Description : Primes and Modular Arithmetic: Do any "complete" primes exist?
Last Answer : answer:((2*3)^2 + 2*3)/2 +2 = 23 = 7*3 + 2 = 2 mod 3. In general, ((2*p)^2 + 2*p)/2 + n = 2*p^2 + p + n = n mod p. I don’t think you asked the right question. Don’t you want to insure that (k^2 + k)/2 is in the orbit of the function given by f(0) = 1; f(n + 1) = f(n) + n – 1?