If Ns=250, determine the earth radius k-factor. A. 1.98 B. 1.23 C. 1.33 D. 1.29

If Ns=250, determine the earth radius k-factor.
A. 1.98
B. 1.23
C. 1.33
D. 1.29
by

1 Answer

Answer :

B. 1.23
by

Related questions

23.98 × 62.49 × 12.03 = ? × 29.97 a) 500 b) 600 c) 900 d) 450 e) 750

Description : 23.98 × 62.49 × 12.03 = ? × 29.97 a) 500 b) 600 c) 900 d) 450 e) 750

Last Answer : 24× 62.5× 12 = ? × 30 24× 750 = ? × 30 ? = (24× 750) / 30 = 600 Answer: b)

Your Western Electric 3A test set meter reading is -23 dBm at at test point level of -8 dB. This is ______ dBrnc0. A. 75 B. 29 C. 30 D. 31

Description : Your Western Electric 3A test set meter reading is -23 dBm at at test point level of -8 dB. This is ______ dBrnc0. A. 75 B. 29 C. 30 D. 31

Last Answer : A. 75

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

What is the time delay introduced by a 75-ft coaxial cable with a dielectric constant of 2.3? A. 1.54 ns B. 11.5 ns C. 115.6 ns D. 1156 ns

Description : What is the time delay introduced by a 75-ft coaxial cable with a dielectric constant of 2.3? A. 1.54 ns B. 11.5 ns C. 115.6 ns D. 1156 ns

Last Answer : C. 115.6 ns

What is transit time (time delay) of a 50-ft length transmission line of the above problem? A. 50 ns B. 100 ns C. 75 ns D. 65 ns

Description : What is transit time (time delay) of a 50-ft length transmission line of the above problem? A. 50 ns B. 100 ns C. 75 ns D. 65 ns

Last Answer : C. 75 ns

If a fiber optic system has a rise time of 38.55 ns, the source rise time is 12 ns and the detector rise time is 12 ns, what is the cable rise time? A. 34.61 ns B. 14.55 ns C. 52.55 ns D. 26.25 ns

Description : If a fiber optic system has a rise time of 38.55 ns, the source rise time is 12 ns and the detector rise time is 12 ns, what is the cable rise time? A. 34.61 ns B. 14.55 ns C. 52.55 ns D. 26.25 ns

Last Answer : A. 34.61 ns

If a fiber optic system has a rise time of 16 ns, the source rise time is 1.5 ns and the detector rise time is 2 ns, what is the cable rise time? A. 14 ns B. 6 ns C. 9 ns D. 12.5 ns

Description : If a fiber optic system has a rise time of 16 ns, the source rise time is 1.5 ns and the detector rise time is 2 ns, what is the cable rise time? A. 14 ns B. 6 ns C. 9 ns D. 12.5 ns

Last Answer : A. 14 ns

What is the velocity factor of coaxial cable with a characteristic impedance of 50Ω and capacitance of 30pF/ft and inductance of 75 nH/ft? A. 0.58 B.0.68 C. 0.98 D. 0.81

Description : What is the velocity factor of coaxial cable with a characteristic impedance of 50Ω and capacitance of 30pF/ft and inductance of 75 nH/ft? A. 0.58 B.0.68 C. 0.98 D. 0.81

Last Answer : B.0.68

Reference temperature use in noise analysis A. 75 K B. 250 K C. 290 K D. 300 K

Description : Reference temperature use in noise analysis A. 75 K B. 250 K C. 290 K D. 300 K

Last Answer : C. 290 K

What is actual length in feet of a one-half wavelength of a coax with a velocity factor of 0.59 at 26 MHz? A. 11.16 B. 40.29 C. 42.46 D. 46.28

Description : What is actual length in feet of a one-half wavelength of a coax with a velocity factor of 0.59 at 26 MHz? A. 11.16 B. 40.29 C. 42.46 D. 46.28

Last Answer : A. 11.16

Let the page fault service time be 10 millisecond(ms) in a computer with average memory access time being 20 nanosecond(ns). If one page fault is generated for every 106 memory accesses, what is the effective access time for memory? (A) 21 ns (B) 23 ns (C) 30 ns (D) 35 ns

Description : Let the page fault service time be 10 millisecond(ms) in a computer with average memory access time being 20 nanosecond(ns). If one page fault is generated for every 106 memory accesses, what is the effective access time for memory? (A) 21 ns (B) 23 ns (C) 30 ns (D) 35 ns

Last Answer : (C) 30 ns

What is the required quality factor for an SSB filter with the following data: center frequency= 1 MHz, the desired attenuation level of the unwanted sideband= 80 dB and the separation between sidebands= 200 Hz? A. 1,250 B. 12,500 C. 125,000 D. 25,000

Description : What is the required quality factor for an SSB filter with the following data: center frequency= 1 MHz, the desired attenuation level of the unwanted sideband= 80 dB and the separation between sidebands= 200 Hz? A. 1,250 B. 12,500 C. 125,000 D. 25,000

Last Answer : C. 125,000

What is the approximate percentage of earth coverage of a geostationary satellite at zero degree elevation? A. 33.3% B. 45.2% C. 42.5% D. 30.5%

Description : What is the approximate percentage of earth coverage of a geostationary satellite at zero degree elevation? A. 33.3% B. 45.2% C. 42.5% D. 30.5%

Last Answer : C. 42.5%

Determine the maximum shearing stress and elongation in a helical steel spring composed of 20 turns of 20-mm-diameter wire on a mean radius of 90 mm when the spring is supporting a load of 1.5 kN. and G = 83 GPa. a. 200 mm b. 105.4 mm c. 150 mm d. 250 mm

Description : Determine the maximum shearing stress and elongation in a helical steel spring composed of 20 turns of 20-mm-diameter wire on a mean radius of 90 mm when the spring is supporting a load of 1.5 kN. and G = 83 GPa. a. 200 mm b. 105.4 mm c. 150 mm d. 250 mm

Last Answer : b. 105.4 mm

Calculate logarithmic decrement if damping factor is 0.33. A 1.36 B 3.23 C 5.16D 2.19

Description : Calculate logarithmic decrement if damping factor is 0.33. A 1.36 B 3.23 C 5.16D 2.19

Last Answer : D 2.19

Calculate logarithmic decrement if damping factor is 0.33. D ( A ) 1.36 ( B ) 3.23 ( C ) 5.16 ( D ) 2.19

Description : Calculate logarithmic decrement if damping factor is 0.33. D ( A ) 1.36 ( B ) 3.23 ( C ) 5.16 ( D ) 2.19

Last Answer : D ) 2.19

Calculate logarithmic decrement if damping factor is 0.33. a. 1.36 b. 3.23 c. 5.16 d. 2.19

Description : Calculate logarithmic decrement if damping factor is 0.33. a. 1.36 b. 3.23 c. 5.16 d. 2.19

Last Answer : d. 2.19

What height must a satellite be placed above the surface of the earth in order for its rotation to be equal to earth’s rotation? A. 26,426.4 miles B. 27,426.4 miles C. 23,426.4 miles D. 22,426.4 miles

Description : What height must a satellite be placed above the surface of the earth in order for its rotation to be equal to earth’s rotation? A. 26,426.4 miles B. 27,426.4 miles C. 23,426.4 miles D. 22,426.4 miles

Last Answer : D. 22,426.4 miles

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

Refer to problem # 11. Determine the force that accelerates if to 12 m/s^2. horizontally along frictionless plane.  A. 2474.23 N  B. 2574.23 N  C. 3474.23 N  D. 2374.23 N Formula : M = wk / g F = ma /k

Description : Refer to problem # 11. Determine the force that accelerates if to 12 m/s^2. horizontally along frictionless plane.  A. 2474.23 N  B. 2574.23 N  C. 3474.23 N  D. 2374.23 N Formula : M = wk / g F = ma /k

Last Answer : 2474.23 N

A system weighing 2kN. Determine the force that accelerate if to 12 m/s^2. a. vertically upward when g = 9.7 m/s^2  A. 4474.23 N  B.5484.23 N  C.4495.23 N  D.5488.23 N Formula: F = m/k (a +g)

Description : A system weighing 2kN. Determine the force that accelerate if to 12 m/s^2. a. vertically upward when g = 9.7 m/s^2  A. 4474.23 N  B.5484.23 N  C.4495.23 N  D.5488.23 N Formula: F = m/k (a +g)

Last Answer : 4474.23 N

What is the noise factor if the equivalent noise temperature is 25 K? A. 1.09 B. 0.09 C. 0.36 dBm D. 0.36

Description : What is the noise factor if the equivalent noise temperature is 25 K? A. 1.09 B. 0.09 C. 0.36 dBm D. 0.36

Last Answer : A. 1.09

ECE Board Exam March 1996 The K-factor under normal atmospheric conditions in a microwave radio data profile calculation is equal to ___________. A. 2/3 B. 0 C. 4/3 D. Infinity

Description : ECE Board Exam March 1996 The K-factor under normal atmospheric conditions in a microwave radio data profile calculation is equal to ___________. A. 2/3 B. 0 C. 4/3 D. Infinity

Last Answer : C. 4/3

A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... , are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz

Last Answer : a) 0.471 and 1.19 Hz

A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... .19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Last Answer : a) 0.471 and 1.19 Hz

If total income of company B in 2008 was Rs.140 crore, what was the total expenditure of that company in the same year? (approx) a) Rs.100.66 cr. b) Rs.110.33 cr. c) Rs.98.22 cr. d) Rs.94.90 cr. e) Rs.96.55 cr.

Description : If total income of company B in 2008 was Rs.140 crore, what was the total expenditure of that company in the same year? (approx) a) Rs.100.66 cr. b) Rs.110.33 cr. c) Rs.98.22 cr. d) Rs.94.90 cr. e) Rs.96.55 cr.

Last Answer : e) Rs.96.55 cr.

An artificial satellite is moving in a circular orbit of radius 42.250 km (approx). Calculate its linear velocity if takes 24 hour to revolve around earth.? -Science

Description : An artificial satellite is moving in a circular orbit of radius 42.250 km (approx). Calculate its linear velocity if takes 24 hour to revolve around earth.? -Science

Last Answer : Given r =42.250 km , T= 24 hour Linear velocity in circular motion is given by v=2πrT=2×3.14×42.25024=11.05km/hrv=2πrT=2×3.14×42.25024=11.05km/hr

What is the frequency range of an aircraft’s Very High Frequency (VHF) communications? A. 118.000 MHz to 136.975 MHz (worldwide up to 151.975 MHz) B. 108.000 MHz to 117.95 MHz C. 329.15 MHz to 335.00 MHz D. 2.0000 MHz to 29.999 MHz

Description : What is the frequency range of an aircraft’s Very High Frequency (VHF) communications? A. 118.000 MHz to 136.975 MHz (worldwide up to 151.975 MHz) B. 108.000 MHz to 117.95 MHz C. 329.15 MHz to 335.00 MHz D. 2.0000 MHz to 29.999 MHz

Last Answer : A. 118.000 MHz to 136.975 MHz (worldwide up to 151.975 MHz)

What quarterwave transformer will match a 100Ω line to an antenna whose value is 175Ω? A. 132.29 Ω B. 150 Ω C. 16.58 Ω D. 137.5 Ω

Description : What quarterwave transformer will match a 100Ω line to an antenna whose value is 175Ω? A. 132.29 Ω B. 150 Ω C. 16.58 Ω D. 137.5 Ω

Last Answer : A. 132.29 Ω

What would be the physical length of a tpical coaxial transmission line that is electrically one-quarter wavelength long at 14.1 MHz? A. 20 meters B. 3.51 meters C. 2.33 meters D. 0.25 meter

Description : What would be the physical length of a tpical coaxial transmission line that is electrically one-quarter wavelength long at 14.1 MHz? A. 20 meters B. 3.51 meters C. 2.33 meters D. 0.25 meter

Last Answer : B. 3.51 meters

How many FM stations would be accommodated I an ordinary TV channel? A. 33 B. 30 C. 40 D. 25

Description : How many FM stations would be accommodated I an ordinary TV channel? A. 33 B. 30 C. 40 D. 25

Last Answer : B. 30

An AM transmitter is rated 100W at 100% modulation. How much power required for the carrier? A. 33.33 W B. 66.66 W C. 83.33 W D. 100 W

Description : An AM transmitter is rated 100W at 100% modulation. How much power required for the carrier? A. 33.33 W B. 66.66 W C. 83.33 W D. 100 W

Last Answer : B. 66.66 W

What is the phase delay of an 800 Hz voice signal if the phase shift is 15 degrees? A. 1.25 µsec B. 52 µsec C. 83.33 µsec D. 26 µsec

Description : What is the phase delay of an 800 Hz voice signal if the phase shift is 15 degrees? A. 1.25 µsec B. 52 µsec C. 83.33 µsec D. 26 µsec

Last Answer : B. 52 µsec

The median of the data 26,56,32,33,60,17,34,29,45 is 33. If 26 is replaced by 62, then find the new median. -Maths 9th

Description : The median of the data 26,56,32,33,60,17,34,29,45 is 33. If 26 is replaced by 62, then find the new median. -Maths 9th

Last Answer : Here, the given data in ascending order is 17, 29, 32, 33, 34, 45, 56, 60, 62 Now median is (9 + 1 / 2)th term i.e. , 5th term Hence, new median is 34.

The median of the data 26,56,32,33,60,17,34,29,45 is 33. If 26 is replaced by 62, then find the new median. -Maths 9th

Description : The median of the data 26,56,32,33,60,17,34,29,45 is 33. If 26 is replaced by 62, then find the new median. -Maths 9th

Last Answer : Here, the given data in ascending order is 17, 29, 32, 33, 34, 45, 56, 60, 62 Now median is (9 + 1 / 2)th term i.e. , 5th term Hence, new median is 34.

The total number of vertebrae in a human being is - (1) 26 (2) 30 (3) 29 (4) 33

Description : The total number of vertebrae in a human being is - (1) 26 (2) 30 (3) 29 (4) 33

Last Answer : (4) 33 Explanation: The vertebral column, also known as backbone or spine, is a bony structure found in Vertebrates. It is formed from the vertebrae.

The ball bearing is subjected to a radial load of 4000 N. Expected life for 90% bearings is 9000 hr and the shaft is rot (a) 42.21 kN (b) 37.29 kN (c) 26.33 kN (d) 35.22 kN

Description : The ball bearing is subjected to a radial load of 4000 N. Expected life for 90% bearings is 9000 hr and the shaft is rot (a) 42.21 kN (b) 37.29 kN (c) 26.33 kN (d) 35.22 kN

Last Answer : (b) 37.29 kN

At what age did Christopher Marlow die? A. 33 B. 29 C. 47 D. 54

Description : At what age did Christopher Marlow die? A. 33 B. 29 C. 47 D. 54

Last Answer : 29

A dealer buys an article marked at Rs. 50,000 at 25% and 10% successive discount. He spends Rs. 5000 on its repair and sells it for Rs. 50,000. What is his loss or gain percentage? 1. 33.63% loss 2. 26.43% gain 3. 1.25% gain 4. 29.03% 5. 27.13% loss

Description : A dealer buys an article marked at Rs. 50,000 at 25% and 10% successive discount. He spends Rs. 5000 on its repair and sells it for Rs. 50,000. What is his loss or gain percentage? 1. 33.63% loss 2. 26.43% gain 3. 1.25% gain 4. 29.03% 5. 27.13% loss

Last Answer : CP of the article  

The total number of vertebrae in a human being is (1) 26 (2) 30 (3) 29 (4) 33

Description : The total number of vertebrae in a human being is (1) 26 (2) 30 (3) 29 (4) 33

Last Answer : 33

Express 98 as a product of its primes (a) 22 × 7 (b) 22 × 72 (c) 2 × 72 (d) 23 × 7

Description : Express 98 as a product of its primes (a) 22 × 7 (b) 22 × 72 (c) 2 × 72 (d) 23 × 7

Last Answer : (c) 2 × 72

3599 ÷ 224.95 × 23.04 = ? + 16.98 × 11.03 a) 130 b) 210 c) 180 d) 115 e) 155

Description : 3599 ÷ 224.95 × 23.04 = ? + 16.98 × 11.03 a) 130 b) 210 c) 180 d) 115 e) 155

Last Answer : 3600 ÷ 225 × 23 = ? +17 × 11 =>16 × 23 = ? + 187 => ? = 368 – 187 =181 ≈ 180 Answer: c)

Given the following data pairs (x, y), find the regression equation. (1, 1.24), (2, 5.23), (3, 7.24), (4, 7.60), (5, 9.97), (6, 14.31), (7, 13.99), (8, 14.88), (9, 18.04), (10, 20.70) a. y = 0.490 x - 0.053 b. y = 2.04 x c. y = 1.98 x + 0.436 d. y = 0.49 x

Description : Given the following data pairs (x, y), find the regression equation. (1, 1.24), (2, 5.23), (3, 7.24), (4, 7.60), (5, 9.97), (6, 14.31), (7, 13.99), (8, 14.88), (9, 18.04), (10, 20.70) a. y = 0.490 x - 0.053 b. y = 2.04 x c. y = 1.98 x + 0.436 d. y = 0.49 x

Last Answer : c. y = 1.98 x + 0.436

A final amplifier of a radio transmitter draws 250 mA of plate current when the plate supply voltage is 1400 volts. If the plate circuit efficiency is 80% and the transmitter is connected to an antenna having a feed impedance of 70 ohms, what is the antenna current at the feed-point? A. 4.0 A B. 2.2 A C. 1.25 A D. 2.0 A

Description : A final amplifier of a radio transmitter draws 250 mA of plate current when the plate supply voltage is 1400 volts. If the plate circuit efficiency is 80% and the transmitter is connected to an antenna having a feed impedance of 70 ohms, ... at the feed-point? A. 4.0 A B. 2.2 A C. 1.25 A D. 2.0 A

Last Answer : D. 2.0 A

The length of a Marconi antenna to operate with 985 kHz is ______. A. 200 ft B. 500 ft C. 250 ft D. 999 ft

Description : The length of a Marconi antenna to operate with 985 kHz is ______. A. 200 ft B. 500 ft C. 250 ft D. 999 ft

Last Answer : C. 250 ft

What is the estimated medium wind loading in the Philippines for antenna tower design? A. 300 kph B. 100 kph C. 200 kph D. 250 kph

Description : What is the estimated medium wind loading in the Philippines for antenna tower design? A. 300 kph B. 100 kph C. 200 kph D. 250 kph

Last Answer : C. 200 kph

The maximum propagation delay of a geostationary satellite is A. 278 ms B. 239 ms C. 300 ms D. 250 ms

Description : The maximum propagation delay of a geostationary satellite is A. 278 ms B. 239 ms C. 300 ms D. 250 ms

Last Answer : A. 278 ms

Which of the following describes a TDM frame? A. A 250-μs frame B. A 125-μs frame C. A 500-μs frame D. A 60-μs frame

Description : Which of the following describes a TDM frame? A. A 250-μs frame B. A 125-μs frame C. A 500-μs frame D. A 60-μs frame

Last Answer : B. A 125-μs frame

What is the end impedance of a half-wave dipole? A. 73 Ω B. 72 Ω C. 250 Ω D. 2500 Ω

Description : What is the end impedance of a half-wave dipole? A. 73 Ω B. 72 Ω C. 250 Ω D. 2500 Ω

Last Answer : D. 2500 Ω

During the night when the F2 layer combines with F1 layer it falls to what approximate height? A. 250 km B. 350 km C. 300 km D. 400 km

Description : During the night when the F2 layer combines with F1 layer it falls to what approximate height? A. 250 km B. 350 km C. 300 km D. 400 km

Last Answer : C. 300 km