Description : If the length of a simple pendulum is halved then its period of oscillation is - (1) doubled (2) halved (3) increased by a factor √ 2 (4) decreased by a factor √ 2
Last Answer : (4) decreased by a factor √ 2
Description : If the length of a simple pendulum is halved then its period of oscillation is (1) doubled (2) halved (3) increased by a factor root 2 (4) decreased by a factor root 2
Last Answer : decreased by a factor root 2
Description : A particle is moving in Simple Harmonic Motion in a simple pendulum with some period of oscillation. Now in order to double the period of oscillation a.The length of pendulum should be quadrupled b.The ... length of pendulum should be reduced to one fourth e.The mass of the bob should be doubled
Last Answer : a. The length of pendulum should be quadrupled
Description : A shaft of length l carries two discs at its two ends. The lowest torsional frequency is ω n . If the shaft length is doubled, then the lowest torsional frequency becomes A ω n /2 B ω n /√2 C √2ω n D 2ω n
Last Answer : B ω n /√2
Description : The time `t` of a complete oscillation of a simple pendulum of length `l` is given by the equation `T=2pisqrt(1/g)` where `g` is constant. What is the
Last Answer : The time `t` of a complete oscillation of a simple pendulum of length `l` is given by the equation `T= ... error in `T` when `l` is increased by 1%?
Description : The time taken by a pendulum to complete one oscillation is called its?
Last Answer : Time period
Description : A proton moves in a uniform magnetic field in a circular path of radius R. If the energy of proton is doubled then the new radius becomes a) R √2 b) 2R c) R 2 d) √2 R
Last Answer : d) √2 R
Description : Oscillation of pendulum is an example of
Last Answer : simple harmonic motion.
Description : What is the oscillation period of the pendulum in the center of the earth ?
Last Answer : The oscillation of the pendulum in the center of the earth is infinite.
Description : The work done by the string of a simple pendulum during one complete oscillation is equal to (1) Total energy of the pendulum (2) Kinetic energy of the pendulum (3) Potential energy of the pendulum (4) Zero
Last Answer : (4) Zero Explanation: Work done by the string of the simple pendulum during one complete oscillation is zero. Tension in the string exactly cancels the component parallel to the string. This leaves a net restoring force back toward the equilibrium position as equal to zero.
Description : Second’s pendulum is a pendulum which executes one oscillation in: (1) Half a second (2) One second (3) Two seconds (4) None of these
Last Answer : (3) Two seconds Explanation: A pendulum is a weight suspended from a pivot so that it can swing freely. A seconds pendulum is a pendulum whose period is precisely two seconds; one second for a swing in one direction and one second for the return swing, a frequency of 1/2 Hz.
Description : Due to energy dissipation by viscous forces in air, if simple harmonic variations of a pendulum die away after some time, then oscillation is said to be: A. undamped B. free C. damped D. dependent
Last Answer : damped
Description : Pendulum "A" swings through one complete oscillation in one second. If Pendulum "B" is four times as long as Pendulum "A", how long does it take Pendulum "B" to swing through one complete oscillation?
Last Answer : ANSWER: 2 SECONDS
Last Answer : Zero
Description : An instrument has two strings. Both have the same length and are uniform. One of the strings is under twice as much tension as the other and also twice the mass of the other. Then which of ... d) Both strings vibrate with the same frequency and have the same wave-length and the same wave velocity.
Last Answer : Ans:(d)
Description : Feedback factor at the frequency of oscillation of a Wien bridge oscillator is: (1) 3 (2) 1/3 (3) 1/29 (4) 3/29
Last Answer : Feedback factor at the frequency of oscillation of a Wien bridge oscillator is: 1/3.
Description : A clock with a second pendulum is gaining 5 minutes a day. To correct it a.The eccentricity of bob with pendulum should be decreased b.The length of the pendulum should be decreased c.The ... .The length of the pendulum should be increased e.The eccentricity of bon with pendulum should be increased
Last Answer : d. The length of the pendulum should be increased
Description : If the mass of the pendulum is doubled, what will its the time period?
Last Answer : Remains same
Description : What happens to the period of a pendulum if the mass of the bob is quadrupled? w) it is cut in half x) it stays the same y) it is doubled z) it is quadrupled
Last Answer : ANSWER: X -- IT STAYS THE SAME
Description : For small oscillations, what happens to the period of a simple pendulum when the mass of the pendulum bob is doubled?
Last Answer : ANSWER: NOTHING or PERIOD IS UNAFFECTED
Description : If the depth of a simply supported beam carrying an isolated load at its centre, is doubled, the deflection of the beam at the centre will be changed by a factor of (A) 2 (B) 1/2 (C) 8 (D) 1/8
Last Answer : (D) 1/8
Description : A simple pendulum is found to vibrate at a frequency of 0.5Hz in vacuum and0.45 Hz in a viscous fluid medium. Find the damping factor. 0.5122 (B) 0.9272 (C) 0.4359 (D) 0.2568
Last Answer : (C) 0.4359
Description : A simple pendulum is found to vibrate at a frequency of 0.5Hz in vacuum and 0.45Hz in a viscous fluid medium. Find the damping factor. A 0.5122 B 0.9237 C 0.4359 D 0.2568
Last Answer : C 0.4359
Description : Natural frequency of simple pendulum is proportional to A. Length B. Acceleration due to gravity C. Both D. None
Last Answer : B. Acceleration due to gravity
Description : If the length of an antenna is changed from 2.5 meters to 2.8 meters, its resonant frequency will A. increase B. depend on the velocity factor so the resonant frequency can either be increased or decreased C. will be unchanged D. decrease
Last Answer : D. decrease
Description : What is the new period of the pendulumThe period of a pendulum is 1.4 seconds. The length of the pendulum is increased by a factor of 4.?
Last Answer : Need answer
Description : In the graph shown below, the region in which frequency ratio (ω/ω n ) > √2 is known as____ A. Amplification region B. Isolation region C. Spring controlled region D. None of the above
Last Answer : B. Isolation region
Description : In vibration isolation system, the transmissibility will be equal to unity, for all values of damping factor, if ω/ωn is A. Equal to 1 B. Equal to √2 C. Less than √2 D. Greater than √2
Last Answer : B. Equal to √2
Description : n vibration isolation system, if ω/ω n is less than √2 , then for all values of the damping factor, the transmissibility will be a) less than unity b) equal to unity c) greater than unity d) zero
Last Answer : c) greater than unity
Description : A circle has radius √2 cm. It is divided into two segments by a chord of length 2cm.Prove that the angle subtended by the chord at a point in major segment is 45 degree . -Maths 9th
Last Answer : Given radius =2 cm Therefore AO=2 cm Let OD be the perpendicular from O on AB And AB =2cm Therefore AD=1cm (perpendicular from the centre bisects the chord) Now in triangle AOD, AO=2 cm ... by a chord at the centre is double of the angle made by the chord at any poin on the circumference)
Description : A column of length l is fixed at both ends. The equivalent length of the column is (A) l/2 (B) l/√2 (C) l (D) 2 l
Last Answer : (A) l/2
Description : What happen to the time period if its lenght of the pendulum is changed?
Last Answer : If the length of a pendulum is increased, the pendulum will take longer to complete a swing, and the clock will slow down. Shortening the pendulum will speed up the clock.
Description : When a person sitting on a swing stands up on the swing, the frequency of oscillation – (1) decreases (2) increases (3) becomes infinite (4) does not change
Last Answer : (2) increases Explanation: In Simple Harmonic Motion, the frequency of the oscillation (1) is the number of oscillations per second which is expressed as f = 1/T where T is the time period (the time for the oscillator to complete one cycle).
Description : One of the following is a possible cause of an abrupt frequency variation in a self exited transmitter oscillator circuits resulting to a poor frequency stability to hold a constant frequency ... capacitor in the oscillator D. Loose connections in the oscillator, amplifier, or antenna circuits.
Last Answer : D. Loose connections in the oscillator, amplifier, or antenna circuits.
Description : A spring mass system has time period of oscillation of 0.25 sec. What will be the natural frequency of the system? A 1 Hz B 2 rad sec C 4 rad/sec D 4 Hz
Last Answer : D 4 Hz
Description : The period of oscillation of a particle undergoing simple harmonic motion is: w) independent of the amplitude of the motion x) directly proportional to the frequency of oscillation y) independent of the frequency of oscillation z) none of the above
Last Answer : ANSWER: W -- INDEPENDENT OF THE AMPLITUDE OF THE MOTION
Description : When a person sitting on a swing stands up on the swing, the frequency of oscillation (1) decreases (2) increases (3) becomes infinite (4) does not change
Last Answer : increases
Description : In a transistor Colpitts oscillator, C1 = 0.001 µF, C2 = 0.01 µF and L = 5 µH. The frequency of oscillation in MHz will be (a) 2.37 MHz (b) 10.00 MHz (c) 11.54 MHz (d) 9.09 MHz
Last Answer : c
Description : Frequency of oscillation of an AMV depends upon 1. RC values of the circuit 2. Collector load resistors 3. Transistor 4. Width of input pulse
Last Answer : Frequency of oscillation of an AMV depends upon RC values of the circuit
Description : If the width of a simply supported beam carrying an isolated load at its centre is doubled, the deflection of the beam at the centre is changed by (A) 1/2 (B) 1/8 (C) 2 (D) 8
Last Answer : (A) 1/2
Description : If the width of a simply supported beam carrying an isolated load at its centre is doubled, the deflection of the beam at the centre is changed by (A) 2 times (B) 4 times (C) 8 times (D) 1/2 times
Last Answer : (C) 8 times
Description : A cantilever beam rectangular in cross-section is subjected to an isolated load at its free end. If the width of the beam is doubled, the deflection of the free end will be changed in the ratio of (A) 8 (B) 1/8 (C) 1/2 (D) 3
Last Answer : (C) 1/2
Description : How many times area is changed, when sides of a triangle are doubled. -Maths 9th
Last Answer : Four times area is changed, when sides of a triangle are doubled.
Description : If bandwidth is doubled, the signal power is _________. A. not changed B. quadrupled C. tripled D. doubled
Last Answer : A. not changed
Description : A sewer has a diameter of 300 mm and slop of 1 in 400. While running full it has a mean velocity of 0.7 m/s. If both the diameter and slope are doubled (to respectively be 600 mm and 1 in 200), what will be the changed mean velocity ... 's formula. (a) 1.59 m/s (b) 2.80 m/s (c) 0.90 m/s (d) 1.00 m/s
Last Answer : (a) 1.59 m/s
Description : The SI standard of time is based on-------? A. the daily rotation of the earth B. the frequency of light emitted by Kr86 C. the yearly revolution of the earth about the sun D. a precision pendulum clock E. none of these (Answer)
Last Answer : E. none of these (Answer)
Description : . In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A Fn =N √(R/L) B Fn =1/N √(R/L) C Fn =N/2 √(R/L) D Fn =N2 √(R/L)
Last Answer : A Fn =N √(R/L)
Description : Frequency of centrifugal pendulum absorber is always proportional to A) Oscillating motion B) Transfer motion C) Speed of rotating body D) All of the above
Last Answer : C) Speed of rotating body
Description : In centrifugal pendulum absorber , the natural frequency in cycle per second can be given by A) Fn =N √(R/L) B) Fn =1/N √(R/L) C) Fn =N/2 √(R/L) D) Fn =N2 √(R/L)
Last Answer : A) Fn =N √(R/L)
Description : The acceleration due to gravity is determined by using a simple pendulum of length l = (100 ± 0.1) cm. If its time period is T = (2 ± 0.01)
Last Answer : The acceleration due to gravity is determined by using a simple pendulum of length l = (100 ... the maximum percentage error in the measurement of g.