You are given the following address: 128.16.32.13/30. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.252, B,128.16.32.12, 128.16.32.15 * 255.255.255.252, C,128.16.32.12, 128.16.32.15 * 255.255.255.252, B,128.16.32.15, 128.16.32.12 * 255.255.255.248, B,128.16.32.12, 128.16.32.15

You are given the following address: 128.16.32.13/30. Determine the subnet
mask, address class, subnet address,
and broadcast address.
* 255.255.255.252, B,128.16.32.12, 128.16.32.15
* 255.255.255.252, C,128.16.32.12, 128.16.32.15
* 255.255.255.252, B,128.16.32.15, 128.16.32.12
* 255.255.255.248, B,128.16.32.12, 128.16.32.15
by

1 Answer

Answer :

Correct answer: A * 255.255.255.248,
by

Related questions

You are given the following address: 15.16.193.6/21. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.248.0, A, 15.16.192.0, 15.16.199.255 * 255.255.248.0, B, 15.16.192.0, 15.16.199.255 * 255.255.248.0, A, 15.16.199.255, 14.15.192.0 * 255.255.242.0, A, 15.16.192.0, 15.16.199.255

Description : You are given the following address: 15.16.193.6/21. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.248.0, A, 15.16.192.0, 15.16.199.255 * 255.255.248.0, B, 15.16.192.0, ... 0, A, 15.16.199.255, 14.15.192.0 * 255.255.242.0, A, 15.16.192.0, 15.16.199.255

Last Answer : Correct answer: A,B & D Subnet addresses in this situation are all in multiples of 8. In this example, 201.222.5.16 is the subnet, 201.22.5.31 is the broadcast address. The rest are valid host IDs on subnet 201.222.5.16.

You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.128, B,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.127, 153.50.6.0 * 255.255.255.224, C,153.50.6.0, 153.50.6.127

Description : You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.128, B,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.0, 153 ... .128, C,153.50.6.127, 153.50.6.0 * 255.255.255.224, C,153.50.6.0, 153.50.6.127

Last Answer : Correct answer: A 255.255.255.224,

You have an IP host address of 201.222.5.121 and a subnet mask of 255.255.255.248. What is the broadcast address? * 201.222.5.127 * 201.222.5.120 * 201.222.5.121 * 201.222.5.122

Description : You have an IP host address of 201.222.5.121 and a subnet mask of 255.255.255.248. What is the broadcast address? * 201.222.5.127 * 201.222.5.120 * 201.222.5.121 * 201.222.5.122

Last Answer : Correct answer: A The easiest way to calculate this is to subtract 255.255.255.248 (subnet mask) from 255.255.255.255, this equals 7. Convert the address 201.222.5.121 to binary- ... mask 255.255.255.248 to binary-11111111 11111111 11111111 11111000. AND them together to get: 11001001 1101111

hosts per subnet. What subnet mask will you use? * 255.255.255.248 * 255.255.255.128 * 255.255.255.192 * 255.255.255.240

Description : hosts per subnet. What subnet mask will you use? * 255.255.255.248 * 255.255.255.128 * 255.255.255.192 * 255.255.255.240

Last Answer : Correct answer: A By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing ... To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248

Correct answer: A By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing 4 bits, you have (2×2x2×2)-2=14. By borrowing 5 bits, you have (2×2x2×2x2)-2=30. To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248

Description : hosts per subnet. What subnet mask will you use? * 255.255.255.248 * 255.255.255.128 * 255.255.255.192 * 255.255.255.240

Last Answer : Correct answer: A By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing ... To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248.

You havea class A network address 10.0.0.0 with 40subnets,but arerequiredto add 60 new subnets very soon. You would like to still allow for the largest possible number of host IDs per subnet. Which subnet mask should youassign? A. 255.240.0.0 B. 255.248.0.0 C. 255.252.0.0 D. 255.254.0.0 E. 255.255.255.255

Description : You havea class A network address 10.0.0.0 with 40subnets,but arerequiredto add 60 new subnets very soon. You would like to still allow for the largest possible number of host IDs per subnet. Which subnet mask should youassign? A. ... B. 255.248.0.0 C. 255.252.0.0 D. 255.254.0.0 E. 255.255.255.255

Last Answer : 255.254.0.0

You are given the IP address of 172.16.2.160 with a subnet mask of 255.255.0.0. What is the network address in binary? * 10101100 00010000 * 00000010 10100000 * 10101100 00000000 * 11100000 11110000

Description : You are given the IP address of 172.16.2.160 with a subnet mask of 255.255.0.0. What is the network address in binary? * 10101100 00010000 * 00000010 10100000 * 10101100 00000000 * 11100000 11110000

Last Answer : Correct answer: A To find the network address, convert the IP address to binary-10101100 000100000 00000010 10100000-then ANDed it with the subnet mask-11111111 11111111 00000000 00000000. The rest is ... that the class of an address can be determined by the numerical value of the first octet

Given the address 172.16.2.120 and the subnet mask of 255.255.255.0. How many hosts are available? * 254 * 510 * 126 * 16,372

Description : Given the address 172.16.2.120 and the subnet mask of 255.255.255.0. How many hosts are available? * 254 * 510 * 126 * 16,372

Last Answer : 254

With anIP address set starting with 150, you currently havesix offices that you are treating as subnets. Plans are in place toopen 10 more officesbefore the end of theyear. What subnet mask should you useto satisfy the needed numberof subnets and maximize thenumberof hosts available at eachsite? A. 192 B. 224 C. 240 D. 248 E. 252

Description : With anIP address set starting with 150, you currently havesix offices that you are treating as subnets. Plans are in place toopen 10 more officesbefore the end of theyear. What subnet mask should you useto ... maximize thenumberof hosts available at eachsite? A. 192 B. 224 C. 240 D. 248 E. 252

Last Answer : 248

With anIP address of 100, you currently have 80 subnets. What subnet mask should you use to maximize the number of available hosts? A. 192 B. 224 C. 240 D. 248 E. 252

Description : With anIP address of 100, you currently have 80 subnets. What subnet mask should you use to maximize the number of available hosts? A. 192 B. 224 C. 240 D. 248 E. 252

Last Answer : 252

Which IP Address Class is INCORRECTLY paired with its range of network numbers? * Class A addresses include 192.0.0.0 through 223.255.255.0 * Class A addresses include 1.0.0.0 through 126.0.0.0 * Class B addresses include 128.0.0.0 through 191.255.0.0 * Class C addresses include 192.0.0.0 through 223.255.255.0 * Class D addresses include 224.0.0.0 through 239.255.255.0

Description : Which IP Address Class is INCORRECTLY paired with its range of network numbers? * Class A addresses include 192.0.0.0 through 223.255.255.0 * Class A addresses include 1.0.0.0 through 126.0.0.0 * Class B ... 192.0.0.0 through 223.255.255.0 * Class D addresses include 224.0.0.0 through 239.255.255.0

Last Answer : 1

You are working with a network thathas the network ID 192.168.10.0. What subnet should you use that supportsup to 25 hosts and a maximum number of subnets? A. 255.255.255.192 B. 255.255.255.224 C. 255.255.255.240 D. 255.255.255.248 E. 255.255.255.252

Description : You are working with a network thathas the network ID 192.168.10.0. What subnet should you use that supportsup to 25 hosts and a maximum number of subnets? A. 255.255.255.192 B. 255.255.255.224 C. 255.255.255.240 D. 255.255.255.248 E. 255.255.255.252

Last Answer : 255.255.255.224

You are working with three networks that have the network IDs 192.168.5.0, 192.168.6.0, and192.168.7.0. What subnet mask can you use to combine these addresses intoone? A. 255.255.252.0 B. 225.255.254.0 C. 255.255.255.240 D. 255.255.255.252

Description : You are working with three networks that have the network IDs 192.168.5.0, 192.168.6.0, and192.168.7.0. What subnet mask can you use to combine these addresses intoone? A. 255.255.252.0 B. 225.255.254.0 C. 255.255.255.240 D. 255.255.255.252

Last Answer : 255.255.252.0

When configuring the subnet mask for an IP address, which formats can be used? * dotted-decimal. * Hexadecimal * Bit-count * Octal * Binary

Description : When configuring the subnet mask for an IP address, which formats can be used? * dotted-decimal. * Hexadecimal * Bit-count * Octal * Binary

Last Answer : Correct answer: A, B &C

What is IP class and number of sub- networks if the subnet mask is 255.224.0.0? a. Class A, 3 b. Class A, 8 c. Class B, 3 d. Class B, 32

Description : What is IP class and number of sub- networks if the subnet mask is 255.224.0.0? a. Class A, 3 b. Class A, 8 c. Class B, 3 d. Class B, 32

Last Answer : b. Class A, 8

On a class B network, how manyhostsare availableat eachsite witha subnet mask of 248? A. 16,382 B. 8,190 C. 4,094 D. 2,046 E. 1,022

Description : On a class B network, how manyhostsare availableat eachsite witha subnet mask of 248? A. 16,382 B. 8,190 C. 4,094 D. 2,046 E. 1,022

Last Answer : 2,046

Which of the following best illustrates the default subnet mask for a class A,B, and C Network? A. 0.0.0.0,0.0.0.1, 0.0.1.1 B. 255.255.255.0, 255.255.0.0,255.0.0.0 C. 255.0.0.0, 255.255.0.0, 255.255.255.0 D. 255.255.0.0, 255.255.255.0,255.255.255.255 E. None of the above

Description : Which of the following best illustrates the default subnet mask for a class A,B, and C Network? A. 0.0.0.0,0.0.0.1, 0.0.1.1 B. 255.255.255.0, 255.255.0.0,255.0.0.0 C. 255.0.0.0, 255.255.0.0, 255.255.255.0 D. 255.255.0.0, 255.255.255.0,255.255.255.255 E. None of the above

Last Answer : 255.0.0.0, 255.255.0.0, 255.255.255.0

What is the default subnet mask for a class C network? A. 127.0.0.1 B. 255.0.0.0 C. 255.255.0.0 D. 255.255.255.0 E. None of the above

Description : What is the default subnet mask for a class C network? A. 127.0.0.1 B. 255.0.0.0 C. 255.255.0.0 D. 255.255.255.0 E. None of the above

Last Answer : 255.255.255.0

A subnet has been assigned a subnet mask of 255.255.255.192. What is the maximum number of hosts that can belong to this subnet? a. 14 b. 30 c. 62 d. 126

Description : A subnet has been assigned a subnet mask of 255.255.255.192. What is the maximum number of hosts that can belong to this subnet? a. 14 b. 30 c. 62 d. 126

Last Answer : c. 62

Which addresses are INCORRECTLY paired with their class? * 240 - 255, Class D * 240 - 255, Class E * 224 - 239, Class D

Description : Which addresses are INCORRECTLY paired with their class? * 240 - 255, Class D * 240 - 255, Class E * 224 - 239, Class D

Last Answer : Correct answer: A & D Address classes are: 1 to 126, Class A; 128 to 191, Class B, 192 to 223, Class C; 224 to 239, Class D; and 240 to 255, Class E.

In a block, the prefix length is /15; what is the mask? A) 255.254.0.0 B) 255.255.255.0 C) 255.255.255.128 D) none of the above

Description : In a block, the prefix length is /15; what is the mask? A) 255.254.0.0 B) 255.255.255.0 C) 255.255.255.128 D) none of the above

Last Answer : 255.254.0.0

Which addresses are INCORRECTLY paired with their class? * 1 to 126, Class A * 128 to 191, Class A * 1 to 126, Class B * 128 to 191, Class B

Description : Which addresses are INCORRECTLY paired with their class? * 1 to 126, Class A * 128 to 191, Class A * 1 to 126, Class B * 128 to 191, Class B

Last Answer : Correct answer: B & C. Address classes are: 1 to 126, Class A; 128 to 191, Class B, 192 to 223, Class C; 224 to 239, Class D; and .

Which addresses are INCORRECTLY paired with their class? * 128 to 191, Class B * 192 to 223 Class B * 128 to 191, Class C * 192 to 223, Class C

Description : Which addresses are INCORRECTLY paired with their class? * 128 to 191, Class B * 192 to 223 Class B * 128 to 191, Class C * 192 to 223, Class C

Last Answer : Correct answer: B & C Address classes are: 1 to 126, Class A; 128 to 191, Class B, 192 to 223, Class C; 224 to 239, Class D; and

Which IP Address Class can have 16 million subnets but support 254 hosts? * Class C * Class A * Class B * Class D

Description : Which IP Address Class can have 16 million subnets but support 254 hosts? * Class C * Class A * Class B * Class D

Last Answer : Correct answer: A Possible Subnets IP Address Class Possible Hosts

You are designing a network which needs to support 200 users. You don't plan to extend the segment beyond the current number of users. Which subnet mask would best meet your needs? Select the best answer. A. 255.255.0.0 B. 255.255.255.0 C. 255.0.0.0 D. 255.224.0.0 E. 255.255.255.200

Description : You are designing a network which needs to support 200 users. You don't plan to extend the segment beyond the current number of users. Which subnet mask would best meet your needs? Select the best answer. A. 255.255.0.0 B. 255.255.255.0 C. 255.0.0.0 D. 255.224.0.0 E. 255.255.255.200

Last Answer : 255.255.255.0

If a Company require 60 hosts then What is the best possible subnet mask? a. 255.255.255.0 b. 255.255.255.192 c. 255.255.225.224 d. 225.225.255.240

Description : If a Company require 60 hosts then What is the best possible subnet mask? a. 255.255.255.0 b. 255.255.255.192 c. 255.255.225.224 d. 225.225.255.240

Last Answer : b. 255.255.255.192

A network on the Internet has a subnet mask of 255.255.240.0. What is the maximum number of hosts it can handle ? (A) 1024 (B) 2048 (C) 4096 (D) 8192

Description : A network on the Internet has a subnet mask of 255.255.240.0. What is the maximum number of hosts it can handle ? (A) 1024 (B) 2048 (C) 4096 (D) 8192

Last Answer : (C) 4096

Which among the following definitions is correct: a) Address - The unique number ID assigned to one host or interface in a network b) Subnet - A portion of a network sharing a particular subnet address c) Subnet mask - A 32 bit combination used to describe which portion of an address refers to the subset and which part refers to the host d) Interface - A network connection e) None of These f) All of the Above

Description : Which among the following definitions is correct: a) Address - The unique number ID assigned to one host or interface in a network b) Subnet - A portion of a network sharing a particular subnet address c) ... to the host d) Interface - A network connection e) None of These f) All of the Above

Last Answer : f) All of the Above

Which among the following definitions is correct: a) Address - The unique number ID assigned to one host or interface in a network b) Subnet - A portion of a network sharing a particular subnet addressc) Subnet mask - A 32 bit combination used to describe which portion of an address refers to thesubset and which part refers to the hostd) Interface - A network connectione) None of Thesef) All of the Above

Description : Which among the following definitions is correct: a) Address - The unique number ID assigned to one host or interface in a network b) Subnet - A portion of a network sharing a particular subnet address c) ... to the host d) Interface - A network connection e) None of These f) All of the Above

Last Answer : f) All of the Above

Can i port forward to my entire subnet ?

Description : Can i port forward to my entire subnet ?

Last Answer : What are you forwarding? A specific port? DHCP dynamicly assigns IPs to all hosts on the subnet? Is assume this is a home network w\ one NAT\router inbetween all computers and a DSL\cable modem ... to a specific 192. I assume you are port forwarding to allow incomming connections on a specific port?

A gas engine has a volume of 300 cc and clearance volume of 25 cc. Its volumetric efficiency is 0.8 and mech efficiency is 0.9. What is the volume of the mixture taken in per stroke? (a) 248 cc (b) 252 cc (c) 264 cc (d) 286 cc

Description : A gas engine has a volume of 300 cc and clearance volume of 25 cc. Its volumetric efficiency is 0.8 and mech efficiency is 0.9. What is the volume of the mixture taken in per stroke? (a) 248 cc (b) 252 cc (c) 264 cc (d) 286 cc

Last Answer : Ans : c

188, 212, 236, ?, 268, 284 a) 260 b) 256 c) 252 d) 248 e) 244

Description : 188, 212, 236, ?, 268, 284 a) 260 b) 256 c) 252 d) 248 e) 244

Last Answer : The pattern is 47×4=188, 53×4=212, 59×4=236, 61×4=244, 67×4=268, 71×4=284 47, 53, 59, 61, 69 and 71 are consecutive prime numbers. Answer: e)

An organization isgranteda block of classless addresses with the starting address 199.34.76.128/29. How manyaddressesare granted? A) 8 B) 16 C) 32 D) none of the above

Description : An organization isgranteda block of classless addresses with the starting address 199.34.76.128/29. How manyaddressesare granted? A) 8 B) 16 C) 32 D) none of the above

Last Answer : 8

What is the size of an IP address? A. 64 bit B. 128 bit C. 16 bit D. 32 bit

Description : What is the size of an IP address? A. 64 bit B. 128 bit C. 16 bit D. 32 bit

Last Answer : D. 32 bit

Why is the subnet mask important in determining the network address?

Description : Why is the subnet mask important in determining the network address?

Last Answer : What is the answer ?

The combination of an IP address and a port number is known as ................... (A) network number (B) socket address (C) subnet mask number (D) MAC address

Description : The combination of an IP address and a port number is known as ................... (A) network number (B) socket address (C) subnet mask number (D) MAC address

Last Answer : (B) socket address

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

How do I determine which, if any, static IP addresses are being used on my home WiFi network?

Description : How do I determine which, if any, static IP addresses are being used on my home WiFi network?

Last Answer : Check the status page of your Router setup.

When you join a new " social networking site " that is asking for your home address before you can become a member, how can you be sure this information will not be used inappropriatly?

Description : When you join a new " social networking site " that is asking for your home address before you can become a member, how can you be sure this information will not be used inappropriatly?

Last Answer : Here's one option: When this happens, open a new tab and do a google search with the following. Type the name of the site in question and then type the word review after it (e.g mastersofhearts.com review) ... your gut likes the most. A review will, of course, tell you if the site is legit or not.

When using access lists, what does a Cisco router check first? * To see if the packet is routable or bridgeable * The destination address * The source address * The packet contents

Description : When using access lists, what does a Cisco router check first? * To see if the packet is routable or bridgeable * The destination address * The source address * The packet contents

Last Answer : Correct answer: A The first thing checked is to see if the packet is routable or bridgeable. If it is not, the packet will be dropped.

Which protocol carries messages such as destination Unreachable, Time Exceeded, Parameter Problem, Source Quench, Redirect, Echo, Echo Reply, Timestamp, Information Request, Information Reply, Address Request, and Address Reply? * ICMP * UDP * TCP * TFTP

Description : Which protocol carries messages such as destination Unreachable, Time Exceeded, Parameter Problem, Source Quench, Redirect, Echo, Echo Reply, Timestamp, Information Request, Information Reply, Address Request, and Address Reply? * ICMP * UDP * TCP * TFTP

Last Answer : Correct answer: A ICMP (Internet Control Message Protocol) is a network layer internet protocol described in RFC # 792. ICMP reports IP packet information such as destination Unreachable, Time ... Echo Reply, Timestamp, Information Request, Information Reply, Address Request, and Address Reply.

There are two processes to pair MAC address with IP addresses. Which process finds an IP address from a MAC address? * RARP * ARP * RIP * IGRP

Description : There are two processes to pair MAC address with IP addresses. Which process finds an IP address from a MAC address? * RARP * ARP * RIP * IGRP

Last Answer : Correct answer: A ARP (Address Resolution Protocol) maps an IP address to the MAC address, RARP (Reverse Address Resolution Protocol) maps the MAC address to the IP address. ARP and RARP work at the internet layer of the Internet Model or the network layer of the OSI model.

What is the loopback address of localhost? A. 0.0.0.0 B. 127.0.0.1 C. 172.16.12.1 D. 255.0.0.0

Description : What is the loopback address of localhost? A. 0.0.0.0 B. 127.0.0.1 C. 172.16.12.1 D. 255.0.0.0

Last Answer : C. 172.16.12.1

Which processes does TCP, but not UDP, use? Source Port - 16 bits, Destination Port - 16 bits, Length - 16 Bits, Checksum - 16 bits, Data * Destination Port - 16 bits, Source Port - 16 bits, Length - 16 Bits, Checksum - 16bits, Data * Source Port - 16 bits, Destination Port - 16 bits, Checksum - 16 Bits, Length - 16 bits, Data * Source Port - 8 bits, Destination Port - 8 bits, Length -8 Bits, Checksum - 8 bits, Data

Description : Which processes does TCP, but not UDP, use?Source Port - 16 bits, Destination Port - 16 bits, Length - 16 Bits, Checksum - 16 bits, Data * Destination Port - 16 bits, Source Port - 16 bits, Length - ... * Source Port - 8 bits, Destination Port - 8 bits, Length -8 Bits, Checksum - 8 bits, Data

Last Answer : Correct answer: A The UDP format for a segment is as follows: Source Port 16 bits Destination Port 16 bits Length 16 bits Checksum 16 bits Data xx bits

A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds, all starting at the same point. After what time will they meet again at the starting point? A.15 minutes 15 seconds B.42 minutes 30 seconds C.42 minutes D.46 minutes 12 seconds E.None of these

Description : A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds, all starting at the same point ... A.15 minutes 15 seconds B.42 minutes 30 seconds C.42 minutes D.46 minutes 12 seconds E.None of these

Last Answer : Answer – D (46 minutes 12 seconds) Explanation – L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 see i.e., 46 min. 12 sec

Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Description : Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Last Answer : Here, the minimum and maximum values of given data are 6 and 32 respectively. Range = 32 – 6 = 26

Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Description : Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Last Answer : Here, the minimum and maximum values of given data are 6 and 32 respectively. Range = 32 – 6 = 26

The virtual address generated by a CPU is 32 bits. The Translation Lookaside Buffer (TLB) can hold total 64 page table entries and a 4-way set associative (i.e. with 4- cache lines in the set). The page size is 4 KB. The minimum size of TLB tag is (A) 12 bits (B) 15 bits (C) 16 bits (D) 20 bits

Description : The virtual address generated by a CPU is 32 bits. The Translation Lookaside Buffer (TLB) can hold total 64 page table entries and a 4-way set associative (i.e. with 4- cache lines in the set). The page size is 4 KB. The minimum size of TLB tag is (A) 12 bits (B) 15 bits (C) 16 bits (D) 20 bits

Last Answer : (C) 16 bits Explanation: VirtualAddress = 32 bits PageSize = 4KB = 12 bits therefore : VPNTag = 20 bits, OffsetTag = 12 bits TLBEntryLength = VPNTag = 20 bits TotalTLBEntries = 64, 4-way implies ... therefore : TLBIndex = 4 bits TLBTag = TLBEntryLength - TLBIndex = 20 - 4 = 16 bits

An IPv6 address is _________ bits long A. 32 B. 64 C. 128 D. none of the above

Description : An IPv6 address is _________ bits long A. 32 B. 64 C. 128 D. none of the above

Last Answer : C. 128

What is size of the IPv6 Address? A. 32 bits B. 64 bits C. 128 bits D. 256 bits

Description : What is size of the IPv6 Address? A. 32 bits B. 64 bits C. 128 bits D. 256 bits

Last Answer : C. 128 bits