Nishu is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the speed of the train? A.35 kmph B.54 kmph C.62 kmph D.70 kmph E.None of these

Nishu is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the speed of the train? A.35 kmph B.54 kmph C.62 kmph D.70 kmph E.None of these
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1 Answer

Answer :

Answer – B (54 kmph)

Explanation – Let the length of the train be x metres.

Then, the train covers x metres in 8 seconds (train is actually covering

itself because length of man is very less compartable to train)and (x +

180) metres in 20 seconds.

equate speed in both case,s=d/t

∴ x/8 =( x + 180) / 20 ⇔ 20x = 8(x + 180) ⇔ x = 120.

∴ Length of the train = 120 m.

Speed of the train = [120/8]m/sec (convert to km/hr i.e x 18/5)

=[120/8] x 18/5kmph = 54 kmph.
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Related questions

A man in a train notices that he can count 21 telephone posts in one minute. If they are known to be 50 meters apart, then at what speed is the train travelling? A.50 kmph B.54 kmph C.60 kmph D.62 kmph E.None of these

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A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes? A.100 m B.150 m C.190 m D.200 m E.None of these

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Description : A bike starts with a speed of 60 km/hr at 8a.m. Due to the problem in engine it reduces its speed as 20 km/hr for every 1 hour. After 9 am, the time taken to covers 15 km is: a) 13 minutes and 20 seconds b) 15 minutes and 09 seconds c) 18 minutes and 15 seconds d) 22 minutes and 30 seconds

Last Answer : 15 min

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Three trains are running from a place A to another place B. Their speeds are in the ratio of 4 : 3 : 5. The time ratio to reach B by trains will be A. 4 : 3 : 5 B. 5 : 3 : 4 C. 15 : 9 : 20 D. 15 : 20 : 12

Description : Three trains are running from a place A to another place B. Their speeds are in the ratio of 4 : 3 : 5. The time ratio to reach B by trains will be A. 4 : 3 : 5 B. 5 : 3 : 4 C. 15 : 9 : 20 D. 15 : 20 : 12

Last Answer : Answer: D(15 : 20 : 12) Explanation: Ratio of speeds = 4 : 3 : 5 Therefore Ratio of times taken [t=d/s or t indirectly proportional to s when distance is same]= (1/4) : (1/3) : (1/5) = 15 : 20 : 12

Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds? A.9 : 28 B.11 : 9 C.11 : 8 D.9 : 22 E.None of these

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Last Answer : Answer – B (11 : 9) Explanation – In the same time, they cover 110 km and 90 km respectively.Ratio of their speeds = 110 : 90 = 11 : 9 

A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is :

Description : A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is : a) 72 metres b) 54 metres c) 55 metres d) 45 metres e) 50 meters

Last Answer : Answer: e)

A 240m train crosses a standing object in 6 seconds. Find the time taken by the train to cross a long pole of length 162.5 m. A) 25 B) 45 C) 10 D) 15

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P,Q & R are on a journey by scorpio. P drives during the 1st 2 hrs at an average speed of 60 km/hr. Q drives during the next 3 hrs at an average speed of 58 km/hr R drives for the next 4 hrs at an average speed of 62 km/hr. They reached their destination after exactly 5 hrs. Their main speed is. a) 60 2/9 b) 62 2/9 c) 60 4/8 d) 62 4 /8

Description : P,Q & R are on a journey by scorpio. P drives during the 1st 2 hrs at an average speed of 60 km/hr. Q drives during the next 3 hrs at an average speed of 58 km/hr R drives for the next 4 hrs at an average speed of 62 ... exactly 5 hrs. Their main speed is. a) 60 2/9 b) 62 2/9 c) 60 4/8 d) 62 4 /8 

Last Answer : A Distance covered by P = 2*60 = 120 km Distance covered by Q = 3* 58 = 174 km Distance covered by R = 4*62 = 248 km Total distance = (120+174+248)km =542 km Total time taken = 2+3+4 = 9 hrs Mean speed = diatance/ time =(542 / 9)km/hr =60 2/9 km/hr

A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train? a) 120 meters b) 180 meters c) 324 meters d) 150 meters

Description : A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train? a) 120 meters b) 180 meters c) 324 meters d) 150 meters

Last Answer : d) 150 meters

Senthil started bike at 5 a.m to reach a temple. After going temple, his bike went out of order. Consequently he rested for 45 mins and came back to his house walking all the way. Senthil reached home at 8 a.m. if bike speed is 20 km/hr and his walking speed is 1 km/hr, then on bike he covered a distance of. a) 3.12 b) 2.76 c) 4.13 d) 2.14

Description : Senthil started bike at 5 a.m to reach a temple. After going temple, his bike went out of order. Consequently he rested for 45 mins and came back to his house walking all the way. Senthil reached home at 8 a.m. if bike ... /hr, then on bike he covered a distance of. a) 3.12 b) 2.76 c) 4.13 d) 2.14

Last Answer : D Time taken = 2 hr 15 mins = 2 ¼ hrs Time = 9/4 hrs Let the required distance be x km Then x/20 + x/1 = 9/4 (X+20x) / 20 = 9/4 21x / 20 = 9/4 84x = 180 X= 2.14 km Therefore the required diatance is 2.14 km

Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr

Description : Ravi walks to and fro to a Gym. He spends 30 minutes in gym. If he walks at speed of 20 km an hour, he returns to home at 8.00 a.m. If he walks at 30 km an hour, he returns to home at 7.30 a.m. How fast must he walk in order to return at 7.15 hours? a) 40 km/hr b) 30 km/hr c) 60 km/hr d) 50 km/hr

Last Answer :  A As per the question, let D be the total distance and ‘t’ is the time taken. So we have: D=20t 20t =30(t-0.5) 20t=30t-15 10t=15 t=3/2 D= 30 km Now, for the condition given we have: 30=S(t-3/4) 30=S(3/2-3/4) 30=S((6-3)/4) 30=S(3/4) S=40 km/hr

In a 2280 m race Dinesh beats Aarav by 360 m or 6 seconds. In another race on the same track at the same speeds. Aarav and karthick start at one end while Dinesh starts at the opposite end. How many metres would Aarav have covered ,by the time Dinesh meets karthick given that Dinesh speed is 16 m/sec more than that of karthick a) 1140 m b) 2280 m c) 2460 m d) 1180 m

Description : In a 2280 m race Dinesh beats Aarav by 360 m or 6 seconds. In another race on the same track at the same speeds. Aarav and karthick start at one end while Dinesh starts at the opposite end. How many metres would Aarav ... is 16 m/sec more than that of karthick a) 1140 m b) 2280 m c) 2460 m d) 1180 m

Last Answer : B Aarav 's speed =360/6 =60 m/s Time taken by Aarav to cover 2280 m =2280/60= 38 seconds Dinesh 's speed = 2280/60=38 m/s karthick 's speed = 22m/s Time taken by Dinesh to meet karthick in ... direction: Distance covered by Aarav: =2280/(38+22) =2280/60 =38 seconds =(38*60)m =2280 m

The average speed of a bus in the upward journey is 50% more than that in the return journey. The bus halts for 2 hrs on reaching the destination. The total time taken for the complete to and from trip is 34 hrs covering a distance of 1600 km. the speed of the bus in the upward journey is. a) 63.24 b) 65.67 c) 63.49 d) 62.49

Description : The average speed of a bus in the upward journey is 50% more than that in the return journey. The bus halts for 2 hrs on reaching the destination. The total time taken for the complete to and from trip is 34 hrs ... speed of the bus in the upward journey is. a) 63.24 b) 65.67 c) 63.49 d) 62.49

Last Answer : D Let the speed in return journey be x km/hr Then speed in upward journey = 150 /100 x = (3/2 x)km/hr Average speed = (2*3x/2*x) / (3x/2 +x) =3x2 / (5x/2) =6x2 / 5x =6x/5 km/hr Therefore (1600 ... 192x = 8000 X = 41.66 Speed in upward journey = (3/2 x ) km/hr =(3/2*41.66) =62.49 km/hr 

Karthiga jogs a speed of 18 km/hr at a distance of 27 km. at what speed would she need to jog during the next 4.5 hrs to have an average of 27km/hr for the entire jogging session. a) 40km/hr b) 30 km/hr c) 20 km/hr d) 35 km/hr

Description : Karthiga jogs a speed of 18 km/hr at a distance of 27 km. at what speed would she need to jog during the next 4.5 hrs to have an average of 27km/hr for the entire jogging session. a) 40km/hr b) 30 km/hr c) 20 km/hr d) 35 km/hr

Last Answer : B Let the speed of jagging be x km/hr Total time taken = (27/18 hrs + 4.5 hrs) =(1.5 hrs + 4.5 hrs) =6 hrs Total distance covered = (27+4.5 x) km Therefore (27 +4.5x) / 6= 27 27+4.5x = 162 4.5x = 135 X=135/4.5 =30 So jagging speed is 30 km/hr

I reach the bus stop 15 min late if I walk at 2 kmph Starting from my office . Instead, if I walk at 3 kmph, I reach the bus stop 10 min early. How far is bus stop from my office? a) 1.5 km b) 2.5 km c) 3.5 km d) 4.5 km

Description : I reach the bus stop 15 min late if I walk at 2 kmph Starting from my office . Instead, if I walk at 3 kmph, I reach the bus stop 10 min early. How far is bus stop from my office? a) 1.5 km b) 2.5 km c) 3.5 km d) 4.5 km

Last Answer : B Let the distance between the office and the bus stop be 1 km Time required at 2 kmph =1/2 =30 mins Time required at 3 kmph =1/3 =20 mins Difference = 30−20=10 min. Actual difference in timings = ... is 1 km ⇒ If difference is 25 min, distance is 2.5 km Hence the required answer is 2.5 km

If Nishu can swim downstream at 6kmph and upstream at 2kmph.What is his speed in still water ? A.5 km/hr B.4 km/hr C.8km/hr D.7km/hr

Description : If Nishu can swim downstream at 6kmph and upstream at 2kmph.What is his speed in still water ? A.5 km/hr B.4 km/hr C.8km/hr D.7km/hr

Last Answer : Answer- B Basic Formula: If the speed downloadstream is a km/ hr and the speed upstream is b km/ hr then Speed in still water is = ½ (a+b) km / hr [memory tool last 2 L cross and make +] Explanation: Given ... still water = ½ (a+b) kmph = ½ (6+2) = 8/2 = 4kmph speed in still water = 4kmph

Ganesh is travelling on his motorbike and has calculated to reach golden temple at 8 p.m if he travels at 30 km/hr; he will reach there at 6 p.m if he travels at 45 km/hr. At what speed must he travel to reach the golden temple at 7 p.m? a) 36 b) 46 c) 32 d) 30

Description : Ganesh is travelling on his motorbike and has calculated to reach golden temple at 8 p.m if he travels at 30 km/hr; he will reach there at 6 p.m if he travels at 45 km/hr. At what speed must he travel to reach the golden temple at 7 p.m? a) 36 b) 46 c) 32 d) 30

Last Answer : A Let the distance travelled be x km x/30 – x/45 = 2 (3x – 2x) / 90 = 2 x/90 = 2 x = 180km Time taken to travel 180 km at 30 km/hr = 180 / 30 = 6 hrs So ganesh started 6 hrs before 8 pm That is 2 pm Required speed = distance / time =(180/5) =36 km/hr

2 pistol were shoot from the same place at an interval of 15 mins and 15 secs but a boy in the train approaching the place hears the second shot 15 mins after the first. The speed of the train(in km/hr),supposing that speed travels at 320 metres per second is. a) 15.166 b) 17.144 c) 18.563 d) 19.188

Description : 2 pistol were shoot from the same place at an interval of 15 mins and 15 secs but a boy in the train approaching the place hears the second shot 15 mins after the first. The speed of the train(in km/hr),supposing that speed travels at 320 metres per second is. a) 15.166 b) 17.144 c) 18.563 d) 19.188

Last Answer : D Let the speed of the train be x m/sec Then distance travelled by the train in 15mins = distance travelled by sound in 15secs X*15*60 = 320*15 900x = 4800 X=4800/900 X=5.33 Speed of the train 5.33 m/s Convert m/s into km/hr 5.33m =(5.33*18/5) =(95.94/5) =19.188 km/hr

Arun steals a van at 8.30 am and drives it at 40km/hr. The theft is discovered at 9 a.m and the owner sets off in another van at 55km/hr. when will he overtake arun? a) 10.20 am b) 12.20am c) 11.20am d) 10.15am

Description : Arun steals a van at 8.30 am and drives it at 40km/hr. The theft is discovered at 9 a.m and the owner sets off in another van at 55km/hr. when will he overtake arun? a) 10.20 am b) 12.20am c) 11.20am d) 10.15am

Last Answer : A Suppose the arin is overtaken x hrs after 8.30 a.m Then distance covered by arun in x hrs = distance covered by the owner in(x-1/2) hrs 40x =55(x-1/2) 40x = 55x -55/2 55x – 40x =55/2 15x=55/2 X = 55/2*1/15 x=55/30 x= 1hr 50mins so the thief is overtaken at 10.20 a.m

Two bike A & B start at the same time from salem to Rasipuram which are 60km apart. If the 2 bikes travel in opposite directions, they meet after 1 hr and if they travel in same direction(from salem towards Rasipuram), then A meets B after 3 hrs. what is the speed of bike A? a) 50 b) 70 c) 90 d) 30

Description : Two bike A & B start at the same time from salem to Rasipuram which are 60km apart. If the 2 bikes travel in opposite directions, they meet after 1 hr and if they travel in same direction(from salem towards Rasipuram), then A meets B after 3 hrs. what is the speed of bike A? a) 50 b) 70 c) 90 d) 30

Last Answer : B Let their speed be x km/hr and y km/hr respectively Then 60 / (x+y) = ½ X+y = 120 ------------->1 Now when they move in same direction (distance travelled by A in 3 hrs) - (Distance travelled by B in ... = 140 X=70 Put x value in 1 we get Y=120 -70=50 Y=50 Therefore A's speed = 70 km/hr

A girl covered a definite distance at same speed. Had she moved 6 km/hr faster, she would have taken 30 mins less. If she had moved 4 km/hr slower, she would have taken 30 mins more. The distance (in km) is. a) 50 b) 40 c) 70 d) 60

Description : A girl covered a definite distance at same speed. Had she moved 6 km/hr faster, she would have taken 30 mins less. If she had moved 4 km/hr slower, she would have taken 30 mins more. The distance (in km) is. a) 50 b) 40 c) 70 d) 60

Last Answer : D Let distance = x km Rate = y km/hr x/y - x / (y+6) = 30/60 (x(y+6)-xy) / y(y+6) = ½ (xy +6x - xy) / y(y+6) = ½ 12x = y(y+6) ------------>1 And x/ (y-4) - x/y = 30/60 (Xy - x(y-4 ... = (y+6) / (y-4) 3y - 12 = 2y +12 Y = 24km Put y value in 1 we get 12x = 24 (24+6) 12x = 24 *30 X=60km

A 1800 km journey of 24 hrs, if 360km is done by van and the rest by train. It takes 60 mins more, if 600km is done by van and the rest by train. The ratio of the speed of the van to that of the train is. a) 2:4 b) 4:3 c) 3:4 d) 5:3

Description : A 1800 km journey of 24 hrs, if 360km is done by van and the rest by train. It takes 60 mins more, if 600km is done by van and the rest by train. The ratio of the speed of the van to that of the train is. a) 2:4 b) 4:3 c) 3:4 d) 5:3

Last Answer : C Let the speed of the van be x km/hr And that of the train be y km/hr 360/x+1440/y = 24 --------------->A Dividing by 24 on both sides 15/x+60/y = 1 ---------1 And 600/x +1200/y =25 Dividing by ... 720/y =9 Y=80 Put y value in A 360/x = 24-18 X=360/6 X=60 Ratio of speeds = 60:80 = 3:4

A passenger train without stopping running at an average speed of 120 km/hr and with stoppages at an average speed of 80 km/hr. What is the total time taken by the train for stoppages on a route of length 480km? a) 2 hours b) 3 hours c) 4 hours d) 5 hours

Description : A passenger train without stopping running at an average speed of 120 km/hr and with stoppages at an average speed of 80 km/hr. What is the total time taken by the train for stoppages on a route of length 480km? a) 2 hours b) 3 hours c) 4 hours d) 5 hours

Last Answer : A Let r = running time of the train s= stoppage time of the train D= total distance travelled by train We have: D/r= 120 and ..(1) D/(r+s) =80 ..(2) Diviving (1)&(2), D/r *(r+s)/D = ... , D=480 kms 480/r= 120 r=4 put r value in (3),we get s/4 =1/2 S = 2 hours