What equation represents a line which is parallel to the line x-4y=-8?

What equation represents a line which is parallel to the line x-4y=-8?
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what- shaneese is buying peanuts and cashews. she has $12 to spend. peanuts cost $3 per pound and cashews cost $4 per pound. if she buys x pounds of peanuts and y pounds of cashews, then the equation that represents the amount of each is 3x + 4y =12?

Description : what- shaneese is buying peanuts and cashews. she has $12 to spend. peanuts cost $3 per pound and cashews cost $4 per pound. if she buys x pounds of peanuts and y pounds of cashews, then the equation that represents the amount of each is 3x + 4y =12?

Last Answer : what is the x- intercept

what- Shaneese is buying peanuts and cashews. She has $12 to spend. Peanuts cost $3 per pound and cashews cost $4 per pound. If she buys x pounds of peanuts and y pounds of cashews, then the equation that represents the amount of each is 3x + 4y = 12.?

Description : what- Shaneese is buying peanuts and cashews. She has $12 to spend. Peanuts cost $3 per pound and cashews cost $4 per pound. If she buys x pounds of peanuts and y pounds of cashews, then the equation that represents the amount of each is 3x + 4y = 12.?

Last Answer : What is the x-intercept?

Which of the following pair of linear equations represent the two parallel tracks of the railway line? a) x-2y-4=0 and 2x + 4y - 12 = 0 c) 2x + 4y -12 = 0 and x +2y-4=0 b) x +2y-4=0 and 2x + 4y +12 = 0 d) 2x + 4y + 12 = 0 and x-2y-4=0

Description : Which of the following pair of linear equations represent the two parallel tracks of the railway line? a) x-2y-4=0 and 2x + 4y - 12 = 0 c) 2x + 4y -12 = 0 and x +2y-4=0 b) x +2y-4=0 and 2x + 4y +12 = 0 d) 2x + 4y + 12 = 0 and x-2y-4=0

Last Answer : c) 2x + 4y -12 = 0 and x +2y-4=0

What is the equation of the line joining the origin with the point of intersection of the lines 4x + 3y = 12 and 3x + 4y = 12 ? -Maths 9th

Description : What is the equation of the line joining the origin with the point of intersection of the lines 4x + 3y = 12 and 3x + 4y = 12 ? -Maths 9th

Last Answer : (b) (5, 6)Let the foot of the perpendicular be M(x1, y1) Slope of line AB, i.e., y = -x + 11 = -1 Slope of line PM = \(rac{y_1-3}{x_1-2}\)Now, PM ⊥ AB⇒ \(\bigg(rac{y_1-3}{x_1-2}\bigg)\) x - ... get 2x1 = 10 ⇒ x1 = 5 Putting x1 in (ii), we get y1 = 6. ∴ Required foot of the perpendicular M is (5, 6).

What equation represents a line that is parallel to the line y-4x plus 5?

Description : What equation represents a line that is parallel to the line y-4x plus 5?

Last Answer : Need answer

Express x in terms of y for the linear equation 23x +4y = -7. -Maths 9th

Description : Express x in terms of y for the linear equation 23x +4y = -7. -Maths 9th

Last Answer : Solution :-

Find the coordinate where the linear equation 3x -4y = 11 meets at x-axis. -Maths 9th

Description : Find the coordinate where the linear equation 3x -4y = 11 meets at x-axis. -Maths 9th

Last Answer : hope it helps

Draw the graph of the linear equation 3x + 4y = 6. At what points, does the graph cut the x-axis and the y-axis? -Maths 9th

Description : Draw the graph of the linear equation 3x + 4y = 6. At what points, does the graph cut the x-axis and the y-axis? -Maths 9th

Last Answer : hope it helps

If a + b = 1 ,and the ordered pair (a, b) satisfies the equation 2x + y = , then it also satisfies (a) 2x + y (b) 3x + 4y = 3 (c) x + 2y = (d) 2x + 4y =

Description : If a + b = 1 ,and the ordered pair (a, b) satisfies the equation 2x + y = , then it also satisfies (a) 2x + y (b) 3x + 4y = 3 (c) x + 2y = (d) 2x + 4y =

Last Answer : (c) x + 2y =

The pair of equation x = 4 and y = 3 graphically represents lines which are e) Parallel f) Intersecting at ( 3,4) g) Coincident h) Intersecting at ( 4,3)

Description : The pair of equation x = 4 and y = 3 graphically represents lines which are e) Parallel f) Intersecting at ( 3,4) g) Coincident h) Intersecting at ( 4,3)

Last Answer : h) Intersecting at ( 4,3)

The pair of equation x = 4 and y = 3 graphically represents lines which are a) Parallel b) Intersecting at ( 3,4) c) Coincident d) Intersecting at ( 4,3)

Description : The pair of equation x = 4 and y = 3 graphically represents lines which are a) Parallel b) Intersecting at ( 3,4) c) Coincident d) Intersecting at ( 4,3)

Last Answer : d) Intersecting at ( 4,3)

Are the lines parallel, perpendicular, or neither3x + 4y = 103y – 4x = 4?

Description : Are the lines parallel, perpendicular, or neither3x + 4y = 103y – 4x = 4?

Last Answer : perpendicular

Out of the following linear equations in two variables, the two representing a pair of parallel lines graphically are: 3x - 4y = 6 3x + 4y = 6 6x + 8y = 12 6x - 8y + 6 = 0 (a) 3x - 4y = 6 and 6x + 8y = 12 (b) 3x - 4y = 6 and 6x - 8y + 6 = 0 (c) 6x + 8y = 12 and 3x + 4y = 6 (d) 6x - 8y + 6 = 0 and 3x + 4y = 6

Description : Out of the following linear equations in two variables, the two representing a pair of parallel lines graphically are: 3x - 4y = 6 3x + 4y = 6 6x + 8y = 12 6x - 8y + 6 = 0 (a) 3x - 4y = 6 and 6x + 8y = 12 (b) 3x - 4y = 6 ... 6 = 0 (c) 6x + 8y = 12 and 3x + 4y = 6 (d) 6x - 8y + 6 = 0 and 3x + 4y = 6

Last Answer : (b) 3x - 4y = 6 and 6x - 8y + 6 = 0

rewrite the equation 4x + 4y = 20 in slope-intercept form. -General Knowledge

Description : rewrite the equation 4x + 4y = 20 in slope-intercept form. -General Knowledge

Last Answer : 4x + 4y = 20 written in slope-intercept form is y = -x + 5. 4x + 4y = 20 4y = -4x + 20 (4y = -4x + 20)/(4) y = -x + 5.

solve this equation: 4y + 228 = 352. -General Knowledge

Description : solve this equation: 4y + 228 = 352. -General Knowledge

Last Answer : 4y + 228 = 352 4y = 352 - 228 4y = 124 y = 124/4 y = 31

Draw the graph of the equation 3x + 4y = 12 and find the co-ordinates of the points of intersection of the equation with the co-ordinate axes. -Maths 9th

Description : Draw the graph of the equation 3x + 4y = 12 and find the co-ordinates of the points of intersection of the equation with the co-ordinate axes. -Maths 9th

Last Answer : Solution :-

Find the equation of normal at point (4, 3) for the hyperbola ` 3x^(2) - 4y^(2) = 14`.

Description : Find the equation of normal at point (4, 3) for the hyperbola ` 3x^(2) - 4y^(2) = 14`.

Last Answer : Find the equation of normal at point (4, 3) for the hyperbola ` 3x^(2) - 4y^(2) = 14`.

The line x – 4y = 6 is the perpendicular bisector of the segment AB and the co-ordinates of B are (1, 3). Find the co-ordinates of A. -Maths 9th

Description : The line x – 4y = 6 is the perpendicular bisector of the segment AB and the co-ordinates of B are (1, 3). Find the co-ordinates of A. -Maths 9th

Last Answer : Co-ordinates of A are \(\bigg(rac{3 imes9+1 imes5}{3+1},rac{3 imes6+1 imes-2}{3+1}\bigg)\) = \(\bigg(rac{32}{4},rac{16}{4}\bigg)\), i.e. (8, 4)Now, \(x\) - 3y + 4 = 0 ⇒ -3y = -\(x\) - 4 ⇒ y = \(rac{x}{3}+rac{4} ... 8) [Using, y - y1 = m (x - x1)]⇒ 3y - 12 = \(x\) - 8 ⇒ 3y - \(x\) = 4.

The normal at a point `P` on the ellipse `x^2+4y^2=16` meets the x-axis at `Qdot` If `M` is the midpoint of the line segment `P Q ,` then the locus of

Description : The normal at a point `P` on the ellipse `x^2+4y^2=16` meets the x-axis at `Qdot` If `M` is the midpoint of the line segment `P Q ,` then the locus of

Last Answer : The normal at a point `P` on the ellipse `x^2+4y^2=16` meets the x-axis at `Qdot` If `M` is ... (pm2sqrt3,pmsqrt1/7)` D. `(pm2sqrt3,pm(4sqrt(3))/4)`

What is the point of contact between the line y equals x plus 4 and the circle x2 plus y2 -8x plus 4y equals 30?

Description : What is the point of contact between the line y equals x plus 4 and the circle x2 plus y2 -8x plus 4y equals 30?

Last Answer : Equations: y = x+4 and x^2 +y^2 -8x +4y = 30It appears that the given line is a tangent line to the givencircle and the point of contact works out as (-1, 3)

What are the points of contact when the line x -y equals 2 crosses the curve x squared -4y squared equals 5 showing work?

Description : What are the points of contact when the line x -y equals 2 crosses the curve x squared -4y squared equals 5 showing work?

Last Answer : If: x -y = 2 then x^2 = (2+y)^2 => 4+4y+y^2If: x^2 -4y^2 = 5 then x^2 = 5+4y^2So: 5+4y^2 = 4+4y+y^2Transposing terms: 3y^2 -4y +1 = 0Factorizing the above: (3y-1)(y-1) = 0 meaning y = 1/3 or y =1By substitution contacts are made at: (7/3, 1/3) and (3, 1)

What are the points of contact between the line x -2y equals 1 and the curve 4y squared -3x squared equals 1?

Description : What are the points of contact between the line x -2y equals 1 and the curve 4y squared -3x squared equals 1?

Last Answer : If: x-2y = 1 Then: x^2 = 4y^2 +4y+1 If: 4y^2 -3x^2 = 1 Then: 4y^2 -3(4y^2 +4y+1) = 1 Removing brackets: 4y^2 -12y^2 -12y -3 = 1 Transposing terms: -8y^2 -12y -4 = 0 Dividing all ... meaning y = -1/2 or -1 By substitution into original linear equation points of contact are at: (0, -1/2) and (-1, -1)

The ratio in which the line 3x + 4y = 7 divides the line joining the points (–2, 1) and (1, 2) is -Maths 9th

Description : The ratio in which the line 3x + 4y = 7 divides the line joining the points (–2, 1) and (1, 2) is -Maths 9th

Last Answer : (a) (–24, –2)Co-ordinates of the point of external division are\(\bigg(rac{m_1\,x_2-m_2\,x_1}{m_1-m_2},rac{m_1y_2-m_2y_1}{m_1-m_2}\bigg)\), i.e.,∴ Required point = \(\bigg(rac{3 imes-6-2 imes4}{3-2},rac{3 imes2-2 imes4}{3-2}\bigg)\)= \(\big(rac{-24}{1},rac{-2}{1}\big)\), i.e., (–24, –2).

Find the solution of the linear equation x+2y = 8 which represents a point on -Maths 9th

Description : Find the solution of the linear equation x+2y = 8 which represents a point on -Maths 9th

Last Answer : We have, x + 2y = 8 ,..(i) (i) When the point is on the X-axis, then put y = 0 in Eq. (i), we get x+2 (0)=8 ⇒ x = 8 Hence, the required point is (8, 0). (ii) When the point is on the Y-axis, then put x = 0 in Eq. (i), we get 0 + 2y = 8 ⇒ y = 8/2 = 4 Hence, the required point is (0, 4).

Find the solution of the linear equation x+2y = 8 which represents a point on -Maths 9th

Description : Find the solution of the linear equation x+2y = 8 which represents a point on -Maths 9th

Last Answer : We have, x + 2y = 8 ,..(i) (i) When the point is on the X-axis, then put y = 0 in Eq. (i), we get x+2 (0)=8 ⇒ x = 8 Hence, the required point is (8, 0). (ii) When the point is on the Y-axis, then put x = 0 in Eq. (i), we get 0 + 2y = 8 ⇒ y = 8/2 = 4 Hence, the required point is (0, 4).

What is 8=4x+4y?

Description : What is 8=4x+4y?

Last Answer : Equation

What is an equivalent expression to 8 plus 7y plus 2x plus 4y plus 4?

Description : What is an equivalent expression to 8 plus 7y plus 2x plus 4y plus 4?

Last Answer : Feel Free to Answer

For what value of k , the following system of equations have infinite solutions : kx + 4y = k-4, 16x + ky = k (a) k = 2 (b) k = 4 (c) k = 6 (d) k = 8

Description : For what value of k , the following system of equations have infinite solutions : kx + 4y = k-4, 16x + ky = k (a) k = 2 (b) k = 4 (c) k = 6 (d) k = 8

Last Answer : (d) k = 8

For what value of k , the following system of equations have infinite solutions : kx + 4y = k-4, 16x + ky = k (a) k = 2 (b) k = 4 (c) k = 6 (d) k = 8

Description : For what value of k , the following system of equations have infinite solutions : kx + 4y = k-4, 16x + ky = k (a) k = 2 (b) k = 4 (c) k = 6 (d) k = 8

Last Answer : (d) k = 8

A simply supported beam is of rectangular section.It carries a uniformly distributed load over the whole span.The deflection at the centre is y.If the depth of beam is doubled ,the deflection at the centre would be a.2y b.4y c.y/2 d.y/8.

Description : A simply supported beam is of rectangular section.It carries a uniformly distributed load over the whole span.The deflection at the centre is y.If the depth of beam is doubled ,the deflection at the centre would be a.2y b.4y c.y/2 d.y/8.

Last Answer : d.y/8.

How do you solve (x-y-1)dx + (4y+x-1)dy = 0?

Description : How do you solve (x-y-1)dx + (4y+x-1)dy = 0?

Last Answer : https://www.geteasysolution.com/ entered that equation and it states that it maust be entered in another way? Link above.

The ellipse `x^2+""4y^2=""4` is inscribed in a rectangle aligned with the coordinate axes, which in turn is inscribed in another ellipse that passes t

Description : The ellipse `x^2+""4y^2=""4` is inscribed in a rectangle aligned with the coordinate axes, which in turn is inscribed in another ellipse that passes t

Last Answer : The ellipse `x^2+""4y^2=""4` is inscribed in a rectangle aligned with the coordinate axes, which in turn is ... 4x^2+48y^2=48` D. `4x^2+64y^2=48`

30. Radical centre of circles drawn on the sides as a diameter of triangle formed by the lines the `3x-4y+6=0`, `x-y+2=0` and `4x+3y-17=0` is

Description : 30. Radical centre of circles drawn on the sides as a diameter of triangle formed by the lines the `3x-4y+6=0`, `x-y+2=0` and `4x+3y-17=0` is

Last Answer : 30. Radical centre of circles drawn on the sides as a diameter of triangle formed by the lines the `3x-4y+6=0`, `x-y+ ... . (-2,3) C. (-2,-3) D. (2,3)

Let x,y,z be real numbers such that 3x, 4y and 5z from a geometric progression while x,y,z form an H.P. If the value of `((x)/(z) +(z)/(x))` can be ex

Description : Let x,y,z be real numbers such that 3x, 4y and 5z from a geometric progression while x,y,z form an H.P. If the value of `((x)/(z) +(z)/(x))` can be ex

Last Answer : Let x,y,z be real numbers such that 3x, 4y and 5z from a geometric progression while x,y,z form an H.P. If ... value equal to A. 29 B. 39 C. 49 D. 59

if x:y=5:7 then find `(3x+4y):(x+2y)` .

Description : if x:y=5:7 then find `(3x+4y):(x+2y)` .

Last Answer : if x:y=5:7 then find `(3x+4y):(x+2y)` .

A pair of linear equations which has a unique solution x = 2, y = -3 is (a) x + y = -1 ; 2x – 3y = -5 (b) 2x + 5y = -11 ; 4x + 10y = -22(c) 2x – y = 1 ; 3x + 2y = 0 (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Description : A pair of linear equations which has a unique solution x = 2, y = -3 is (a) x + y = -1 ; 2x – 3y = -5 (b) 2x + 5y = -11 ; 4x + 10y = -22(c) 2x – y = 1 ; 3x + 2y = 0 (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Last Answer : (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

If x:y =3:4,in the ratio of (7x-4y) : ( 3x + y) a) 2:11 b) 4:9 c) 5:13 d) 6:5 e) 13:5

Description : If x:y =3:4,in the ratio of (7x-4y) : ( 3x + y) a) 2:11 b) 4:9 c) 5:13 d) 6:5 e) 13:5

Last Answer : An easy way to solve this question is use x = 3, y=4 7x – 4y = 21 – 16 = 5 3x + y = 9+4 = 13 Required ratio = 5:13 Answer: c)

Draw the graph of the equation represented by a straight Line which is parallel to the X-axis and at a distance 3 units below it. -Maths 9th

Description : Draw the graph of the equation represented by a straight Line which is parallel to the X-axis and at a distance 3 units below it. -Maths 9th

Last Answer : Any straight line parallel to X-axis in negative direction of Y-axis is given by y = - k, where k is the distance of the line from the X-axis. Here, k = 3. Therefore, the equation of the line is y = -3. To ... , plot the points (1,-3), (2, -3) and (3, -3) and join them. This is the required graph.

Draw the graph of the equation represented by a straight Line which is parallel to the X-axis and at a distance 3 units below it. -Maths 9th

Description : Draw the graph of the equation represented by a straight Line which is parallel to the X-axis and at a distance 3 units below it. -Maths 9th

Last Answer : Any straight line parallel to X-axis in negative direction of Y-axis is given by y = - k, where k is the distance of the line from the X-axis. Here, k = 3. Therefore, the equation of the line is y = -3. To ... , plot the points (1,-3), (2, -3) and (3, -3) and join them. This is the required graph.

Write the equation of a line parallel to x-axis and passing through the point (–3, –4). -Maths 9th

Description : Write the equation of a line parallel to x-axis and passing through the point (–3, –4). -Maths 9th

Last Answer : Solution :- y = -4

Write the equation of the line parallel to the x-axis at distance 3 units above x-axis. -Maths 9th

Description : Write the equation of the line parallel to the x-axis at distance 3 units above x-axis. -Maths 9th

Last Answer : Solution :-

Draw the graph of the equation represented by the straight line which is parallel to the x-axis and 3 units above it. -Maths 9th

Description : Draw the graph of the equation represented by the straight line which is parallel to the x-axis and 3 units above it. -Maths 9th

Last Answer : Solution :- Any straight line parallel to x-axis is given by y = a, where a is the distance of the line from the x-axis. Here a = 3. Therefore the equation of the line is y = 3. To draw the graph of this equation plot the points (0, 3) and (3, 3) and join them.

Write the equation of line parallel to x- axis. -Maths 9th

Description : Write the equation of line parallel to x- axis. -Maths 9th

Last Answer : answer:

The line L is given by x/5 + y/b = 1 passes through the point (13, 32). The line K is parallel to L and has the equation -Maths 9th

Description : The line L is given by x/5 + y/b = 1 passes through the point (13, 32). The line K is parallel to L and has the equation -Maths 9th

Last Answer : (a) 45º The equations of the given lines are: A\(x\) + By = A + B ⇒ By = -A\(x\) + (A + B) ⇒ y = \(-rac{A}{B}x\) + \(rac{(A+B)}{B}\) ....(i)and A(\(x\) - y) + B(\(x\) ... (ii) = m2 = \(rac{(A+B)}{B-A}\)Let θ be the angle between both the lines, then∴ tan θ = 1 ⇒ θ = tan-1 (1) = 45°.

what- shaneese is buying peanuts and cashews. she has $12 to spend. peanuts cost $3 per pound and cashews cost $4 per pound. she buys X pounds of peanuts and Y pounds of cashews. Which equation represents the amount of the mix?

Description : what- shaneese is buying peanuts and cashews. she has $12 to spend. peanuts cost $3 per pound and cashews cost $4 per pound. she buys X pounds of peanuts and Y pounds of cashews. Which equation represents the amount of the mix?

Last Answer : 3x + 4y = 12

Find the following products: (i) (3x + 2y + 2z) (9x2 + 4y2 + 4z2 – 6xy – 4yz – 6zx) (ii) (4x -3y + 2z) (16x2 + 9y2+ 4z2 + 12xy + 6yz – 8zx) (iii) (2a – 3b – 2c) (4a2 + 9b2 + 4c2 + 6ab – 6bc + 4ca) (iv) (3x -4y + 5z) (9x2 + 16y2 + 25z2 + 12xy- 15zx + 20yz) -Maths 9th

Description : Find the following products: (i) (3x + 2y + 2z) (9x2 + 4y2 + 4z2 – 6xy – 4yz – 6zx) (ii) (4x -3y + 2z) (16x2 + 9y2+ 4z2 + 12xy + 6yz – 8zx) (iii) (2a – 3b – 2c) (4a2 + 9b2 + 4c2 + 6ab – 6bc + 4ca) (iv) (3x -4y + 5z) (9x2 + 16y2 + 25z2 + 12xy- 15zx + 20yz) -Maths 9th

Last Answer : answer:

please solve these for me3x+4y?

Description : please solve these for me3x+4y?

Last Answer : daïras

Who 4y times 3x?

Description : Who 4y times 3x?

Last Answer : Ggsbsnsjdnd

Solve for `y : (4y)/(3) -5 lt 10`

Description : Solve for `y : (4y)/(3) -5 lt 10`

Last Answer : Solve for `y : (4y)/(3) -5 lt 10` A. `y lt 27//24` B. `t lt 33//4` C. `y lt 45//4` D. `y lt 59//4`

4y +y?

Description : 4y +y?

Last Answer : 5y