The line L is given by x/5 + y/b = 1 passes through the point (13, 32). The line K is parallel to L and has the equation -Maths 9th

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Answer :

(a) 45º The equations of the given lines are: A\(x\) + By = A + B ⇒ By = –A\(x\) + (A + B) ⇒ y = \(-rac{A}{B}x\) + \(rac{(A+B)}{B}\)                 ....(i)and A(\(x\) – y) + B(\(x\) + y) = 2B ⇒ (A + B)\(x\) + (B – A) y = 2B⇒ y = \(rac{-(A+B)}{(B-A)}x\) + \(rac{2B}{(B-A)}\)            ....(ii)∴ Slope of line (i) = m1 = \(-rac{A}{B}\)Slope of line (ii) = m2 = \(rac{(A+B)}{B-A}\)Let θ be the angle between both the lines, then∴ tan θ = 1 ⇒ θ = tan–1 (1) = 45°.

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