Is 198 divisible by 11?

Is 198 divisible by 11?
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Answer :

Yes and it is exactly 18 times 11 = 198
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Related questions

Is 198 divisible by 11?

Description : Is 198 divisible by 11?

Last Answer : Yes and it is exactly 18 times 11 = 198

How many times can 11 go into 198?

Description : How many times can 11 go into 198?

Last Answer : Exactly 18 times

what is a 4 digit number that is divisible by 11 an17?

Description : what is a 4 digit number that is divisible by 11 an17?

Last Answer : 1870 is divisible by both 17 and 111870 / 17 = 1101870 / 11 = 170

to determine if 913 = 10×91 + 3 is divisible by 11

Description : to determine if 913 = 10×91 + 3 is divisible by 11

Last Answer : find that m = (11×9+1)÷10 = 10. Then mq+t = 10×3+91 = 121; this is divisible by 11 (with quotient 11)

What least number would be subtracted from 427398 so that the remaining number is divisible by 15? 1. 13 2. 3 3. 16 4. 11 5. 14

Description : What least number would be subtracted from 427398 so that the remaining number is divisible by 15? 1. 13 2. 3 3. 16 4. 11 5. 14

Last Answer : Answer- 2 ( 3) Explanation:- On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted 

There are two congruent triangles each with area 198 cm^2. Triangle DEF is placed over triangle ABC in such a way that the centroid of -Maths 9th

Description : There are two congruent triangles each with area 198 cm^2. Triangle DEF is placed over triangle ABC in such a way that the centroid of -Maths 9th

Last Answer : answer:

What is 7,198 rounded to the nearest thousand?

Description : What is 7,198 rounded to the nearest thousand?

Last Answer : 7000

What is the GCF of 44 88 198?

Description : What is the GCF of 44 88 198?

Last Answer : 22 is the GCF of 44, 88 and 198.

How many times does 60 go in to 198?

Description : How many times does 60 go in to 198?

Last Answer : 3 with 18 remaining198 - 18 = 180 = 60 x 3

What is the perimeter of 198.81 in a squre?

Description : What is the perimeter of 198.81 in a squre?

Last Answer : It is 56.4 units.

How do you write 0.198 in word form?

Description : How do you write 0.198 in word form?

Last Answer : What is the answer ?

What is the perimeter of 198.81 in a squre?

Description : What is the perimeter of 198.81 in a squre?

Last Answer : It is 56.4 units.

What is the answer to Write 198 as a product of primes?

Description : What is the answer to Write 198 as a product of primes?

Last Answer : 2 x 3 x 3 x 11

Number of amino acid residues in prolactin is (A) 51 (B) 84 (C) 191 (D) 198

Description : Number of amino acid residues in prolactin is (A) 51 (B) 84 (C) 191 (D) 198

Last Answer : Answer : D

Number of amino acid residues in human growth hormone is (A) 51 (B) 84 (C) 191 (D) 198

Description : Number of amino acid residues in human growth hormone is (A) 51 (B) 84 (C) 191 (D) 198

Last Answer : Answer : C

The population of Pakistan according to 2017 Census is: A. 198 million B. 207 million C. 142.5 million D. 202 million

Description : The population of Pakistan according to 2017 Census is: A. 198 million B. 207 million C. 142.5 million D. 202 million

Last Answer : ANSWER: B

The population of Pakistan according to 2017 Census is: A. 198 million B. 207 million C. 142.5 million D. 202 million

Description : The population of Pakistan according to 2017 Census is: A. 198 million B. 207 million C. 142.5 million D. 202 million

Last Answer : ANSWER: B

What is the free space attenuation of a satellite communications system operating at 36,000 km above the earth at 5.0 GHz? A. 198 dB B. 202 dB C. 142 dB D. 138 dB

Description : What is the free space attenuation of a satellite communications system operating at 36,000 km above the earth at 5.0 GHz? A. 198 dB B. 202 dB C. 142 dB D. 138 dB

Last Answer : A. 198 dB

Which of the following radioactive wastes emits all α, β & γ rays and hence is the most hazardous of all radioactive emitters? (A) I-131 (B) Sr-90 (C) Au-198 (D) Ra-226

Description : Which of the following radioactive wastes emits all α, β & γ rays and hence is the most hazardous of all radioactive emitters? (A) I-131 (B) Sr-90 (C) Au-198 (D) Ra-226

Last Answer : (D) Ra-226

3 4 12 45 ? 1005 a) 152 b) 198 c) 144 d) 192 e) None of these

Description : 3 4 12 45 ? 1005 a) 152 b) 198 c) 144 d) 192 e) None of these

Last Answer : Answer: e)

√1369 ×√1444 +√?=1420 a) 14 b) 196 c) 198 d) 194 e) 16

Description : √1369 ×√1444 +√?=1420 a) 14 b) 196 c) 198 d) 194 e) 16

Last Answer : √1369 ×√1444 - √? =1420 Or, √(37)2 ×√(38)2×√? = 1420 Or,37 × 38 ×√? = 1420 Or,1406 + √? =1420 Or, √? = 1420 -1406 =14 ? = 196 Answer: b)

A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds, all starting at the same point. After what time will they meet again at the starting point? A.15 minutes 15 seconds B.42 minutes 30 seconds C.42 minutes D.46 minutes 12 seconds E.None of these

Description : A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds, all starting at the same point ... A.15 minutes 15 seconds B.42 minutes 30 seconds C.42 minutes D.46 minutes 12 seconds E.None of these

Last Answer : Answer – D (46 minutes 12 seconds) Explanation – L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 see i.e., 46 min. 12 sec

How many students studying Dentistry know only either English or Hindi? (1) 166 (2) 162 (3) 308 (4) 198 (5) 248

Description : How many students studying Dentistry know only either English or Hindi? (1) 166 (2) 162 (3) 308 (4) 198 (5) 248

Last Answer : 4) 198

What radioactive element is routinely used in treating hyperthyroidism, and in reducing thyroid activity? w) Iron-59 x) Gold-198 y) Cobalt-60 z) Iodine-131

Description : What radioactive element is routinely used in treating hyperthyroidism, and in reducing thyroid activity? w) Iron-59 x) Gold-198 y) Cobalt-60 z) Iodine-131

Last Answer : ANSWER: Z -- IODINE-131

What is the longest and yet the shortest thing in the world; the swiftest and yet the slowest; the most divisible and the most extended; the least valued and the most regretted; without which nothing can be done; which devours every thing, however small, and yet gives life and spirits to every object, however great? -Riddles

Description : What is the longest and yet the shortest thing in the world; the swiftest and yet the slowest; the most divisible and the most extended; the least valued and the most regretted; without which ... every thing, however small, and yet gives life and spirits to every object, however great? -Riddles

Last Answer : Time.

For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Description : For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Last Answer : Let p(x) = x3 -2mx2 +16 Since, p(x) is divisible by (x+2), then remainder = 0 P(-2) = 0 ⇒ (-2)3 -2m(-2)2 + 16=0 ⇒ -8-8m+16=0 ⇒ 8 = 8 m m = 1 Hence, the value of m is 1 .

Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Description : Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Last Answer : Let p(x) = 2x4 - 5x3 + 2x2 - x+ 2 firstly, factorise x2-3x+2. Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term] = x(x-2)-1 (x-2)= (x-1)(x-2) Hence, 0 of x2-3x+2 are land 2. We have to prove that, 2x4 ... )2 - 2 + 2 = 2x16-5x8+2x4+ 0 = 32 - 40 + 8 = 40 - 40 =0 Hence, p(x) is divisible by x2-3x+2.

For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Description : For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Last Answer : Let p(x) = x3 -2mx2 +16 Since, p(x) is divisible by (x+2), then remainder = 0 P(-2) = 0 ⇒ (-2)3 -2m(-2)2 + 16=0 ⇒ -8-8m+16=0 ⇒ 8 = 8 m m = 1 Hence, the value of m is 1 .

Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Description : Without actual division, prove that 2x4 – 5x3 + 2x2 – x+ 2 is divisible by x2-3x+2. -Maths 9th

Last Answer : Let p(x) = 2x4 - 5x3 + 2x2 - x+ 2 firstly, factorise x2-3x+2. Now, x2-3x+2 = x2-2x-x+2 [by splitting middle term] = x(x-2)-1 (x-2)= (x-1)(x-2) Hence, 0 of x2-3x+2 are land 2. We have to prove that, 2x4 ... )2 - 2 + 2 = 2x16-5x8+2x4+ 0 = 32 - 40 + 8 = 40 - 40 =0 Hence, p(x) is divisible by x2-3x+2.

FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Description : FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Last Answer : As the given polynomial divisible by x-2 means the polynomial satisfies for the value x=2 So putting x=2 in x²+(4-k)x+2 yields 0 ⇒2²+(4-k)2+2=0 ⇒4+8-2k+2=0 ⇒ 2k=14 ⇒ k= ... ;-3x+2 if factorized yields (x-1)(x-2). Thus is divisible by x-2 as well as divisible by x-1.

FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Description : FOR WHAT VALUE OF K, THE POLYNOMIAL X2+(4-K)X+2 IS DIVISIBLE BY X-2 -Maths 9th

Last Answer : The value of 'k' is 4

An integer is chosen at random from the first two hundred positive integers. What is the probability that the integer chosen is divisible by 6 or 8 ? -Maths 9th

Description : An integer is chosen at random from the first two hundred positive integers. What is the probability that the integer chosen is divisible by 6 or 8 ? -Maths 9th

Last Answer : As there are 200 integers, total number of exhaustive, mutually exclusive and equally likely cases, i.e, n(S) = 200 Let A : Event of integer chosen from 1 to 200 being divisible by 6⇒ n(A) = 33 \(\bigg(rac{200}{6}=33rac{1}{3}\ ... (rac{25}{200}\) - \(rac{8}{200}\) = \(rac{50}{200}\) = \(rac{1}{4}\).

Find the probability that a two digit number formed by the digit 1, 2, 3, 4 and 5 is divisible by 4. -Maths 9th

Description : Find the probability that a two digit number formed by the digit 1, 2, 3, 4 and 5 is divisible by 4. -Maths 9th

Last Answer : The two digit numbers can be formed by putting any of 5 digits at the one 's place and also one of the 5 digits at ten's place. So, Total number of 2-digit numbers that can be formed using these 5-digits = 5 5 = ... 52}, i.e, 5 in number. ∴ Required probability = \(rac{5}{25}\) = \(rac{1}{5}.\)

A five digit number is formed by the digits 0, 1, 2, 3, 4 (without repetition). Find the probability that the number formed is divisible by 4 ? -Maths 9th

Description : A five digit number is formed by the digits 0, 1, 2, 3, 4 (without repetition). Find the probability that the number formed is divisible by 4 ? -Maths 9th

Last Answer : Without repetition, a five -digit number can be formed using the five digits in 5! ways (5 4 3 2 1) Out of these 5! numbers, 4! numbers will be starting with digit 0. (0 (fixed) 4 3 2 1) ∴ Total ... + 6 + 6 + 4 + 4 + 4 = 30∴ Required probability = \(rac{30}{96}\) = \(rac{5}{16}.\)

If three natural numbersfrom 1 to 100 are selected randomly, then the probability that all are divisible by both 2 and 3 is -Maths 9th

Description : If three natural numbersfrom 1 to 100 are selected randomly, then the probability that all are divisible by both 2 and 3 is -Maths 9th

Last Answer : (c) \(rac{4}{1155}\)Let n(S) = Number of ways of selecting 3 numbers from 100 numbers = 100C3 Let E : Event of selecting three numbers divisible by both 2 and 3 from numbers 1 to 100 = Event of selecting three ... C_3}{^{100}C_3}\) = \(rac{16 imes15 imes14}{100 imes99 imes98}\) = \(rac{4}{1155}\).

For what value of m will the expression 3x^3 + mx^2 + 4x – 4m be divisible by x + 2 ? -Maths 9th

Description : For what value of m will the expression 3x^3 + mx^2 + 4x – 4m be divisible by x + 2 ? -Maths 9th

Last Answer : f(x) = 3x3 + mx2 + 4x – 4m f(x) is divisible by (x + 2) if f(–2) = 0 Now f(–2) = 3(–2)3 + m(–2)2 + 4(–2) – 4m = – 24 + 4m – ... ; 4m = – 32 ≠ 0 ∴ No such value of m exists for which (x + 2) is a factor of the given expression

If x^5 – 9x^2 + 12x – 14 is divisible by (x – 3), what is the remainder ? -Maths 9th

Description : If x^5 – 9x^2 + 12x – 14 is divisible by (x – 3), what is the remainder ? -Maths 9th

Last Answer : answer:

Without actual division show that 2x^4 – 6x^3 + 3x^2 + 3x – 2 is exactly divisible by x^2 – 3x + 2 -Maths 9th

Description : Without actual division show that 2x^4 – 6x^3 + 3x^2 + 3x – 2 is exactly divisible by x^2 – 3x + 2 -Maths 9th

Last Answer : answer:

Without actual division, show that (x – 1)^2n – x^2n + 2x – 1 is divisible by 2x^3 – 3x^2 + x. -Maths 9th

Description : Without actual division, show that (x – 1)^2n – x^2n + 2x – 1 is divisible by 2x^3 – 3x^2 + x. -Maths 9th

Last Answer : answer:

For what value of k, will the expression (3x^3 – kx^2 + 4x + 16) be divisible by (x – k/2) ? -Maths 9th

Description : For what value of k, will the expression (3x^3 – kx^2 + 4x + 16) be divisible by (x – k/2) ? -Maths 9th

Last Answer : Given f(x) = 3x³ - kx² + 4x + 16. Since (x - k/2) is a factor of polynomial. This means x = k/2 is the zero of the given polynomial. ⇒ f(k/2) = 3(k/2)³ - k(k/2)² + 4(k/2) + 16 ⇒ 0 ... - 4k + 32) + 4(k² - 4k + 32) ⇒ 0 = (k + 4)(k² - 4k + 32) ⇒ k = -4.

x^4 + xy^3 + x^3y + xz^3 + y^4 + yz^3 is divisible by : -Maths 9th

Description : x^4 + xy^3 + x^3y + xz^3 + y^4 + yz^3 is divisible by : -Maths 9th

Last Answer : answer:

If the expression (px^3 + x^2 – 2x – q) is divisible by (x – 1) and (x + 1), then the values of p and q respectively are ? -Maths 9th

Description : If the expression (px^3 + x^2 – 2x – q) is divisible by (x – 1) and (x + 1), then the values of p and q respectively are ? -Maths 9th

Last Answer : Let f(x)=px3+x2−2x−q Since f(x) is divisible by (x−1) and (x+1) so x=1 and −1 must make f(x)=0. Therefore, p+1−2−q=0, i.e., p−q=1; and −p+1+2−q=0, i.e., p+q=3 Thus p=2 and q=1

If the polynomial x^6 + px^5 + qx^4 – x^2 – x – 3 is divisible by x^4 – 1, then the value of p^2 + q^2 is : -Maths 9th

Description : If the polynomial x^6 + px^5 + qx^4 – x^2 – x – 3 is divisible by x^4 – 1, then the value of p^2 + q^2 is : -Maths 9th

Last Answer : The divisor is x4−1=(x−1)(x+1)(x2+1) By factor theorem, f(1)=f(−1)=0 Thus, 1+p+q−1−1−3=0 and 1+q−1−3=p−1 i.e., p+q=4 and p−q=−2 Adding the two, 2p=2 i.e. p=1 and ∴ q=3. ∴ p2+q2=1+9=10

Which one of the following is divisible by (1 + a + a^5) and (1 + a^4 + a^5) individually ? -Maths 9th

Description : Which one of the following is divisible by (1 + a + a^5) and (1 + a^4 + a^5) individually ? -Maths 9th

Last Answer : answer:

Consider the following statements : 1. a^n + b^n is divisible by a + b if n = 2k + 1, where k is a positive integer. -Maths 9th

Description : Consider the following statements : 1. a^n + b^n is divisible by a + b if n = 2k + 1, where k is a positive integer. -Maths 9th

Last Answer : Statement (1) is correct as for k = 1, n = 2 × 1 + 1 = 3. ∴ a3 + b3 = (a + b) (a2 + b2 – ab) which is divisible by (a + b), statement (2) is also correct as for k = 1, n = 2, ∴ a2 – b2 = (a – b) (a + b) which is divisible by (a – b).

What should be subtracted from 27x^3 – 9x^2 – 6x – 5 to make it exactly divisible by (3x – 1) -Maths 9th

Description : What should be subtracted from 27x^3 – 9x^2 – 6x – 5 to make it exactly divisible by (3x – 1) -Maths 9th

Last Answer : answer:

(x^n – a^n) is divisible by (x – a) -Maths 9th

Description : (x^n – a^n) is divisible by (x – a) -Maths 9th

Last Answer : answer:

If 4x^2 – 6x + m is divisible by x – 3, which one of the following is the greatest divisor of m ? -Maths 9th

Description : If 4x^2 – 6x + m is divisible by x – 3, which one of the following is the greatest divisor of m ? -Maths 9th

Last Answer : answer:

Find the polynomial of least degree which should be subtracted from the polynomial x4 + 2x3 – 4x2 + 6x – 3 so that it is exactly divisible by x2 – x + 1. -Maths 10th

Description : Find the polynomial of least degree which should be subtracted from the polynomial x4 + 2x3 – 4x2 + 6x – 3 so that it is exactly divisible by x2 – x + 1. -Maths 10th

Last Answer : Here, p(x) = x4 + 2x3 - 4x2 + 6x - 3, g(x) = x2 - x +1 On dividing p(x) by g(x) Therefore (x-1) must be subtracted from the polynomial p(x) to make it divisible by g(x).

is this biconditional true or falseA number is even if and only if it is divisible by 2.?

Description : is this biconditional true or falseA number is even if and only if it is divisible by 2.?

Last Answer : 1