Each gm of protein on complete oxidation yields (A) 0.21 gm water (B) 0.31 gm water (C) 0.41 gm water (D) 0.51 gm water

Each gm of protein on complete oxidation yields (A) 0.21 gm water (B) 0.31 gm water (C) 0.41 gm water (D) 0.51 gm water
by

1 Answer

Answer :

Answer :  C
by
selected

Related questions

During which decade did the population record a negative growth rate? (a) 1921-31 (b) 1911-21 (c) 1941-51 (d) 1931-41

Description : During which decade did the population record a negative growth rate? (a) 1921-31 (b) 1911-21 (c) 1941-51 (d) 1931-41

Last Answer : Ans: (b)

During which decade did the population of India record a negative growth rate? (1) 1921-31 (2) 1911-21 (3) 1941-51 (4) 1931-41

Description : During which decade did the population of India record a negative growth rate? (1) 1921-31 (2) 1911-21 (3) 1941-51 (4) 1931-41

Last Answer : (2) 1911-21 Explanation: Negative Population growth rate or decline in population can refer to the decline in population of humans. It is a term usually used to describe any great reduction in a ... famines accounted for this decline. Plague epidemic in 1918 took a toll of 140 lakh human lives.

One gram of protein on complete oxidation in the body yields about (A) 2 Kcal (B) 4 Kcal (C) 8 Kcal (D) 12 Kcal

Description : One gram of protein on complete oxidation in the body yields about (A) 2 Kcal (B) 4 Kcal (C) 8 Kcal (D) 12 Kcal

Last Answer : Answer : B

The oxidation of 100 gm of fat yields (A) 50 gm water (B) 107 gm water (C) 150 gm water (D) 200 gm water

Description : The oxidation of 100 gm of fat yields (A) 50 gm water (B) 107 gm water (C) 150 gm water (D) 200 gm water

Last Answer : Answer : B

Water derived in gm from complete oxidation of each gm of carbohydrate is about (A) 0.15 (B) 0.25 (C) 0.35 (D) 0.55

Description : Water derived in gm from complete oxidation of each gm of carbohydrate is about (A) 0.15 (B) 0.25 (C) 0.35 (D) 0.55

Last Answer : Answer : D

Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41

Description : Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41 

Last Answer :  Answer: A (i) Percentage scored in Mathematics = 120/180 100  = 12000/180  =1200/18  = 66 2 /3 % (ii) Total maximum of all the three subjects = 150 + 160 + 200 = 510 and Total score in the ... percentage on the whole = (400/510 100)  = (40000/510)  = 4000/51  = 78 22/51 %

One gram of fat on complete oxidation in the body yields about (A) 4 Kcal (B) 6 Kcal (C) 9 Kcal (D) 12 Kcal

Description : One gram of fat on complete oxidation in the body yields about (A) 4 Kcal (B) 6 Kcal (C) 9 Kcal (D) 12 Kcal

Last Answer : Answer : C

One gram of carbohydrate on complete oxidation in the body yields about (A) 1 Kcal (B) 4 Kcal (C) 6 Kcal (D) 9 Kcal

Description : One gram of carbohydrate on complete oxidation in the body yields about (A) 1 Kcal (B) 4 Kcal (C) 6 Kcal (D) 9 Kcal

Last Answer : Answer : B

Complete oxidation of one molecule of glucose into CO2 and H2O yields (A) 8 ATP equivalents (B) 15 ATP equivalents (C) 30 ATP equivalents (D) 38 ATP equivalents

Description : Complete oxidation of one molecule of glucose into CO2 and H2O yields (A) 8 ATP equivalents (B) 15 ATP equivalents (C) 30 ATP equivalents (D) 38 ATP equivalents

Last Answer : Answer : D

Oxidation of which substance in the body yields the most calories (A) Glucose (B) Glycogen (C) Protein (D) Lipids

Description : Oxidation of which substance in the body yields the most calories (A) Glucose (B) Glycogen (C) Protein (D) Lipids

Last Answer : D

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

Based onthe Clos criteria, if N = 200, then k mustbe equal to or greater than____. A) 21 B) 19 C) 31 D) 41

Description : Based onthe Clos criteria, if N = 200, then k mustbe equal to or greater than____. A) 21 B) 19 C) 31 D) 41

Last Answer : 19

In Wheat Crown root initiation stage comes —- days after sowing a. 21 b. 11 c. 31 d. 41

Description : In Wheat Crown root initiation stage comes —- days after sowing a. 21 b. 11 c. 31 d. 41

Last Answer : a. 21

The average of 3,8,7 and a is 6 and the average of 19,2,7, a and b is 11. What is the value of b? A) 11 B) 21 C) 31 D) 41

Description : The average of 3,8,7 and a is 6 and the average of 19,2,7, a and b is 11. What is the value of b? A) 11 B) 21 C) 31 D) 41 

Last Answer : B) We have (3+8+7+a+6/5)=6 24 =a = 30 A=6 Also (19+2+7+a+b/5)=11 19+2+7+6+b=55 34+b=55 b=21

A molecule of glucose on complete oxidation yields howmany ATP molecules in case of aerobic respiration? -Do You Know?

Description : A molecule of glucose on complete oxidation yields howmany ATP molecules in case of aerobic respiration? -Do You Know?

Last Answer : answer:

A molecule of glucose on complete oxidation yields howmany ATP molecules in case of aerobic respiration?

Description : A molecule of glucose on complete oxidation yields howmany ATP molecules in case of aerobic respiration?

Last Answer : 36

How many ATP molecules could maximally be generated from one molecule of glucose, if the complete oxidation of one mole of glucose to CO2 and H2O yields 686 kcal and the useful chemical energy available in the high energy phosphate bond of one mole of ATP is 12 kcal? (a) 1 (b) 2 (c) 30 (d) 57

Description : How many ATP molecules could maximally be generated from one molecule of glucose, if the complete oxidation of one mole of glucose to CO2 and H2O yields 686 kcal and the useful chemical energy available in the high energy phosphate bond of one mole of ATP is 12 kcal? (a) 1 (b) 2 (c) 30 (d) 57

Last Answer : d) 57

CRH is a polypeptide made up of (A) 39 amino acids (B) 41 amino acids (C) 51 amino acids (D) 84 amino acids

Description : CRH is a polypeptide made up of (A) 39 amino acids (B) 41 amino acids (C) 51 amino acids (D) 84 amino acids

Last Answer : Answer : B

ACTH is a polypeptide made up of (A) 39 amino acids (B) 41 amino acids (C) 51 amino acids (D) 84 amino acids

Description : ACTH is a polypeptide made up of (A) 39 amino acids (B) 41 amino acids (C) 51 amino acids (D) 84 amino acids

Last Answer : Answer : A

Oxidation of which substance in the body yields the most calories (A) Glucose (B) Glycogen (C) Protein (D) Lipids

Description : Oxidation of which substance in the body yields the most calories (A) Glucose (B) Glycogen (C) Protein (D) Lipids

Last Answer : (D) Lipids

Hydrated density of HD lipoproteins is (A) 0.94 gm/ml (B) 0.94–1.006 gm/ml (C) 1.006–1.063 gm/ml (D) 1.063–1.21 gm/ml

Description : Hydrated density of HD lipoproteins is (A) 0.94 gm/ml (B) 0.94–1.006 gm/ml (C) 1.006–1.063 gm/ml (D) 1.063–1.21 gm/ml

Last Answer : Answer : D

Hydrated density of (HD) lipoproteins is (A) 0.94 gm/ml (B) 0.94-1.006 gm/ml (C) 1.006-1.063 gm/ml (D) 1.063-1.21 gm/l

Description : Hydrated density of (HD) lipoproteins is (A) 0.94 gm/ml (B) 0.94-1.006 gm/ml (C) 1.006-1.063 gm/ml (D) 1.063-1.21 gm/l

Last Answer : Answer : B

Oxidation of one molecule of glucose yields (A) 12 ATP (B) 24 ATP (C) 38 ATP (D) 38 ATP

Description : Oxidation of one molecule of glucose yields (A) 12 ATP (B) 24 ATP (C) 38 ATP (D) 38 ATP

Last Answer : Answer : D

Which of the following statement regarding β-oxidation is true? (A) Requires β-ketoacyl CoA as a substrate (B) Forms CoA thioesters (C) Requires GTP for its activity (D) Yields acetyl CoA as a product

Description : Which of the following statement regarding β-oxidation is true? (A) Requires β-ketoacyl CoA as a substrate (B) Forms CoA thioesters (C) Requires GTP for its activity (D) Yields acetyl CoA as a product

Last Answer : Answer : A

Oxidation of galactose with conc HNO3 yields (A) Mucic acid (B) Glucuronic acid (C) Saccharic acid (D) Gluconic acid

Description : Oxidation of galactose with conc HNO3 yields (A) Mucic acid (B) Glucuronic acid (C) Saccharic acid (D) Gluconic acid

Last Answer : A

The holder (an adult and not a minor) of a certificate who desire to make a nomination will apply in a) NC 36 b) NC 51 c) NC 10 d) NC 41

Description : The holder (an adult and not a minor) of a certificate who desire to make a  nomination will apply in a) NC 36 b) NC 51 c) NC 10 d) NC 41

Last Answer : b) NC 51

The holder (an adult and not a minor) of a certificate who desire to make a nomination will apply in a) NC 36 b) NC 51 c) NC 10 d) NC 41

Description : The holder (an adult and not a minor) of a certificate who desire to make a  nomination will apply in a) NC 36 b) NC 51 c) NC 10 d) NC 41

Last Answer : b) NC 51

An asset of Rs.85,000 was purchased for Rs.75,000 and was recorded in the books at Rs.85,000. What is the correct amount of profit to be reported in the books? a) Rs.1,47,000 b) Rs. 1,51,000 c) Rs.1,63,000 d) Rs.1,41,000

Description : An asset of Rs.85,000 was purchased for Rs.75,000 and was recorded in the books at Rs.85,000. What is the correct amount of profit to be reported in the books? a) Rs.1,47,000 b) Rs. 1,51,000 c) Rs.1,63,000 d) Rs.1,41,000

Last Answer : b) Rs. 1,51,000

The minimum and maximum clearances of check rails at all BG level crossings shall be a) 51 to 57 mm* b) 44 to 48 mm c) 41 to 45 mm d) 55 to 70 mm

Description : The minimum and maximum clearances of check rails at all BG level crossings shall be a) 51 to 57 mm* b) 44 to 48 mm c) 41 to 45 mm d) 55 to 70 mm

Last Answer : a) 51 to 57 mm*

Daily protein requirement of an adult woman is (A) 0.5 gm/kg of body weight (B) 0.8 gm/kg of body weight (C) 1.0 gm/kg of body weight (D) 1.5 gm/kg of body weight

Description : Daily protein requirement of an adult woman is (A) 0.5 gm/kg of body weight (B) 0.8 gm/kg of body weight (C) 1.0 gm/kg of body weight (D) 1.5 gm/kg of body weight

Last Answer : Answer : C

Daily protein requirement of an adult man is (A) 0.5 gm/kg of body weight (B) 0.8 gm/kg of body weight (C) 1.0 gm/kg of body weight (D) 1.5 gm/kg of body weight

Description : Daily protein requirement of an adult man is (A) 0.5 gm/kg of body weight (B) 0.8 gm/kg of body weight (C) 1.0 gm/kg of body weight (D) 1.5 gm/kg of body weight

Last Answer : Answer : C

What is the insertion loss of connector type splices for a single mode optical fiber? A. 0.51 dB B. 0.49 dB C. 0.31 dB D. 0.38 db

Description : What is the insertion loss of connector type splices for a single mode optical fiber? A. 0.51 dB B. 0.49 dB C. 0.31 dB D. 0.38 db

Last Answer : D. 0.38 db

What is the insertion loss of connector-type splices for a single mode fiber optics? ∙ a. 0.51 dB ∙ b. 0.31 dB ∙ c. 0.49 dB ∙ d. 0.38 dB

Description : What is the insertion loss of connector-type splices for a single mode fiber optics? ∙ a. 0.51 dB ∙ b. 0.31 dB ∙ c. 0.49 dB ∙ d. 0.38 dB

Last Answer : d. 0.38 dB

Insulin is made up of (A) A single polypeptide chain having 51 amino acid residues (B) A single polypeptide chain having 84 amino acid residues (C) A-chain having 21 and B-chain having 30 amino acid residues (D) A-chain having 30 and B-chain having 21 amino acid residues

Description : Insulin is made up of (A) A single polypeptide chain having 51 amino acid residues (B) A single polypeptide chain having 84 amino acid residues (C) A-chain having 21 and B-chain having 30 amino acid residues (D) A-chain having 30 and B-chain having 21 amino acid residues

Last Answer : Answer : C

What is the gain, in dB of a helical antenna with diameter of λ/3, 10 turns at pitch of λ/4, used at 100 MHz? A. 16 B. 41.1 C. 31.4 D. 1.25

Description : What is the gain, in dB of a helical antenna with diameter of λ/3, 10 turns at pitch of λ/4, used at 100 MHz? A. 16 B. 41.1 C. 31.4 D. 1.25

Last Answer : A. 16

A cantilever shaft having 50 mm diameter and a length of 300 mm has a disc of mass 100 kg at its free end. The Young’s modulus for the shaft material is 200 GN/m 2 . Determine the frequency of transverse vibrations of the shaft. a) 31 b) 35 c) 37 d) 41

Description : A cantilever shaft having 50 mm diameter and a length of 300 mm has a disc of mass 100 kg at its free end. The Young’s modulus for the shaft material is 200 GN/m 2 . Determine the frequency of transverse vibrations of the shaft. a) 31 b) 35 c) 37 d) 41

Last Answer : d) 41

The staff reading at a distance of 80 m from a level with the bubble at its centre is 1.31 m. When the bubble is moved by 5 divisions out of the centre, the reading is 1.39 m. The angular value of the one division of the bubble, is (A) 28.8 sec (B) 41.25 sec (C) 14.52 sec (D) 25.05

Description : The staff reading at a distance of 80 m from a level with the bubble at its centre is 1.31 m. When the bubble is moved by 5 divisions out of the centre, the reading is 1.39 m. The angular value of the one division of the bubble, is (A) 28.8 sec (B) 41.25 sec (C) 14.52 sec (D) 25.05

Last Answer : (B) 41.25 sec

Specific heat of air at constant pressure is equal to  (a) 0.17  (b) 0.21  (c) 0.24  (d) 1.0  (e) 1.41

Description : Specific heat of air at constant pressure is equal to  (a) 0.17  (b) 0.21  (c) 0.24  (d) 1.0  (e) 1.41

Last Answer : Answer : c

The number of amino acids in single chain polypeptide glucagons is (A) 21 (B) 29 (C) 31 (D) 39

Description : The number of amino acids in single chain polypeptide glucagons is (A) 21 (B) 29 (C) 31 (D) 39

Last Answer : Answer : B

Sufficient energy required to produce 3 ATP from 3 ADP and 3 pi is (A) –21,900 cal (B) 29,900 cal (C) 31,900 cal (D) 39,900 cal

Description : Sufficient energy required to produce 3 ATP from 3 ADP and 3 pi is (A) –21,900 cal (B) 29,900 cal (C) 31,900 cal (D) 39,900 cal

Last Answer : A

Protein bound iodine in blood is present to the extent of _______ / dL (A) 3–8 mg (B) 4–8 mg (C) 3–8 gm (D) 4–8 gm

Description : Protein bound iodine in blood is present to the extent of _______ / dL (A) 3–8 mg (B) 4–8 mg (C) 3–8 gm (D) 4–8 gm

Last Answer : Answer : A

In a person increase in weight in gms per gm of protein consumption represents (A) Protein efficiency ratio (B) Digestibility value of proteins (C) Biological value of proteins (D) Net protein utilisation

Description : In a person increase in weight in gms per gm of protein consumption represents (A) Protein efficiency ratio (B) Digestibility value of proteins (C) Biological value of proteins (D) Net protein utilisation

Last Answer : Answer : A

The gain in body weight (gm) per gm of protein ingested is known as (A) Net protein utilisation (B) Protein efficiency ratio (C) Digestibility coefficient (D) Biological value of protein

Description : The gain in body weight (gm) per gm of protein ingested is known as (A) Net protein utilisation (B) Protein efficiency ratio (C) Digestibility coefficient (D) Biological value of protein

Last Answer : Answer : B

Biological value of a protein is (A) The percentage of ingested protein/nitrogen absorbed into circulation (B) The percentage of ingested protein/nitrogen in the body (C) The percentage of ingested protein utilised for protein synthesis in the body (D) The gain in body weight (gm) per gm of protein ingested

Description : Biological value of a protein is (A) The percentage of ingested protein/nitrogen absorbed into circulation (B) The percentage of ingested protein/nitrogen in the body (C) The percentage of ingested protein utilised ... synthesis in the body (D) The gain in body weight (gm) per gm of protein ingested

Last Answer : Answer : B

The maturity value on Rs 10 denomination of RD account opened on or after 01 Dec 2011 and up to 31 Mar 12 and 01 Apr 12 is(Interest @8.4%) a) 728.29 b) 738.62, 747 c) 738.51 d) 738.10

Description : The maturity value on Rs 10 denomination of RD account opened on or after 01 Dec 2011 and up to 31 Mar 12 and 01 Apr 12 is(Interest @8.4%) a) 728.29 b) 738.62, 747 c) 738.51 d) 738.10

Last Answer : b) 738.62, 747

Compute the maximum shearing stress developed in a phosphor bronze spring having mean diameter of 200 mm and consisting of 24 turns of 20-mm diameter wire when the spring is stretched 100 mm. and G = 42 GPa. a. 51 MPa b. 31.89 MPa c. 80 MPa d. 70 MPa

Description : Compute the maximum shearing stress developed in a phosphor bronze spring having mean diameter of 200 mm and consisting of 24 turns of 20-mm diameter wire when the spring is stretched 100 mm. and G = 42 GPa. a. 51 MPa b. 31.89 MPa c. 80 MPa d. 70 MPa

Last Answer : b. 31.89 MPa

Calculate the magnetic moment when a field of B= 51 units is subjected to a torque of 20 units. a) 0.39 b) 4.2 c) 2.55 d) 3.21

Description : Calculate the magnetic moment when a field of B= 51 units is subjected to a torque of 20 units. a) 0.39 b) 4.2 c) 2.55 d) 3.21

Last Answer : a) 0.39

Biological value of egg protein is (A) 94 (B) 60 (C) 51 (D) 40

Description : Biological value of egg protein is (A) 94 (B) 60 (C) 51 (D) 40

Last Answer : Answer : A

A beam 3m long simply supported at its ends ,is carrying a point load W at the centre.If the slope at the ends of the beam should not exceed 10,find the deflection at the centre of beam? a.18.41 mm b.13.45 mm c.17.45 mm d.21.67 mm.

Description : A beam 3m long simply supported at its ends ,is carrying a point load W at the centre.If the slope at the ends of the beam should not exceed 10,find the deflection at the centre of beam? a.18.41 mm b.13.45 mm c.17.45 mm d.21.67 mm.

Last Answer : c.17.45 mm

Compared to the resting state, vigorously contracting muscle shows (A) An increased conversion of pyruvate to lactate (B) Decreased oxidation of pyruvate of CO2 and water (C) A decreased NADH/NAD+ ratio (D) Decreased concentration of AMP CARBOHYDRATES AND CARBOHYDRATE METABOLISM 21

Description : Compared to the resting state, vigorously contracting muscle shows (A) An increased conversion of pyruvate to lactate (B) Decreased oxidation of pyruvate of CO2 and water (C) A decreased NADH/NAD+ ratio (D) Decreased concentration of AMP CARBOHYDRATES AND CARBOHYDRATE METABOLISM 21

Last Answer : A