% of 400 + 35% of 240 = ?% of 1648 a) 85 b) 75 c) 125 d) 50 e) None of these

Last Answer : 740 + 84 = 16.48 × ? 824 = 16.48 × ? ? = 50 Answer: d)

In how many ways letter of the world BANKING can be arranged so that vowels always come together? 1)240 2)120 3)720 4)540

Description : In how many ways letter of the world BANKING can be arranged so that vowels always come together? 1)240 2)120 3)720 4)540

Last Answer : 3)720 Exp: [(6!)/(2!)]×(2!)=360×2=720 [(6!)/(2!)]-letters formed, 2!- Vowels.

A school has 4 sections of class 12, such that half the number of students of 1st section, 1/3rd of 2nd section, 1/4th of 3rd section and 1/5th of the 4th section are equal. If total number of students in class 12 is 420, find the number of students in sections 1st and 2nd. A) 180 B) 120 C) 240 D) 150 E) 260

Description : A school has 4 sections of class 12, such that half the number of students of 1st section, 1/3rd of 2nd section, 1/4th of 3rd section and 1/5th of the 4th section are equal. If total number of students in ... find the number of students in sections 1st and 2nd. A) 180 B) 120 C) 240 D) 150 E) 260

Last Answer : Answer: D Let number of students in 4 sections be A, B, C, D respectively. Then 1/2 of A = 1/3 of b = 1/4 of C = 1/5 of D So A : B : C : D = 2 : 3 : 4 : 5 [When A/2 = B/3 = C/4, then ratio A: B : C = 2 : 3 : 4] So students in 1st and 2nd section = [(2+3)/(2+3+4+5)] * 420 = 150

There is road besides a river. Two friends started from a place P, moved to a shopping mall situated at another place Q and then returned to P again. One of them moves on a cycle at a speed of 12 km/hr, while the other sails on a boat at a speed of 10 km/hr. If the river flows at the speed of 4 km/hr, which of the two friends will return to place P? A. Both B. Boater C. Cyclist D. None of these

Description : There is road besides a river. Two friends started from a place P, moved to a shopping mall situated at another place Q and then returned to P again. One of them moves on a cycle at a speed of 12 km/ ... which of the two friends will return to place P? A. Both B. Boater C. Cyclist D. None of these 

Last Answer : Answer-C Explanation: The cyclist moves both ways at a speed of 12khr so average speed fo the cyclist - 12 km/hr boat sailor moves downstream at 10+4 = 14km/hr and upstream 10- 4 = 6km/hr ... 8.4km/hr The average speed of cyclist is greater .so,cyclist comes first and return to place P.

P and Q invest in a business in the ratio 3 : 2. If 5% of the total profit goes to charity and P’s share is Rs. 855, the total profit is: A.Rs. 1435 B.Rs. 1500 C.Rs. 1538 D.Rs. 1580

Description : P and Q invest in a business in the ratio 3 : 2. If 5% of the total profit goes to charity and P’s share is Rs. 855, the total profit is: A.Rs. 1435 B.Rs. 1500 C.Rs. 1538 D.Rs. 1580

Last Answer : Answer- B (Rs.1500) Explanation: Let the total profit be Rs. 100. After paying to charity, A’s share = Rs. 95 x 3/5 = Rs. 57. If A’s share is Rs. 57, total profit = Rs. 100. If A’s share Rs. 855, total profit =(100/57) x 855 = 1500.