The following function plays an important role in the experimental modal analysis: a. time-response function b. modal-response function c. frequency-response function

The following function plays an important role in the experimental modal analysis:
a. time-response function
b. modal-response function
c. frequency-response function
by

1 Answer

Answer :

c. frequency-response function
by

Related questions

A single degree of freedom spring-mass system is subjected to a harmonic force of constant amplitude. For an excitation frequency of √3k/m , the ratio of the amplitude of steady state response to the static deflection of the spring is __________ A. 0.2 B. 0.5 C. 0.8 D. None of the above

Description : A single degree of freedom spring-mass system is subjected to a harmonic force of constant amplitude. For an excitation frequency of √3k/m , the ratio of the amplitude of steady state response to the static deflection of the spring is __________ A. 0.2 B. 0.5 C. 0.8 D. None of the above

Last Answer : B. 0.5

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Last Answer : (C) 0.4359

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Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 25.62 rad/sec B 20.78 rad/sec C 14.4 rad/sec D 15.33 rad/sec

Description : Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 25.62 rad/sec B 20.78 rad/sec C 14.4 rad/sec D 15.33 rad/sec

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What is meant by critical damping coefficient? A Frequency of damped free vibrations is less than zero B The motion is aperiodic in nature C Both a. and b. D None of the above

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Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A 12.32 Hz B 4.10 Hz C 6.16 HzD None of the above

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The number of cycles described in one second is known as _______. A period of vibration B cycle C frequency D all of the above

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Last Answer : C number of cycles per second

A car having a mass of 1000 kg deflects its springs 4 cm under its load. Determine the natural frequency of the car in vertical direction. A 5 Hz B 4.67 Hz C 9.8 Hz D 2.49 Hz

Description : A car having a mass of 1000 kg deflects its springs 4 cm under its load. Determine the natural frequency of the car in vertical direction. A 5 Hz B 4.67 Hz C 9.8 Hz D 2.49 Hz

Last Answer : D 2.49 Hz

While calculating the natural frequency of a spring-mass system, the effect of the mass of the spring is accounted for by adding X times its value to the mass, where X is A 1/2 B 1/3 C 1/4 D 3⁄4

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If the mass of body increases A Frequency increases 4 times B Frequency decreases 4 times C Frequency become half D Frequency become double

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Last Answer : C Frequency become half

The motion of a system executing harmonic motion with one natural frequency is known as _______ A. principal mode of vibration B. natural mode of vibration C. both a. and b. D. none of the above

Description : The motion of a system executing harmonic motion with one natural frequency is known as _______ A. principal mode of vibration B. natural mode of vibration C. both a. and b. D. none of the above

Last Answer : C. both a. and b.

Which of the following statements is/are true? A. Torsional vibrations do not occur in a three rotor system, if rotors rotate in same direction B. Shaft vibrates with maximum frequency when rotors rotate in same direction C. Zero node behavior is observed in rotors rotating in opposite direction D. All of the above

Description : Which of the following statements is/are true? A. Torsional vibrations do not occur in a three rotor system, if rotors rotate in same direction B. Shaft vibrates with maximum frequency when rotors ... C. Zero node behavior is observed in rotors rotating in opposite direction D. All of the above

Last Answer : A. Torsional vibrations do not occur in a three rotor system, if rotors rotate in same direction

A shaft of diameter d carries two discs at its two ends. The lowest torsional frequency is ω n . If the diameter is doubled, then the lowest torsional frequency becomes A 4ω n B ω n /2 C ω n /4 D 4ω n

Description : A shaft of diameter d carries two discs at its two ends. The lowest torsional frequency is ω n . If the diameter is doubled, then the lowest torsional frequency becomes A 4ω n B ω n /2 C ω n /4 D 4ω n

Last Answer : D 4ω n

A shaft of length l carries two discs at its two ends. The lowest torsional frequency is ω n . If the shaft length is doubled, then the lowest torsional frequency becomes A ω n /2 B ω n /√2 C √2ω n D 2ω n

Description : A shaft of length l carries two discs at its two ends. The lowest torsional frequency is ω n . If the shaft length is doubled, then the lowest torsional frequency becomes A ω n /2 B ω n /√2 C √2ω n D 2ω n

Last Answer : B ω n /√2

The number of natural frequency in two rotor system is A Zero B Infinite C Two D One

Description : The number of natural frequency in two rotor system is A Zero B Infinite C Two D One

Last Answer : C Two

Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 21 rad/sec B 25.62 rad/sec C 20.22 Hz D 3.15 Hz

Description : Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 21 rad/sec B 25.62 rad/sec C 20.22 Hz D 3.15 Hz

Last Answer : B 25.62 rad/sec

In above numerical what will be the frequency corresponding to the peak amplitude A 14.18rad/sec B 24.13rad/sec C 20.22rad/sec D 22.32rad/sec

Description : In above numerical what will be the frequency corresponding to the peak amplitude A 14.18rad/sec B 24.13rad/sec C 20.22rad/sec D 22.32rad/sec

Last Answer : A 14.18rad/sec

A simple pendulum is found to vibrate at a frequency of 0.5Hz in vacuum and 0.45Hz in a viscous fluid medium. Find the damping factor. A 0.5122 B 0.9237 C 0.4359 D 0.2568

Description : A simple pendulum is found to vibrate at a frequency of 0.5Hz in vacuum and 0.45Hz in a viscous fluid medium. Find the damping factor. A 0.5122 B 0.9237 C 0.4359 D 0.2568

Last Answer : C 0.4359

In coulomb damping the frequency of damped vibrations is A Equal to that of undamped vibrations B Less than that of undamped vibrationsC More than that of undamped vibrations D Independent of the frequency of undamped vibration

Description : In coulomb damping the frequency of damped vibrations is A Equal to that of undamped vibrations B Less than that of undamped vibrationsC More than that of undamped vibrations D Independent of the frequency of undamped vibration

Last Answer : A Equal to that of undamped vibrations