The average weight of M,N and O is 168 kg. If P joins the group, the average weight of the group becomes 160 kg. If another man Q who weighs 6kg more than P replaces M, then the average of N,O,P and Qbecomes158 kg. What is the weight of M? A) 175 B) 140 C) 145 D) 150

The average weight of M,N and O is 168 kg. If P joins the group, the average weight of the group becomes 160 kg. If another man Q who weighs 6kg more than P replaces M, then the average of N,O,P and Qbecomes158 kg. What is the weight of M? A) 175 B) 140 C) 145 D) 150 
by

1 Answer

Answer :

D)

M+N+O =168 * 3 =504

M+N+O+P=160*4=640……(1)

P=136 kg and Q =142 kg

N+O+P+Q =158*4 =632

N+O+P =632-142 =490…..(2)

from 1 & 2,

M=640-490 =150kg
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Related questions

The average of weight of three men A,B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg.more than that of D, replaces A, then the average weight of B,C,D and E becomes 79 kg. The weight of A is : a) 70 kg b) 72 kg c) 75 kg d) 80 kg e) 78 kg

Description : The average of weight of three men A,B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg.more than that of D, replaces A, then the average weight of B,C ... 79 kg. The weight of A is : a) 70 kg b) 72 kg c) 75 kg d) 80 kg e) 78 kg

Last Answer : A+B+C = 3×84=252 A+B+C+D= (4×80)=320 D = (320-252)=68 and E = (68+3)=71 Now, B+C+D+E = (4×79)=316 B+C+D=(316-71)=245 kg So, A = (320-245)=75 kg Answer: c)

Average age of A, B, C is 90yrs, however when D joins them, then the average comes down to 80 yrs. Now a new person E, whose age is six-fifth of the age of D, replaces A and the new average is 78. What is age of A? A) 64 B) 68 C) 62 D) 66

Description : Average age of A, B, C is 90yrs, however when D joins them, then the average comes down to 80 yrs. Now a new person E, whose age is six-fifth of the age of D, replaces A and the new average is 78. What is age of A? A) 64 B) 68 C) 62 D) 66

Last Answer : B) according to the question A+B+C/3=90 => A+B+C =270…………..(1) A+B+C +D/4=80 => A+B+C +D=320………(2) From the equation 1 and 2 D=50 E =6/5×50=60 E+B+C +D/4=78 => E+B+C +D =312 B+C +D =312-60=252……………..(3) From 2and 3 The age of A=320-252=68

The average age of 160 boys in a class is 58 yrs. The average group of 30 boys in the class is 42 yrs and the average of another group of 50 boys in the class is 36 years. What is the average age of the remaining boys? A) 72.58 B) 74.25 C) 77.75 D) 75.68

Description : The average age of 160 boys in a class is 58 yrs. The average group of 30 boys in the class is 42 yrs and the average of another group of 50 boys in the class is 36 years. What is the average age of the remaining boys? A) 72.58 B) 74.25 C) 77.75 D) 75.68 

Last Answer : C) Total age of 160 boys = 160* 58= 9280 total age of 30 boys = 30 * 42= 1260 total age of next 50boys = 50 * 36= 1800 average of the remaining boys = [(9280-{1260+1800})/[160 - (30 + 50)] =>9280-3060/80 =>6220/80 =77.75yrs

When a girl weighing 90 kgs left a class, the average weight of the remaining 119 students increased by 400 g. What is the average weight of the remaining 119 students? A) 124 B) 138 C) 145 D) 116

Description : When a girl weighing 90 kgs left a class, the average weight of the remaining 119 students increased by 400 g. What is the average weight of the remaining 119 students? A) 124 B) 138 C) 145 D) 116

Last Answer :  B Let the average weight of the 119 students be X. Therefore, the total weight of the 119 of them will be 119X. The questions states that when the weight of this student who left is added, the total ... , the average weight decreases by 0.4 kgs. (119X+90)/120=X−0.4 ⇒119X+90=120X−48  ⇒X=138

A group of 4 persons joins in javelin throw competition. The best player scored 42.5 points. If he had scored 46 points, the average score for the team would have been 42. The number of points the team scored. A) 164.5 B) 166.5 C) 169.7 D) 162.5

Description : A group of 4 persons joins in javelin throw competition. The best player scored 42.5 points. If he had scored 46 points, the average score for the team would have been 42. The number of points the team scored. A) 164.5 B) 166.5 C) 169.7 D) 162.5

Last Answer : A) Let the total score be ‘x’. (X+46 – 42.5)/4 = 42 X + 3.5 = 42 * 4 X + 3.5 = 168 X = 168 – 3.5 X = 164.5

The average age of 150 students in a class is 40% of the number of students in the class and the average age of a group of 50 students present in the class is 32yrs and the average age of another 50 students in the class is 36yrs. What is the average age of the remaining students in the class? A) 102 B) 118 C) 112 D) 108

Description : The average age of 150 students in a class is 40% of the number of students in the class and the average age of a group of 50 students present in the class is 32yrs and the average age of another 50 students ... is the average age of the remaining students in the class? A) 102 B) 118 C) 112 D) 108

Last Answer : C) 150 students average 150×40/100=60 years According to the question, 150×60=50×32+50×36+50×X 50×X=9000-1600-1800 50x=5600 X=112

A cricketer played 3 matches in tournament. The respective ratio between the scores of first and second matches was 3:7 and that between the scores of second and third matches between was 7 :2. the difference between first and third matches was 84 runs, what was the cricketer average score in all the matches together? A) 336 B) 146 C) 168 D) 189

Description : A cricketer played 3 matches in tournament. The respective ratio between the scores of first and second matches was 3:7 and that between the scores of second and third matches between was 7 :2. the difference ... the cricketer average score in all the matches together? A) 336 B) 146 C) 168 D) 189

Last Answer : A) The ratio between first and second matches equal to 3 :7 The ratio between second and third matches=7:2 The difference between first and third matches=3x-2x=84 runs = 84 Required average=1008/3=336 .

Students of two colleges appeared for Talent test carrying 250marks as maximum. The average of their marks for college1 & college 2 are 160 & 180respectively. If the number of students of college 1 is the half of the number of students of college 2, then what is the average marks of all students of both the college? A) 170 B) 110 C) 173.33 D) 177.33

Description : Students of two colleges appeared for Talent test carrying 250marks as maximum. The average of their marks for college1 & college 2 are 160 & 180respectively. If the number of students of college 1 is the half of the ... marks of all students of both the college? A) 170 B) 110 C) 173.33 D) 177.33

Last Answer : C) let the number of students of college 2 be '2N' then the number of students of college1 is 'N' the average marks for college1 is 160 the average marks for college 2 is 180 total marks of ... = 360N average marks of all students of both the colleges = (160N + 360N)/N+2N = 173.33marks

The average height of 50 students in a class is 182 cm. 40 students whose average height is 182.5 cm left the class and 50 students whose average height is 180.5 cm joined the class. Find the average height of the present? A) 180.41 B) 175.5 C) 180.55 D) 185.5

Description : The average height of 50 students in a class is 182 cm. 40 students whose average height is 182.5 cm left the class and 50 students whose average height is 180.5 cm joined the class. Find the average height of the present? A) 180.41 B) 175.5 C) 180.55 D) 185.5

Last Answer : A) The average of the students leaving the class as well as joining the class to be 182 so that the average remains the same. But it is given that the average of the 40 students leaving the class is 182. ... strength of the class. Hence the average of the present class = 182 - 95/60 = 180.5 cm

The average monthly income of M and N is Rs. 12100. The average monthly income of N and O is Rs. 10500 and the average monthly income of O and M is Rs. 14400. What is the monthly income of N? A) 4200 B) 8200 C) 5600 D) 7600

Description : The average monthly income of M and N is Rs. 12100. The average monthly income of N and O is Rs. 10500 and the average monthly income of O and M is Rs. 14400. What is the monthly income of N? A) 4200 B) 8200 C) 5600 D) 7600

Last Answer : B) The average monthly income of M and N is Rs. 12100. The average monthly income of N and O is Rs. 10500 and the average monthly income of O and M is Rs. 14400. M+ N = 2 12100 = 24200 . (Equation ... +O - (O+M) = 24200+21000-28800 => 2xN = 16400 then N= 8200 N's monthly income = Rs. 8200

The average salary per head of all the employees in a company is Rs. 180. The average salary of 24 employees is Rs. 1040and the average salary per head of the rest is Rs. 160. Find the total number of employees in the workshop. A) 2841 B) 1056 C) 1195 D) 2145

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Last Answer :  B) Average = Sum of observations/Number of observations Let the number of employees be x. Given, the average salary per head of all the employees in a company is Rs. 180 So, the sum of salary of all the employees in ... (x - 24) = 180x ⇒ 24960+ 160x - 3840 = 180x ⇒ 20x = 2112 ⇒ x = 1056

A batch of 50 people has the oldest person with 160 years of age. The average of the batch is reduced by 2, if the oldest person is replaced by someone new, Find the age of the new person. A) 45 B) 30 C) 60 D) 75

Description : A batch of 50 people has the oldest person with 160 years of age. The average of the batch is reduced by 2, if the oldest person is replaced by someone new, Find the age of the new person. A) 45 B) 30 C) 60 D) 75

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Distance between two stations P & Q is 1556km. A passenger train covers the journey from P to Q at 168km per hr and return back to P with a uniform speed of 112km/hr. Find the Average speed of the train during the whole journey? A) 124.4 km/hr B) 130.4km/hr C) 134.4 km/hr D) 130.0 km/hr

Description : Distance between two stations P & Q is 1556km. A passenger train covers the journey from P to Q at 168km per hr and return back to P with a uniform speed of 112km/hr. Find the Average speed of the train during the whole journey? A) 124.4 km/hr B) 130.4km/hr C) 134.4 km/hr D) 130.0 km/hr

Last Answer : C) Given x= 168 , y = 112 Required average speed = (2xy / x + y) km/hr = 2 * 168 *112 / 168 + 112 = 37632 / 280 =134.4 km/hr

In shewak's opinion, his weight is greater than 76 kg but less than 83 kg. His sister doest not agree with shewak and she thinks that shewak’s weight is greater than 71 kg but less than 81 kg. His father's view is that his weight cannot be greater than 79 kg. If all are them are correct in their estimation, what is the average of different probable weights of shewak? A) 67kg B) 68kg C) 72kg D) 78kg

Description : In shewak's opinion, his weight is greater than 76 kg but less than 83 kg. His sister doest not agree with shewak and she thinks that shewak's weight is greater than 71 kg but less than 81 kg. His ... , what is the average of different probable weights of shewak? A) 67kg B) 68kg C) 72kg D) 78kg

Last Answer :  Answer: D) Let shewak's weight be X kg. According to shewak , 76 < X < 83 According to shewak 's sister, 71 < X < 81. According to shewak 's father, X ≤ 79 The values satisfying all the above conditions are 77, 78and 79. Required average=[ (77+78+79)/3] = 201/ 3 = 78kg.

The average weight of 45 passenger on board an aircraft is 50 kg. If the weight of 5 members of the crew is added, the average is reduced by half kilogram . What is the average weight of the crew members?

Description : The average weight of 45 passenger on board an aircraft is 50 kg. If the weight of 5 members of the crew is added, the average is reduced by half kilogram . What is the average weight of the crew members?

Last Answer : Total weight of 45 passenger = 45 x 50 = 2250 kg Total weight of 45 passenger and 5 crews = 50 x 49.5 = 2475 kg Total weight of 5 crews = 2475-2250 = 225kg Average weight of 5 crews = 225/5 = 45kg.

If the mean of P, Q,R is A and PQ + QR + RP =0, then the mean of p^2,Q^2,R^2 is. A) 2A^2 B) 4A^2 C) A^2 D) 3A^2

Description : If the mean of P, Q,R is A and PQ + QR + RP =0, then the mean of p^2,Q^2,R^2 is. A) 2A^2 B) 4A^2 C) A^2 D) 3A^2

Last Answer : D) We have (P + Q + R)/3 = A P+Q+R = 3A (P+Q+R)^2 = 9A^2 P^2+Q^2+R^2 + 2 (PQ + QR + PR) = 9A^2 P^2+Q^2+R^2 = 9A^2 Required mean = (P^2+Q^2+R^2)/3 = 9A^2/3= 3A^2

A man wnt uphill with a speed of 20 km.p.h. and came downhill with a speed of 30 km p.h. The average speed for his journey was (a) 25 km. p.h. (b) 22 1/2 km. p.h. (c) 24 km. p.h. (d) 25 1/2 km. p.h.

Description : A man wnt uphill with a speed of 20 km.p.h. and came downhill with a speed of 30 km p.h. The average speed for his journey was (a) 25 km. p.h. (b) 22 1/2 km. p.h. (c) 24 km. p.h. (d) 25 1/2 km. p.h.

Last Answer : 24 km.p.h.

The average marks scored by two Class A1 and A2 students are 120 and 130 respectively. If 8 students are moved from Class A2 to Class A1 and the average marks of the two Class get interchanged. Find the total number of students in two Class put together, if the average marks scored by the 8 students who moved is 150 A) 25 B) 30 C) 35 D) 40

Description : The average marks scored by two Class A1 and A2 students are 120 and 130 respectively. If 8 students are moved from Class A2 to Class A1 and the average marks of the two Class get interchanged. Find the total number ... average marks scored by the 8 students who moved is 150 A) 25 B) 30 C) 35 D) 40

Last Answer :  D)  let the number of students in Class A1 be x and class A2 be y. Total marks scored by the students will be 120x and 130y, the average gets interchanged after moving student from y Thus we get, 130y- ... (x+8) 120x+1200=130x+1040 10x=160 X=16 Thus the total number of students =24+16=40

4 years ago, the average age of x and y was 22 years. With z joining them, the average becomes 26 years. How ols is z now? A) 62yrs B) 50yrs C) 38 yrs D) 54yrs

Description :  4 years ago, the average age of x and y was 22 years. With z joining them, the average becomes 26 years. How ols is z now? A) 62yrs B) 50yrs C) 38 yrs D) 54yrs

Last Answer : C) age of (x+y) 4 yrs ago= (22 * 2)yrs =44 age of (x+y+z)=(26 *3)yrs =78yrs Therefore z’s age = (78-44)yrs =34 yrs. Current age of z =38 yrs

Normal blood pressure of man is – (1) 80/120 mm Hg (2) 90/140 mm Hg (3) 120/160 mm Hg (4) 85/150 mm Hg

Description : Normal blood pressure of man is – (1) 80/120 mm Hg (2) 90/140 mm Hg (3) 120/160 mm Hg (4) 85/150 mm Hg

Last Answer : (1) 80/120 mm Hg Explanation: Normal blood pressure is considered to be at or below 120 over 80 (120/80).

The average weight of a group of 22students is 34kg. When the weight of the staff is also included, the average weight increases by 2kg. What is the weight of the staff? A. 80 kgs B. 54 kgs C. 47 kgs D. 33kgs

Description : The average weight of a group of 22students is 34kg. When the weight of the staff is also included, the average weight increases by 2kg. What is the weight of the staff? A. 80 kgs B. 54 kgs C. 47 kgs D. 33kgs 

Last Answer : A) The average weight of a group of 22students = 34 kgs. Therefore, the total weight of the group = 22*34 = 748 kg When the weight of the staff is included, there are 23 individuals. The average ... , the total weight of the 22 students plus the staff = 23* 36= 828 828-748=80 kg.

There are two groups of a class consisting of 72 and 88 students respectively. If the average weight of 1st group is 80kg and the weight of 2nd group is 70kg. Find the average weight of whole class? A) 64kg B) 74.5kg C) 84.5kg D) 54kg

Description : There are two groups of a class consisting of 72 and 88 students respectively. If the average weight of 1st group is 80kg and the weight of 2nd group is 70kg. Find the average weight of whole class? A) 64kg B) 74.5kg C) 84.5kg D) 54kg

Last Answer :  B)  Total weight of (72 + 88) = (72*80) + (88 * 70)kg = (5760 + 6160)kg  = 11,920kg  Average weight of the whole class = 11920 / 160  = 74.5 kg

An industry employed 1200 men and 800 women and the average salary was Rs 51 per day. If a woman got Rs 10 less than a man , then what are their daily salary?(mens and women respectively) A) men Rs 25 and women Rs 35 B) men Rs 45 and women Rs 55 C) men Rs 35 and women Rs 25 D) men Rs 55 and women Rs 45

Description : An industry employed 1200 men and 800 women and the average salary was Rs 51 per day. If a woman got Rs 10 less than a man , then what are their daily salary?(mens and women respectively) A) men Rs 25 and women Rs ... Rs 45 and women Rs 55 C) men Rs 35 and women Rs 25 D) men Rs 55 and women Rs 45

Last Answer : D) Let the daily salary of man be Rs’x’ Then the daily salary of a women = Rs (x-100 Now 1200x + 800(x-10) = 51 *(1200+800) 1200x+800x -8000 = 51*2000 2000x = 102000+8000 =110000 X=55 Therefore mens daily salary Rs 55 and womens daily salary Rs 45

13 6 7 9 20 47.5 ? a) 149.5 b) 140.5 c) 150.5 d) 147.5 e) 145.5

Description : 13 6 7 9 20 47.5 ? a) 149.5 b) 140.5 c) 150.5 d) 147.5 e) 145.5

Last Answer : The series is × 0.5 – 0.5, × 1 + 1, ×1.5 – 1.5, ×2 + 2, ... Answer: e)

If the arithmetic mean of 150 numbers is calculated 70. If each number is increased by 10, then mean of new number is. A) 70 B) 80 C) 90 D) 60

Description : If the arithmetic mean of 150 numbers is calculated 70. If each number is increased by 10, then mean of new number is. A) 70 B) 80 C) 90 D) 60

Last Answer : B) Arithmetic mean of numbers = 70 Sum of 150 numbers = (70 * 150) =10500 Total increase = (150 * 10) = 1500 Increased sum = 10500 + 1500 = 12000 Increased average = 12000/150 =80

The cost per unit of a product manufactured in a factory amounts to Rs. 160 (75% variable) when the production is 10,000 units. When production increases by 25%, the cost of production will be Rs. per unit. (a) Rs. 145 (b) Rs. 150

Description : The cost per unit of a product manufactured in a factory amounts to Rs. 160 (75% variable) when the production is 10,000 units. When production increases by 25%, the cost of production will be Rs. per unit. (a) Rs. 145 (b) Rs. 150

Last Answer : (c) Rs. 152

Nithish bought two purses which together cost him Rs.440. He sold one of the purse at a loss of 20% and the other one at a gain of 40%. The selling price of both purse are same. Then find out the cost price of both purse. a) Rs.150 and Rs.290 b) Rs.140 and Rs.300 c) Rs.170 and Rs.270 d) Rs.160 and Rs.280 e) None of the Above

Description : Nithish bought two purses which together cost him Rs.440. He sold one of the purse at a loss of 20% and the other one at a gain of 40%. The selling price of both purse are same. Then find out the cost price of both ... Rs.140 and Rs.300 c) Rs.170 and Rs.270 d) Rs.160 and Rs.280 e) None of the Above

Last Answer : 80/100 * x = 140/100 * y x = 7/4y x + y = 440 7/4 y + y = 440 y = 160 ; x = 280 Answer: d)

A 53-year-old man presented with hypertension of 150/110 mmHg. He is generally asymptomatic and has no previous medical history of note. He is a smoker of 5 cigarettes daily and drinks modest quantities of alcohol. He takes no prescribed medications. Examination reveals a BMI of 33.5 kg/2 but nil else. The following detail his investigations: Serum sodium 146 mmol/l (NR 133-145) Serum potassium 3.2 mmol/l (NR 3.5 - 5) Urinary potassium excretion 42 mmol/l (NR less than 30) What is the likely diagnosis? 1) Adrenocortical adenoma 2) Bartter's syndrome 3) Liddle's syndrome 4) Liquorice ingestion 5) Pheochromocytoma

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Last Answer : Answers-1 This patient is most likely to have Conn's syndrome as reflected by the hypokalaemic hypertension. Liquorice ingestion or Liddle's syndrome are again possible causes of ... hypertension (often diastolic hypertension), muscular weakness, paresthesias, headache, polyuria, and polydipsia."

Two train travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 8 seconds. Then length of the faster train is: A.120 m B.140 m C.160 m D.180 m E.None of these

Description : Two train travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 8 seconds. Then length of the faster train is: A.120 m B.140 m C.160 m D.180 m E.None of these

Last Answer : Answer – D (180 m) Explanation – When OPP. direction-PLUS Relative speed = (36 + 45) km/hr = [81 x 5/18] m/sec = [45/2] m/sec. Length of train = [45/2 x 8] m = 180 m.

Most bacteria are killed at ____º to ____ºF, but spores are not. a. 150, 175 c. 160, 200 b. 180, 200 d. 175, 200

Description : Most bacteria are killed at ____º to ____ºF, but spores are not. a. 150, 175 c. 160, 200 b. 180, 200 d. 175, 200

Last Answer : b. 180, 200

A certain company employed 600 men and 400 women and the average wage was 2.55 per hour.If a women got 50 paise less than a man, what were their wages per hour ? (a) Man rs 3.00,Woman Rs 2.50 (b) Man Rs 3.50, Woman Rs 3.00 (c) Man Rs 2.75, Woman Rs 2.25 (d) Man Rs 3.25, Woman Rs 2.75

Description : A certain company employed 600 men and 400 women and the average wage was 2.55 per hour.If a women got 50 paise less than a man, what were their wages per hour ? (a) Man rs 3.00,Woman Rs 2.50 (b) Man Rs 3.50, Woman Rs 3.00 (c) Man Rs 2.75, Woman Rs 2.25 (d) Man Rs 3.25, Woman Rs 2.75

Last Answer : Man = Rs 2.75, woman = Rs 2.25

A ship sails out to a mark at the rate of 10 km per hour and sails back at th rate of 15 km per hour. What is its average rate of sailing? (a) 10 km. p.h. (b) 12 km. p.h. (c) 15 km. p.h. (d) 11 km. p.h.

Description : A ship sails out to a mark at the rate of 10 km per hour and sails back at th rate of 15 km per hour. What is its average rate of sailing? (a) 10 km. p.h. (b) 12 km. p.h. (c) 15 km. p.h. (d) 11 km. p.h.

Last Answer : 12 km. p.h.

The average monthly income of certain fashion designers is F and that other workers is N. The number of fashion designer workers is 33 times that of other workers. The average monthly income (in rs) of all the worker is. A) F+N/2 B) F+33N/12 C) 33F+N/22 D) (33F+N)/34

Description : The average monthly income of certain fashion designers is F and that other workers is N. The number of fashion designer workers is 33 times that of other workers. The average monthly income (in rs) of all the worker is. A) F+N/2 B) F+33N/12 C) 33F+N/22 D) (33F+N)/34

Last Answer : D) Let the number of other workers be ‘x’. The number of fashion design workers = 33x Total number of workers = 34x Average monthly income = (F * 33x)+(N*x)/34x =x(33F + N)/34x =(33F + N)/34.

A man spends Rs 1,800 per month on an average for the first four mouths and Rs 2,000 per month for the nest 8 months and saves Rs 5,600 a year. What is his average monthly income ?

Description : A man spends Rs 1,800 per month on an average for the first four mouths and Rs 2,000 per month for the nest 8 months and saves Rs 5,600 a year. What is his average monthly income ?

Last Answer : Total expenditure during first four months = 1,800 x 4 = Rs 7,200 Total expenditure during the next 8 months = 2,000 x 8 = Rs 16,000 Saving = Rs 5,600 Total of expenditure and saving (equal to income ... ,200+ 16,000 + 5,600=Rs 28,800 Average monthly income = 28,800 /12 = Rs 2,400

The Cricketer average score in 40 over is 21, if the man scores 23runs in 8over, 26 runs in 10 over and 18runs in 14 over. What is the average score in remaining over? A) 18 B) 19 C) 16 D) 20

Description : The Cricketer average score in 40 over is 21, if the man scores 23runs in 8over, 26 runs in 10 over and 18runs in 14 over. What is the average score in remaining over? A) 18 B) 19 C) 16 D) 20 

Last Answer : A) According to the question 40*21=23*8+26*10+18*14+8×X 840=184+260+252+8x 8x=144  X=144/8=18 runs

The average height of the students in a group was 360cm. When 10 students whose height is 292.8cm are newly admitted. The average height of the group was reduced by 24cm.How many students are present in the group? A) 29 B) 25 C) 28 D) 14

Description : The average height of the students in a group was 360cm. When 10 students whose height is 292.8cm are newly admitted. The average height of the group was reduced by 24cm.How many students are present in the group? A) 29 B) 25 C) 28 D) 14

Last Answer : Answer: C) let the number of students initially in the class be A, then, total height = A * 360------ 1 again the no of students increased = A + 10 then, total height A + 10 student = (A +10) * 336 ... 3 (A+10) *336-2928 =A*360 336A+3360-2928=360A A=18 Number of students in class = 18+10=28

The average age of K and L is 48 years. If M replaced K, the average age would be 40 and if M replaced L, the average would be 44. What are the ages of K,L,M repectively? A) 58, 46, 22 B) 32, 44, 36 C) 52,44,36 D) 56, 22,38

Description :  The average age of K and L is 48 years. If M replaced K, the average age would be 40 and if M replaced L, the average would be 44. What are the ages of K,L,M repectively? A) 58, 46, 22 B) 32, 44, 36 C) 52,44,36 D) 56, 22,38

Last Answer : Answer: C)  Total age of K& L = 48*2 = 96 yrs----->1 Total age of L& M = 40*2 = 80yrs----->2 Total age of K& M = 44*2 = 88 yrs----->3 from 1, 2, 3 K+L+M =132---->4 from 1 & 4, M= 36 from 2 & 4, K=52 from 3 & 4, L=44 Hence the required answer is 52,44,36 

The average weight of x,y,z is 90kg. If the average weight of x and y be 80kg and that of y and z be 86kg. Find the weight of y A) 66kg B) 63kg C) 62kg D) 70kg

Description : The average weight of x,y,z is 90kg. If the average weight of x and y be 80kg and that of y and z be 86kg. Find the weight of y A) 66kg B) 63kg C) 62kg D) 70kg 

Last Answer : C)  Let x ,y ams z represent their individual weights. Then,  X + y + z = ( 90 * 3) = 270kg  X+ y = 80 *2 = 160kg  Y + z = 86 * 2 = 172kg  Therefore y = (x + y) + ( y+z) – (x+y+z) = 160 + 172 – 270  Y= 62kg.

One Astronomical unit is equal to how much Km in whole numbers? A. 160 million km B. 140 million km C. 150 million km (Answer) D. 130 million km

Description : One Astronomical unit is equal to how much Km in whole numbers? A. 160 million km B. 140 million km C. 150 million km (Answer) D. 130 million km

Last Answer : C. 150 million km (Answer)

The desirable camber for straight roads with water bound macadam or gravel surface, is (A) 1 in 33 to 1 in 25 (B) 1 in 40 to 1 in 33 (C) 1 in 150 to 1 in 140 (D) 1 in 160 to 1 in 140

Description : The desirable camber for straight roads with water bound macadam or gravel surface, is (A) 1 in 33 to 1 in 25 (B) 1 in 40 to 1 in 33 (C) 1 in 150 to 1 in 140 (D) 1 in 160 to 1 in 140

Last Answer : Answer: Option B

The desirable camber for straight cement concrete roads, is (A) 1 in 33 to 1 in 25 (B) 1 in 40 to 1 in 33 (C) 1 in 150 to 1 in 140 (D) 1 in 160 to 1 in 140

Description : The desirable camber for straight cement concrete roads, is (A) 1 in 33 to 1 in 25 (B) 1 in 40 to 1 in 33 (C) 1 in 150 to 1 in 140 (D) 1 in 160 to 1 in 140

Last Answer : Answer: Option D

The desirable camber for straight roads with thin bituminous surfacing, is (A) 1 in 33 to 1 in 25 (B) 1 in 40 to 1 in 33 (C) 1 in 150 to 1 in 140 (D) 1 in 160 to 1 in 140

Description : The desirable camber for straight roads with thin bituminous surfacing, is (A) 1 in 33 to 1 in 25 (B) 1 in 40 to 1 in 33 (C) 1 in 150 to 1 in 140 (D) 1 in 160 to 1 in 140

Last Answer : Answer: Option C

What is the total number of students enrolled in all the three classes together ? (1) 150 (2) 125 (3) 140 (4) 160 (5) None of these

Description : What is the total number of students enrolled in all the three classes together ? (1) 150 (2) 125 (3) 140 (4) 160 (5) None of these

Last Answer : (5) None of these

The average age of 11 daughters of a family is 12yrs. Average age of the daughters together with their parents is 27yrs. If mother is 14yrs younger than father. Then find the father's age A) 127 yrs B) 116.5 yrs C) 168yrs D) 170yrs

Description : The average age of 11 daughters of a family is 12yrs. Average age of the daughters together with their parents is 27yrs. If mother is 14yrs younger than father. Then find the father's age A) 127 yrs B) 116.5 yrs C) 168yrs D) 170yrs

Last Answer : Answer: B) Total age of 11 daughters of a family = 11*12 = 132 father age = 14 +mother age total age of the family (11 daughters + father + mother) is, 132+mother +14+ mother = 27 * 13 mother = 102.5 father age = 14+102.5 =116.5years

18 friends went to a restaurant for taking their breakfast. 17 of them spent RS.24 each on their breakfast and the last one spent RS.16 more then the average expenditure of all the 18. What was the total money spent by them? A) 228 B) 448.9 C) 458.6 D) 428.0

Description : 18 friends went to a restaurant for taking their breakfast. 17 of them spent RS.24 each on their breakfast and the last one spent RS.16 more then the average expenditure of all the 18. What was the total money spent by them? A) 228 B) 448.9 C) 458.6 D) 428.0 

Last Answer : B)  Let the average expenditure of all the 18 be Rs ‘x’.  Then (24 * 17) + (x + 16) = 18x 424 + x = 18x x = 24.9 therefore total money spent 18x  = 18 * 24.9  = Rs.448.9

In an exam the average marks obtained by a candidate is 82 per paper. If he had obtained 32 marks more in science paper & 28more marks in social paper, then his average per paper is increased by 15 marks. Then how many papers when there in examination? A) 10 B) 6 C) 4 D) 8

Description : In an exam the average marks obtained by a candidate is 82 per paper. If he had obtained 32 marks more in science paper & 28more marks in social paper, then his average per paper is increased by 15 marks. Then how many papers when there in examination? A) 10 B) 6 C) 4 D) 8 

Last Answer : C)  let the number of paper be x total mark earned him = 82x then,, 82x+32+28= 97x 15x=60 x= 4 =number of subjects

In a post graduate examination the marks obtained by a student is 75 per paper. If he had obtained 33 marks more in Evs paper & 27 more marks in science paper, then his average per paper is increased by 3 marks. Then how many papers were there in exam? A) 10 B) 12 C) 14 D) 20

Description : In a post graduate examination the marks obtained by a student is 75 per paper. If he had obtained 33 marks more in Evs paper & 27 more marks in science paper, then his average per paper is increased by 3 marks. Then how many papers were there in exam? A) 10 B) 12 C) 14 D) 20

Last Answer : Answer: D)  Let the number of paper be A. Then total marks earned him = 75A from questions, 75A + 33+ 27= 78A 3A = 60=> A=20 = number of subjects

on analyzing the result of an competitive exam the teacher found that the average for the entire the class was 69 marks. If we say that average of 10 % of the students scored 77 marks and average of 28 % of the students scored 66 marks, then calculate average marks of the remaining students of the class A) 67.54 B) 68.26 C) 66.91 D) 69.06

Description :  on analyzing the result of an competitive exam the teacher found that the average for the entire the class was 69 marks. If we say that average of 10 % of the students scored 77 marks and average of 28 % of the ... marks of the remaining students of the class A) 67.54 B) 68.26 C) 66.91 D) 69.06 

Last Answer : D) average of entire class = 69marks average of 28 % of the students = 66 marks average of 10% of the students = 77 marks then % of remaining students = (100- 10 - 28) = 62% let the average of 62% of the ... (62*x)+770+1848= 6900 62 * x = 6900-770-1848 62*x = 4282 x = 69.06

The average expenditure of A, Band C is Rs 10000 per month. Also, the average expenditure of B, C and D is Rs 14000 per month. If the average expenditure of D is thrice of that of A then the average expenditure of B and C is: A) 12000 B) 15000 C) 18000 D) 21000

Description : The average expenditure of A, Band C is Rs 10000 per month. Also, the average expenditure of B, C and D is Rs 14000 per month. If the average expenditure of D is thrice of that of A then the average expenditure of B and C is: A) 12000 B) 15000 C) 18000 D) 21000

Last Answer : A) Total expenditure of A, B & C=3×10000=30000 Total expenditure of B, C & D =3×14000=42000 D-A=42000-30000=12000 Also, we are given D=3A. so 3A-A =12000 & A=6000 Total expenditure of B & C=30000-6000=24000 Average expenditure of B& C=24000/2 =12000

If the average of two numbers are 138& product is 2241. Then find the difference of both numbers? A) 225.40 B) 259.25 C) 267.81 D) 294.57

Description : If the average of two numbers are 138& product is 2241. Then find the difference of both numbers? A) 225.40 B) 259.25 C) 267.81 D) 294.57

Last Answer : B) let the two number be a & b sum of two numbers, a+b = 138*2 =276---1 product of two numbers, a*b=2241 (a+b)2 = a2 + 2ab + b2 ------2 (a-b)2 = a2 -2ab +b2 ------3 solving 2 & 3, 76176 - (a-b)2 = 4*2241 a-b = 259.25