Is 0.15 greater than 0.51?

Is 0.15 greater than 0.51?
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No because 0.51 is greater than 0.15
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Two half-reactions of an electrochemical cell are given below : MnO–4 (aq) + 8H+ (aq) + 5e– → Mn2+ (aq) + 4H2O (I), E° = 1.51 V Sn2+ (aq) → Sn4+ (aq) + 2e–, E° = + 0.15 V. Construct the redox equation from the standard potential of the cell and predict if the reaction is reactant favoured or product favoured. -Chemistry

Description : Two half-reactions of an electrochemical cell are given below : MnO-4 (aq) + 8H+ (aq) + 5e- → Mn2+ (aq) + 4H2O (I), E° = 1.51 V Sn2+ (aq) → Sn4+ (aq) + 2e- ... the redox equation from the standard potential of the cell and predict if the reaction is reactant favoured or product favoured. -Chemistry

Last Answer : The reactions can be represented at anode and at cathode in the following ways : At anode (oxidation) : Sn2+ → = Sn4+ (aq) + 2e- ] 5 E° = + 0.15 V At cathode (reduction) : MnO-4(aq) + 8H+ ... = E°cathode - E°anode = 1.51 - 0.15 = + 1.36 V ∴ Positive value of E°cell favours formation of product.

Two half-reactions of an electrochemical cell are given below : MnO–4 (aq) + 8H+ (aq) + 5e– → Mn2+ (aq) + 4H2O (I), E° = 1.51 V Sn2+ (aq) → Sn4+ (aq) + 2e–, E° = + 0.15 V. Construct the redox reaction equation from the two half-reactions and calculate the cell potential from the standard potentials and predict if the reaction is reactant or product favoured. -Chemistry

Description : Two half-reactions of an electrochemical cell are given below : MnO-4 (aq) + 8H+ (aq) + 5e- → Mn2+ (aq) + 4H2O (I), E° = 1.51 V Sn2+ (aq) → Sn4+ (aq) + ... -reactions and calculate the cell potential from the standard potentials and predict if the reaction is reactant or product favoured. -Chemistry

Last Answer : The reactions can be represented at anode and at cathode in the following ways : At anode (oxidation) : Sn2+ → Sn4+ (aq) + 2e- ] 5 E° = + 0.15 V Af cathode (reduction) : MnO-4(aq) + 8H+ ( ... = E°cathode - E°anode = 1.51 - 0.15 = + 1.36 V ∴ Positive value of E°cell favours formation of product.

We're going to ring payphones at 51.4648N, 0.1293W and 51.5144N, 0.1388W in 15 minutes. If someone answers it with your team's name, you get the points.

Description : We're going to ring payphones at 51.4648N, 0.1293W and 51.5144N, 0.1388W in 15 minutes. If someone answers it with your team's name, you get the points.

Last Answer : (1st is at Clapham, 0207 274 6457, 2nd is at Oxford Circus, 0207 734 8401)

What is 2.51 x 1.15?

Description : What is 2.51 x 1.15?

Last Answer : 2.8865

What is 14.51 rounded to 15?

Description : What is 14.51 rounded to 15?

Last Answer : If 14.51 is rounded to 15, then it is rounding to the nearestwhole number.

Standard free energy (∆G°) of hydrolysis of creatine phosphate is (A) -–51.4 KJ/mol (B) –43.1 KJ/mol (C) –30.5 KJ/mol (D) –15.9 KJ/mol

Description : Standard free energy (∆G°) of hydrolysis of creatine phosphate is (A) -–51.4 KJ/mol (B) –43.1 KJ/mol (C) –30.5 KJ/mol (D) –15.9 KJ/mol

Last Answer : Answer : B

It takes 6 hours to dry a wet solid from 50% moisture content to the critical moisture content of 15%. How much longer it will take to dry the solid to 10% moisture content, under the same drying conditions? (The equilibrium moisture content of the solid is 5%). (A) 15 min (B) 51 min (C) 71 min (D) 94 min

Description : It takes 6 hours to dry a wet solid from 50% moisture content to the critical moisture content of 15%. How much longer it will take to dry the solid to 10% moisture content, under the same drying conditions? (The ... 5%). (A) 15 min (B) 51 min (C) 71 min (D) 94 min

Last Answer : (C) 71 min

For Q 51, find coordinates of point on circle at u=0 a.11.6, 7 b.7, 11 c.11, 7 d.11.5, 7.5

Description : For Q 51, find coordinates of point on circle at u=0 a.11.6, 7 b.7, 11 c.11, 7 d.11.5, 7.5

Last Answer : a.11.6, 7

A flywheel weighs 400 kg and has a radius of gyration of 30 cm about its axis of rotation. It is mounted on a shaft subjected to a moment of 40 kgm. If the flywheel starts from restits speed after 3 seconds wil be a.10.9 rad/sec b.19.0 rad/sec c.51.2 rad/sec d.3.33 rad/sec e.16.35 rad/sec

Description : A flywheel weighs 400 kg and has a radius of gyration of 30 cm about its axis of rotation. It is mounted on a shaft subjected to a moment of 40 kgm. If the flywheel starts from restits speed after 3 seconds wil be a.10.9 rad/sec b.19.0 rad/sec c.51.2 rad/sec d.3.33 rad/sec e.16.35 rad/sec

Last Answer : d. 3.33 rad/sec

What is 0.51 rounded to the nearest hundredth?

Description : What is 0.51 rounded to the nearest hundredth?

Last Answer : You wouldn't do anything to this. 0.51 is another way to writefifty-one hundredths.

How do you write 0.51 in words?

Description : How do you write 0.51 in words?

Last Answer : fifty-one hundredths

Each gm of protein on complete oxidation yields (A) 0.21 gm water (B) 0.31 gm water (C) 0.41 gm water (D) 0.51 gm water

Description : Each gm of protein on complete oxidation yields (A) 0.21 gm water (B) 0.31 gm water (C) 0.41 gm water (D) 0.51 gm water

Last Answer : Answer : C

What is the insertion loss of connector type splices for a single mode optical fiber? A. 0.51 dB B. 0.49 dB C. 0.31 dB D. 0.38 db

Description : What is the insertion loss of connector type splices for a single mode optical fiber? A. 0.51 dB B. 0.49 dB C. 0.31 dB D. 0.38 db

Last Answer : D. 0.38 db

What would be the physical length of a tpical coaxial transmission line that is electrically one-quarter wavelength long at 14.1 MHz? A. 20 meters B. 3.51 meters C. 2.33 meters D. 0.25 meter

Description : What would be the physical length of a tpical coaxial transmission line that is electrically one-quarter wavelength long at 14.1 MHz? A. 20 meters B. 3.51 meters C. 2.33 meters D. 0.25 meter

Last Answer : B. 3.51 meters

Calculate the magnetic moment when a field of B= 51 units is subjected to a torque of 20 units. a) 0.39 b) 4.2 c) 2.55 d) 3.21

Description : Calculate the magnetic moment when a field of B= 51 units is subjected to a torque of 20 units. a) 0.39 b) 4.2 c) 2.55 d) 3.21

Last Answer : a) 0.39

If a function is described by F = (3x + z, y 2 − sin x 2 z, xz + ye x5 ), then the divergence theorem value in the region 0<x<1, 0<y<3 and 0<z<2 will be a) 13 b) 26 c) 39 d) 51

Description : If a function is described by F = (3x + z, y 2 − sin x 2 z, xz + ye x5 ), then the divergence theorem value in the region 0

Last Answer : c) 39

What partof 192.168.10.51 is the Network ID, assuming a default subnet mask? A. 192 B. 192.168.10 C. 0.0.0.5 D. 51 E. None of the above

Description : What partof 192.168.10.51 is the Network ID, assuming a default subnet mask? A. 192 B. 192.168.10 C. 0.0.0.5 D. 51 E. None of the above

Last Answer : 192.168.10

In the above problem, find the potential energy of the mass with respect to datum. (Formula: P = mgz/k )  a. 4875 j  b. 0.51 j  c. 0.46 j  d. None of the above

Description : In the above problem, find the potential energy of the mass with respect to datum. (Formula: P = mgz/k )  a. 4875 j  b. 0.51 j  c. 0.46 j  d. None of the above

Last Answer : 4875 j

What is the insertion loss of connector-type splices for a single mode fiber optics? ∙ a. 0.51 dB ∙ b. 0.31 dB ∙ c. 0.49 dB ∙ d. 0.38 dB

Description : What is the insertion loss of connector-type splices for a single mode fiber optics? ∙ a. 0.51 dB ∙ b. 0.31 dB ∙ c. 0.49 dB ∙ d. 0.38 dB

Last Answer : d. 0.38 dB

Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, 49, 50, 74, 75, 99,100 B. 10, 50, 75,100, 250, 1000 C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Description : Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, ... C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Last Answer : C. 0, 1,10,11, 50, 51, 75, 76,100,101

Is 0.15 greater than 0.09?

Description : Is 0.15 greater than 0.09?

Last Answer : Yes it is.

A 600 mm square bearing plate settles by 15 mm in plate load test on a cohesion-less soil under an intensity of loading of 0.2 N/ram². The settlement of a prototype shallow footing 1 m square under the same intensity of loading is (A) 15 mm (B) Between 15 mm and 25 mm (C) 25 mm (D) Greater than 25 mm

Description : A 600 mm square bearing plate settles by 15 mm in plate load test on a cohesion-less soil under an intensity of loading of 0.2 N/ram². The settlement of a prototype shallow footing 1 m square under the same intensity of ... (A) 15 mm (B) Between 15 mm and 25 mm (C) 25 mm (D) Greater than 25 mm

Last Answer : Answer: Option B

For the number A[15:0] = 0110110010001111, A[14:13] is ______ A[3:2]. a. less than b. greater than c. the same as d . cannot be determined

Description : For the number A[15:0] = 0110110010001111, A[14:13] is ______ A[3:2]. a. less than b. greater than c. the same as d . cannot be determined

Last Answer : c. the same as

The diameter of earth is 12,757 kilometers the diameter of satum is 120,664 the diameters of uranus is 51,499 is the sum of these three plantes diameters more or less than jupiter diameter of 142,804 kilometers by how much answer?

Description : The diameter of earth is 12,757 kilometers the diameter of satum is 120,664 the diameters of uranus is 51,499 is the sum of these three plantes diameters more or less than jupiter diameter of 142,804 kilometers by how much answer?

Last Answer : 2

An industry employed 1200 men and 800 women and the average salary was Rs 51 per day. If a woman got Rs 10 less than a man , then what are their daily salary?(mens and women respectively) A) men Rs 25 and women Rs 35 B) men Rs 45 and women Rs 55 C) men Rs 35 and women Rs 25 D) men Rs 55 and women Rs 45

Description : An industry employed 1200 men and 800 women and the average salary was Rs 51 per day. If a woman got Rs 10 less than a man , then what are their daily salary?(mens and women respectively) A) men Rs 25 and women Rs ... Rs 45 and women Rs 55 C) men Rs 35 and women Rs 25 D) men Rs 55 and women Rs 45

Last Answer : D) Let the daily salary of man be Rs’x’ Then the daily salary of a women = Rs (x-100 Now 1200x + 800(x-10) = 51 *(1200+800) 1200x+800x -8000 = 51*2000 2000x = 102000+8000 =110000 X=55 Therefore mens daily salary Rs 55 and womens daily salary Rs 45