What Is The Radius If The Circle Passes Through The Point (-5-9)?

What Is The Radius If The Circle Passes Through The Point (-5-9)?
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What equation represents the circle whose center is (-5,3) and that passes through the point (-1,3)?

Description : What equation represents the circle whose center is (-5,3) and that passes through the point (-1,3)?

Last Answer : -40

A circle is represented by center point [5,5] and radius 6 units. Find the parametricequation of circle and determine the various points on circle in first quadrant if increment in angle by 45o a.9.24,9.24 b.9.42,9.42 c.9,9 d.11,5

Description : A circle is represented by center point [5,5] and radius 6 units. Find the parametricequation of circle and determine the various points on circle in first quadrant if increment in angle by 45o a.9.24,9.24 b.9.42,9.42 c.9,9 d.11,5

Last Answer : a.9.24,9.24

Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th

Description : Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th

Last Answer : STEP1: Draw a circle with centre at point O and radius 5 cm. STEP2: Draw its cord AB. STEP3: With centre A as centre and radius more than half of AB, draw two arcs, one on each side ... is perpendicular bisector of AB which is chord of circle, Hence, it passes through the centre of the circle.

Prove that the line joining the mid-points of two parallel chords of a circle passes through the centre. -Maths 9th

Description : Prove that the line joining the mid-points of two parallel chords of a circle passes through the centre. -Maths 9th

Last Answer : Let AB and CD be two parallel chords having P and Q as their mid-points, respectively. Let O be the centre of the circle. Join OP and OQ and draw OX | | AB | | CD. Since, Pis the mid-point of AB. ⇒ OP ... 90° Now, ∠POX + ∠XOQ = 90° + 90° = 180° so, POQ is a straight line . Hence proved

If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : According to question prove that the two chords are parallel.

If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : Given : E and F are mid points of 2 chords AB and CD respectively. Line EF passes through centre. To prove : AB||CD ∠ OFC = ∠ OEA = 90° as line drawn through the centre to bisect the ... EF as traversal for lines AB and CD as alternate interior angles on same side are equal. Therefore, AB || CD

Prove that the line joining the mid-points of two parallel chords of a circle passes through the centre. -Maths 9th

Description : Prove that the line joining the mid-points of two parallel chords of a circle passes through the centre. -Maths 9th

Last Answer : Let AB and CD be two parallel chords having P and Q as their mid-points, respectively. Let O be the centre of the circle. Join OP and OQ and draw OX | | AB | | CD. Since, Pis the mid-point of AB. ⇒ OP ... 90° Now, ∠POX + ∠XOQ = 90° + 90° = 180° so, POQ is a straight line . Hence proved

If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : According to question prove that the two chords are parallel.

If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : Given : E and F are mid points of 2 chords AB and CD respectively. Line EF passes through centre. To prove : AB||CD ∠ OFC = ∠ OEA = 90° as line drawn through the centre to bisect the ... EF as traversal for lines AB and CD as alternate interior angles on same side are equal. Therefore, AB || CD

AB and CD are equal and parallel chords of a circle with centre O. Then AC passes through the centre O. [Agree `//` Disagree]

Description : AB and CD are equal and parallel chords of a circle with centre O. Then AC passes through the centre O. [Agree `//` Disagree]

Last Answer : AB and CD are equal and parallel chords of a circle with centre O. Then AC passes through the centre O. [Agree `//` Disagree]

Which of the following latitudes passes through India? [RRB 1994] (a) Equator (b) Arctic Circle (c) Tropic of Capricorn (d) Tropic of Cancer

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Last Answer : Ans: (d)

The longest circle which can be drawn on the earth’s surface passes through where?

Description : The longest circle which can be drawn on the earth’s surface passes through where?

Last Answer : Equator

A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

Description : A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

Last Answer : ∵ PM = MQ = 1/2 = PQ = 45 cm and OP = 7.5 cm In right angled ΔOMP, using phthagoras theorem OM2 = OP2 - PM2 ⇒OM2 = 7.52 - 4.52 ⇒OM2 = 56.25 - 20.25 ⇒OM2 = 36 ∴ OM = √36 = 6 cm

A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

Description : A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

Last Answer : ∵ PM = MQ = 1/2 = PQ = 45 cm and OP = 7.5 cm In right angled ΔOMP, using phthagoras theorem OM2 = OP2 - PM2 ⇒OM2 = 7.52 - 4.52 ⇒OM2 = 56.25 - 20.25 ⇒OM2 = 36 ∴ OM = √36 = 6 cm

What equation describes a line that passes through the point (-14) and is perpendicular to the line 4x-3y-9?

Description : What equation describes a line that passes through the point (-14) and is perpendicular to the line 4x-3y-9?

Last Answer : If you mean point (-1, 4) and equation of 4x-3y = -9 then y =4/3x+3Slope of equation: 4/3Perpendicular slope: -3/4Perpendicular equation: y-4 = -3/4(x--1) => 4y = -3x+13

What is the circumstances of a circle with a radius of 9.7 inches Use 3.14 for pi?

Description : What is the circumstances of a circle with a radius of 9.7 inches Use 3.14 for pi?

Last Answer : I assume you mean "circumference".The circumference of a circle with a radius of 9.7 inches is 60.95 inches.Circumference = 2 * pi * radius-or-2 * 3.14 * 9.7 = 60.95

What is the equation for a circle with a center of (0 0) and a radius of 9?

Description : What is the equation for a circle with a center of (0 0) and a radius of 9?

Last Answer : The equation of the circle is: x^2 + y^2 = 81

What is the area in feet of a circle with a radius of 9?

Description : What is the area in feet of a circle with a radius of 9?

Last Answer : Area of circle: pi times 9 squared = 254.469 square feet roundedto 3 decimal places

What is the area in feet of a circle with a radius of 9?

Description : What is the area in feet of a circle with a radius of 9?

Last Answer : Area of circle: pi times 9 squared = 254.469 square feet roundedto 3 decimal places

Point A(5, 1) is the centre of the circle with radius 13 units. AB ⊥ chord PQ. B is (2, –3). The length of chord PQ is -Maths 9th

Description : Point A(5, 1) is the centre of the circle with radius 13 units. AB ⊥ chord PQ. B is (2, –3). The length of chord PQ is -Maths 9th

Last Answer : (c) ParallelogramAB = \(\sqrt{(4-7)^2+(5-6)^2}\) = \(\sqrt{9+1}\) = \(\sqrt{10}\)BC = \(\sqrt{(7-4)^2+(6-3)^2}\) = \(\sqrt{9+9}\) = \(3\sqrt2\)CD =\(\sqrt{(4-1)^2+(3-2) ... = \(2\sqrt{13}\)AB = CD, BC = AD and AC ≠ BD ⇒ opposite sides are equal and diagonals are not equal. ⇒ ABCD is a parallelogram.

When The circle below is centered at the point (-1 -3) and has a radius of length 5. What is its equation?

Description : When The circle below is centered at the point (-1 -3) and has a radius of length 5. What is its equation?

Last Answer : Equation of the circle: (x+1)^2 +(y+3)^2 = 25

The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm

A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th

Description : A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th

Last Answer : Given, AB is a chord of a circle, which is equal to the radius of the circle, i.e., AB = BO …(i) Join OA, AC and BC. Since, OA = OB= Radius of circle OA = AS = BO

The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm

A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th

Description : A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th

Last Answer : Given, AB is a chord of a circle, which is equal to the radius of the circle, i.e., AB = BO …(i) Join OA, AC and BC. Since, OA = OB= Radius of circle OA = AS = BO

A circle has radius √2 cm. It is divided into two segments by a chord of length 2cm.Prove that the angle subtended by the chord at a point in major segment is 45 degree . -Maths 9th

Description : A circle has radius √2 cm. It is divided into two segments by a chord of length 2cm.Prove that the angle subtended by the chord at a point in major segment is 45 degree . -Maths 9th

Last Answer : Given radius =2 cm Therefore AO=2 cm Let OD be the perpendicular from O on AB And AB =2cm Therefore AD=1cm (perpendicular from the centre bisects the chord) Now in triangle AOD, AO=2 cm ... by a chord at the centre is double of the angle made by the chord at any poin on the circumference)

What is the equation for a circle centered at the point (-13) and has a radius of length 4. What is the equation?

Description : What is the equation for a circle centered at the point (-13) and has a radius of length 4. What is the equation?

Last Answer : It is (x + 1)2 + (y - 3)2 = 42

What is the equation for a circle centered at the point (-1 3) and has a radius of length 4. What is the equation?

Description : What is the equation for a circle centered at the point (-1 3) and has a radius of length 4. What is the equation?

Last Answer : Equation: (x+1)^2 +(y-3)^2 = 16

What is the equation of The circle below is centered at the point (-2 -3) and has a radius of length 7.?

Description : What is the equation of The circle below is centered at the point (-2 -3) and has a radius of length 7.?

Last Answer : Equation of circle: (x+2)^2 +(y+3) = 49

When The circle below is centered at the point (2 -3) and has a radius of length 4. What is its equation?

Description : When The circle below is centered at the point (2 -3) and has a radius of length 4. What is its equation?

Last Answer : The equation of the circle is: (x-2)^2 + (y+3)^2 = 16

When The circle below is centered at the point (-3 -4) and has a radius of length 2. What is its equation?

Description : When The circle below is centered at the point (-3 -4) and has a radius of length 2. What is its equation?

Last Answer : The equation is: (x+3)^2 + (y+4)^2 = 4

When The circle below is centered at the point (3 2) and has a radius of length 7. What is its equation?

Description : When The circle below is centered at the point (3 2) and has a radius of length 7. What is its equation?

Last Answer : Equation of circle: (x-3)^2 +(y-2)^2 = 49

If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th

Description : If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th

Last Answer : According to question the radius of the circle passing through the points A, B and C .

If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th

Description : If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th

Last Answer : According to question the radius of the circle passing through the points A, B and C .

Identify an equation in slope-intercept from for the line parallel to y=4x-9 that passes through (-5,3)?

Description : Identify an equation in slope-intercept from for the line parallel to y=4x-9 that passes through (-5,3)?

Last Answer : food

Find the value of k if the line on 2x + y = k passes through the point (3,5). -Maths 9th

Description : Find the value of k if the line on 2x + y = k passes through the point (3,5). -Maths 9th

Last Answer : Solution :-

Find the equation of the line which passes through the point of intersection of the lines 2x – y + 5 = 0 -Maths 9th

Description : Find the equation of the line which passes through the point of intersection of the lines 2x – y + 5 = 0 -Maths 9th

Last Answer : (a) 45º 3x + y - 7 = 0 ⇒ y = -3x + 7 ⇒ Slope (m1) = -3 x + 2y + 9 = 0 ⇒ y = \(rac{-x}{2}\) - \(rac{9}{2}\) ⇒ Slope (m2) = \(-rac{1}{2}\)If θ is the angle between the given lines, then tan θ = \(\ ... \bigg|rac{-rac{5}{2}}{1+rac{3}{2}}\bigg|\)= \(\bigg|rac{-rac{5}{2}}{rac{5}{2}}\bigg|\) = 1∴ θ = 45°.

The line L is given by x/5 + y/b = 1 passes through the point (13, 32). The line K is parallel to L and has the equation -Maths 9th

Description : The line L is given by x/5 + y/b = 1 passes through the point (13, 32). The line K is parallel to L and has the equation -Maths 9th

Last Answer : (a) 45º The equations of the given lines are: A\(x\) + By = A + B ⇒ By = -A\(x\) + (A + B) ⇒ y = \(-rac{A}{B}x\) + \(rac{(A+B)}{B}\) ....(i)and A(\(x\) - y) + B(\(x\) ... (ii) = m2 = \(rac{(A+B)}{B-A}\)Let θ be the angle between both the lines, then∴ tan θ = 1 ⇒ θ = tan-1 (1) = 45°.

Find the equation of the straight line with a positive gradient which passes through the point (–5, 0) -Maths 9th

Description : Find the equation of the straight line with a positive gradient which passes through the point (–5, 0) -Maths 9th

Last Answer : (d) Both (a) and (c)Since the line passes through A(a, 0) and B(0, b), it makes intercepts a and b on x-axis and y-axis respectively. Let the equation of this line in the intercept from be \(rac{x}{a}\) + \(rac{y}{a}\) ... \(rac{x}{-12}\) + \(rac{y}{-5}\) = 1⇒ 5x + 12y = 60 and 5x + 12y + 60 = 0.

A straight line passes through the points (5, 0) and (0, 3). The length of the perpendicular from the point (4, 4) on the line is: -Maths 9th

Description : A straight line passes through the points (5, 0) and (0, 3). The length of the perpendicular from the point (4, 4) on the line is: -Maths 9th

Last Answer : (b) \(rac{\sqrt{17}}{2}\)Equation of the line through the points (5, 0) and (0, 3) y - 0 = \(rac{3-0}{0-5}\) (x - 5)⇒ y = \(rac{-3}{5}\)(x - 5)⇒ 5y + 3x - 15 = 0 ∴ Distance of perpendicular from ... (rac{|20+12-15|}{\sqrt{25+9}{}}\) = \(rac{17}{\sqrt{34}}\) units. = \(rac{\sqrt{17}}{2}\) units.

What is an equation of the line that is perpendicular to y plus 1-3(x-5) and passes through the point (4-6)?

Description : What is an equation of the line that is perpendicular to y plus 1-3(x-5) and passes through the point (4-6)?

Last Answer : Need answer

For Q 51, find radius of circle a.3 b.3.6 c.4 d.3.5

Description : For Q 51, find radius of circle a.3 b.3.6 c.4 d.3.5

Last Answer : b.3.6

Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the A distance between AB and CD is 6 cm, find the radius of the circle. -Maths 9th

Description : Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the A distance between AB and CD is 6 cm, find the radius of the circle. -Maths 9th

Last Answer : Join OA and OC. Let the radius of the circle be r cm and O be the centre Draw OP⊥AB and OQ⊥CD. We know, OQ⊥CD, OP⊥AB and AB∥CD. Therefore, points P,O and Q are collinear. So, PQ=6 cm. Let OP=x. Then, ... r2=52+(2.5)2=25+6.25=31.25 ⇒r2=31.25⇒r=5.6 Hence, the radius of the circle is 5.6 cm

Three girls Reshma, Salma and Mandeep are playing a game by standing on a circle of radius 5 m drawn in a park. -Maths 9th

Description : Three girls Reshma, Salma and Mandeep are playing a game by standing on a circle of radius 5 m drawn in a park. -Maths 9th

Last Answer : Solution :- Let R, S and M represent the position of Reshma, Salma and Mandeep respectively. Clearly △RSM is an isosceles triangle as RS = SM = 6m Join OS which intersect RM at A. In △ROS and △MOS OR = OM ( ... . ∴ RM = 2RA RM = 2 x 4.8 = 9.6m Hence, distance between Reshma and Mandeep is 9.6m.

If the sides of a triangle are 3 cm, 4 cm and 5 cm, then what is the radius of the circum-circle? -Maths 9th

Description : If the sides of a triangle are 3 cm, 4 cm and 5 cm, then what is the radius of the circum-circle? -Maths 9th

Last Answer : Semi-perimeter of triangle (s) = \(rac{3+4+5}{2}\)cm = 6 cm∴ Area of triangle A = \(\sqrt{s(s-a)(s-b)(s-c)}\) = \(\sqrt{6 imes3 imes2 imes1}\) cm2 = 6 cm2∴ Radius of circum-circle = \(rac{abc}{4( ext{Area of}\,\Delta)}\) = \(rac{3+4+5}{4 imes60}\) cm = 2.5 cm

In a right triangle we know a perpendicular 22.5 cm and a radius of a circle inscribed 4.5 cm. Determine the remaining sides and angles of the triangle.

Last Answer : I determined and what next? A circle inscribed in a triangle This is a circle that touches all sides of the triangle. The center of the circle inscribed in the triangle ABC is the intersection of the axes of the ... the 2nd series of the summer part of KMS 2009 / 2010.pdf example no.6" in Slovak

(i) The radius of a circle is increasing at the rate of 5 cm/sec. Find the rate of increasing of its perimeter. (ii) If the area of a circle increases

Description : (i) The radius of a circle is increasing at the rate of 5 cm/sec. Find the rate of increasing of its perimeter. (ii) If the area of a circle increases

Last Answer : (i) The radius of a circle is increasing at the rate of 5 cm/sec. Find the rate ... to its circumference is iversely proportional to its radius.

What is the diameter of a circle if the radius is 5.9cm?

Description : What is the diameter of a circle if the radius is 5.9cm?

Last Answer : The diameter of a circle is twice its radius and so 2 times 5.9= 11.8cm

What is the equation for a circle with a center of (-1 -5) and a radius of 6?

Description : What is the equation for a circle with a center of (-1 -5) and a radius of 6?

Last Answer : The equation is: (x+1)^2 +(y+5)^2 = 36

If the radius of a circle that is 5 what is the area?

Description : If the radius of a circle that is 5 what is the area?

Last Answer : It is 78.5 square units.