How many square feet in a 40' diameter circle?

How many square feet in a 40' diameter circle?
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1 Answer

Answer :

Area of circle: pi times radius squared
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Description : what is the diameter of a circle with 746 square feet?

Last Answer : First look at the equation for the area of a circle and work backwards. A=PiD, so 746=PiD. then divide by Pi. You should end up with D=237.6

If a piece of metal is 8 feet long what would the diameter be if it was bent into a circle?

Description : If a piece of metal is 8 feet long what would the diameter be if it was bent into a circle?

Last Answer : You want the formula for the diameter (2r) if you have the circumference? If the formula for circumference is 2(pi)r, you simply do the algebra to determine r c=2(pi)r. Divide both sides of the equation by r and you have c/r=2(pi). Then divide both sides by r and you have c=2pi/r

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Last Answer : Area of circle: pi*4 squared = 50.265 square feet to threedecimal places

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Last Answer : Using 3.14 as Pi the area of circle is: 961.625

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Last Answer : Using 3.14 as Pi the area of circle is: 123.83657600000001

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Description : What is the diameter of a circle with the area 49pi square units?

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Description : Find total number coils in a spring having square and ground ends. Deflection in the spring is 6mm when load of 1100N is applied. Modulus of rigidity is 81370N/mm². Wire diameter and pitch circle diameter are 10mm and 50mm respectively. a) 7 b) 6 c) 5 d) 4

Last Answer : a) 7

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Description : What is the circumference of a circle with a diameter of 40 millimeters.?

Last Answer : 125.66 mm

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Last Answer : Tobacco.

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Last Answer : Area of circle: pi times 9 squared = 254.469 square feet roundedto 3 decimal places

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Description : What is the area of a 0.5 feet circle?

Last Answer : Area of a circle: pi*radius squared

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Description : What is the area in feet of a circle with a radius of 9?

Last Answer : Area of circle: pi times 9 squared = 254.469 square feet roundedto 3 decimal places

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Description : What is a polynomial for the area of a circle with radius(x plus 2) feet?

Last Answer : A = pi()*(x2 + 4x +4) square feet.

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Description : The moment of inertia of a semi-circle of radius r with respect to a centroidal axis parallel to the diameter is a.0.33 r2 b.0.11 r2 c.0.055 r2 d.0.05 r2 e.0.22 r2

Last Answer : b. 0.11 r2

which of the following shows the diameter of a circle -General Knowledge

Description : which of the following shows the diameter of a circle -General Knowledge

Last Answer : D shows the diameter bcz the line cuts the circle in a half.

If two chords of a circle with a common end-point are inclined equally to the diameter through this common end-point, then prove that chords are equal. -Maths 9th

Description : If two chords of a circle with a common end-point are inclined equally to the diameter through this common end-point, then prove that chords are equal. -Maths 9th

Last Answer : Let AB and AC be two chords and AD be the diameter of the circle . Draw OL ⊥ AB and OM ⊥ AC . In ΔOLA and ΔOMA ∠ OLA = ∠ OMA = 90° OA = OA [common sides] ∠ OAL = ∠ OAM [given] . OLA ≅ OMA [by ASA congruency] OL =OM (by CPCT) Chords AM and AC are equidistant from O. ∴ AB = AC Hence proved.

A circle with centre O and diameter COB is given. If AB and CD are parallel, then show that chord AC is equal to chord BD. -Maths 9th

Description : A circle with centre O and diameter COB is given. If AB and CD are parallel, then show that chord AC is equal to chord BD. -Maths 9th

Last Answer : O Join AC and BD. Given, COB is the diameter of circle. ∠CAB = ∠BDC = 90° [angle in a semi-circle] Also, AB II CD ∠ABC = ∠DCB (alternate angles] Now, ∠ACB = 90° - ∠ABC and ∠DBC = 90° - ∠DCB = ... = ∠DBC BC = BC [common sides] ΔABC = ΔDCB [by ASA congruency] ∴ AC = BD [by CPCT] Hence Proved.

The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm

AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, then find the distance of AB from the centre of the circle. -Maths 9th

Description : AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, then find the distance of AB from the centre of the circle. -Maths 9th

Last Answer : ∵ The perpendicular drawn from the centre to the chord bisects it. ∴ AM = 1/2 AB = 1/2 × 30 cm = 15 cm Also, OA = 1/2 AD = 1/2 × 34 cm = 17 cm In rt. △OAM, we have OA2 = OM2 + AM2 172 = OM2 + 152 ⇒ 289 = OM2 + 225 ⇒ OM2 = 289 - 225 ⇒ OM2 = 64 ⇒ OM = √64 = 8 cm

AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, the distance of AB from the centre of the circle is -Maths 9th

Description : AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, the distance of AB from the centre of the circle is -Maths 9th

Last Answer : (d) Given, AD = 34 cm and AB = 30 cm In figure, draw OL ⊥ AB. Since, the perpendicular from the centre of a circle to a chord bisects the chord.

In figure, AOB is a diameter of the circle and C, D, E are any three points on the semi-circle. -Maths 9th

Description : In figure, AOB is a diameter of the circle and C, D, E are any three points on the semi-circle. -Maths 9th

Last Answer : Since, A, C, D and E are four point on a circle, then ACDE is a cyclic quadrilateral. ∠ACD+ ∠AED = 180° …(i) [sum of opposite angles in a cyclic quadrilateral is 180°]

If bisectors of opposite angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle. -Maths 9th

Description : If bisectors of opposite angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle. -Maths 9th

Last Answer : Given, ABCD is a cyclic quadrilateral. DP and QB are the bisectors of ∠D and ∠B, respectively. To prove PQ is the diameter of a circle. Construction Join QD and QC.

If two chords of a circle with a common end-point are inclined equally to the diameter through this common end-point, then prove that chords are equal. -Maths 9th

Description : If two chords of a circle with a common end-point are inclined equally to the diameter through this common end-point, then prove that chords are equal. -Maths 9th

Last Answer : Let AB and AC be two chords and AD be the diameter of the circle . Draw OL ⊥ AB and OM ⊥ AC . In ΔOLA and ΔOMA ∠ OLA = ∠ OMA = 90° OA = OA [common sides] ∠ OAL = ∠ OAM [given] . OLA ≅ OMA [by ASA congruency] OL =OM (by CPCT) Chords AM and AC are equidistant from O. ∴ AB = AC Hence proved.

A circle with centre O and diameter COB is given. If AB and CD are parallel, then show that chord AC is equal to chord BD. -Maths 9th

Description : A circle with centre O and diameter COB is given. If AB and CD are parallel, then show that chord AC is equal to chord BD. -Maths 9th

Last Answer : O Join AC and BD. Given, COB is the diameter of circle. ∠CAB = ∠BDC = 90° [angle in a semi-circle] Also, AB II CD ∠ABC = ∠DCB (alternate angles] Now, ∠ACB = 90° - ∠ABC and ∠DBC = 90° - ∠DCB = ... = ∠DBC BC = BC [common sides] ΔABC = ΔDCB [by ASA congruency] ∴ AC = BD [by CPCT] Hence Proved.

The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm

AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, then find the distance of AB from the centre of the circle. -Maths 9th

Description : AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, then find the distance of AB from the centre of the circle. -Maths 9th

Last Answer : ∵ The perpendicular drawn from the centre to the chord bisects it. ∴ AM = 1/2 AB = 1/2 × 30 cm = 15 cm Also, OA = 1/2 AD = 1/2 × 34 cm = 17 cm In rt. △OAM, we have OA2 = OM2 + AM2 172 = OM2 + 152 ⇒ 289 = OM2 + 225 ⇒ OM2 = 289 - 225 ⇒ OM2 = 64 ⇒ OM = √64 = 8 cm

AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, the distance of AB from the centre of the circle is -Maths 9th

Description : AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, the distance of AB from the centre of the circle is -Maths 9th

Last Answer : (d) Given, AD = 34 cm and AB = 30 cm In figure, draw OL ⊥ AB. Since, the perpendicular from the centre of a circle to a chord bisects the chord.

In figure, AOB is a diameter of the circle and C, D, E are any three points on the semi-circle. -Maths 9th

Description : In figure, AOB is a diameter of the circle and C, D, E are any three points on the semi-circle. -Maths 9th

Last Answer : Since, A, C, D and E are four point on a circle, then ACDE is a cyclic quadrilateral. ∠ACD+ ∠AED = 180° …(i) [sum of opposite angles in a cyclic quadrilateral is 180°]

If bisectors of opposite angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle. -Maths 9th

Description : If bisectors of opposite angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle. -Maths 9th

Last Answer : Given, ABCD is a cyclic quadrilateral. DP and QB are the bisectors of ∠D and ∠B, respectively. To prove PQ is the diameter of a circle. Construction Join QD and QC.

If AOB is a diameter of a circle [Fig. 10.8] and C is a point on the circle, then prove that AC* +BC*=AB*. -Maths 9th

Description : If AOB is a diameter of a circle [Fig. 10.8] and C is a point on the circle, then prove that AC* +BC*=AB*. -Maths 9th

Last Answer : Solution :- As, ∠ C = 90° (Angle in the semicircle) ∴ AC2 + BC2 = AB2 (By Pythagoras Theorem)

A semi-circle of diameter 14 cm has three chords of equal length connecting the two end points of the diameter so as -Maths 9th

Description : A semi-circle of diameter 14 cm has three chords of equal length connecting the two end points of the diameter so as -Maths 9th

Last Answer : (c)\(\bigg(rac{147 imes\sqrt3}{4}\bigg)\) cm2Take the trapezoid ABCD in the semi-circle with centre O such that AD = DC = CB. Now, complete the circle and draw an identical trapezoid in the other semicircle also. Then, ADCBEF ... {1}{2}\)x \(rac{3\sqrt3}{2}\) x 49 = \(rac{147 imes\sqrt3}{4}\) cm2.

Draw a circle of diameter 6.4 cm. Then draw two tangents to the circle from a point P at a distance 6.4 cm from the centre of the circle. -Maths 9th

Description : Draw a circle of diameter 6.4 cm. Then draw two tangents to the circle from a point P at a distance 6.4 cm from the centre of the circle. -Maths 9th

Last Answer : clear .

What is the area of a circle whose diameter is 10?

Description : What is the area of a circle whose diameter is 10?

Last Answer : Using 3.14 as Pi the area of circle is: 78.5

What is the diameter of a circle if its radius is r ?

Description : What is the diameter of a circle if its radius is r ?

Last Answer : If the radius of a circle is r then the diameter is 2r .

What is the chord and diameter of a circle ?

Description : What is the chord and diameter of a circle ?

Last Answer : The chord of any two points joining a circle is the chord of the circle. And the center of the circle is the diameter of the oyster circle.

In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.

Description : In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.

Last Answer : In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.

In the given figure, AB is the diameter and `/_ADC = 2 /_BDC`. If `/_ BCD =70^(@)`, then find the angle made by AC at the centre of the circle.

Description : In the given figure, AB is the diameter and `/_ADC = 2 /_BDC`. If `/_ BCD =70^(@)`, then find the angle made by AC at the centre of the circle.

Last Answer : In the given figure, AB is the diameter and `/_ADC = 2 /_BDC`. If `/_ BCD =70^(@)`, then find the angle made by AC at the centre of the circle.

In the figure below, `bar(MN)` is the diameter of the circle with centre O. `bar(NP)` bisects the `/_ANM`. If `/_ NMA =33^(@)`, then find `/_ ANP`.

Description : In the figure below, `bar(MN)` is the diameter of the circle with centre O. `bar(NP)` bisects the `/_ANM`. If `/_ NMA =33^(@)`, then find `/_ ANP`.

Last Answer : In the figure below, `bar(MN)` is the diameter of the circle with centre O. `bar(NP)` bisects the `/_ANM`. If `/_ NMA =33^(@)`, then find `/_ ANP`.

A wire has resistance `12 Omega`. It is bent in the form of a circle. The effective resistance between two points across a diameter is.

Description : A wire has resistance `12 Omega`. It is bent in the form of a circle. The effective resistance between two points across a diameter is.

Last Answer : A wire has resistance `12 Omega`. It is bent in the form of a circle. The effective resistance between two ... ` B. `6Omega` C. `3Omega` D. `24Omega`

What is the diameter of a circle if the radius is 5.9cm?

Description : What is the diameter of a circle if the radius is 5.9cm?

Last Answer : The diameter of a circle is twice its radius and so 2 times 5.9= 11.8cm

What is the diameter of a circle with a circumference of 12.25?

Description : What is the diameter of a circle with a circumference of 12.25?

Last Answer : Diameter of circle: 12.25/pi = 3.899 rounded to 3 decimalplaces

If the diameter of the circle is 30 mm then what is the radius of the circle?

Description : If the diameter of the circle is 30 mm then what is the radius of the circle?

Last Answer : The radius if the circle is half of its diameter and so 30/2 =15 mm

What will happen if the diameter of the circle doubles how will the circumference change?

Description : What will happen if the diameter of the circle doubles how will the circumference change?

Last Answer : The circumference also doubles.

If a circle has a circumference of 132 inch what is the diameter?

Description : If a circle has a circumference of 132 inch what is the diameter?

Last Answer : Diameter of circle: 132/pi = 42 inches rounded to the nearestwhole number

What is the center of the circle with a diameter whose endpoints are (27) and (-6-1)?

Description : What is the center of the circle with a diameter whose endpoints are (27) and (-6-1)?

Last Answer : Diameter endpoints: (2, 7) and (-6, -1)Centre of circle will be the midpoint which is: (-2, 3)

How do you find the diameter of a circle with the width and length?

Description : How do you find the diameter of a circle with the width and length?

Last Answer : The width, or the length of a circle are its diameter.

How do you find the circumference of a circle knowing only the diameter?

Description : How do you find the circumference of a circle knowing only the diameter?

Last Answer : Circumference of a circle: pi times diameter