Which IP Address Class is INCORRECTLY paired with its range of network numbers? * Class A addresses include 192.0.0.0 through 223.255.255.0 * Class A addresses include 1.0.0.0 through 126.0.0.0 * Class B addresses include 128.0.0.0 through 191.255.0.0 * Class C addresses include 192.0.0.0 through 223.255.255.0 * Class D addresses include 224.0.0.0 through 239.255.255.0

Which IP Address Class is INCORRECTLY paired with its range of network
numbers?
* Class A addresses include 192.0.0.0 through 223.255.255.0
* Class A addresses include 1.0.0.0 through 126.0.0.0
* Class B addresses include 128.0.0.0 through 191.255.0.0
* Class C addresses include 192.0.0.0 through 223.255.255.0
* Class D addresses include 224.0.0.0 through 239.255.255.0
by

2 Answers

Answer :

Correct answer: A Class A addresses include 192.0.0.0 through 223.255.255.0
by

Answer :

1
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Related questions

Which addresses are INCORRECTLY paired with their class? * 128 to 191, Class B * 192 to 223 Class B * 128 to 191, Class C * 192 to 223, Class C

Description : Which addresses are INCORRECTLY paired with their class? * 128 to 191, Class B * 192 to 223 Class B * 128 to 191, Class C * 192 to 223, Class C

Last Answer : Correct answer: B & C Address classes are: 1 to 126, Class A; 128 to 191, Class B, 192 to 223, Class C; 224 to 239, Class D; and

Which addresses are INCORRECTLY paired with their class? * 1 to 126, Class A * 128 to 191, Class A * 1 to 126, Class B * 128 to 191, Class B

Description : Which addresses are INCORRECTLY paired with their class? * 1 to 126, Class A * 128 to 191, Class A * 1 to 126, Class B * 128 to 191, Class B

Last Answer : Correct answer: B & C. Address classes are: 1 to 126, Class A; 128 to 191, Class B, 192 to 223, Class C; 224 to 239, Class D; and .

Which addresses are INCORRECTLY paired with their class? * 240 - 255, Class D * 240 - 255, Class E * 224 - 239, Class D

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Last Answer : Correct answer: A & D Address classes are: 1 to 126, Class A; 128 to 191, Class B, 192 to 223, Class C; 224 to 239, Class D; and 240 to 255, Class E.

You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.128, B,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.127, 153.50.6.0 * 255.255.255.224, C,153.50.6.0, 153.50.6.127

Description : You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.128, B,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.0, 153 ... .128, C,153.50.6.127, 153.50.6.0 * 255.255.255.224, C,153.50.6.0, 153.50.6.127

Last Answer : Correct answer: A 255.255.255.224,

hosts per subnet. What subnet mask will you use? * 255.255.255.248 * 255.255.255.128 * 255.255.255.192 * 255.255.255.240

Description : hosts per subnet. What subnet mask will you use? * 255.255.255.248 * 255.255.255.128 * 255.255.255.192 * 255.255.255.240

Last Answer : Correct answer: A By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing ... To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248

You are given the following address: 15.16.193.6/21. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.248.0, A, 15.16.192.0, 15.16.199.255 * 255.255.248.0, B, 15.16.192.0, 15.16.199.255 * 255.255.248.0, A, 15.16.199.255, 14.15.192.0 * 255.255.242.0, A, 15.16.192.0, 15.16.199.255

Description : You are given the following address: 15.16.193.6/21. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.248.0, A, 15.16.192.0, 15.16.199.255 * 255.255.248.0, B, 15.16.192.0, ... 0, A, 15.16.199.255, 14.15.192.0 * 255.255.242.0, A, 15.16.192.0, 15.16.199.255

Last Answer : Correct answer: A,B & D Subnet addresses in this situation are all in multiples of 8. In this example, 201.222.5.16 is the subnet, 201.22.5.31 is the broadcast address. The rest are valid host IDs on subnet 201.222.5.16.

You are given the following address: 128.16.32.13/30. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.252, B,128.16.32.12, 128.16.32.15 * 255.255.255.252, C,128.16.32.12, 128.16.32.15 * 255.255.255.252, B,128.16.32.15, 128.16.32.12 * 255.255.255.248, B,128.16.32.12, 128.16.32.15

Description : You are given the following address: 128.16.32.13/30. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.252, B,128.16.32.12, 128.16.32.15 * 255.255.255.252, C,128.16.32.12 ... , B,128.16.32.15, 128.16.32.12 * 255.255.255.248, B,128.16.32.12, 128.16.32.15

Last Answer : Correct answer: A * 255.255.255.248,

Given the address 172.16.2.120 and the subnet mask of 255.255.255.0. How many hosts are available? * 254 * 510 * 126 * 16,372

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Last Answer : 254

You are given the IP address of 172.16.2.160 with a subnet mask of 255.255.0.0. What is the network address in binary? * 10101100 00010000 * 00000010 10100000 * 10101100 00000000 * 11100000 11110000

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Description : You have an IP host address of 201.222.5.121 and a subnet mask of 255.255.255.248. What is the broadcast address? * 201.222.5.127 * 201.222.5.120 * 201.222.5.121 * 201.222.5.122

Last Answer : Correct answer: A The easiest way to calculate this is to subtract 255.255.255.248 (subnet mask) from 255.255.255.255, this equals 7. Convert the address 201.222.5.121 to binary- ... mask 255.255.255.248 to binary-11111111 11111111 11111111 11111000. AND them together to get: 11001001 1101111

In the network 200.10.11.144/27, the fourth octet (in decimal) of the last IP address of the network which can be assigned to a host is ________ a. 158 b. 255 c. 222 d. 223

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Correct answer: A By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing 4 bits, you have (2×2x2×2)-2=14. By borrowing 5 bits, you have (2×2x2×2x2)-2=30. To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248

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Last Answer : (B) Class B

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Description : "Local area connection doesn't have a valid IP configuration" on Windows 7; Why?

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What do you mean by the TCP/IP Model?

Description : What do you mean by the TCP/IP Model?

Last Answer : TCP/IP stands for Transmission control protocol and Internet protocol. It describes how the data will get transmitted and routed from end to end communication. 

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Description : Which is the protocol that maps varying IP addresses to the Physical MAC Address of a machine in a LAN network? a. ARQ (Automatic Repeat Request) b. ARP (Address Resolution Protocol) c. SLIP (Serial Line Internet Protocol) d. PLIP (Parallel Line Internet Protocol)

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Last Answer : d) All of the Above

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Description : ………………….. is responsible for converting the higher level protocol addresses (IP addresses) to physical network addresses. A) Address Resolution Protocol (ARP) B) Reverse Address Resolution Protocol (RARP) C) Bootstrap Protocol (BOOTP) D) Internet Control Message Protocol (ICMP)

Last Answer : A) Address Resolution Protocol (ARP)

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Description : In a block, the mask is 255.255.192.0; what is the prefix length? A) /20 B) /28 C) /18 D) none of the above

Last Answer : /18

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Description : Which of the following statement is true? I. An address with all bits 1 is interpreted as all networks or all hosts. II. The class A network 128.0.0.0 is defined as the loopback network. a. i only b. ii only c. Both A and B d. None of the above

Last Answer : a. i only

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Last Answer : A) i only

When you join a new " social networking site " that is asking for your home address before you can become a member, how can you be sure this information will not be used inappropriatly?

Description : When you join a new " social networking site " that is asking for your home address before you can become a member, how can you be sure this information will not be used inappropriatly?

Last Answer : Here's one option: When this happens, open a new tab and do a google search with the following. Type the name of the site in question and then type the word review after it (e.g mastersofhearts.com review) ... your gut likes the most. A review will, of course, tell you if the site is legit or not.

When using access lists, what does a Cisco router check first? * To see if the packet is routable or bridgeable * The destination address * The source address * The packet contents

Description : When using access lists, what does a Cisco router check first? * To see if the packet is routable or bridgeable * The destination address * The source address * The packet contents

Last Answer : Correct answer: A The first thing checked is to see if the packet is routable or bridgeable. If it is not, the packet will be dropped.

Which protocol carries messages such as destination Unreachable, Time Exceeded, Parameter Problem, Source Quench, Redirect, Echo, Echo Reply, Timestamp, Information Request, Information Reply, Address Request, and Address Reply? * ICMP * UDP * TCP * TFTP

Description : Which protocol carries messages such as destination Unreachable, Time Exceeded, Parameter Problem, Source Quench, Redirect, Echo, Echo Reply, Timestamp, Information Request, Information Reply, Address Request, and Address Reply? * ICMP * UDP * TCP * TFTP

Last Answer : Correct answer: A ICMP (Internet Control Message Protocol) is a network layer internet protocol described in RFC # 792. ICMP reports IP packet information such as destination Unreachable, Time ... Echo Reply, Timestamp, Information Request, Information Reply, Address Request, and Address Reply.

An organization isgranteda block of classless addresses with the starting address 199.34.76.128/29. How manyaddressesare granted? A) 8 B) 16 C) 32 D) none of the above

Description : An organization isgranteda block of classless addresses with the starting address 199.34.76.128/29. How manyaddressesare granted? A) 8 B) 16 C) 32 D) none of the above

Last Answer : 8