Siva leaves chennai at 3 am and reaches Hyderabad at 11 am . Anirudh leaves Hyderabad at 5 am and reaches chennai at 12:00 noon. At what time do they cross each other? a) 7 : 52am b) 8 : 25am c) 6 : 52am d) 9 : 25am

Siva leaves chennai at 3 am and reaches Hyderabad at 11 am . Anirudh leaves Hyderabad at 5 am and reaches chennai at 12:00 noon. At what time do they cross each other? a) 7 : 52am b) 8 : 25am c) 6 : 52am d) 9 : 25am
by

1 Answer

Answer :

C

Time taken by Siva = 8 h

Time taken by Anirudh = 7 h

For your convenience take the product of times taken by both as a distance.

Then the distance = 56km

Since, Siva covers half of the distance in 2 hours(i.e at 5 am)

Now, the rest half (i.e 28 km) will be coverd by both Anirudh and Siva

Time taken by them = 28/15 = 1 hr 52 min

Thus , they will cross each other at 6 : 52am.


by

Related questions

Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds? A.9 : 28 B.11 : 9 C.11 : 8 D.9 : 22 E.None of these

Description : Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds? A.9 : 28 B.11 : 9 C.11 : 8 D.9 : 22 E.None of these

Last Answer : Answer – B (11 : 9) Explanation – In the same time, they cover 110 km and 90 km respectively.Ratio of their speeds = 110 : 90 = 11 : 9 

A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.? A.15 B.8 C.7 D.10 E.None of these

Description : A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.? A.15 B.8 C.7 D.10 E.None of these

Last Answer : Answer – C (7) Explanation – Relative speed = (2 + 3) = 5 rounds per hourSo, they cross each other 5 times in an hour and 2 times in half an hourHence, they cross each other 7 times before 9.30 a.m.

Arun steals a van at 8.30 am and drives it at 40km/hr. The theft is discovered at 9 a.m and the owner sets off in another van at 55km/hr. when will he overtake arun? a) 10.20 am b) 12.20am c) 11.20am d) 10.15am

Description : Arun steals a van at 8.30 am and drives it at 40km/hr. The theft is discovered at 9 a.m and the owner sets off in another van at 55km/hr. when will he overtake arun? a) 10.20 am b) 12.20am c) 11.20am d) 10.15am

Last Answer : A Suppose the arin is overtaken x hrs after 8.30 a.m Then distance covered by arun in x hrs = distance covered by the owner in(x-1/2) hrs 40x =55(x-1/2) 40x = 55x -55/2 55x – 40x =55/2 15x=55/2 X = 55/2*1/15 x=55/30 x= 1hr 50mins so the thief is overtaken at 10.20 a.m

Kishore is travelling on his bike and has calculated to reach point P at 4 pm if he travels at 20 kmph. He will reach there at 12 noon if he travels at 30 kmph. At what speed must he travel to reach P at 2 pm? a) 18 kmph b) 12 kmph c) 24 kmph d) 16 kmph

Description : Kishore is travelling on his bike and has calculated to reach point P at 4 pm if he travels at 20 kmph. He will reach there at 12 noon if he travels at 30 kmph. At what speed must he travel to reach P at 2 pm? a) 18 kmph b) 12 kmph c) 24 kmph d) 16 kmph

Last Answer : C Let the distance be x km Travelling at 20 kmph, Kishore will reach point P at 4pm. Travelling at 30 kmph, Kishore will reach point P at 12noon. Therefore, time taken when travelling at 20km - ... his travelling time must be (12-2)=10 hours Hence, required speed =240/10=24 kmph

Mr.Aneesh left for city 1 from city 2 at 3.00 pm. He travelled at the speed of 60km/hr for 1 and half hours. After that the speed was reduced to 15 km/hr. If the distance between two cities is 120 kms, at what time did Mr.Aneesh reach city 1 ? a) 6.30 pm. b) 5.30 pm. c) 7.30 pm. d) 8.30 pm.

Description : Mr.Aneesh left for city 1 from city 2 at 3.00 pm. He travelled at the speed of 60km/hr for 1 and half hours. After that the speed was reduced to 15 km/hr. If the distance between two cities is 120 kms, at what time did Mr.Aneesh reach city 1 ? a) 6.30 pm. b) 5.30 pm. c) 7.30 pm. d) 8.30 pm.

Last Answer : A Mr.Aneesh travelled 60 km/hr for 1 1/2 hours (3/2 hours). Distance covered in 3/2 hours = 60 x 3/2 = 90 km. Therefore, remaining distance = 120 -90 = 30 km After 3/2 hours, the speed was ... village 2 at 3.00 pm + 3 hours 30 minutes = 6.30pm Hence the required answer is 6.30 pm.

Find the speed and average speed of a bus which leaves salem at 4 p.m. and reaches madurai in the same day at 8 p.m. The distance between the two stations is 216 km and the total time for stoppage is 1 hour between these stations. a) 54,72 b) 62,84 c) 72,54 d) 82,64

Description :  Find the speed and average speed of a bus which leaves salem at 4 p.m. and reaches madurai in the same day at 8 p.m. The distance between the two stations is 216 km and the total time for stoppage is 1 hour between these stations. a) 54,72 b) 62,84 c) 72,54 d) 82,64

Last Answer : C Total time taken = 4 hours; Time of stoppage = 1 hour, that is, actual time taken = 4 hours - 1 hours = 3 hours Speed = Distance/Time = 216/3 = 72 km/hr Average speed = Total Distance/ Total Time = 216/4 = 54 km/hr

The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Description : The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Last Answer : Answer – C (11 am) Explanation – Suppose they meet x hrs after 8 a.m. Then, (Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs] = 330 60x + 75(x – 1) = 330 x = 3 So, they meet at (8 + 3), i.e. 11 a.m

Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? A.12 sec B.18 sec C.14 sec D.25 sec E.None of these

Description : Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? A.12 sec B.18 sec C.14 sec D.25 sec E.None of these

Last Answer : Answer – A (12 sec) Explanation – Speed of the first train = [120 / 10] m/sec = 12 m/sec. Speed of the second train = [120 / 15] m/sec = 8 m/sec. Relative speed = (12 + 8) = m/sec = 20 m/sec. ∴ Required time = (120 + 120) / 20 secc = 12 sec

Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr

Description : Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr

Last Answer :  A As per the question, let D be the total distance and ‘t’ is the time taken. So we have: D=20t 20t =30(t-0.5) 20t=30t-15 10t=15 t=3/2 D= 30 km Now, for the condition given we have: 30=S(t-3/4) 30=S(3/2-3/4) 30=S((6-3)/4) 30=S(3/4) S=40 km/hr

Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is: A.12 kmph B.24 kmph C.36 kmph D.48 kmph E.None of these

Description : Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is: A.12 kmph B.24 kmph C.36 kmph D.48 kmph E.None of these

Last Answer : Answer – C (36 kmph) Explanation – Let the speed of each train be x m/sec. Then, relative speed of the two trains = 2x m/sec. So, 2x = (120 + 120)/12 ⇔ 2x = 20 ⇔ x = 10. ∴ Speed of each train = 10 m/sec = [10 x 18/5] km/hr = 36 km/hr

A bus starts at bus stop and reaches a destination in 4 hours. If it travels first and second half at the speed of 40 km/hr and 50 km/hr respectively then the distance between bus stop and destination is a) 177.7 km b) 154.2 km c) 163.5 km d) 147.3 km

Description : A bus starts at bus stop and reaches a destination in 4 hours. If it travels first and second half at the speed of 40 km/hr and 50 km/hr respectively then the distance between bus stop and destination is a) 177.7 km b) 154.2 km c) 163.5 km d) 147.3 km

Last Answer : A Let the distance between bus stop and destination be X. The total time taken by the bus to cover X = 4 hours Since X/2 by 40km/hr and remaining X/2 by 50km/hr Then by Time = distance/speed, we have ... = 1600 9X = 1600 X = 1600/9 = 177.7 Hence 177.7 km is the required answer.

If Gowtham ride a bike at 30 km/hr, then he arrives at a certain place at 3 p.m. If he ride at 45 km/hr, he will arrive at the same place at 1 P.m. At what speed must he ride to get there at noon? a) 18 km/hr b) 24 km/hr c) 36 km/hr d) 28 km/hr

Description : If Gowtham ride a bike at 30 km/hr, then he arrives at a certain place at 3 p.m. If he ride at 45 km/hr, he will arrive at the same place at 1 P.m. At what speed must he ride to get there at noon? a) 18 km/hr b) 24 km/hr c) 36 km/hr d) 28 km/hr

Last Answer : C When speed of gowtham = 30 km/hr =d/t and, When speed of the gowtham = 45 km/hr =d/(t−2) Equating the value of d: 30t =45(t-2) 30t=45t-90 15t=90 t=6 hours Finally desired speed =d/(t-1) =30t/(t-1) =30*6/(6-1) =180/5 =36 km/hr

The distance between two stations ooty and chennai is 615km. A train with speed of 75 km/h leaves ooty at 8:00 am towards chennai. Another train with speed of 105 km/h leaves Chennai at 9 : 00 am towards ooty . Then, at what time both trains meet? A) 6 B) 12 C) 18 D) 24

Description : The distance between two stations ooty and chennai is 615km. A train with speed of 75 km/h leaves ooty at 8:00 am towards chennai. Another train with speed of 105 km/h leaves Chennai at 9 : 00 am towards ooty . Then, at what time both trains meet? A) 6 B) 12 C) 18 D) 24

Last Answer : ANSWER:B  Explanation:  First train leaves at 8.00am and second leaves at 9.00am  So,first train that is , from ooty to Chennai has covered  75 km distance in 1 hr.  So , distance left by between the station = ... the trains will meet , 3 hr after second train left  i.e., 9.00 am +3 = 12.00 pm

Four pipes can fill a reservoir in 15, 20, 30 and 60 hours respectively. The first one was opened at 6 AM, second at 7 AM, thir da t 8 AM and the fourth at 9 AM. When will the reservoir be filled ? (A) 11 AM (B) 12 Noon (C) 1 PM (D) 1:30 PM

Description : Four pipes can fill a reservoir in 15, 20, 30 and 60 hours respectively. The first one was opened at 6 AM, second at 7 AM, thir da t 8 AM and the fourth at 9 AM. When will the reservoir be filled ? (A) 11 AM (B) 12 Noon (C) 1 PM (D) 1:30 PM

Last Answer : Answer: C

Three trains are running from a place A to another place B. Their speeds are in the ratio of 4 : 3 : 5. The time ratio to reach B by trains will be A. 4 : 3 : 5 B. 5 : 3 : 4 C. 15 : 9 : 20 D. 15 : 20 : 12

Description : Three trains are running from a place A to another place B. Their speeds are in the ratio of 4 : 3 : 5. The time ratio to reach B by trains will be A. 4 : 3 : 5 B. 5 : 3 : 4 C. 15 : 9 : 20 D. 15 : 20 : 12

Last Answer : Answer: D(15 : 20 : 12) Explanation: Ratio of speeds = 4 : 3 : 5 Therefore Ratio of times taken [t=d/s or t indirectly proportional to s when distance is same]= (1/4) : (1/3) : (1/5) = 15 : 20 : 12

A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes? A.100 m B.150 m C.190 m D.200 m E.None of these

Description : A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes? A.100 m B.150 m C.190 m D.200 m E.None of these

Last Answer : Answer- A(100m) Explanation: Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr Distance covered in 6 minutes =[(1/60)*6] km = (1/10)km = 100 m. Distance between the thief and policeman = (200 – 100) m = 100 m.

P,Q & R are on a journey by scorpio. P drives during the 1st 2 hrs at an average speed of 60 km/hr. Q drives during the next 3 hrs at an average speed of 58 km/hr R drives for the next 4 hrs at an average speed of 62 km/hr. They reached their destination after exactly 5 hrs. Their main speed is. a) 60 2/9 b) 62 2/9 c) 60 4/8 d) 62 4 /8

Description : P,Q & R are on a journey by scorpio. P drives during the 1st 2 hrs at an average speed of 60 km/hr. Q drives during the next 3 hrs at an average speed of 58 km/hr R drives for the next 4 hrs at an average speed of 62 ... exactly 5 hrs. Their main speed is. a) 60 2/9 b) 62 2/9 c) 60 4/8 d) 62 4 /8 

Last Answer : A Distance covered by P = 2*60 = 120 km Distance covered by Q = 3* 58 = 174 km Distance covered by R = 4*62 = 248 km Total distance = (120+174+248)km =542 km Total time taken = 2+3+4 = 9 hrs Mean speed = diatance/ time =(542 / 9)km/hr =60 2/9 km/hr

Ganesh is travelling on his motorbike and has calculated to reach golden temple at 8 p.m if he travels at 30 km/hr; he will reach there at 6 p.m if he travels at 45 km/hr. At what speed must he travel to reach the golden temple at 7 p.m? a) 36 b) 46 c) 32 d) 30

Description : Ganesh is travelling on his motorbike and has calculated to reach golden temple at 8 p.m if he travels at 30 km/hr; he will reach there at 6 p.m if he travels at 45 km/hr. At what speed must he travel to reach the golden temple at 7 p.m? a) 36 b) 46 c) 32 d) 30

Last Answer : A Let the distance travelled be x km x/30 – x/45 = 2 (3x – 2x) / 90 = 2 x/90 = 2 x = 180km Time taken to travel 180 km at 30 km/hr = 180 / 30 = 6 hrs So ganesh started 6 hrs before 8 pm That is 2 pm Required speed = distance / time =(180/5) =36 km/hr

Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these

Description : Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these 

Last Answer : Answer – A (27 7/9 m) Explanation – When SAME direction- MINUS Relative speed = (40-20) km/hr = [20 x 5/18] m/sec = [50/9] m/sec. Length of faster train = sxt=[50/9 x 5] m = 250/9 m = 27 7/9 m.

Anand takes 9 hours more than Babu to cover 150 km. Suppose the time taken by Anand is 30 minutes less than Babu he must double his speed. Then the speed of Anand will be: a) 7.64 km/hr. b) 7.43km/hr. c) 7.89 km/hr. d) 7.25 km/hr.

Description : Anand takes 9 hours more than Babu to cover 150 km. Suppose the time taken by Anand is 30 minutes less than Babu he must double his speed. Then the speed of Anand will be: a) 7.64 km/hr. b) 7.43km/hr. c) 7.89 km/hr. d) 7.25 km/hr.

Last Answer : C Let Anand 's speed be X km/hr. And let the time taken by Babu be Y. Since Anand takes 9+Y hours to cross 150km at X km/hr. i.e., 150 / X = 9+Y ---eqn1 And he takes Y - 1/2 hours to cross 150km at 2X km ... )/ 2x = 19/2 150/2X =19/2 150/X = 19 X = 7.89 Hence Anand 's speed is 7.89 km/hr.

A bike starts with a speed of 60 km/hr at 8a.m. Due to the problem in engine it reduces its speed as 20 km/hr for every 1 hour. After 9 am, the time taken to covers 15 km is: a) 13 minutes and 20 seconds b) 15 minutes and 09 seconds c) 18 minutes and 15 seconds d) 22 minutes and 30 seconds

Description : A bike starts with a speed of 60 km/hr at 8a.m. Due to the problem in engine it reduces its speed as 20 km/hr for every 1 hour. After 9 am, the time taken to covers 15 km is: a) 13 minutes and 20 seconds b) 15 minutes and 09 seconds c) 18 minutes and 15 seconds d) 22 minutes and 30 seconds

Last Answer : 15 min

Senthil started bike at 5 a.m to reach a temple. After going temple, his bike went out of order. Consequently he rested for 45 mins and came back to his house walking all the way. Senthil reached home at 8 a.m. if bike speed is 20 km/hr and his walking speed is 1 km/hr, then on bike he covered a distance of. a) 3.12 b) 2.76 c) 4.13 d) 2.14

Description : Senthil started bike at 5 a.m to reach a temple. After going temple, his bike went out of order. Consequently he rested for 45 mins and came back to his house walking all the way. Senthil reached home at 8 a.m. if bike ... /hr, then on bike he covered a distance of. a) 3.12 b) 2.76 c) 4.13 d) 2.14

Last Answer : D Time taken = 2 hr 15 mins = 2 ¼ hrs Time = 9/4 hrs Let the required distance be x km Then x/20 + x/1 = 9/4 (X+20x) / 20 = 9/4 21x / 20 = 9/4 84x = 180 X= 2.14 km Therefore the required diatance is 2.14 km

Three friends X, Y and Z run a running race, Y finished 12 meters ahead of Z and 18 m ahead of X, while Z finished 8m ahead of X. If each friends runs the entire distance at their respective constant speeds, what is the length of the race? a) 16m b) 48m c) 24m d) 12m

Description : Three friends X, Y and Z run a running race, Y finished 12 meters ahead of Z and 18 m ahead of X, while Z finished 8m ahead of X. If each friends runs the entire distance at their respective constant speeds, what is the length of the race? a) 16m b) 48m c) 24m d) 12m 

Last Answer : B Let the length of the race track be 'd'. When Y finished the race, X and Z would have run (d−18) and (d−12) meters respectively. When Z finishes the race, X would have run (d-8) meters. The ratio of ... d2 -20d+96= d2 -18d 20d-18d=96 d=96/2=48m hence the length of the race track is 48m

Shreya travel the first part of her journey at 160 kmph and the second part at 240 kmph and cover the total distance of 3840 km to her destination in 20 hours. How long did the first part of her journey last? a) 8 hrs b) 12 hrs c) 16 hrs d) 10 hrs

Description : Shreya travel the first part of her journey at 160 kmph and the second part at 240 kmph and cover the total distance of 3840 km to her destination in 20 hours. How long did the first part of her journey last? a) 8 hrs b) 12 hrs c) 16 hrs d) 10 hrs

Last Answer : B The total time of journey = 20 hours. Let 'x' hours be the time that shreya travelled at 160 kmph Therefore, 20-x hours would be time that she travelled at 240 kmph. Hence, she would have covered x*160+( ... 20-x)*240 =3840 160x +4800-240x =3840 240x-160x=4800-3840 80x= 960 X=960/80=12 hrs

P is thrice as fast as Q and Q is 4 times as fast as R. If the journey covered by R is 48 mins, then the time to be covered by Q. a) 12 b) 14 c) 10 d) 6

Description : P is thrice as fast as Q and Q is 4 times as fast as R. If the journey covered by R is 48 mins, then the time to be covered by Q. a) 12 b) 14 c) 10 d) 6 

Last Answer : A Let R's speed = x km/hr Then Q's speed = 4x km/hr P's speed = 12x km/hr Ratio of speeds of P<Q<R = 12x :4x:x =12:4:1 Ratio of time taken = 1/12: ¼:1 =1:3:12 If R ... mins, then Q takes 3 mins If R takes 48 mins, then Q takes =(3/12 *48)mins =(144/120mins =12mins

The distance between salem and trichy is 170 km. A bus starts from salem at 6 a.m. and travels towards trichy at 20 km/hr. Another bus starts from trichy at 7 a.m. and travels towards salem at 30 km/hr. At what time will they meet? a) 7a.m b) 8a.m c) 9a.m d) 10a.m

Description : The distance between salem and trichy is 170 km. A bus starts from salem at 6 a.m. and travels towards trichy at 20 km/hr. Another bus starts from trichy at 7 a.m. and travels towards salem at 30 km/hr. At what time will they meet? a) 7a.m b) 8a.m c) 9a.m d) 10a.m

Last Answer : D Assume that they meet x hours after 6 a.m. Then, Bus 1, starting from salem, travels x hours till the bus meet. Distance travelled by bus 1 in x hours =20x km bus 2, starting from trichy , travels (x−1) hours ... +30=50x 200=50x X=4 Hence, the bus meet 4 hours after 6 a.m., i.e. at 10a.m

Robert travels from his home to anna park at a distance of 125 miles in 11/4 hrs. He returns to home in 2 hrs 15 mints. His average speed is. a) 50 b) 40 c) 30 d) 20

Description : Robert travels from his home to anna park at a distance of 125 miles in 11/4 hrs. He returns to home in 2 hrs 15 mints. His average speed is. a) 50 b) 40 c) 30 d) 20 

Last Answer : A Speed from home to annapark: (125*4/11)mph = (500/11)mph Speed from annapark to home: (125*4/9)mph = (500/9) mph Average speed = 2xy / (x+y) mph =[(2*500/11 *500/9) / (500/11+500/9)]mph =(500000/99) / ((4500+5500)/99) =(500000/99) / 10000 /99 =50mph

A car covers a distance of 1120 metres in 1 minute whereas a bus covers a distance of 56 kms in 44 minutes. What is the ratio of their speed? a) 22:25 b) 25:22 c) 11:15 d) 15:11

Description : A car covers a distance of 1120 metres in 1 minute whereas a bus covers a distance of 56 kms in 44 minutes. What is the ratio of their speed? a) 22:25 b) 25:22 c) 11:15 d) 15:11

Last Answer : A Speed of the Car = 1120 m/minute Speed of the bus=56 kms in 44 minutes =56/44 km/m =56000/44 m/mints Speed of the car : Speed of the bus, =1120:56000/44 =280:14000/44 =20:1000/44 =880:1000 =88:100 Required ratio =22:25

A race course is 250 m long. P and Q run a race and P wins by 4m. Q and R run over the same course and Q win by 3m. R and S run over it and S wins by 12m. If P and S run over it, then who would win and by how much? a) P by 4.82m b) S by 5.30m c) P by 7.25m d) Q by 6.54m

Description : A race course is 250 m long. P and Q run a race and P wins by 4m. Q and R run over the same course and Q win by 3m. R and S run over it and S wins by 12m. If P and S run over it, then who would win and by how much? a) P by 4.82m b) S by 5.30m c) P by 7.25m d) Q by 6.54m

Last Answer : B If P covers 250m, Q covers 246 m If Q covers 250m, R covers 247 m If S covers 250m, R covers 238m Now if Q covers 246 m, then R will cover =247/250*246=243.048 If R covers 243.048 m, then S will cover= ... 048=255.30 If P and S run over 250 m, then S win by =(255.30-250) S win by = 5.30 m

Jackson travels a distance of 100km in 5 hrs. How much faster in kilometer per hr, on an average, must he travel to make a journey in 5/3 hr less time? a) 5 km/hr b) 10km/hr c) 6 km/hr d) 8 km/hr

Description : Jackson travels a distance of 100km in 5 hrs. How much faster in kilometer per hr, on an average, must he travel to make a journey in 5/3 hr less time? a) 5 km/hr b) 10km/hr c) 6 km/hr d) 8 km/hr

Last Answer : B Time required = (5 hrs – 5/3 hrs) =(5 hrs – 100 mints) = (5 hrs – 1hr 40 mints) = 3 hrs 20 mints = 3 1/3 hrs Required speed = (100*3/10) km/hr =30 km/hr Original speed = (100/5)km/hr = 20 km/hr Difference speed = required speed – original speed =(30-20) =10km/hr

2 bus start from A & B respectively and travel towards each other at a speed of 150 km/hr and 120 km/hr respectively. By the time they meet, the first bus has travelled by 300km more than the second. The distance between A & B is a) 2700 b) 2800 c) 2750 d) 2457

Description : 2 bus start from A & B respectively and travel towards each other at a speed of 150 km/hr and 120 km/hr respectively. By the time they meet, the first bus has travelled by 300km more than the second. The distance between A & B is a) 2700 b) 2800 c) 2750 d) 2457

Last Answer : A At the time of meeting, Let the distance travelled by the second bus be xkm Then distance covered by the 1st bus is (x+300)km x/120= (x+300) /150 150x = 120(x+300) 150x = 120x +36000 30x = ... X=36000/30 X=1200 So the distance covered between A & B =(x+x+300) =(1200+1200+300) =2700km.

A royal enfield bike starts with the speed of 210 km/hr with its speed increasing every 2 hrs by 30km/hr, in how many hrs will it cover 1035km? a) 2 1/2 hr b) 4 1 /2 hr c) 6 1 /2 hr d) 7 1 /2 hr

Description : A royal enfield bike starts with the speed of 210 km/hr with its speed increasing every 2 hrs by 30km/hr, in how many hrs will it cover 1035km? a) 2 1/2 hr b) 4 1 /2 hr c) 6 1 /2 hr d) 7 1 /2 hr

Last Answer : B Distance covered in 1st 2 hrs = (210*2)km =420km Distance covered in next 2 hrs = (240*2)km =480km Remaining distance = 1035 – (420+480) =1035 – 900 =135km Speed in 5th hr = 270 km/hr Time taken to cover 135 km = 135/270 = ½ hr Total time taken = (2+2+1/2) =4 ½ hrs

Geetha runs at a speed of 12 km per hour and she increases her speed in every hour by 1 km per hour. In how many hours will he covers 27.8km ? a) 1 1/4 hours b) 2 1/3 hours. c) 3 1/2 hours. d) 2 1/5 hours.

Description : Geetha runs at a speed of 12 km per hour and she increases her speed in every hour by 1 km per hour. In how many hours will he covers 27.8km ? a) 1 1/4 hours b) 2 1/3 hours. c) 3 1/2 hours. d) 2 1/5 hours.

Last Answer : D Geetha starts with 12 kmph. Distance covered in first 1 hour = 12 km she increases her speed in every hour by 1 km. Speed in 2nd hour = 13 km/hr Distance covered in 2nd hour = 13 km Remaining distance = 27.8 ... total time = 1 + 1 + 1/5 hours = 2 1/5 hours. Hence the answer is 2 1/5 hours.

The speed of a car increases by 2 kms after every one hour. If the distance travelled in the first one hour was 35 kms, what was the total distance traveled in 12 hours? A.456 kms B.482 kms C.552 kms D.556 kms E.None of these

Description : The speed of a car increases by 2 kms after every one hour. If the distance travelled in the first one hour was 35 kms, what was the total distance traveled in 12 hours? A.456 kms B.482 kms C.552 kms D.556 kms E.None of these

Last Answer : Answer – C (552 kms) Explanation – Total distance travelled in 12 hours = (35 + 37 + 39 + …… upto 12 terms) This is an A.P. with first term, a = 35, number of terms, n = 12, common difference, d =2. Required distance =12/2 (2 x 35 + (12 – 1) x 2) = 6(70 + 22) = 552 kms

Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour? A.10 min B.12 min C.18 min D.15 min E.None of these

Description : Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour? A.10 min B.12 min C.18 min D.15 min E.None of these

Last Answer : Answer – A (10 min) Explanation – Due to stoppages, it covers 9 km less.Time taken to cover 9 km = (9/54 x 60) min = 10 min

A goat is noticed by a lion from a distance of 350m. the goat starts running and the lion chases him. The goat and the lion run at the ratio of 30km and 31km per hr respectively. What is the distance between them after 12 mins? a) 120m b) 100m c) 150m d) 170m

Description : A goat is noticed by a lion from a distance of 350m. the goat starts running and the lion chases him. The goat and the lion run at the ratio of 30km and 31km per hr respectively. What is the distance between them after 12 mins? a) 120m b) 100m c) 150m d) 170m

Last Answer : C To find out the relative speed of the goat and lion (31-30) = 1 km/hr Distance covered in 12 mins =(1/60*12)km =1/5 km =(1000/5)m =200m Distance between the goat and lion = (350 – 200)m =150m

Raghu starts a bike at 40 km/hr and he increases his speed in every hour by 4 km/hr. Then the maximum distance covered by him in 12 hours is: a) 744 km b) 658 km c) 436 km d) 512 km

Description : Raghu starts a bike at 40 km/hr and he increases his speed in every hour by 4 km/hr. Then the maximum distance covered by him in 12 hours is: a) 744 km b) 658 km c) 436 km d) 512 km

Last Answer : A Speed of the rider = 40km/hr. Distance covered in 1st hour = 40 km. He increased his speed in every 1 hour by 4 km/hr. Distance covered in every 1 hours will be, 44, 48, ,... upto 12 terms.(for 12 hours). ... (2(40)+(11)4) = 6(80 + 44) = 6(124) = 744. Hence, he covers 744 km in 12 hours.

A monkey takes 16 jumps for every 20 jumps of a dog but 12 jumps of a monkey are equal to 16 jumps of the dog. Compare their speeds a) 15:16 b) 17:16 c) 16:15 d) 16:17

Description : A monkey takes 16 jumps for every 20 jumps of a dog but 12 jumps of a monkey are equal to 16 jumps of the dog. Compare their speeds a) 15:16 b) 17:16 c) 16:15 d) 16:17

Last Answer : C Let the distance covered in 1 jump of the monkey be x and, Distance covered in 1 jump of the dog be y Then 12 x = 16y X = 16 / 12 y ---------->1 Ratio of speed of monkey and dog = Ratio of distances covered by them in the same time =16x : 20y =256 /12 y : 20y (from 1) =256 : 240 = 16:15

The speed of a van increases by 5 kmph after every one hour. If the distance travelled in the first one hour was 55 km, what was the total distance travelled in 8 hours? a) 580km b) 116km c) 147km d) 240km

Description : The speed of a van increases by 5 kmph after every one hour. If the distance travelled in the first one hour was 55 km, what was the total distance travelled in 8 hours? a) 580km b) 116km c) 147km d) 240km

Last Answer :  A Distance travelled in 1ST hour =55 km Speed of the van increases by 5 kmph after every one hour. Hence, distance travelled in 2nd hour =60 km distance travelled in 3rd hour =65 km and so on Total distance travelled =(55+60+……..+(8 terms)) =8/2(2*55+(8-1)5) =4(110+35) =580km

In covering a definite distance, the speeds of P & Q are in the ratio of 5:6. P takes 45 mins more than Q to reach the target. The time taken by P to reach the target is. a) 4 hrs 20 mins b) 4 hrs 45 mins c) 2hrs 30 mins d) 4hrs 30 mins

Description : In covering a definite distance, the speeds of P & Q are in the ratio of 5:6. P takes 45 mins more than Q to reach the target. The time taken by P to reach the target is. a) 4 hrs 20 mins b) 4 hrs 45 mins c) 2hrs 30 mins d) 4hrs 30 mins

Last Answer : D Ratio of speeds = 5:6 Ratio of time =6:5 Suppose P takes 6x hrs and Q takes 5x hrs to reach the target. Then, 6x – 5x = 45/60 X=3/4 Time taken by P = 6x hrs =(6*3/4)hrs =4.5 hrs i.e., the time taken by P to reach the target is 4hrs 30mins

A bus can travel 25% faster than a van. Both start from a certain shop at the same time and reach poin P, 37.5 kms away from the shop at the same time time. On the way, however, the bus lost about 6.25 mins while shopping at the some such places. The speed of the van is. a) 72 b) 73 c) 74 d) 75

Description : A bus can travel 25% faster than a van. Both start from a certain shop at the same time and reach poin P, 37.5 kms away from the shop at the same time time. On the way, however, the bus lost about 6.25 mins while shopping at the some such places. The speed of the van is. a) 72 b) 73 c) 74 d) 75 

Last Answer : A Let speed of the car be x kmph The speed of the train = 125x/100 =5x/4 km/hr Therefore 37.5 / x – 37.5 /(5x/4) = 6.25 /60 37.5 / x – (37.5*4)/5x = 6.25 / 60 37.5 / x – 150 / 5x = 6.25 / 60 37.5 / x – 30/x = 6.25 / 60 7.5 / x = 6.25 / 60 6.25x = 7.5*60 X=72 km/hr

Anitha takes 8 hrs 20 mints in walking to a temple and riding back. She would have gained 3 hrs by riding both ways. The time she would take to walk both ways is. a) 15hrs 40mints b) 16hrs 40 mints c) 18 hrs 40 mints d) 19 hrs 40 mints

Description : Anitha takes 8 hrs 20 mints in walking to a temple and riding back. She would have gained 3 hrs by riding both ways. The time she would take to walk both ways is. a) 15hrs 40mints b) 16hrs 40 mints c) 18 hrs 40 mints d) 19 hrs 40 mints

Last Answer : D Let the distance be x km. then, (time taken to walk x km)+(time taken to ride x km) = 25/3 hrs (time taken to walk 3x km)+(time taken to ride 3x km) = 25/3*3 =25hrs But the time taken to ride 3xkm=(25/ ... 16/3 hrs Time taken to walk 3x km = (25 - 16/3)hrs =(75 - 16)/3 =59/3 =19 hrs 40mins

Two train travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 8 seconds. Then length of the faster train is: A.120 m B.140 m C.160 m D.180 m E.None of these

Description : Two train travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 8 seconds. Then length of the faster train is: A.120 m B.140 m C.160 m D.180 m E.None of these

Last Answer : Answer – D (180 m) Explanation – When OPP. direction-PLUS Relative speed = (36 + 45) km/hr = [81 x 5/18] m/sec = [45/2] m/sec. Length of train = [45/2 x 8] m = 180 m.

Nishu is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the speed of the train? A.35 kmph B.54 kmph C.62 kmph D.70 kmph E.None of these

Description : Nishu is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the speed of the train? A.35 kmph B.54 kmph C.62 kmph D.70 kmph E.None of these

Last Answer : Answer - B (54 kmph) Explanation - Let the length of the train be x metres. Then, the train covers x metres in 8 seconds (train is actually covering itself because length of man is very less compartable to train)and (x + ... /8]m/sec (convert to km/hr i.e x 18/5) =[120/8] x 18/5kmph = 54 kmph.

In a 2280 m race Dinesh beats Aarav by 360 m or 6 seconds. In another race on the same track at the same speeds. Aarav and karthick start at one end while Dinesh starts at the opposite end. How many metres would Aarav have covered ,by the time Dinesh meets karthick given that Dinesh speed is 16 m/sec more than that of karthick a) 1140 m b) 2280 m c) 2460 m d) 1180 m

Description : In a 2280 m race Dinesh beats Aarav by 360 m or 6 seconds. In another race on the same track at the same speeds. Aarav and karthick start at one end while Dinesh starts at the opposite end. How many metres would Aarav ... is 16 m/sec more than that of karthick a) 1140 m b) 2280 m c) 2460 m d) 1180 m

Last Answer : B Aarav 's speed =360/6 =60 m/s Time taken by Aarav to cover 2280 m =2280/60= 38 seconds Dinesh 's speed = 2280/60=38 m/s karthick 's speed = 22m/s Time taken by Dinesh to meet karthick in ... direction: Distance covered by Aarav: =2280/(38+22) =2280/60 =38 seconds =(38*60)m =2280 m

A girl covered a definite distance at same speed. Had she moved 6 km/hr faster, she would have taken 30 mins less. If she had moved 4 km/hr slower, she would have taken 30 mins more. The distance (in km) is. a) 50 b) 40 c) 70 d) 60

Description : A girl covered a definite distance at same speed. Had she moved 6 km/hr faster, she would have taken 30 mins less. If she had moved 4 km/hr slower, she would have taken 30 mins more. The distance (in km) is. a) 50 b) 40 c) 70 d) 60

Last Answer : D Let distance = x km Rate = y km/hr x/y - x / (y+6) = 30/60 (x(y+6)-xy) / y(y+6) = ½ (xy +6x - xy) / y(y+6) = ½ 12x = y(y+6) ------------>1 And x/ (y-4) - x/y = 30/60 (Xy - x(y-4 ... = (y+6) / (y-4) 3y - 12 = 2y +12 Y = 24km Put y value in 1 we get 12x = 24 (24+6) 12x = 24 *30 X=60km

Two bike A & B start at the same time from salem to Rasipuram which are 60km apart. If the 2 bikes travel in opposite directions, they meet after 1 hr and if they travel in same direction(from salem towards Rasipuram), then A meets B after 3 hrs. what is the speed of bike A? a) 50 b) 70 c) 90 d) 30

Description : Two bike A & B start at the same time from salem to Rasipuram which are 60km apart. If the 2 bikes travel in opposite directions, they meet after 1 hr and if they travel in same direction(from salem towards Rasipuram), then A meets B after 3 hrs. what is the speed of bike A? a) 50 b) 70 c) 90 d) 30

Last Answer : B Let their speed be x km/hr and y km/hr respectively Then 60 / (x+y) = ½ X+y = 120 ------------->1 Now when they move in same direction (distance travelled by A in 3 hrs) - (Distance travelled by B in ... = 140 X=70 Put x value in 1 we get Y=120 -70=50 Y=50 Therefore A's speed = 70 km/hr

A passenger train without stopping running at an average speed of 120 km/hr and with stoppages at an average speed of 80 km/hr. What is the total time taken by the train for stoppages on a route of length 480km? a) 2 hours b) 3 hours c) 4 hours d) 5 hours

Description : A passenger train without stopping running at an average speed of 120 km/hr and with stoppages at an average speed of 80 km/hr. What is the total time taken by the train for stoppages on a route of length 480km? a) 2 hours b) 3 hours c) 4 hours d) 5 hours

Last Answer : A Let r = running time of the train s= stoppage time of the train D= total distance travelled by train We have: D/r= 120 and ..(1) D/(r+s) =80 ..(2) Diviving (1)&(2), D/r *(r+s)/D = ... , D=480 kms 480/r= 120 r=4 put r value in (3),we get s/4 =1/2 S = 2 hours

In a 2700 m race around a round track of length 300m, abi and kabi meet at the end of the 3rd minute, for the first time after the start of the race. All the runners maintain uniform speed throughout the race. If abi runs at twice the speed of the kabi. Find the time taken by abi to finish the race. a) 27 mints b) 32 mints c) 5 mints d) 23 mints

Description : In a 2700 m race around a round track of length 300m, abi and kabi meet at the end of the 3rd minute, for the first time after the start of the race. All the runners maintain uniform speed throughout the race. ... time taken by abi to finish the race. a) 27 mints b) 32 mints c) 5 mints d) 23 mints

Last Answer : A As, abi is twice as fast as the kabi, abi would have completed two rounds by the time kabi completes one round. And that is their second meeting. Their first meeting takes place after the abi ... 300m ⇒He takes 2700/300 *3 =27 mints Hence he takes 27 minutes to finish the race.

A bus can travel 25% faster than a jeep. Both start from point P at the same time and reach point Q, 225 kms away from P, at the same time. On the way, however, the bus lost about 37.5 minutes while stopping at the certain place. What is the speed of the jeep? a) 64 km/hr b) 72 km/hr c) 68 km/hr d) 56 km/hr

Description : A bus can travel 25% faster than a jeep. Both start from point P at the same time and reach point Q, 225 kms away from P, at the same time. On the way, however, the bus lost about 37.5 minutes while stopping at the ... is the speed of the jeep? a) 64 km/hr b) 72 km/hr c) 68 km/hr d) 56 km/hr

Last Answer : B Let speed of the jeep =x kmph Then, speed of the bus =(100+25)x/100 =125x/100 =5x/4 kmph Time taken by the jeep to travel from P to Q =225/x hours Time taken by the bus to travel from p to Q =225/(5x/4) + ... 225/x=900/5x+37.5/60 225/x=180/x+37.5/60 45/x =37.5/60 37.5x=45*60 X=72 km/hr