Description : The locus of the moment of inertia about inclined axes to the principal axis, is (A) Straight line (B) Parabola (C) Circle (D) Ellipse
Last Answer : (D) Ellipse
Description : The locus of the end point of the resultant of the normal and tangential components of the stress on an inclined plane, is (A) Circle (B) Parabola (C) Ellipse (D) Straight line
Last Answer : (C) Ellipse
Description : Find the coordinate where the linear equation 3x -4y = 11 meets at x-axis. -Maths 9th
Last Answer : hope it helps
Description : Which of the following is the locus of a point that moves in such a manner that its distance from a fixed point is equal to its distance from a fixed line multiplied by a constant greater than one (A) Ellipse (B) Hyperbola (C) Parabola (D) Circle
Last Answer : (B) Hyperbola
Description : If a length of a line segment is 6 and another line segment is 8 how long is the major axis of the ellipse?
Last Answer : The answer will depend on what, if anything, the line segmentshave to do with the ellipse.
Description : The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q, then parallelogram PBQR is completed (see figure). -Maths 9th
Last Answer : Join AC and QP, also it is given that AQ || CP ∴ △ACQ and △APQ are on the same base AQ and lie between the same parallels AQ || CP. ∴ ar(△ACQ) = ar(△APQ) or ar(△ABC) + ar(△ABQ) = ar(△BPQ) + ar(△ABQ) or ar(△ABC) = ar( △BPQ) or 1/2 ar(||gm ABCD) = 1/2 ar(||gm PBQR) or ar(||gm ABCD) = ar(||gm PBQR)
Description : The endpoint A of a line segment AB is (3 , -1). If midpoint of AB is (5,7) then the coordinates of the point B are: (a) (7,13) (b) (7,15) (c) (4,3) (d) (4,4)
Last Answer : (b) (7,15)
Description : The ellipse `x^2+""4y^2=""4` is inscribed in a rectangle aligned with the coordinate axes, which in turn is inscribed in another ellipse that passes t
Last Answer : The ellipse `x^2+""4y^2=""4` is inscribed in a rectangle aligned with the coordinate axes, which in turn is ... 4x^2+48y^2=48` D. `4x^2+64y^2=48`
Description : P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th
Last Answer : (i) In △ARB,P is the mid point of AB and PD || BR. ∴ D is a mid - point of AR [converse of mid - point theorem] ∴ AR = 2AD But BC = AD [opp sides of ||gm ABCD] Thus, AR = 2BC (ii) ∴ ABCD is a ... a mid - point of AR and DQ || AB ∴ Q is a mid point of BR [converse of mid - point theorem] ⇒ BR = 2BQ
Description : In trapezium ABCD, AB || DC and L is the mid-point of BC. Through L, a line PQ || AD has been drawn which meets AB in P and DC produced in Q. -Maths 9th
Last Answer : According to question prove that ar (ABCD) = ar (APQD).
Description : Find the equation of normal to the curve `y(x-2)(x-3)-x+7=0` at that point at which the curve meets X-axis.
Last Answer : Find the equation of normal to the curve `y(x-2)(x-3)-x+7=0` at that point at which the curve meets X-axis.
Description : A line segment has an endpoint at (3, 2). If the midpoint of the line segment is (6, -2), what are the coordinates of the point at the other end of the line segment?
Last Answer : (9,4)
Description : The line x – 4y = 6 is the perpendicular bisector of the segment AB and the co-ordinates of B are (1, 3). Find the co-ordinates of A. -Maths 9th
Last Answer : Co-ordinates of A are \(\bigg(rac{3 imes9+1 imes5}{3+1},rac{3 imes6+1 imes-2}{3+1}\bigg)\) = \(\bigg(rac{32}{4},rac{16}{4}\bigg)\), i.e. (8, 4)Now, \(x\) - 3y + 4 = 0 ⇒ -3y = -\(x\) - 4 ⇒ y = \(rac{x}{3}+rac{4} ... 8) [Using, y - y1 = m (x - x1)]⇒ 3y - 12 = \(x\) - 8 ⇒ 3y - \(x\) = 4.
Description : The graph of the linear equation 2x+ 3y = 6 is a line which meets the X-axis at the point. -Maths 9th
Last Answer : (c) Since, the graph of linear equation 2x + 3y = 6 meets the X-axis. So, we put y = 0 in 2x + 3y = 6 ⇒ 2x + 3(0) = 6 = 2x + 0 = 6 ⇒ x = 6/2 ⇒ x = 3 Hence, the coordinate on X-axis is (3, 0).
Description : What is the distance from a point on the x axis to the centre of a circle when a tangent line at the point 3 4 meets the circle of x2 plus y2 -2x -6y plus 5 equals 0?
Last Answer : Circle equation: x^2 +y^2 -2x -6y +5 = 0Completing the squares: (x-1)^2 +(y-3)^2 = 5Centre of circle: (1, 3)Tangent line meets the x-axis at: (0, 5)Distance from (0, 5) to (1, 3) = 5 units using the distanceformula
Description : How could you find the y-coordinate of the midpoint of a vertical line segment with endpoint at (00) and (015)?
Last Answer : If you mean endpoints of (0, 0) and (0, 15) then the midpoint isat (0, 7.5)
Description : How do I find the midpoint of the line segment joining the points (-1,3) and (-9,8)?
Last Answer : 85
Description : What’s s the midpoint of the line segment with endpoints (-5.5, -6.1) and (-0.5, 9.1)?
Last Answer : M = (-5.5+-0.5, -6.1+9.1) = -6.0, 3.0
Description : The midpoint of the line segment joining the points B and D is: (a) (10,11) (b) (11,5) (c) (7/2,11/2) (d) (5,11/2)
Last Answer : (c) (7/2,11/2)
Description : Two congruent circles intersect each other at point A and B.Through A any line segment PAQ is drawn so that P,Q lie on the two circles.Prove that BP = BQ. -Maths 9th
Last Answer : Solution :- Let, O and O' be the centres of two congruent circles. As, AB is the common chord of these circles. ∴ ACB = ADB As congruent arcs subtent equal angles at the centre. ∠AOB = ∠AO'B ⇒ 1/2∠AOB = 1/2∠AO'B ⇒ ∠BPA = ∠BQA ⇒ BP = BQ (Sides opposite to equal angles)
Description : The line segment joining P(5, –2) and Q(9, 6) is divided in the ratio 3 : 1 by a point A -Maths 9th
Last Answer : Comparing y = 5\(x\) –7 with y = m\(x\) + c, the slope of given line = m = 5 ∴ Equation of a line parallel to y = 5\(x\) – 7 having y-intercept = –1 is y = 5\(x\) – 1.
Description : What methods could you use to calculate the x-coordinate of the midpoint of a horizontal segment with the endpoints of (-60) and (60)?
Last Answer : If you mean endpoints of (-6, 0) and (6, 0) then the midpoint isat the origin of (0, 0)
Description : How to find the crossing point of root locus in imaginary axis.
Last Answer : Method (i) by Routh Hurwitz criterion Method (ii) by letting s=jw in the characteristics equation.
Description : In root locus plot, a point on the real axis lies on the locus, if the number of open loop poles plus zeros on real axis to the a) left of the point is odd b) left of the point is even . c) right of the pointis odd d) right of the point is even
Last Answer : In root locus plot, a point on the real axis lies on the locus, if the number of open loop poles plus zeros on real axis to the right of the pointis odd
Description : In figure, ABCDE is any pentagon. BP drawn parallel to AC meets DC produced at P and EQ drawn parallel to AD meets CD produced at Q. -Maths 9th
Last Answer : Given ABCDE is a pentagon. BP || AC and EQ|| AD. To prove ar (ABCDE) = ar (APQ) Proof We know that, triangles on the same base and between the same parallels are equal in area. Here, ΔADQ and ΔADE lie on the ... ar (ΔACD) = ar (ΔADE) + ar (ΔACB) + ar (ΔACD) ⇒ ar (ΔAPQ) = ar (ABCDE) Hence proved.
Description : In Fig. 9.30, ABCDE is any pentagon. BP drawn parallel to AC meets DC produced at P and EQ drawn parallel to AD meets CD produced at Q. Prove that ar (ABCDE) = ar(APQ). -Maths 9th
Last Answer : hope its clearhope its clear
Description : For two charges 3C and -3C separated by 1cm and are located at distances 5cm and 7cm respectively from the point P, then the distance between their midpoint and the point P will be a) 5.91 b) 12.6 c) 2 d) 9
Last Answer : a) 5.91
Description : Draw the graph of the linear equation 3x + 4y = 6. At what points, does the graph cut the x-axis and the y-axis? -Maths 9th
Description : How would you calculate the midpoint of the horizontal segment with endpoints at (0 0) and (20 0)?
Last Answer : Points: (0, 0) and (20, 0)Midpoint: (10, 0)
Description : What is the midpoint of the segment -1 5 and -6 -2?
Last Answer : Points: (-1, 5) and (-6, -2)Midpoint: (-3.5, 1.5)
Description : What is Trapezoid is the segment that connects the midpoint of the legs of the trapezoid?
Last Answer : It is called the median.
Description : True or False The intersection of the segment and its bisector is the segment's midpoint.?
Last Answer : TRUE
Description : Points P, Q, R and S divide a line segment joining A (2, 6) and B (7, -4) in five equal parts. Find the coordinates of P and R. -Maths 9th
Last Answer : this is the ans hope its clear
Description : What is the perpendicular bisector equation of a line segment with endpoints of p q and 7p 3q?
Last Answer : A line with slope m has a perpendicular with slope m' such that:mm' = -1→ m' = -1/mThe line segment with endpoints (p, q) and (7p, 3q) has slope:slope = change in y / change in x→ m = (3q - q)/(7p - p) = ... - 4p)→ y = -3px/q + 12p² + 2q→ qy = 12p²q + 2q² - 3pxAnother Answer: qy =-3px +12p^2 +2q^2
Description : For a fixed beam with midpoint load point moment for x
Last Answer : b. P/8(4x-L)
Description : The tangent at any point P of a curve C meeta the x-axis at Q whose abscissa is positive and OP = OQ where O is origin, if C is a family of parabola h
Last Answer : The tangent at any point P of a curve C meeta the x-axis at Q whose abscissa is positive and OP = OQ ... , then find value of `(4(alpha+beta))/a` ?
Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th
Last Answer : (d) We know that, a point lies on X-axis, if its y-coordinate is zero. So, on plotting the given points on graph paper, we get Q and O lie on the X-axis.
Description : In a 2280 m race Dinesh beats Aarav by 360 m or 6 seconds. In another race on the same track at the same speeds. Aarav and karthick start at one end while Dinesh starts at the opposite end. How many metres would Aarav ... is 16 m/sec more than that of karthick a) 1140 m b) 2280 m c) 2460 m d) 1180 m
Last Answer : B Aarav 's speed =360/6 =60 m/s Time taken by Aarav to cover 2280 m =2280/60= 38 seconds Dinesh 's speed = 2280/60=38 m/s karthick 's speed = 22m/s Time taken by Dinesh to meet karthick in ... direction: Distance covered by Aarav: =2280/(38+22) =2280/60 =38 seconds =(38*60)m =2280 m
Description : An ellipse and a hyperbola have the same centre as origin, the same foci and the minor-axis of the one is the same as the conhugate axis of the other
Last Answer : An ellipse and a hyperbola have the same centre as origin, the same foci and the minor-axis of the one is the same ... 2)` equals A. 1 B. 2 C. 3 D. 4
Description : What is the equation for an ellipse with a center at the origin and one focus st(1,1)and the length of the semimajor axis is 4.?
Last Answer : Use the standard form (x−h)2a2+(y−k)2b2=1 ( x − h ) 2 a 2 + ( y − k ) 2 b 2 = 1 . If the x-coordinates of the given vertices and foci are the same, then the major axis is parallel to the y-axis. Use the standard form (x−h)2b2+(y−k)2a2=1 ( x − h ) 2 b 2 + ( y − k ) 2 a 2 = 1 .
Description : The Lissajous pattern on the screen of a CRO is an ellipse with major axis in quadrant 2 and quadrant 4. Then the phase difference between two signals Can be : (A) 270° (B) 210° (C) 180° (D) 300°
Last Answer : The Lissajous pattern on the screen of a CRO is an ellipse with major axis in quadrant 2 and quadrant 4. Then the phase difference between two signals Can be : 210°
Description : What is the point of contact between the line y equals x plus 4 and the circle x2 plus y2 -8x plus 4y equals 30?
Last Answer : Equations: y = x+4 and x^2 +y^2 -8x +4y = 30It appears that the given line is a tangent line to the givencircle and the point of contact works out as (-1, 3)