From the following, which one is also known as low-frequency Transducer? (A) Stroboscope (B) Accelerometer (C) Vibrometer (D) None of the above

From the following, which one is also known as low-frequency Transducer?
(A) Stroboscope
(B) Accelerometer
(C) Vibrometer
(D) None of the above
by

1 Answer

Answer :

(C) Vibrometer
by

Related questions

The accelerometer is used as a transducer to measure earthquake in Richter scale. Its design is based on the principle that A Its natural frequency is very low in comparison to the frequency of vibration B Its natural frequency is very high in comparison to the frequency of vibration C Its natural frequency is equal to the frequency of vibration D Measurement of vibratory motion is without any reference point

Description : The accelerometer is used as a transducer to measure earthquake in Richter scale. Its design is based on the principle that A Its natural frequency is very low in comparison to the frequency ... is equal to the frequency of vibration D Measurement of vibratory motion is without any reference point

Last Answer : C Its natural frequency is equal to the frequency of vibration

The accelerometer is used as a transducer to measure earthquake in Richter scale. Its design is based on the principle that a) its natural frequency is very low in comparison to the frequency of vibration b) its natural frequency is very high in comparison to the frequency of vibration c) its natural frequency is equal to the frequency of vibration d) measurement of vibratory motion is without any reference point

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Last Answer : c) its natural frequency is equal to the frequency of vibration

The accelerometer is used as a transducer to measure earthquake in Richter scale. Its design is based on the principle that ______. (A) its natural frequency is very low in comparison to the frequency of vibration (B) its natural frequency is very high in comparison to the frequency of vibration (C) its natural frequency is equal to the frequency of vibration (D) measurement of vibratory motion is without any reference poin

Description : The accelerometer is used as a transducer to measure earthquake in Richter scale. Its design is based on the principle that ______. (A) its natural frequency is very low in comparison to the ... is equal to the frequency of vibration (D) measurement of vibratory motion is without any reference poin

Last Answer : (C) its natural frequency is equal to the frequency of vibration

The accelerometer is used as a transducer to measure earthquake in Richter scale. Its design is based on the principle that a) its natural frequency is very low in comparison to the frequency of vibration b) its natural frequency is very high in comparison to the frequency of vibration c) its natural frequency is equal to the frequency of vibration d) measurement of vibratory motion is without any reference poin

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Last Answer : c) its natural frequency is equal to the frequency of vibration

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Last Answer : a. seismometer

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Last Answer : B cycle

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Last Answer : C. both a. and b.

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. The motion completed during one time period is known as _______. A. period of vibration B. cycle C. frequency D. all of the above

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Last Answer : B. cycle

The motion of a system executing harmonic motion with one natural frequency is known as _______ A) principal mode of vibration B) natural mode of vibration C) both a. and b. D)none of the above

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Last Answer : C) both a. and b.

The number of cycles described in one second is known as _______. C ( A ) period of vibration ( B ) cycle ( C ) frequency ( D ) all of the above

Description : The number of cycles described in one second is known as _______. C ( A ) period of vibration ( B ) cycle ( C ) frequency ( D ) all of the above

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Last Answer : B) Damped vibrations

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An accelerometer has input range of 0 to 10g, natural frequency 30 Hz and mass 0.001 kg. The range of the

Description : An accelerometer has input range of 0 to 10g, natural frequency 30 Hz and mass 0.001 kg. The range of the secondary displacement transducer in mm required to cover the input range is (A) 0 to 2.76 (B) 0 to 9.81 (C) 0 to 11.20 (D) 0 to 52.10

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A mass of 1 kg is attached to two identical springs each with stiffness k = 20 kN/m as shown in the figure. Under frictionless condition, the natural frequency of the system in Hz is close to * 1 point (A) 32 (B) 23 (C) 16 (D) 11

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Last Answer : (A) ωn

. In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A Fn =N √(R/L) B Fn =1/N √(R/L) C Fn =N/2 √(R/L) D Fn =N2 √(R/L)

Description : . In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A Fn =N √(R/L) B Fn =1/N √(R/L) C Fn =N/2 √(R/L) D Fn =N2 √(R/L)

Last Answer : A Fn =N √(R/L)

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A simple pendulum is found to vibrate at a frequency of 0.5Hz in vacuum and0.45 Hz in a viscous fluid medium. Find the damping factor. 0.5122 (B) 0.9272 (C) 0.4359 (D) 0.2568

Description : A simple pendulum is found to vibrate at a frequency of 0.5Hz in vacuum and0.45 Hz in a viscous fluid medium. Find the damping factor. 0.5122 (B) 0.9272 (C) 0.4359 (D) 0.2568

Last Answer : (C) 0.4359

The static deflection of a spring under gravity, when a mass of 1 kg is suspended from it, is 1 mm. Assume the acceleration due to gravity g = 10 m/s^2. The natural frequency of this spring-mass system (in rad/s) is A 100 B 150 C 200 D 250

Description : The static deflection of a spring under gravity, when a mass of 1 kg is suspended from it, is 1 mm. Assume the acceleration due to gravity g = 10 m/s^2. The natural frequency of this spring-mass system (in rad/s) is A 100 B 150 C 200 D 250

Last Answer : A 100

Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 25.62 rad/sec B 20.78 rad/sec C 14.4 rad/sec D 15.33 rad/sec

Description : Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 25.62 rad/sec B 20.78 rad/sec C 14.4 rad/sec D 15.33 rad/sec

Last Answer : A 25.62 rad/sec

What is meant by critical damping coefficient? A Frequency of damped free vibrations is less than zero B The motion is aperiodic in nature C Both a. and b. D None of the above

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Last Answer : B The motion is aperiodic in nature

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A 12.32 Hz B 4.10 Hz C 6.16 HzD None of the above

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A 12.32 Hz B 4.10 Hz C 6.16 HzD None of the above

Last Answer : C 6.16 Hz

Frequency is equal to ______. A time period B 1/time period C *time period D /time period

Description : Frequency is equal to ______. A time period B 1/time period C *time period D /time period

Last Answer : B 1/time period

What is the effect on the undamped natural frequency of a single-degree-of-freedom system if the mass of the system is increased? A The frequency will increase B The frequency will stay the same C The frequency will decrease D None of these

Description : What is the effect on the undamped natural frequency of a single-degree-of-freedom system if the mass of the system is increased? A The frequency will increase B The frequency will stay the same C The frequency will decrease D None of these

Last Answer : C The frequency will decrease

Frequency of vibrations is usually expressed in A number of cycles per hour B number of cycles per minute C number of cycles per secondD None of these

Description : Frequency of vibrations is usually expressed in A number of cycles per hour B number of cycles per minute C number of cycles per secondD None of these

Last Answer : C number of cycles per second

A car having a mass of 1000 kg deflects its springs 4 cm under its load. Determine the natural frequency of the car in vertical direction. A 5 Hz B 4.67 Hz C 9.8 Hz D 2.49 Hz

Description : A car having a mass of 1000 kg deflects its springs 4 cm under its load. Determine the natural frequency of the car in vertical direction. A 5 Hz B 4.67 Hz C 9.8 Hz D 2.49 Hz

Last Answer : D 2.49 Hz

While calculating the natural frequency of a spring-mass system, the effect of the mass of the spring is accounted for by adding X times its value to the mass, where X is A 1/2 B 1/3 C 1/4 D 3⁄4

Description : While calculating the natural frequency of a spring-mass system, the effect of the mass of the spring is accounted for by adding X times its value to the mass, where X is A 1/2 B 1/3 C 1/4 D 3⁄4

Last Answer : B 1/3

If the mass of body increases A Frequency increases 4 times B Frequency decreases 4 times C Frequency become half D Frequency become double

Description : If the mass of body increases A Frequency increases 4 times B Frequency decreases 4 times C Frequency become half D Frequency become double

Last Answer : C Frequency become half

Which of the following statements is/are true? A. Torsional vibrations do not occur in a three rotor system, if rotors rotate in same direction B. Shaft vibrates with maximum frequency when rotors rotate in same direction C. Zero node behavior is observed in rotors rotating in opposite direction D. All of the above

Description : Which of the following statements is/are true? A. Torsional vibrations do not occur in a three rotor system, if rotors rotate in same direction B. Shaft vibrates with maximum frequency when rotors ... C. Zero node behavior is observed in rotors rotating in opposite direction D. All of the above

Last Answer : A. Torsional vibrations do not occur in a three rotor system, if rotors rotate in same direction

A shaft of diameter d carries two discs at its two ends. The lowest torsional frequency is ω n . If the diameter is doubled, then the lowest torsional frequency becomes A 4ω n B ω n /2 C ω n /4 D 4ω n

Description : A shaft of diameter d carries two discs at its two ends. The lowest torsional frequency is ω n . If the diameter is doubled, then the lowest torsional frequency becomes A 4ω n B ω n /2 C ω n /4 D 4ω n

Last Answer : D 4ω n

A shaft of length l carries two discs at its two ends. The lowest torsional frequency is ω n . If the shaft length is doubled, then the lowest torsional frequency becomes A ω n /2 B ω n /√2 C √2ω n D 2ω n

Description : A shaft of length l carries two discs at its two ends. The lowest torsional frequency is ω n . If the shaft length is doubled, then the lowest torsional frequency becomes A ω n /2 B ω n /√2 C √2ω n D 2ω n

Last Answer : B ω n /√2

The number of natural frequency in two rotor system is A Zero B Infinite C Two D One

Description : The number of natural frequency in two rotor system is A Zero B Infinite C Two D One

Last Answer : C Two

Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 21 rad/sec B 25.62 rad/sec C 20.22 Hz D 3.15 Hz

Description : Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 21 rad/sec B 25.62 rad/sec C 20.22 Hz D 3.15 Hz

Last Answer : B 25.62 rad/sec

In above numerical what will be the frequency corresponding to the peak amplitude A 14.18rad/sec B 24.13rad/sec C 20.22rad/sec D 22.32rad/sec

Description : In above numerical what will be the frequency corresponding to the peak amplitude A 14.18rad/sec B 24.13rad/sec C 20.22rad/sec D 22.32rad/sec

Last Answer : A 14.18rad/sec

A simple pendulum is found to vibrate at a frequency of 0.5Hz in vacuum and 0.45Hz in a viscous fluid medium. Find the damping factor. A 0.5122 B 0.9237 C 0.4359 D 0.2568

Description : A simple pendulum is found to vibrate at a frequency of 0.5Hz in vacuum and 0.45Hz in a viscous fluid medium. Find the damping factor. A 0.5122 B 0.9237 C 0.4359 D 0.2568

Last Answer : C 0.4359

In coulomb damping the frequency of damped vibrations is A Equal to that of undamped vibrations B Less than that of undamped vibrationsC More than that of undamped vibrations D Independent of the frequency of undamped vibration

Description : In coulomb damping the frequency of damped vibrations is A Equal to that of undamped vibrations B Less than that of undamped vibrationsC More than that of undamped vibrations D Independent of the frequency of undamped vibration

Last Answer : A Equal to that of undamped vibrations

A 1 kg mass is suspended by a spring having a stiffness of 0.4 N/mm. Determine the natural frequency. A 20 rad/sec B 30 rad/sec C 20 Hz D 30 Hz

Description : A 1 kg mass is suspended by a spring having a stiffness of 0.4 N/mm. Determine the natural frequency. A 20 rad/sec B 30 rad/sec C 20 Hz D 30 Hz

Last Answer : B 30 rad/sec