Prove N = Ns (1 — S).

Prove N = Ns (1 — S).
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Prove N = Ns (1 — S).


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If N is the algebraic difference of grades, S is the minimum sight distance in metres, the length (L) of a summit curve is (A) NS/4 (B) NS²/4 (C) N²S/4(D) (NS)²/4

Description : If N is the algebraic difference of grades, S is the minimum sight distance in metres, the length (L) of a summit curve is (A) NS/4 (B) NS²/4 (C) N²S/4 (D) (NS)²/4

Last Answer : Answer: Option B

If N is the net difference of grades, S is the minimum overtaken sight distance in metres, the length (L) of a summit curve, is (A) NS/4 (B) NS²/4 (C) NS²/4.8 (D) NS²/9.6

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For two stage network the switching elements for M inlets with r blocks and N outlets with s blocks is given by (A) Ms + Nr (B) Mr + Ns (C) (M + N) (r + s) (D) (M + N)rs

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Last Answer : a) 0.471 and 1.19 Hz

A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

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Last Answer : c) 54 or 55 only

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Last Answer : Join OE. In ΔOME and ΔONE, OM =ON [equal chords are equidistant from the centre] ∠OME = ∠ONE = 90° OE =OE [common sides] ∠OME ≅ ∠ONE [by SAS congruency] ⇒ ME = NE [by CPCT] In quadrilateral OMEN, ... =ON , ME = NE and ∠OME = ∠ONE = ∠MEN = ∠MON = 90° Hence, OMEN is a square. Hence proved.

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Description : In the given figure, equal chords AB and CD of a circle with centre O cut at right angles at E. If M and N are the mid-points of AB and CD respectively, prove that OMEN is a square. -Maths 9th

Last Answer : Join OE. In ΔOME and ΔONE, OM =ON [equal chords are equidistant from the centre] ∠OME = ∠ONE = 90° OE =OE [common sides] ∠OME ≅ ∠ONE [by SAS congruency] ⇒ ME = NE [by CPCT] In quadrilateral OMEN, ... =ON , ME = NE and ∠OME = ∠ONE = ∠MEN = ∠MON = 90° Hence, OMEN is a square. Hence proved.

If a is a positive rational number and n is a positive integer greater than 1, prove that an is a rational number . -Maths 9th

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Last Answer : We know that product of two rational number is always a rational number. Hence if a is a rational number then a2 = a x a is a rational number, a3 = 4:2 x a is a rational number. ∴ an = an-1 x a is a rational number.

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Last Answer : answer:

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P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

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Last Answer : Given In quadrilateral ABCD, P, Q, R and S are the mid-points of the sides AB, BC, CD and DA, respectively. Also, AC = BD and AC ⊥ BD. To prove PQRS is a square. Proof Now, in ΔADC, S and R are the mid-points of the sides AD and DC respectively, then by mid-point theorem,

P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

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