A woman with two genes for haemophilia and one gene for colour blindness on one of the ‘X’ chromosomes marries a normal man. How will the progeny be? (a) 50% haemophilic colour-blind sons and 50% normal sons. (b) 50% haemophilic daughters (carrier) and 50% colour blind daughters (carrier). (c) All sons and daughters haemophilic and colour- blind. (d) Haemophilic and colour-blind daughters.

A woman with two genes for haemophilia and
one gene for colour blindness on one of the ‘X’
chromosomes marries a normal man. How will the
progeny be?
(a) 50% haemophilic colour-blind sons and 50%
normal sons.
(b) 50% haemophilic daughters (carrier) and 50%
colour blind daughters (carrier).
(c) All sons and daughters haemophilic and colour-
blind.
(d) Haemophilic and colour-blind daughters.
by

1 Answer

Answer :

(b) 50% haemophilic daughters (carrier) and 50%
colour blind daughters (carrier).
by

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