4x + 5y?

Question

4x + 5y?

asked Jan 11, 2022 by anonymous

1 Answer

Answer :

9

answered Jan 11, 2022 by anonymous
selected Jan 11, 2022 by anonymous

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Find the following products: (i) (3x + 2y) (9X2 – 6xy + Ay2) (ii) (4x – 5y) (16x2 + 20xy + 25y2) (iii) (7p4 + q) (49p8 – 7p4q + q2) -Maths 9th

Description : Find the following products: (i) (3x + 2y) (9X2 – 6xy + Ay2) (ii) (4x – 5y) (16x2 + 20xy + 25y2) (iii) (7p4 + q) (49p8 – 7p4q + q2) -Maths 9th

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A pair of linear equations which has a unique solution x = 2, y = -3 is (a) x + y = -1 ; 2x – 3y = -5 (b) 2x + 5y = -11 ; 4x + 10y = -22(c) 2x – y = 1 ; 3x + 2y = 0 (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Description : A pair of linear equations which has a unique solution x = 2, y = -3 is (a) x + y = -1 ; 2x – 3y = -5 (b) 2x + 5y = -11 ; 4x + 10y = -22(c) 2x – y = 1 ; 3x + 2y = 0 (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Last Answer : (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

How can I factor out a problem like this 5y(x-3)+(3-x)?

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Last Answer : answer:To be precise, the factoring in your first example is not (x-3) (5y+1 x), it's (x-3) ( 5y+1). Maybe that was just a typo on your part (but it's the kind of typo that can ... accordingly. But I only said that because of the error that you gave in your example. It may not apply at all.

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Description : 6x^+17xy+5y^ -Maths 9th

Last Answer : what we have to do to this question??? we have to factorise or do something else?

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Description : Simplify (2x- 5y)3 – (2x+ 5y)3. -Maths 9th

Last Answer : (2x -5y)3 - (2x + 5y)3 = [(2x)3 - (5y)3 - 3(2x)(5y)(2x - 5y)] -[(2x)3 + (5y)3 + 3(2x)(5y)(2x+5y)] [using identity, (a - b)3 = a3 -b3 - 3ab and (a + b)3 =a3 +b3 + 3ab] = (2x)3 - (5y)3 - ... 2x)3- (5y)3 - 30xy (2x + 5y) = -2 (5y)3 - 30xy(2x - 5y + 2x + 5y) = -2 x 125y3 - 30xy(4x) = -250y3 -120x2y

The linear equation 2x – 5y = 7 has -Maths 9th

Description : The linear equation 2x – 5y = 7 has -Maths 9th

Last Answer : (c) In the given equation 2x – 5y = 7, for every value of x, we get a corresponding value of y and vice-versa. Therefore, the linear equation has infinitely many solutions.

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Description : The equation 2x+ 5y = 7 has a unique solution, if x and y are -Maths 9th

Last Answer : (a) In natural numbers, there is only one pair i.e., (1, 1) which satisfy the given equation but in positive real numbers, real numbers and rational numbers there are many pairs to satisfy the given linear equation.

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Description : 6x^+17xy+5y^ -Maths 9th

Last Answer : what we have to do to this question??? we have to factorise or do something else?

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Description : Simplify (2x- 5y)3 – (2x+ 5y)3. -Maths 9th

Last Answer : (2x -5y)3 - (2x + 5y)3 = [(2x)3 - (5y)3 - 3(2x)(5y)(2x - 5y)] -[(2x)3 + (5y)3 + 3(2x)(5y)(2x+5y)] [using identity, (a - b)3 = a3 -b3 - 3ab and (a + b)3 =a3 +b3 + 3ab] = (2x)3 - (5y)3 - ... 2x)3- (5y)3 - 30xy (2x + 5y) = -2 (5y)3 - 30xy(2x - 5y + 2x + 5y) = -2 x 125y3 - 30xy(4x) = -250y3 -120x2y

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Last Answer : (c) In the given equation 2x – 5y = 7, for every value of x, we get a corresponding value of y and vice-versa. Therefore, the linear equation has infinitely many solutions.

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Last Answer : (a) In natural numbers, there is only one pair i.e., (1, 1) which satisfy the given equation but in positive real numbers, real numbers and rational numbers there are many pairs to satisfy the given linear equation.

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