Consider the following schemas:
Branch = (Branch-name, Assets, Branch-city)
Customer = (Customer-name, Bank-name, Customer-city)
Borrow = (Branch-name, loan-number, customer account-number)
Deposit = (Branch-name, Account-number, Customer-name, Balance)
Using relational Algebra, the query that finds customers who have balance more than 10,000 is .................
(A) πcustomer-name(σbalance> 10000(Deposit))
(B) σcustomer-name(σbalance> 10000(Deposit))
(C) πcustomer-name(σbalance> 10000(Borrow))
(D) σcustomer-name(σbalance> 10000(Borrow))
Branch = (Branch-name, Assets, Branch-city)
Customer = (Customer-name, Bank-name, Customer-city)
Borrow = (Branch-name, loan-number, customer account-number)
Deposit = (Branch-name, Account-number, Customer-name, Balance)
Using relational Algebra, the query that finds customers who have balance more than 10,000 is .................
(A) πcustomer-name(σbalance> 10000(Deposit))
(B) σcustomer-name(σbalance> 10000(Deposit))
(C) πcustomer-name(σbalance> 10000(Borrow))
(D) σcustomer-name(σbalance> 10000(Borrow))