Which one is nota contiguous mask? A) 255.255.255.254 B) 255.255.224.0 C) 255.148.0.0 D) all are

Which one is nota contiguous mask?
A)
255.255.255.254
B)
255.255.224.0
C)
255.148.0.0
D)
all are
by

1 Answer

Answer :

255.148.0.0
by

Related questions

In a block, the prefix length is /15; what is the mask? A) 255.254.0.0 B) 255.255.255.0 C) 255.255.255.128 D) none of the above

Description : In a block, the prefix length is /15; what is the mask? A) 255.254.0.0 B) 255.255.255.0 C) 255.255.255.128 D) none of the above

Last Answer : 255.254.0.0

You are working with three networks that have the network IDs 192.168.5.0, 192.168.6.0, and192.168.7.0. What subnet mask can you use to combine these addresses intoone? A. 255.255.252.0 B. 225.255.254.0 C. 255.255.255.240 D. 255.255.255.252

Description : You are working with three networks that have the network IDs 192.168.5.0, 192.168.6.0, and192.168.7.0. What subnet mask can you use to combine these addresses intoone? A. 255.255.252.0 B. 225.255.254.0 C. 255.255.255.240 D. 255.255.255.252

Last Answer : 255.255.252.0

You havea class A network address 10.0.0.0 with 40subnets,but arerequiredto add 60 new subnets very soon. You would like to still allow for the largest possible number of host IDs per subnet. Which subnet mask should youassign? A. 255.240.0.0 B. 255.248.0.0 C. 255.252.0.0 D. 255.254.0.0 E. 255.255.255.255

Description : You havea class A network address 10.0.0.0 with 40subnets,but arerequiredto add 60 new subnets very soon. You would like to still allow for the largest possible number of host IDs per subnet. Which subnet mask should youassign? A. ... B. 255.248.0.0 C. 255.252.0.0 D. 255.254.0.0 E. 255.255.255.255

Last Answer : 255.254.0.0

You are designing a network which needs to support 200 users. You don't plan to extend the segment beyond the current number of users. Which subnet mask would best meet your needs? Select the best answer. A. 255.255.0.0 B. 255.255.255.0 C. 255.0.0.0 D. 255.224.0.0 E. 255.255.255.200

Description : You are designing a network which needs to support 200 users. You don't plan to extend the segment beyond the current number of users. Which subnet mask would best meet your needs? Select the best answer. A. 255.255.0.0 B. 255.255.255.0 C. 255.0.0.0 D. 255.224.0.0 E. 255.255.255.200

Last Answer : 255.255.255.0

If a Company require 60 hosts then What is the best possible subnet mask? a. 255.255.255.0 b. 255.255.255.192 c. 255.255.225.224 d. 225.225.255.240

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Last Answer : b. 255.255.255.192

What is IP class and number of sub- networks if the subnet mask is 255.224.0.0? a. Class A, 3 b. Class A, 8 c. Class B, 3 d. Class B, 32

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Given the address 172.16.2.120 and the subnet mask of 255.255.255.0. How many hosts are available? * 254 * 510 * 126 * 16,372

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Last Answer : 254

You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.128, B,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.127, 153.50.6.0 * 255.255.255.224, C,153.50.6.0, 153.50.6.127

Description : You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.128, B,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.0, 153 ... .128, C,153.50.6.127, 153.50.6.0 * 255.255.255.224, C,153.50.6.0, 153.50.6.127

Last Answer : Correct answer: A 255.255.255.224,

You are working with a network thathas the network ID 192.168.10.0. What subnet should you use that supportsup to 25 hosts and a maximum number of subnets? A. 255.255.255.192 B. 255.255.255.224 C. 255.255.255.240 D. 255.255.255.248 E. 255.255.255.252

Description : You are working with a network thathas the network ID 192.168.10.0. What subnet should you use that supportsup to 25 hosts and a maximum number of subnets? A. 255.255.255.192 B. 255.255.255.224 C. 255.255.255.240 D. 255.255.255.248 E. 255.255.255.252

Last Answer : 255.255.255.224

With anIP address set starting with 150, you currently havesix offices that you are treating as subnets. Plans are in place toopen 10 more officesbefore the end of theyear. What subnet mask should you useto satisfy the needed numberof subnets and maximize thenumberof hosts available at eachsite? A. 192 B. 224 C. 240 D. 248 E. 252

Description : With anIP address set starting with 150, you currently havesix offices that you are treating as subnets. Plans are in place toopen 10 more officesbefore the end of theyear. What subnet mask should you useto ... maximize thenumberof hosts available at eachsite? A. 192 B. 224 C. 240 D. 248 E. 252

Last Answer : 248

With anIP address of 100, you currently have 80 subnets. What subnet mask should you use to maximize the number of available hosts? A. 192 B. 224 C. 240 D. 248 E. 252

Description : With anIP address of 100, you currently have 80 subnets. What subnet mask should you use to maximize the number of available hosts? A. 192 B. 224 C. 240 D. 248 E. 252

Last Answer : 252

In a block, the mask is 255.255.192.0; what is the prefix length? A) /20 B) /28 C) /18 D) none of the above

Description : In a block, the mask is 255.255.192.0; what is the prefix length? A) /20 B) /28 C) /18 D) none of the above

Last Answer : /18

In a block, the prefix length is /24; what is the mask? A) 255.255.255.0 B) 255.255.242.0 C) 255.255.0.0 D) none of the above

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Which of the following best illustrates the default subnet mask for a class A,B, and C Network? A. 0.0.0.0,0.0.0.1, 0.0.1.1 B. 255.255.255.0, 255.255.0.0,255.0.0.0 C. 255.0.0.0, 255.255.0.0, 255.255.255.0 D. 255.255.0.0, 255.255.255.0,255.255.255.255 E. None of the above

Description : Which of the following best illustrates the default subnet mask for a class A,B, and C Network? A. 0.0.0.0,0.0.0.1, 0.0.1.1 B. 255.255.255.0, 255.255.0.0,255.0.0.0 C. 255.0.0.0, 255.255.0.0, 255.255.255.0 D. 255.255.0.0, 255.255.255.0,255.255.255.255 E. None of the above

Last Answer : 255.0.0.0, 255.255.0.0, 255.255.255.0

What is the default subnet mask for a class C network? A. 127.0.0.1 B. 255.0.0.0 C. 255.255.0.0 D. 255.255.255.0 E. None of the above

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Last Answer : c. 62

Which IP Address Class is INCORRECTLY paired with its range of network numbers? * Class A addresses include 192.0.0.0 through 223.255.255.0 * Class A addresses include 1.0.0.0 through 126.0.0.0 * Class B addresses include 128.0.0.0 through 191.255.0.0 * Class C addresses include 192.0.0.0 through 223.255.255.0 * Class D addresses include 224.0.0.0 through 239.255.255.0

Description : Which IP Address Class is INCORRECTLY paired with its range of network numbers? * Class A addresses include 192.0.0.0 through 223.255.255.0 * Class A addresses include 1.0.0.0 through 126.0.0.0 * Class B ... 192.0.0.0 through 223.255.255.0 * Class D addresses include 224.0.0.0 through 239.255.255.0

Last Answer : 1

In classful addressing, the IP address 190.255.254.254 belongs to (A) Class A (B) Class B (C) Class C (D) Class D

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Last Answer : (B) Class B

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Last Answer : atmosphere

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Description : Which addresses are INCORRECTLY paired with their class? * 240 - 255, Class D * 240 - 255, Class E * 224 - 239, Class D

Last Answer : Correct answer: A & D Address classes are: 1 to 126, Class A; 128 to 191, Class B, 192 to 223, Class C; 224 to 239, Class D; and 240 to 255, Class E.

What is the resultof ANDing 254 and 15? A) 254 B) 14 C) 0 D) none of the above

Description : What is the resultof ANDing 254 and 15? A) 254 B) 14 C) 0 D) none of the above

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You are given the IP address of 172.16.2.160 with a subnet mask of 255.255.0.0. What is the network address in binary? * 10101100 00010000 * 00000010 10100000 * 10101100 00000000 * 11100000 11110000

Description : You are given the IP address of 172.16.2.160 with a subnet mask of 255.255.0.0. What is the network address in binary? * 10101100 00010000 * 00000010 10100000 * 10101100 00000000 * 11100000 11110000

Last Answer : Correct answer: A To find the network address, convert the IP address to binary-10101100 000100000 00000010 10100000-then ANDed it with the subnet mask-11111111 11111111 00000000 00000000. The rest is ... that the class of an address can be determined by the numerical value of the first octet

You are given the following address: 15.16.193.6/21. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.248.0, A, 15.16.192.0, 15.16.199.255 * 255.255.248.0, B, 15.16.192.0, 15.16.199.255 * 255.255.248.0, A, 15.16.199.255, 14.15.192.0 * 255.255.242.0, A, 15.16.192.0, 15.16.199.255

Description : You are given the following address: 15.16.193.6/21. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.248.0, A, 15.16.192.0, 15.16.199.255 * 255.255.248.0, B, 15.16.192.0, ... 0, A, 15.16.199.255, 14.15.192.0 * 255.255.242.0, A, 15.16.192.0, 15.16.199.255

Last Answer : Correct answer: A,B & D Subnet addresses in this situation are all in multiples of 8. In this example, 201.222.5.16 is the subnet, 201.22.5.31 is the broadcast address. The rest are valid host IDs on subnet 201.222.5.16.

A network on the Internet has a subnet mask of 255.255.240.0. What is the maximum number of hosts it can handle ? (A) 1024 (B) 2048 (C) 4096 (D) 8192

Description : A network on the Internet has a subnet mask of 255.255.240.0. What is the maximum number of hosts it can handle ? (A) 1024 (B) 2048 (C) 4096 (D) 8192

Last Answer : (C) 4096

A zone is a contiguous portion of a ………….. of the DNS namespace whose database records exist and are managed in a……….. DNS database file. A. domain, particular B. Class, particular C. tree, local D. Domain, every

Description : A zone is a contiguous portion of a ………….. of the DNS namespace whose database records exist and are managed in a……….. DNS database file. A. domain, particular B. Class, particular C. tree, local D. Domain, every

Last Answer : A. domain, particular

How many hostsare attached to eachof the local area networks at your site? A. 128 B. 254 C. 256 D. 64 E. None of the above

Description : How many hostsare attached to eachof the local area networks at your site? A. 128 B. 254 C. 256 D. 64 E. None of the above

Last Answer : 254

Correct answer: A By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing 4 bits, you have (2×2x2×2)-2=14. By borrowing 5 bits, you have (2×2x2×2x2)-2=30. To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248

Description : hosts per subnet. What subnet mask will you use? * 255.255.255.248 * 255.255.255.128 * 255.255.255.192 * 255.255.255.240

Last Answer : Correct answer: A By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing ... To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248.

hosts per subnet. What subnet mask will you use? * 255.255.255.248 * 255.255.255.128 * 255.255.255.192 * 255.255.255.240

Description : hosts per subnet. What subnet mask will you use? * 255.255.255.248 * 255.255.255.128 * 255.255.255.192 * 255.255.255.240

Last Answer : Correct answer: A By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing ... To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248

You have an IP host address of 201.222.5.121 and a subnet mask of 255.255.255.248. What is the broadcast address? * 201.222.5.127 * 201.222.5.120 * 201.222.5.121 * 201.222.5.122

Description : You have an IP host address of 201.222.5.121 and a subnet mask of 255.255.255.248. What is the broadcast address? * 201.222.5.127 * 201.222.5.120 * 201.222.5.121 * 201.222.5.122

Last Answer : Correct answer: A The easiest way to calculate this is to subtract 255.255.255.248 (subnet mask) from 255.255.255.255, this equals 7. Convert the address 201.222.5.121 to binary- ... mask 255.255.255.248 to binary-11111111 11111111 11111111 11111000. AND them together to get: 11001001 1101111

You are given the following address: 128.16.32.13/30. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.252, B,128.16.32.12, 128.16.32.15 * 255.255.255.252, C,128.16.32.12, 128.16.32.15 * 255.255.255.252, B,128.16.32.15, 128.16.32.12 * 255.255.255.248, B,128.16.32.12, 128.16.32.15

Description : You are given the following address: 128.16.32.13/30. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.252, B,128.16.32.12, 128.16.32.15 * 255.255.255.252, C,128.16.32.12 ... , B,128.16.32.15, 128.16.32.12 * 255.255.255.248, B,128.16.32.12, 128.16.32.15

Last Answer : Correct answer: A * 255.255.255.248,

What is the resultof ANDing 0 and15? A) 255 B) 15 C) 0 D) none of the above

Description : What is the resultof ANDing 0 and15? A) 255 B) 15 C) 0 D) none of the above

Last Answer : 0

What is the resultof ANDing 255 and 15? A) 255 B) 15 C) 0 D) none of the above

Description : What is the resultof ANDing 255 and 15? A) 255 B) 15 C) 0 D) none of the above

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Last Answer : 255.255.255.255

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Last Answer : C. 172.16.12.1

HOSTS file entries are limited to how many characters? A. 8 B. 255 C. 500 D. Unlimited E. None of the above

Description : HOSTS file entries are limited to how many characters? A. 8 B. 255 C. 500 D. Unlimited E. None of the above

Last Answer : 255

In the network 200.10.11.144/27, the fourth octet (in decimal) of the last IP address of the network which can be assigned to a host is ________ a. 158 b. 255 c. 222 d. 223

Description : In the network 200.10.11.144/27, the fourth octet (in decimal) of the last IP address of the network which can be assigned to a host is ________ a. 158 b. 255 c. 222 d. 223

Last Answer : a. 158

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In _______forwarding, the mask anddestination addresses are both 0.0.0.0 in therouting table. A) next-hop B) network-specific C) host-specific D) default

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What partof 192.168.10.51 is the Network ID, assuming a default subnet mask? A. 192 B. 192.168.10 C. 0.0.0.5 D. 51 E. None of the above

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In classless addressing, the prefix length defines the_____________. A) netid B) hostid C) mask D) none of the above

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The safe stopping sight distance D, may be computed from the equation (A) D = 0.278 Vt + V²/254f (B) D = 0.254 Vt + V²/278f (C) D = 0.254 Vt + V²/225f (D) D = 0.225 Vt + V²/254f

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Last Answer : Answer: Option A

Write the following decimals in the place value table. (a) 0.29 (b) 2.08 (c) 19.60 (d) 148.32 (e) 200.812 -Maths 9th

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Last Answer : (a) 0.29 = 0.2 + 0.09 = 2 / 10 + 9 / 100 (b) 2.08 = 2 + 0.08 = 2 + 8 / 100 (c) 19.60 = 19 + 0.60 = 10 + 9 + 6 / 10 (d) 148.32 = 148 + 0.3 + 0. ... / 100 (e) 200.812 = 200 + 0.8 + 0.01 + 0.002 =200 + 8 / 10 + 1 / 100 + 2 / 1000HundredsTensOnesTenthsHundredthsThousandths000290002080019600148320200812

What is the normal level of K+ in the serum ? (A) 137–148 mEq/L (B) 120–160 mEq/L (C) 3.9–5.0 mEq/L (D) 0.3–0.59 mEq/L

Description : What is the normal level of K+ in the serum ? (A) 137–148 mEq/L (B) 120–160 mEq/L (C) 3.9–5.0 mEq/L (D) 0.3–0.59 mEq/L

Last Answer : Answer : C