How do you write 0.51 in words?

How do you write 0.51 in words?
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1 Answer

Answer :

fifty-one hundredths
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Related questions

How do you write 51.5 million in number format?

Description : How do you write 51.5 million in number format?

Last Answer : As a number it is: 51,500,000 = 51.5 million

For Q 51, find coordinates of point on circle at u=0 a.11.6, 7 b.7, 11 c.11, 7 d.11.5, 7.5

Description : For Q 51, find coordinates of point on circle at u=0 a.11.6, 7 b.7, 11 c.11, 7 d.11.5, 7.5

Last Answer : a.11.6, 7

A flywheel weighs 400 kg and has a radius of gyration of 30 cm about its axis of rotation. It is mounted on a shaft subjected to a moment of 40 kgm. If the flywheel starts from restits speed after 3 seconds wil be a.10.9 rad/sec b.19.0 rad/sec c.51.2 rad/sec d.3.33 rad/sec e.16.35 rad/sec

Description : A flywheel weighs 400 kg and has a radius of gyration of 30 cm about its axis of rotation. It is mounted on a shaft subjected to a moment of 40 kgm. If the flywheel starts from restits speed after 3 seconds wil be a.10.9 rad/sec b.19.0 rad/sec c.51.2 rad/sec d.3.33 rad/sec e.16.35 rad/sec

Last Answer : d. 3.33 rad/sec

Two half-reactions of an electrochemical cell are given below : MnO–4 (aq) + 8H+ (aq) + 5e– → Mn2+ (aq) + 4H2O (I), E° = 1.51 V Sn2+ (aq) → Sn4+ (aq) + 2e–, E° = + 0.15 V. Construct the redox equation from the standard potential of the cell and predict if the reaction is reactant favoured or product favoured. -Chemistry

Description : Two half-reactions of an electrochemical cell are given below : MnO-4 (aq) + 8H+ (aq) + 5e- → Mn2+ (aq) + 4H2O (I), E° = 1.51 V Sn2+ (aq) → Sn4+ (aq) + 2e- ... the redox equation from the standard potential of the cell and predict if the reaction is reactant favoured or product favoured. -Chemistry

Last Answer : The reactions can be represented at anode and at cathode in the following ways : At anode (oxidation) : Sn2+ → = Sn4+ (aq) + 2e- ] 5 E° = + 0.15 V At cathode (reduction) : MnO-4(aq) + 8H+ ... = E°cathode - E°anode = 1.51 - 0.15 = + 1.36 V ∴ Positive value of E°cell favours formation of product.

Two half-reactions of an electrochemical cell are given below : MnO–4 (aq) + 8H+ (aq) + 5e– → Mn2+ (aq) + 4H2O (I), E° = 1.51 V Sn2+ (aq) → Sn4+ (aq) + 2e–, E° = + 0.15 V. Construct the redox reaction equation from the two half-reactions and calculate the cell potential from the standard potentials and predict if the reaction is reactant or product favoured. -Chemistry

Description : Two half-reactions of an electrochemical cell are given below : MnO-4 (aq) + 8H+ (aq) + 5e- → Mn2+ (aq) + 4H2O (I), E° = 1.51 V Sn2+ (aq) → Sn4+ (aq) + ... -reactions and calculate the cell potential from the standard potentials and predict if the reaction is reactant or product favoured. -Chemistry

Last Answer : The reactions can be represented at anode and at cathode in the following ways : At anode (oxidation) : Sn2+ → Sn4+ (aq) + 2e- ] 5 E° = + 0.15 V Af cathode (reduction) : MnO-4(aq) + 8H+ ( ... = E°cathode - E°anode = 1.51 - 0.15 = + 1.36 V ∴ Positive value of E°cell favours formation of product.

What is 0.51 rounded to the nearest hundredth?

Description : What is 0.51 rounded to the nearest hundredth?

Last Answer : You wouldn't do anything to this. 0.51 is another way to writefifty-one hundredths.

Is 0.15 greater than 0.51?

Description : Is 0.15 greater than 0.51?

Last Answer : No because 0.51 is greater than 0.15

Each gm of protein on complete oxidation yields (A) 0.21 gm water (B) 0.31 gm water (C) 0.41 gm water (D) 0.51 gm water

Description : Each gm of protein on complete oxidation yields (A) 0.21 gm water (B) 0.31 gm water (C) 0.41 gm water (D) 0.51 gm water

Last Answer : Answer : C

What is the insertion loss of connector type splices for a single mode optical fiber? A. 0.51 dB B. 0.49 dB C. 0.31 dB D. 0.38 db

Description : What is the insertion loss of connector type splices for a single mode optical fiber? A. 0.51 dB B. 0.49 dB C. 0.31 dB D. 0.38 db

Last Answer : D. 0.38 db

What would be the physical length of a tpical coaxial transmission line that is electrically one-quarter wavelength long at 14.1 MHz? A. 20 meters B. 3.51 meters C. 2.33 meters D. 0.25 meter

Description : What would be the physical length of a tpical coaxial transmission line that is electrically one-quarter wavelength long at 14.1 MHz? A. 20 meters B. 3.51 meters C. 2.33 meters D. 0.25 meter

Last Answer : B. 3.51 meters

Calculate the magnetic moment when a field of B= 51 units is subjected to a torque of 20 units. a) 0.39 b) 4.2 c) 2.55 d) 3.21

Description : Calculate the magnetic moment when a field of B= 51 units is subjected to a torque of 20 units. a) 0.39 b) 4.2 c) 2.55 d) 3.21

Last Answer : a) 0.39

If a function is described by F = (3x + z, y 2 − sin x 2 z, xz + ye x5 ), then the divergence theorem value in the region 0<x<1, 0<y<3 and 0<z<2 will be a) 13 b) 26 c) 39 d) 51

Description : If a function is described by F = (3x + z, y 2 − sin x 2 z, xz + ye x5 ), then the divergence theorem value in the region 0

Last Answer : c) 39

What partof 192.168.10.51 is the Network ID, assuming a default subnet mask? A. 192 B. 192.168.10 C. 0.0.0.5 D. 51 E. None of the above

Description : What partof 192.168.10.51 is the Network ID, assuming a default subnet mask? A. 192 B. 192.168.10 C. 0.0.0.5 D. 51 E. None of the above

Last Answer : 192.168.10

In the above problem, find the potential energy of the mass with respect to datum. (Formula: P = mgz/k )  a. 4875 j  b. 0.51 j  c. 0.46 j  d. None of the above

Description : In the above problem, find the potential energy of the mass with respect to datum. (Formula: P = mgz/k )  a. 4875 j  b. 0.51 j  c. 0.46 j  d. None of the above

Last Answer : 4875 j

What is the insertion loss of connector-type splices for a single mode fiber optics? ∙ a. 0.51 dB ∙ b. 0.31 dB ∙ c. 0.49 dB ∙ d. 0.38 dB

Description : What is the insertion loss of connector-type splices for a single mode fiber optics? ∙ a. 0.51 dB ∙ b. 0.31 dB ∙ c. 0.49 dB ∙ d. 0.38 dB

Last Answer : d. 0.38 dB

Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, 49, 50, 74, 75, 99,100 B. 10, 50, 75,100, 250, 1000 C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Description : Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, ... C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Last Answer : C. 0, 1,10,11, 50, 51, 75, 76,100,101

We're going to ring payphones at 51.4648N, 0.1293W and 51.5144N, 0.1388W in 15 minutes. If someone answers it with your team's name, you get the points.

Description : We're going to ring payphones at 51.4648N, 0.1293W and 51.5144N, 0.1388W in 15 minutes. If someone answers it with your team's name, you get the points.

Last Answer : (1st is at Clapham, 0207 274 6457, 2nd is at Oxford Circus, 0207 734 8401)