You have an IP host address of 201.222.5.121 and a subnet mask of 255.255.255.248. What is the broadcast address? * 201.222.5.127 * 201.222.5.120 * 201.222.5.121 * 201.222.5.122

You have an IP host address of 201.222.5.121 and a subnet mask of
255.255.255.248. What is the broadcast address?
* 201.222.5.127
* 201.222.5.120
* 201.222.5.121
* 201.222.5.122
by

1 Answer

Answer :

Correct answer: A
The easiest way to calculate this is to subtract 255.255.255.248 (subnet mask) from
255.255.255.255, this
equals 7. Convert the address 201.222.5.121 to binary–11001001 11011110
00000101 01111001. Convert the
mask 255.255.255.248 to binary–11111111 11111111 11111111 11111000. AND
them together to get: 11001001 1101111
by

Related questions

You are given the following address: 15.16.193.6/21. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.248.0, A, 15.16.192.0, 15.16.199.255 * 255.255.248.0, B, 15.16.192.0, 15.16.199.255 * 255.255.248.0, A, 15.16.199.255, 14.15.192.0 * 255.255.242.0, A, 15.16.192.0, 15.16.199.255

Description : You are given the following address: 15.16.193.6/21. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.248.0, A, 15.16.192.0, 15.16.199.255 * 255.255.248.0, B, 15.16.192.0, ... 0, A, 15.16.199.255, 14.15.192.0 * 255.255.242.0, A, 15.16.192.0, 15.16.199.255

Last Answer : Correct answer: A,B & D Subnet addresses in this situation are all in multiples of 8. In this example, 201.222.5.16 is the subnet, 201.22.5.31 is the broadcast address. The rest are valid host IDs on subnet 201.222.5.16.

You are given the following address: 128.16.32.13/30. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.252, B,128.16.32.12, 128.16.32.15 * 255.255.255.252, C,128.16.32.12, 128.16.32.15 * 255.255.255.252, B,128.16.32.15, 128.16.32.12 * 255.255.255.248, B,128.16.32.12, 128.16.32.15

Description : You are given the following address: 128.16.32.13/30. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.252, B,128.16.32.12, 128.16.32.15 * 255.255.255.252, C,128.16.32.12 ... , B,128.16.32.15, 128.16.32.12 * 255.255.255.248, B,128.16.32.12, 128.16.32.15

Last Answer : Correct answer: A * 255.255.255.248,

You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.128, B,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.127, 153.50.6.0 * 255.255.255.224, C,153.50.6.0, 153.50.6.127

Description : You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.128, B,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.0, 153 ... .128, C,153.50.6.127, 153.50.6.0 * 255.255.255.224, C,153.50.6.0, 153.50.6.127

Last Answer : Correct answer: A 255.255.255.224,

Correct answer: A By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing 4 bits, you have (2×2x2×2)-2=14. By borrowing 5 bits, you have (2×2x2×2x2)-2=30. To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248

Description : hosts per subnet. What subnet mask will you use? * 255.255.255.248 * 255.255.255.128 * 255.255.255.192 * 255.255.255.240

Last Answer : Correct answer: A By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing ... To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248.

hosts per subnet. What subnet mask will you use? * 255.255.255.248 * 255.255.255.128 * 255.255.255.192 * 255.255.255.240

Description : hosts per subnet. What subnet mask will you use? * 255.255.255.248 * 255.255.255.128 * 255.255.255.192 * 255.255.255.240

Last Answer : Correct answer: A By borrowing 5 bits from the last octet, you can. have 30 subnets. If you borrowed only 4 bits you could only have 14 subnets. The formula is (2 to the power of n)-2. By borrowing ... To get 20 subnets, you would need to borrow 5 bits so the subnet mask would be 255.255.255.248

You are given the IP address of 172.16.2.160 with a subnet mask of 255.255.0.0. What is the network address in binary? * 10101100 00010000 * 00000010 10100000 * 10101100 00000000 * 11100000 11110000

Description : You are given the IP address of 172.16.2.160 with a subnet mask of 255.255.0.0. What is the network address in binary? * 10101100 00010000 * 00000010 10100000 * 10101100 00000000 * 11100000 11110000

Last Answer : Correct answer: A To find the network address, convert the IP address to binary-10101100 000100000 00000010 10100000-then ANDed it with the subnet mask-11111111 11111111 00000000 00000000. The rest is ... that the class of an address can be determined by the numerical value of the first octet

Given the address 172.16.2.120 and the subnet mask of 255.255.255.0. How many hosts are available? * 254 * 510 * 126 * 16,372

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You havea class A network address 10.0.0.0 with 40subnets,but arerequiredto add 60 new subnets very soon. You would like to still allow for the largest possible number of host IDs per subnet. Which subnet mask should youassign? A. 255.240.0.0 B. 255.248.0.0 C. 255.252.0.0 D. 255.254.0.0 E. 255.255.255.255

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Last Answer : 255.254.0.0

When configuring the subnet mask for an IP address, which formats can be used? * dotted-decimal. * Hexadecimal * Bit-count * Octal * Binary

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In the network 200.10.11.144/27, the fourth octet (in decimal) of the last IP address of the network which can be assigned to a host is ________ a. 158 b. 255 c. 222 d. 223

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Last Answer : 255.255.255.0

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Last Answer : 1

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Last Answer : 248

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Last Answer : 255.255.255.224

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Last Answer : 2,046

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Last Answer : 255.255.252.0

Consider the given network implementation scenario. For the given classful NID 199.10.20.0/24, the requirement is to create 13 subnets. With given details, find the range of first and last valid IP in 15th subnet. a. 199.10.20.208 to 199.10.20.222 b. 199.10.20.225 to 199.10.20.238 c. 199.10.20.193 to 199.10.20.206 d. Not of these

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Last Answer : 255.0.0.0, 255.255.0.0, 255.255.255.0

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Description : 121 ? 113 138 89 170 49 a) 125 b) 110 c) 122 d) 120 e) 133

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Description : "Local area connection doesn't have a valid IP configuration" on Windows 7; Why?

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Description : Explain the different Layers of TCP/IP Model.

Last Answer : Application Layer, Transport Layer, Network or Internet Layer, Network interface layer.

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Description : What do you mean by the TCP/IP Model?

Last Answer : TCP/IP stands for Transmission control protocol and Internet protocol. It describes how the data will get transmitted and routed from end to end communication. 

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Description : Which fields of an IP packet provide for fragmentation of datagrams to allow differing MTUs in the internet? * Identification * Flags * Frag Offset * Type of Service * Total Length

Last Answer : Correct answer: A, B & C The following are the fields in an IP segment, their length, and their definitions: VERS (Version number - 16 bits) HLEN (Number of 32-bit words in the header - 4 bits) ... Address (32 bits) IP Options (network testing, debugging, security and others - 4 bits) Data (4 bits).

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Description : What field tells the Internet layer how to handle an IP packet? * Type of Service * IdentificationFlags * Frag Offset

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Description : Where would network testing be included in an IP packet? * IP Options field * Identification field * Type of Service field * Reservation field

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Description : Two of the protocols that can be carried in the Protocol field of an IP packet are? * TCP * UDP * FTP * TFTP

Last Answer : Correct answer: A & B The following are the fields in an IP segment, their length, and their definitions: VERS (Version number - 16 bits) HLEN (Number of 32-bit words in the header - 4 bits) Type ... (32 bits) IP Options (network testing, debugging, security and others - 4 bits) Data (4 bits).

Ok, i was host in Modern Warfare 2 today, and people say they lagg but i dont. please help?

Description : Ok, i was host in Modern Warfare 2 today, and people say they lagg but i dont. please help?

Last Answer : it means that they had a sub-par connection to your computer. Because the game is hosted on your computer, you have little to no lagg. I’d suggest stopping any downloads you have going on if you’re going to host, as that tends to hog your bandwidth. Or, you could just let someone else host.

Why is the subnet mask important in determining the network address?

Description : Why is the subnet mask important in determining the network address?

Last Answer : What is the answer ?