What equation describes a line that passes through the point (-14) and is perpendicular to the line 4x-3y-9?

1 Answer

Answer :

If you mean point (-1, 4) and equation of 4x-3y = -9 then y =4/3x+3Slope of equation: 4/3Perpendicular slope: -3/4Perpendicular equation: y-4 = -3/4(x--1) => 4y = -3x+13

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