Study the pedigree chart of a certain family given below and select the correct conclusion which can be drawn for the character. (a) The female parent is heterozygous. (b) The parents could not have had a normal daughter for this character. (c) The trait under study could not be colour blindness. (d) The male parent is homozygous dominant.

Study the pedigree chart of a certain family given
below and select the correct conclusion which can
be drawn for the character.
(a) The female parent is heterozygous.
(b) The parents could not have had a normal
daughter for this character.
(c) The trait under study could not be colour
blindness.
(d) The male parent is homozygous dominant.
by

1 Answer

Answer :

(a) The female parent is heterozygous.
by

Related questions

Study the pedigree chart given below. What does it show? (a) Inheritance of a condition like phenylketonuria as an autosomal recessive trait. (b) The pedigree chart is wrong as this is not possible. (c) Inheritance of a recessive sex-linked disease like haemophilia. (d) Inheritance of a sex-linked inborn error of metabolism like phenylketonuria

Description : Study the pedigree chart given below. What does it show? (a) Inheritance of a condition like phenylketonuria as an autosomal recessive trait. (b) The pedigree chart is wrong as this is ... disease like haemophilia. (d) Inheritance of a sex-linked inborn error of metabolism like phenylketonuria

Last Answer : (a) Inheritance of a condition like phenylketonuria as an autosomal recessive trait.

If a homozygous dominant parent and a heterozygous parent are crossed what percentage of the offspring are expected to be homozygous recessive?

Description : If a homozygous dominant parent and a heterozygous parent are crossed what percentage of the offspring are expected to be homozygous recessive?

Last Answer : Rr

.A normal green male maize is crossed with albino female. The progeny is albino because (a) trait for a albinism is dominant (b) the albinos have biochemical to destroy plastids derived from green male (c) plastids are inherited from female parent (d) green plastids of male must have mutated.

Description : .A normal green male maize is crossed with albino female. The progeny is albino because (a) trait for a albinism is dominant (b) the albinos have biochemical to destroy plastids derived from green male (c) plastids are inherited from female parent (d) green plastids of male must have mutated.

Last Answer : (c) plastids are inherited from female paren

4. Crossing a Dominant character with (Homozygous & Hetrozygous) with a recessive trait to know the genome is called;- a) Back cross b) Monohybrid Cross C) Test Cross d)Dihybrid Cross

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Last Answer : (b) genes for characters are located on the sex- chromosomes

For peas, round seed shape (R) is dominant to wrinkled seed shape (r). A homozygous dominant plant is crossed with a heterozygous plant. What are the expected ratios for genotype and phenotype of the offspring?

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Last Answer : rr, Rr

An organism with two identical alleles is (a) dominant (b) hybrid (c) heterozygous (d) homozygous.

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An allele is dominant if it is expressed in (a) both homozygous and heterozygous states (b) second generation (c) heterozygous combination (d) homozygous combination.

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A gene is said to be dominant if (a) it expresses its effect only in homozygous state (b) it expresses its effect only in heterozygous condition (c) it expresses its effect both in homozygous and heterozygous condition (d) it never expresses its effect in any condition.

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Last Answer : (c) it expresses its effect both in homozygous and

If a male who is heterozygous for an autosomal trait mates with a female who is also heterozygous for that trait, what percent of their offspring are likely to be heterozygous for this trait as well?

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Last Answer : ANSWER: 50%

How you can determine whether or not the black parent is homozygous or heterozygous for the condition?

Description : How you can determine whether or not the black parent is homozygous or heterozygous for the condition?

Last Answer : You are not giving enough information to solve this. But, in practice, further crosses will give some clue if the same results occur. If that happens, then the parent in homozygous dominant.

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The quickest way to produce homozygous breeding lines from heterozygous parents is through: (a) Half-seed technique (b) doubled haploids (c) Introgression (d) Aneuploidy

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Description : Explain homozygous and heterozygous parents.

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Last Answer : Answer: C

Is color blindness a trait controlled by a dominant allele on the x chromosome?

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Last Answer : Need answer

Which one of the following symbols and its representation, used in human pedigree analysis is correct? (a) Mating between relatives (b) Unaffected male (c) Unaffected female (d) Male affected

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Difference between homozygous and heterozygous. -Biology

Description : Difference between homozygous and heterozygous. -Biology

Last Answer : answer:

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Last Answer : homozygous

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n the following human pedigree, the filled symbols represent the affected individuals. Identify the type of given pedigree. (i) (ii) (iii) (iv) (a) Autosomal recessive (b) X-linked dominant (c) Autosomal dominant (d) X-linked recessive

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Which one of the following conditions correctly describes the manner of determining the sex? (a) Homozygous sex chromosomes (ZZ) determine female sex in birds. (b) XO type of sex chromosomes determine male sex in grasshopper. (c) XO condition in humans as found in Turner’s syndrome, determines female sex. (d) Homozygous sex chromosomes (XX) produce male in Drosophila.

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Last Answer : (b) XO type of sex chromosomes determine male sex in grasshopper.

Haemophilia is more common in males because it is a (a) recessive character carried by Y-chromosome (b) dominant character carried by Y-chromosome (c) dominant trait carried by X-chromosome (d) recessive trait carried by X-chromosome.

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The genotype of a plant showing the dominant phenotype can be determined by (a) test cross (b) dihybrid cross (c) pedigree analysis (d) back cross.

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Of both normal parents, the chances of a male child becoming colour blind are (a) none (b) possible only when all the four grand parents had normal vision (c) possible only when father’s mother was colour blind (d) possible only when mother’s father was colour blind.

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Last Answer : (d) possible only when mother’s father was colour blind.

A woman with normal vision, but whose father was colour blind, marries a colour blind man. Suppose that the fourth child of this couple was a boy. This boy (a) may be colour blind or may be of normal vision (b) must be colour blind (c) must have normal colour vision (d) will be partially colour blind since he is heterozygous for the colour blind mutant allele

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Last Answer : (a) may be colour blind or may be of normal vision

If a colour-blind man marries a woman who is homozygous for normal colour vision, the probability of their son being colour-blind is (a) 0 (b) 0.5 (c) 0.75 (d) 1.

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Last Answer : a) 0

Which of the following genetic disorders in man are caused by a dominant gene? 1. Edwards Syndrome 2. Huntington's disease 3. Marfan Syndrome 4. Thalassemia Select the correct answer using codes given below: (a) 1 and 3 (b) 1 and 4 (c) 2 and 3 (d) 2 and 4

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If the pattern of inheritance for a trait is complete dominance then an organism heterozygous for the trait would normally express what?

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Last Answer : What is the answer ?

Given below are two premises, with four conclusions drawn from them (taking singly or together); which conclusions are validly drawn ? Select the correct answer from the codes given below : Premises : (i) All bats are mammals. (ii) Birds are not bats. Conclusions : (a) Birds are not mammals. (b) Bats are not birds. (c) All mammals are bats. (d) Some mammals are bats. Codes : (A) (a), (b) and (d) (B) (b) and (d) (C) (a) and (c) (D) (b), (c) and (d)

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Last Answer : Answer: B

If yellow flower color is dominant to blue flower color what will plant that is heterozygous be?

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Last Answer : What is the answer ?

In fruit flies long wings are dominant to short wings. Cross a heterozygous long winged fruit fly with another heterozygous long winged fruit fly. what are the expected genotype and phenotype ratios?

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Last Answer : Need answer

In pea plants, yellow seeds are dominant to green. If a heterozygous yellow seeded plant is crossed with a green seeded plant, what ratio of yellow and green seeded plants would you expect in F1 generation? (a) 9 : 1 (b) 1 : 3 (c) 3 : 1 (d) 50 : 50

Description : In pea plants, yellow seeds are dominant to green. If a heterozygous yellow seeded plant is crossed with a green seeded plant, what ratio of yellow and green seeded plants would you expect in F1 generation? (a) 9 : 1 (b) 1 : 3 (c) 3 : 1 (d) 50 : 50

Last Answer : (d) 50 : 50

What is A chart that traces the inheritance of a trait in a family is called a(n)?

Description : What is A chart that traces the inheritance of a trait in a family is called a(n)?

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Description : Read the following five statements (A - E) and answer as asked next to them. (A) In Equisetum, the female gametophyte is retained on the parent sporophyte. (B) In Ginkgo, male gametophyte is not independent. (C ... . How many of the above statements are correct? (a) Two (b) Three (c) Four (d) One

Last Answer : (d) One

Given below are some characteristics of reasoning. Select the code that states a characteristic which is not of deductive reasoning: (A) The conclusion must be based on observation and experiment (B) The conclusion should be supported by the premise/premises (C) The conclusion must follow from the premise/premises necessarily (D) The argument may be valid or invalid

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Last Answer : (a) Archego- Female Gemma Rhizoids niophore thallus cup

A woman with two genes for haemophilia and one gene for colour blindness on one of the ‘X’ chromosomes marries a normal man. How will the progeny be? (a) 50% haemophilic colour-blind sons and 50% normal sons. (b) 50% haemophilic daughters (carrier) and 50% colour blind daughters (carrier). (c) All sons and daughters haemophilic and colour- blind. (d) Haemophilic and colour-blind daughters.

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Last Answer : (b) 50% haemophilic daughters (carrier) and 50% colour blind daughters (carrier).

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Last Answer : (d) natural selection whereby the darker forms were selected.

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Last Answer : (d) (ii) (iii) (iv) (i)

F1 x homozygous recessive parent

Description : F1 x homozygous recessive parent

Last Answer : Ans. Test Cross

Tissue culture technique can produce infinite number of new plants from a small parental tissue. The economic importance of the technique is in raising(a) genetically uniform population identical to the original parent (b) homozygous diploid plants (c) new species (d) variants through picking up somaclonal variations.

Description : Tissue culture technique can produce infinite number of new plants from a small parental tissue. The economic importance of the technique is in raising (a) genetically uniform population ... homozygous diploid plants (c) new species (d) variants through picking up somaclonal variations.

Last Answer : (a) genetically uniform population identical to the original parent