In the graph shown below, the region in which frequency ratio (ω/ω n ) > √2 is known as____ A. Amplification region B. Isolation region C. Spring controlled region D. None of the above

In the graph shown below, the region in which frequency ratio (ω/ω n ) > √2 is known
as____
A. Amplification region
B. Isolation region
C. Spring controlled region
D. None of the above
by

1 Answer

Answer :

B. Isolation region
by

Related questions

Consider the steady-state absolute amplitude equation shown below, if ω / ω n = √2 then amplitude ratio (X/Y) =? (X/Y) = √{1 + [ 2ξ (ω/ω n )] 2 } / √{[1 – (ω/ω n ) 2 ] 2 + {2ξ (ω/ω n ) 2 } A. 0 B. 1 C. less than 1 D. greater than 1

Description : Consider the steady-state absolute amplitude equation shown below, if ω / ω n = √2 then amplitude ratio (X/Y) =? (X/Y) = √{1 + [ 2ξ (ω/ω n )] 2 } / √{[1 – (ω/ω n ) 2 ] 2 + {2ξ (ω/ω n ) 2 } A. 0 B. 1 C. less than 1 D. greater than 1

Last Answer : B. 1

n vibration isolation system, if ω/ω n is less than √2 , then for all values of the damping factor, the transmissibility will be a) less than unity b) equal to unity c) greater than unity d) zero

Description : n vibration isolation system, if ω/ω n is less than √2 , then for all values of the damping factor, the transmissibility will be a) less than unity b) equal to unity c) greater than unity d) zero

Last Answer : c) greater than unity

In vibration isolation system, the transmissibility will be equal to unity, for all values of damping factor, if ω/ωn is A. Equal to 1 B. Equal to √2 C. Less than √2 D. Greater than √2

Description : In vibration isolation system, the transmissibility will be equal to unity, for all values of damping factor, if ω/ωn is A. Equal to 1 B. Equal to √2 C. Less than √2 D. Greater than √2

Last Answer : B. Equal to √2

A shaft of length l carries two discs at its two ends. The lowest torsional frequency is ω n . If the shaft length is doubled, then the lowest torsional frequency becomes A ω n /2 B ω n /√2 C √2ω n D 2ω n

Description : A shaft of length l carries two discs at its two ends. The lowest torsional frequency is ω n . If the shaft length is doubled, then the lowest torsional frequency becomes A ω n /2 B ω n /√2 C √2ω n D 2ω n

Last Answer : B ω n /√2

The condition to be fulfilled in the design of spring for vibration isolation of a system where excitation is due to a rotating unbalance is A) ω << ωn B) ω = ωn C) ω > ωn D) ω >> ωn

Description : The condition to be fulfilled in the design of spring for vibration isolation of a system where excitation is due to a rotating unbalance is A) ω ωn D) ω >> ωn

Last Answer : A) ω

The natural frequency of a spring-mass system on earth is ω n . The natural frequency of this system on the moon (g moon = g earth /6) is a) ω n b) 0.408ω n c) 0.204ω n d) 0.167ω n

Description : The natural frequency of a spring-mass system on earth is ω n . The natural frequency of this system on the moon (g moon = g earth /6) is a) ω n b) 0.408ω n c) 0.204ω n d) 0.167ω n

Last Answer : a) ω n

The natural frequency of a spring-mass system on earth is ω n . The natural frequency of this system on the moon (g moon = g earth /6) is a) ω n b) 0.408ω n c) 0.204ω n d) 0.167ω n

Description : The natural frequency of a spring-mass system on earth is ω n . The natural frequency of this system on the moon (g moon = g earth /6) is a) ω n b) 0.408ω n c) 0.204ω n d) 0.167ω n

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In vibration isolation system, if ω/ω n > 1, then the phase difference between the transmitted force and the disturbing force is A. 0° B. 90° C. 180° D. 270°

Description : In vibration isolation system, if ω/ω n > 1, then the phase difference between the transmitted force and the disturbing force is A. 0° B. 90° C. 180° D. 270°

Last Answer : C. 180°

In vibration isolation system, if ω/ω n < 2, then for all values of damping factor, the transmissibility will be a) less than unity b) equal to unity c) greater than unity d) zero

Description : In vibration isolation system, if ω/ω n < 2, then for all values of damping factor, the transmissibility will be a) less than unity b) equal to unity c) greater than unity d) zero

Last Answer : c) greater than unity

In vibration isolation system, if ω/ω n , then the phase difference between the transmitted force and the disturbing force is a) 0° b) 90° c) 180° d) 270°

Description : In vibration isolation system, if ω/ω n , then the phase difference between the transmitted force and the disturbing force is a) 0° b) 90° c) 180° d) 270°

Last Answer : c) 180°

In vibration isolation system, if ω/ω n < 2, then for all values of damping factor, the transmissibility will be a) less than unity b) equal to unity c) greater than unity d) zero

Description : In vibration isolation system, if ω/ω n < 2, then for all values of damping factor, the transmissibility will be a) less than unity b) equal to unity c) greater than unity d) zero

Last Answer : c) greater than unity

In vibration isolation system, if ω/ω n , then the phase difference between the transmitted force and the disturbing force is a) 0° b) 90° c) 180° d) 270

Description : In vibration isolation system, if ω/ω n , then the phase difference between the transmitted force and the disturbing force is a) 0° b) 90° c) 180° d) 270

Last Answer : c) 180°

In vibration isolation system, if ω/ω n > 1, then the phase difference between the transmitted force and the disturbing force is a) 0° b) 90° c) 180° d) 270°

Description : In vibration isolation system, if ω/ω n > 1, then the phase difference between the transmitted force and the disturbing force is a) 0° b) 90° c) 180° d) 270°

Last Answer : c) 180°

Which of the following vibro-meters have frequency ratio (ω/ω n ) << 1? A. Accelerometers B. Velometers C. Both A. and B. D. None of the above

Description : Which of the following vibro-meters have frequency ratio (ω/ω n )

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A vibrating machine of 100 kg is mounted on a rubber pad which has stiffness of 500 N/m. Determine force transmitted to the foundation if the unbalanced force 500 N acts on it. The frequency ratio (ω/ω n ) is 1.5 and ξ = 0.5 A. 461.62 N B. 400.23 N C. 450 N D. Insufficient data

Description : A vibrating machine of 100 kg is mounted on a rubber pad which has stiffness of 500 N/m. Determine force transmitted to the foundation if the unbalanced force 500 N acts on it. The frequency ratio (ω/ω n ) is 1.5 and ξ = 0.5 A. 461.62 N B. 400.23 N C. 450 N D. Insufficient data

Last Answer : A. 461.62 N

The ratio of the force transmitted to the force applied is known as the ____________ of the spring support. A. isolation factor B. transmissibility ratio C. both A and B D. none of the above

Description : The ratio of the force transmitted to the force applied is known as the ____________ of the spring support. A. isolation factor B. transmissibility ratio C. both A and B D. none of the above

Last Answer : C. both A and B

The ratio of the force transmitted to the force applied is known as the ____________ of the spring support. (A) isolation factor (B) transmissibility ratio (C) both A and B (D) none of the above

Description : The ratio of the force transmitted to the force applied is known as the ____________ of the spring support. (A) isolation factor (B) transmissibility ratio (C) both A and B (D) none of the above

Last Answer : (C) both A and B

In vibration isolation system, if ω/ωn, then the phase difference between the transmitted force and the disturbing force is A 0° B 90° C 180° D 270°

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Last Answer : C 180°

In vibration isolation system, if ω/ωn < 2, then for all values of damping factor, the transmissibility will be A less than unity B equal to unity C greater than unity D zero

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Last Answer : C greater than unity

Calculate equivalent stiffness of the spring for the system shown below, which has spring stiffness of 3000 N/m a. 1000 N/m b. 2250 N/m c. 2000 N/m d. None of the above

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A shaft of diameter d carries two discs at its two ends. The lowest torsional frequency is ω n . If the diameter is doubled, then the lowest torsional frequency becomes A 4ω n B ω n /2 C ω n /4 D 4ω n

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The two resonant frequency ratio (ω/ ω2) in a dynamic vibration absorber system for a mass ratio 0.2 are given by A) 0 ; 1.0 B) 0.801 ; 1.248 C) 0.458 ; 1.124 D) 0.642 ; 1.558

Description : The two resonant frequency ratio (ω/ ω2) in a dynamic vibration absorber system for a mass ratio 0.2 are given by A) 0 ; 1.0 B) 0.801 ; 1.248 C) 0.458 ; 1.124 D) 0.642 ; 1.558

Last Answer : B) 0.801 ; 1.248

Calculate damping ratio if mass = 200Kg, ω = 20rad/s and damping coefficient = 800 N/m/s A. 0.03 B. 0.04 C. 0.05 D. 0.06

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Last Answer : A. 0.03

Calculate damping ratio from the following data: mass = 200Kg ω = 20rad/s damping coefficient = 1000 N/m/s a) 0.03 b) 0.04 c) 0.05 d) 0.06

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Last Answer : b) 0.04

Calculate damping ratio from the following data: mass = 200Kg ω = 20rad/s damping coefficient = 800 N/m/s a) 0.03 b) 0.04 c) 0.05 d) 0.06

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Determine the equivalent spring constant of the system shown in FigK1=10 N/m, K2=20 N/m. K3=30 N/m, K4=34 N/m, K5=40 N/m a) 10N/m b)20N/m c)30N/m d) None

Description : Determine the equivalent spring constant of the system shown in FigK1=10 N/m, K2=20 N/m. K3=30 N/m, K4=34 N/m, K5=40 N/m a) 10N/m b)20N/m c)30N/m d) None

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Calculate critical damping coefficient in N/m/s from the following data: mass = 100Kg ω = 40rad/s a) 25,132 b) 26,132 c) 27,132 d) 28,132

Description : Calculate critical damping coefficient in N/m/s from the following data: mass = 100Kg ω = 40rad/s a) 25,132 b) 26,132 c) 27,132 d) 28,132

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for the system shown below K1=20N/m K1=10N/m K1=20N/m K1=50N/mFind W such that the natural frequency of the system will be 1.592 cycles per second a)0.125kg b)0.25kg c)0.5kg 4)4kg

Description : for the system shown below K1=20N/m K1=10N/m K1=20N/m K1=50N/mFind W such that the natural frequency of the system will be 1.592 cycles per second a)0.125kg b)0.25kg c)0.5kg 4)4kg

Last Answer : b)0.25kg

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A 12.32 Hz B 4.10 Hz C 6.16 HzD None of the above

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A 12.32 Hz B 4.10 Hz C 6.16 HzD None of the above

Last Answer : C 6.16 Hz

A 1 kg mass is suspended by a spring having a stiffness of 0.4 N/mm. Determine the natural frequency. A 20 rad/sec B 30 rad/sec C 20 Hz D 30 Hz

Description : A 1 kg mass is suspended by a spring having a stiffness of 0.4 N/mm. Determine the natural frequency. A 20 rad/sec B 30 rad/sec C 20 Hz D 30 Hz

Last Answer : B 30 rad/sec

Determine natural frequency of a system, which has equivalent spring stiffness of 43200 N/m and mass of 12 kg. A 40.22 rad/sec B 40 Hz C 60 Hz D 60 rad/sec

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Last Answer : D 60 rad/sec

A weight of 50 N is suspended from a spring of stiffness 4000N/m and subjected to a harmonic force of magnitude 60N and frequency 60 Hz. what will be the static displacement of the spring due to maximum applied force A. 0.015m B. 0.15 m C. 15 m D. 150m

Description : A weight of 50 N is suspended from a spring of stiffness 4000N/m and subjected to a harmonic force of magnitude 60N and frequency 60 Hz. what will be the static displacement of the spring due to maximum applied force A. 0.015m B. 0.15 m C. 15 m D. 150m

Last Answer : B. 0.15 m

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A. 12.32 Hz B. 4.10 Hz C. 6.16 Hz D. None of the above

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A. 12.32 Hz B. 4.10 Hz C. 6.16 Hz D. None of the above

Last Answer : C. 6.16 Hz

Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 –3 m 3. Natural frequency of the system = 60 rad/sec A. 100.5 x 10 3 N-s/m B. 80 x 10 3 N-s/m C. 42 x 10 3 N-s/m D. None of the above

Description : Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 -3 m 3. Natural frequency of the system = 60 rad/sec ... /m B. 80 x 10 3 N-s/m C. 42 x 10 3 N-s/m D. None of the above

Last Answer : C. 42 x 10 3 N-s/m

Calculate damped natural frequency, if a spring mass damper system is subjected to periodic disturbing force of 30 N. Damping coefficient is equal to 0.76 times of critical damping coefficient and undamped natural frequency is 5 rad/sec A. 3.99 rad/sec B. 2.13 rad/sec C. 4.12 rad/sec D. 3.24 rad/sec

Description : Calculate damped natural frequency, if a spring mass damper system is subjected to periodic disturbing force of 30 N. Damping coefficient is equal to 0.76 times of critical damping coefficient and undamped natural frequency is 5 rad/sec A. 3.99 rad/sec B. 2.13 rad/sec C. 4.12 rad/sec D. 3.24 rad/sec

Last Answer : D. 3.24 rad/sec

A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. A. 5.14 Hz B. 9.14 Hz C. 11.14 Hz D. 28.14 Hz

Description : A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. A. 5.14 Hz B. 9.14 Hz C. 11.14 Hz D. 28.14 Hz

Last Answer : C. 11.14 Hz

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A) 12.32 Hz B) 4.10 Hz C) 6.16 Hz D) None of the above

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A) 12.32 Hz B) 4.10 Hz C) 6.16 Hz D) None of the above

Last Answer : C) 6.16 Hz

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? C ( A )12.32 Hz (B) 4.10 Hz ( C )6.16 Hz (D)None of the above

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? C ( A )12.32 Hz (B) 4.10 Hz ( C )6.16 Hz (D)None of the above

Last Answer : ( C )6.16 Hz

In spring mass experiment, the natural frequency of 10 kg mass was found to be 12 rad/sec. the stiffness of the spring is A. 800 N/m B. 1200 N/m C. 1440 N/m D. 2000 N/m

Description : In spring mass experiment, the natural frequency of 10 kg mass was found to be 12 rad/sec. the stiffness of the spring is A. 800 N/m B. 1200 N/m C. 1440 N/m D. 2000 N/m

Last Answer : C. 1440 N/m

A 10 Kg mass suspended by spring of stiffness 1000 N/m. the natural frequency of the system after giving excitation will be A. 0 Hz B. 1.59 Hz C. 2 Hz D. 15.9 Hz

Description : A 10 Kg mass suspended by spring of stiffness 1000 N/m. the natural frequency of the system after giving excitation will be A. 0 Hz B. 1.59 Hz C. 2 Hz D. 15.9 Hz

Last Answer : B. 1.59 Hz

A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... , are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz

Last Answer : a) 0.471 and 1.19 Hz

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m mass of 20 kg? a. 12.32 Hz b. 4.10 Hz c. 6.16 Hz d. None of the above

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m mass of 20 kg? a. 12.32 Hz b. 4.10 Hz c. 6.16 Hz d. None of the above

Last Answer : c. 6.16 Hz

Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 –3 m 3. Natural frequency of the system = 60 rad/sec a. 100.5 x 10 3 N-s/m b. 80 x 10 3 N-s/m c. 42 x 10 3 N-s/m d. None of the above

Description : Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 -3 m 3. Natural frequency of the system = 60 rad/sec ... /m b. 80 x 10 3 N-s/m c. 42 x 10 3 N-s/m d. None of the above

Last Answer : c. 42 x 10 3 N-s/m

A spring-mass system has a natural frequency of 10 rad/sec. When the spring constant is reduced by 800 N/m, the frequency is altered by 45 percent. Find the mass and spring constant of the original system. a)11.47kg and 1147.95N/m b)8.95kg and 895.25N/m c) 7.265kg and 726.5N/m d)None

Description : A spring-mass system has a natural frequency of 10 rad/sec. When the spring constant is reduced by 800 N/m, the frequency is altered by 45 percent. Find the mass and spring constant of the original system. a)11.47kg and 1147.95N/m b)8.95kg and 895.25N/m c) 7.265kg and 726.5N/m d)None

Last Answer : a)11.47kg and 1147.95N/m

A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. (A) 5.14 Hz (B) 9.14 Hz (C) 11.14 Hz (D) 28.14 Hz

Description : A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. (A) 5.14 Hz (B) 9.14 Hz (C) 11.14 Hz (D) 28.14 Hz

Last Answer : (C) 11.14 Hz

A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... .19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Last Answer : a) 0.471 and 1.19 Hz

A single degree of freedom spring-mass system is subjected to a harmonic force of constant amplitude. For an excitation frequency of √3k/m , the ratio of the amplitude of steady state response to the static deflection of the spring is __________ A. 0.2 B. 0.5 C. 0.8 D. None of the above

Description : A single degree of freedom spring-mass system is subjected to a harmonic force of constant amplitude. For an excitation frequency of √3k/m , the ratio of the amplitude of steady state response to the static deflection of the spring is __________ A. 0.2 B. 0.5 C. 0.8 D. None of the above

Last Answer : B. 0.5

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Description : Isolation factor is twice the transmissibility ratio. a) True b) False

Last Answer : b) False

According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the differential equation for damped free vibrations having single degree of freedom. What will be the solution to this differential equation if the system is critically damped? A x = (A + Bt) e – ωt B x = X e – ξωt (sin ω d t + Φ) C x = (A – Bt) e – ωt D x = X e – ξωt (cos ω d t + Φ)

Description : According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the differential equation for damped free vibrations having single degree of freedom. What will be the solution to this differential equation if the system is ... Φ) C x = (A - Bt) e - ωt D x = X e - ξωt (cos ω d t + Φ)

Last Answer : A x = (A + Bt) e – ωt

According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the differential equation for damped free vibrations having single degree of freedom. What will be the solution to this differential equation if the system is critically damped? A. x = (A + Bt) e – ωt B. x = X e – ξωt (sin ω d t + Φ) C. x = (A – Bt) e – ωt D. x = X e – ξωt (cos ω d t + Φ

Description : According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the differential equation for damped free vibrations having single degree of freedom. What will be the solution to this differential equation if the system is ... ) C. x = (A - Bt) e - ωt D. x = X e - ξωt (cos ω d t + Φ

Last Answer : A. x = (A + Bt) e – ωt