There are two groups of a class consisting of 72 and 88 students respectively. If the average weight of 1st group is 80kg and the weight of 2nd group is 70kg. Find the average weight of whole class? A) 64kg B) 74.5kg C) 84.5kg D) 54kg

There are two groups of a class consisting of 72 and 88 students respectively. If the average weight of 1st group is 80kg and the weight of 2nd group is 70kg. Find the average weight of whole class? A) 64kg B) 74.5kg C) 84.5kg D) 54kg
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1 Answer

Answer :

 B)

 Total weight of (72 + 88) = (72*80) + (88 * 70)kg

= (5760 + 6160)kg

 = 11,920kg

 Average weight of the whole class = 11920 / 160

 = 74.5 kg


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Related questions

The average weight of x,y,z is 90kg. If the average weight of x and y be 80kg and that of y and z be 86kg. Find the weight of y A) 66kg B) 63kg C) 62kg D) 70kg

Description : The average weight of x,y,z is 90kg. If the average weight of x and y be 80kg and that of y and z be 86kg. Find the weight of y A) 66kg B) 63kg C) 62kg D) 70kg 

Last Answer : C)  Let x ,y ams z represent their individual weights. Then,  X + y + z = ( 90 * 3) = 270kg  X+ y = 80 *2 = 160kg  Y + z = 86 * 2 = 172kg  Therefore y = (x + y) + ( y+z) – (x+y+z) = 160 + 172 – 270  Y= 62kg.

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on analyzing the result of an competitive exam the teacher found that the average for the entire the class was 69 marks. If we say that average of 10 % of the students scored 77 marks and average of 28 % of the students scored 66 marks, then calculate average marks of the remaining students of the class A) 67.54 B) 68.26 C) 66.91 D) 69.06

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The average age of three -seventh of class is 49, what should be the average of remaining four-seventh students so that the average of the entire class is 63? A) 24.5 B) 86.5 C) 73.5 D) 25.5

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Last Answer : C) According to the question, 63=3/7×49+4/7×y 63=147/7+4y/7 441=147+4y 4y=294 Y=73.5

The average score in a bank examination of 13 students of a class is 50. If the scores of the top five students are not considered, the average score of the remaining students falls by 5. The pass mark was 35 and the maximum mark was 100. It is also known that none of the students failed. If each of the top five scorers had distinct integral scores, the maximum possible score of the topper is. A) 85 B) 90 C) 95 D) 100

Description : The average score in a bank examination of 13 students of a class is 50. If the scores of the top five students are not considered, the average score of the remaining students falls by 5. The pass mark ... integral scores, the maximum possible score of the topper is. A) 85 B) 90 C) 95 D) 100

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The average marks of a class of 90 students is 126. Out Of them, 4 scores zero, first 60 students scored an average of 116, next 24 scored an average of 118. What is the mark obtained by the remaining student in the class? A) 750 B) 862 C) 774 D) 875

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A group of 210 students appeared in some test. The mean of of students is found to be 60. The mean of the remaining students is found to be 78. The mean of the whole group will be: (A) 80 (B) 76 (C) 74 (D) 72

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Description : The average height of the students in a group was 360cm. When 10 students whose height is 292.8cm are newly admitted. The average height of the group was reduced by 24cm.How many students are present in the group? A) 29 B) 25 C) 28 D) 14

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In an competitive examination, the average was found to be 72 marks. After detecting the errors the marks of 94 candidates had to be charged from 90 to 66 each, and the average is reduced to 64 marks. Find the total number of candidates who took the exam. A) 282 B) 382 C) 828 D) 200

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A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : NEED ANSWER

A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

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The average height of a batch is 344 cm. 16more students with an average height of 320 cm joined the batch therefore decreasing the average height of the batch by 12 cm. Find the total strength of the batch? A) 12 B) 11 C) 14 D) 16

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Description : There are three different categories of jobs A, B and C. The average salary of the students who got the job of A and B categories is Rs.32 lakh per annum. The average salary of the student who got the job of B ... 30 & 44 B) lies between 48 & 56 C) lies between 38 & 45 D) lies between 49 & 50

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Distance between two stations P & Q is 1556km. A passenger train covers the journey from P to Q at 168km per hr and return back to P with a uniform speed of 112km/hr. Find the Average speed of the train during the whole journey? A) 124.4 km/hr B) 130.4km/hr C) 134.4 km/hr D) 130.0 km/hr

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67,74,78,?,92,94 a) 86 b) 85 c) 83 d) 84 e) 88

Description : 67,74,78,?,92,94 a) 86 b) 85 c) 83 d) 84 e) 88

Last Answer : The next term is obtained by adding the unit’s digit to the number. Hence the missing number =78+8=86 Answer: a)

A group of students of arithmetic mean of the marks in a test was 63. The brightest 30% of them secured a mean score of 70 and the dullest 15% a mean score of 41. The mean score of remaining 55 % is A) 63.675 B) 61.785 C) 65.181 D) 66.67

Description : A group of students of arithmetic mean of the marks in a test was 63. The brightest 30% of them secured a mean score of 70 and the dullest 15% a mean score of 41. The mean score of remaining 55 % is A) 63.675 B) 61.785 C) 65.181 D) 66.67

Last Answer : C) Let the requird mean score be ‘x’ Then (30*70)+(15*41)+55x = 63*100 2100+615+55x=6300 2715+55x=6300 55x=3585 X=65.181

The average of weight of three men A,B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg.more than that of D, replaces A, then the average weight of B,C,D and E becomes 79 kg. The weight of A is : a) 70 kg b) 72 kg c) 75 kg d) 80 kg e) 78 kg

Description : The average of weight of three men A,B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg.more than that of D, replaces A, then the average weight of B,C ... 79 kg. The weight of A is : a) 70 kg b) 72 kg c) 75 kg d) 80 kg e) 78 kg

Last Answer : A+B+C = 3×84=252 A+B+C+D= (4×80)=320 D = (320-252)=68 and E = (68+3)=71 Now, B+C+D+E = (4×79)=316 B+C+D=(316-71)=245 kg So, A = (320-245)=75 kg Answer: c)

A group of 4 persons joins in javelin throw competition. The best player scored 42.5 points. If he had scored 46 points, the average score for the team would have been 42. The number of points the team scored. A) 164.5 B) 166.5 C) 169.7 D) 162.5

Description : A group of 4 persons joins in javelin throw competition. The best player scored 42.5 points. If he had scored 46 points, the average score for the team would have been 42. The number of points the team scored. A) 164.5 B) 166.5 C) 169.7 D) 162.5

Last Answer : A) Let the total score be ‘x’. (X+46 – 42.5)/4 = 42 X + 3.5 = 42 * 4 X + 3.5 = 168 X = 168 – 3.5 X = 164.5

The average weight of 45 passenger on board an aircraft is 50 kg. If the weight of 5 members of the crew is added, the average is reduced by half kilogram . What is the average weight of the crew members?

Description : The average weight of 45 passenger on board an aircraft is 50 kg. If the weight of 5 members of the crew is added, the average is reduced by half kilogram . What is the average weight of the crew members?

Last Answer : Total weight of 45 passenger = 45 x 50 = 2250 kg Total weight of 45 passenger and 5 crews = 50 x 49.5 = 2475 kg Total weight of 5 crews = 2475-2250 = 225kg Average weight of 5 crews = 225/5 = 45kg.

In shewak's opinion, his weight is greater than 76 kg but less than 83 kg. His sister doest not agree with shewak and she thinks that shewak’s weight is greater than 71 kg but less than 81 kg. His father's view is that his weight cannot be greater than 79 kg. If all are them are correct in their estimation, what is the average of different probable weights of shewak? A) 67kg B) 68kg C) 72kg D) 78kg

Description : In shewak's opinion, his weight is greater than 76 kg but less than 83 kg. His sister doest not agree with shewak and she thinks that shewak's weight is greater than 71 kg but less than 81 kg. His ... , what is the average of different probable weights of shewak? A) 67kg B) 68kg C) 72kg D) 78kg

Last Answer :  Answer: D) Let shewak's weight be X kg. According to shewak , 76 < X < 83 According to shewak 's sister, 71 < X < 81. According to shewak 's father, X ≤ 79 The values satisfying all the above conditions are 77, 78and 79. Required average=[ (77+78+79)/3] = 201/ 3 = 78kg.

The price of a necklace, passing through a 3 persons, rises on the whole by 32.5%. If the 1st and the 2nd sellers earned 10% and 12.5% profit respectively. Find the percentage profit earned by the 3rd seller.

Description : The price of a necklace, passing through a 3 persons, rises on the whole by 32.5%. If the 1st and the 2nd sellers earned 10% and 12.5% profit respectively. Find the percentage profit earned by the 3rd seller. 

Last Answer : Let the original price of the necklace be Rs x and Let the profit earned by the 3rd seller be P% Then (100+P)% of 112.5% of 110% of x = 132.5% of x (100+P/100)*(112.5/100)*(x) = 132.5/100 ... /12375 100+P = 107.07 P= 107.07 - 100 = 7.07% The percentage profit earned by the 3rd seller = 7%

The mean of 8 article was found to be 15. On rechecking, it was found that two article were wrongly taken as 11 and 9 instead of 16 and 14 respectively. Find the correct mean. A) 17.25 B) 13.65 C) 16.54 D) 16.25

Description : The mean of 8 article was found to be 15. On rechecking, it was found that two article were wrongly taken as 11 and 9 instead of 16 and 14 respectively. Find the correct mean. A) 17.25 B) 13.65 C) 16.54 D) 16.25

Last Answer : D) Calculated mean of 8 articles = 15 Incorrect sum of these 8 articles = (15*8) = 120. Correct sum of these 8 articles = (incorrect sum) - (sum of incorrect articles) + (sum of actual articles) = [120 ... (30)] = 130 Therefore, correct mean = 130/8 = 16.25 Hence, the correct mean is 16.25.

An Aided school has only three classes which contain 70, 36 and 40students respectively. The pass percentage of these classes are30,25 and 20 respectively. The pass percentage of the aided school is A) 23 % B) 15% C) 26 % D) 30%

Description : An Aided school has only three classes which contain 70, 36 and 40students respectively. The pass percentage of these classes are30,25 and 20 respectively. The pass percentage of the aided school is A) 23 % B) 15% C) 26 % D) 30% 

Last Answer : C) Total number of students passed in class1 = 30/100 *70 = 21 Total number of students passed in class 2= 25/100 *36 = 9 Total number of students passed in class 3= 20/100 *40 = 8 Total number of students passed in the school = 38 Thus, pass percentage of the school = 38 /146*100 = 26 %

A school has 4 sections of class 12, such that half the number of students of 1st section, 1/3rd of 2nd section, 1/4th of 3rd section and 1/5th of the 4th section are equal. If total number of students in class 12 is 420, find the number of students in sections 1st and 2nd. A) 180 B) 120 C) 240 D) 150 E) 260

Description : A school has 4 sections of class 12, such that half the number of students of 1st section, 1/3rd of 2nd section, 1/4th of 3rd section and 1/5th of the 4th section are equal. If total number of students in ... find the number of students in sections 1st and 2nd. A) 180 B) 120 C) 240 D) 150 E) 260

Last Answer : Answer: D Let number of students in 4 sections be A, B, C, D respectively. Then 1/2 of A = 1/3 of b = 1/4 of C = 1/5 of D So A : B : C : D = 2 : 3 : 4 : 5 [When A/2 = B/3 = C/4, then ratio A: B : C = 2 : 3 : 4] So students in 1st and 2nd section = [(2+3)/(2+3+4+5)] * 420 = 150

How many bottles are in each group when 1700 bottles of water arranged into 4 groups with the 2nd group having 20 more than the 1st the 3rd twice the 2nd and the 4th 10 more than the 3rd?

Description : How many bottles are in each group when 1700 bottles of water arranged into 4 groups with the 2nd group having 20 more than the 1st the 3rd twice the 2nd and the 4th 10 more than the 3rd?

Last Answer : let the number of bottles in the first group be BThenthe 2nd group has 1st + 20 = B + 20 bottles;the 3rd group has 2nd Ã- 2 = 2 Ã- (B + 20) = 2B + 40 bottles;the 4th group has 3rd + ... = 580 bottlesChecking: 265 + 285 + 570 + 580 = 1700 The groups contain 265, 285, 570 and 580 bottles respectively.

The average of 5 numbers is 9 and the average of the last three numbers is 5.Find the average of the first two numbers.

Description : The average of 5 numbers is 9 and the average of the last three numbers is 5.Find the average of the first two numbers.

Last Answer : Sum of 5 numbers = 9 x 5 = 45 Sum of last three numbers = 15 The average of 1st two numbers = 45-15/2 = 30/2 = 15.

The batting average for 20 innings of a cricketer is 25 runs. His highest score exceeds his lowest score by 86 runs. If these two innings are excluded, the average of the remaining 18 innings is 22runs. Find out the highest score of the player. A) 85 B) 90 C) 95 D) 100

Description : The batting average for 20 innings of a cricketer is 25 runs. His highest score exceeds his lowest score by 86 runs. If these two innings are excluded, the average of the remaining 18 innings is 22runs. Find out the highest score of the player. A) 85 B) 90 C) 95 D) 100

Last Answer : C) Total runs scored by the player in 20 innings = 20*25 Total runs scored by the player in 18 innings after excluding two innings = 18 22 Sum of the scores of the excluded innings = 20 25 - 18 22 = 104 Given that ... Now x + 86 + x = 104 => 2x = 18 then x = 9 Highest score = 9+ 86 = 95

At the average age of siva and sasi is equal to the average age of somu and ramu. if the ratio of age of siva and sasi 1:3 and somu age is equal to the three by two of siva age. What is the present age of somu if ramu age is 25years? A) 12 B) 15 C) 18 D) 21

Description : At the average age of siva and sasi is equal to the average age of somu and ramu. if the ratio of age of siva and sasi 1:3 and somu age is equal to the three by two of siva age. What is the present age of somu if ramu age is 25years? A) 12 B) 15 C) 18 D) 21

Last Answer : B) siva:sasi=x:3x siva+sasi/2=somu + ramu/2 X+3X=3/2×X+25 5X=50 X=10 Siva’s age is 10 then somu's age = 3/2×10=15 years