How do i do this question The gradient of the line joining (-13) to (pq) is -2. The gradient of the line joining (pq) to (52) is -1. Calculate the values of p and q?

How do i do this question The gradient of the line joining (-13) to (pq) is -2. The gradient of the line joining (pq) to (52) is -1. Calculate the values of p and q?
by

1 Answer

Answer :

If you mean point of (-1, 3) with a gradient of -2 and point (5,2) with a gradient of -1 then as straight line equations they workout as y = -2x+1 and y = -x+4 respectively.As to the values of p and q not enough information has beengiven.
by

Related questions

Points P,Q,R(in this order) divide the line joining the points A(-2,2) and B(2,8) into four equal parts. The coordinates of the point Q are: (a) (-1,7/2) (b) (1,13/2) (c) (0,5) (d) (5,1/2)

Description : Points P,Q,R(in this order) divide the line joining the points A(-2,2) and B(2,8) into four equal parts. The coordinates of the point Q are: (a) (-1,7/2) (b) (1,13/2) (c) (0,5) (d) (5,1/2)

Last Answer : (c) (0,5)

In trapezium ABCD, AB || DC and L is the mid-point of BC. Through L, a line PQ || AD has been drawn which meets AB in P and DC produced in Q. -Maths 9th

Description : In trapezium ABCD, AB || DC and L is the mid-point of BC. Through L, a line PQ || AD has been drawn which meets AB in P and DC produced in Q. -Maths 9th

Last Answer : According to question prove that ar (ABCD) = ar (APQD).

In trapezium ABCD, AB || DC and L is the mid-point of BC. Through L, a line PQ || AD has been drawn which meets AB in P and DC produced in Q. -Maths 9th

Description : In trapezium ABCD, AB || DC and L is the mid-point of BC. Through L, a line PQ || AD has been drawn which meets AB in P and DC produced in Q. -Maths 9th

Last Answer : According to question prove that ar (ABCD) = ar (APQD).

If P, Q and R are three points on a line and Q is between P and R,then prove that PR - QR= PQ. -Maths 9th

Description : If P, Q and R are three points on a line and Q is between P and R,then prove that PR - QR= PQ. -Maths 9th

Last Answer : Solution :-

PQ and RS are two equal and parallel line segments.Any points M not lying on PQ or RS is joined to Q and S and lines through P parallel to SM meet at N.Prove that line segments MN and PQ are equal and parallel to each other. -Maths 9th

Description : PQ and RS are two equal and parallel line segments.Any points M not lying on PQ or RS is joined to Q and S and lines through P parallel to SM meet at N.Prove that line segments MN and PQ are equal and parallel to each other. -Maths 9th

Last Answer : hope its clear

Two circles with centre O and O' intersect at two points A and B. A line PQ is drawn parallel to OO' through B intersecting the circles at P and Q. Prove that PQ = 2 OO'. -Maths 9th

Description : Two circles with centre O and O' intersect at two points A and B. A line PQ is drawn parallel to OO' through B intersecting the circles at P and Q. Prove that PQ = 2 OO'. -Maths 9th

Last Answer : Solution :- Construction: Draw two circles having centres O and O' intersecting at points A and B. Draw a parallel line PQ to OO' ... iii) Again, OO' = MN [As OO' NM is a rectangle] ...(iv) ⇒ 2OO' = PQ Hence proved.

A combination of four resistances is shown in Fig. 4.59. Calculate the potential difference between the points P and Q, and the values of currents flo

Description : A combination of four resistances is shown in Fig. 4.59. Calculate the potential difference between the points P and Q, and the values of currents flo

Last Answer : A combination of four resistances is shown in Fig. 4.59. Calculate the potential difference ... of currents flowing in the different resistances.

When two concurrent and coplaner forces P and Q act at an angle of 180?, their resultant will be a a.moment equal to PQ b.couple c.(P-Q) d.107 dynes e.zero

Description : When two concurrent and coplaner forces P and Q act at an angle of 180?, their resultant will be a a.moment equal to PQ b.couple c.(P-Q) d.107 dynes e.zero

Last Answer : c. (P-Q)

ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that: (i) SR || AC and SR = 1/2 AC (ii) PQ = SR (iii) PQRS is a parallelogram. -Maths 9th

Description : ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that: (i) SR || AC and SR = 1/2 AC (ii) PQ = SR (iii) PQRS is a parallelogram. -Maths 9th

Last Answer : . Solution: (i) In ΔDAC, R is the mid point of DC and S is the mid point of DA. Thus by mid point theorem, SR || AC and SR = ½ AC (ii) In ΔBAC, P is the mid point of AB and Q is the mid point of BC. ... ----- from question (ii) ⇒ SR || PQ - from (i) and (ii) also, PQ = SR , PQRS is a parallelogram.

Points P and Q have been taken on opposite sides AB and CD, respectively of a parallelogram ABCD such that AP = CQ. Show that AC and PQ bisect each other. -Maths 9th

Description : Points P and Q have been taken on opposite sides AB and CD, respectively of a parallelogram ABCD such that AP = CQ. Show that AC and PQ bisect each other. -Maths 9th

Last Answer : According to question parallelogram ABCD such that AP = CQ.

If bisectors of opposite angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle. -Maths 9th

Description : If bisectors of opposite angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle. -Maths 9th

Last Answer : Given, ABCD is a cyclic quadrilateral. DP and QB are the bisectors of ∠D and ∠B, respectively. To prove PQ is the diameter of a circle. Construction Join QD and QC.

Points P and Q have been taken on opposite sides AB and CD, respectively of a parallelogram ABCD such that AP = CQ. Show that AC and PQ bisect each other. -Maths 9th

Description : Points P and Q have been taken on opposite sides AB and CD, respectively of a parallelogram ABCD such that AP = CQ. Show that AC and PQ bisect each other. -Maths 9th

Last Answer : According to question parallelogram ABCD such that AP = CQ.

If bisectors of opposite angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle. -Maths 9th

Description : If bisectors of opposite angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle. -Maths 9th

Last Answer : Given, ABCD is a cyclic quadrilateral. DP and QB are the bisectors of ∠D and ∠B, respectively. To prove PQ is the diameter of a circle. Construction Join QD and QC.

In angle PQR angle P = 80 .If PQ =PR find angle Q and angle R -Maths 9th

Description : In angle PQR angle P = 80 .If PQ =PR find angle Q and angle R -Maths 9th

Last Answer : a triangle includes 3 angles summing up as 180° so 180 =

Using data p=3, q=11, n=pq, d=7 in RSA algorithm find the cipher text of the given plain text SUZANNE (A) BUTAEEZ (B) SUZANNE (C) XYZABCD (D) ABCDXYZ

Description : Using data p=3, q=11, n=pq, d=7 in RSA algorithm find the cipher text of the given plain text SUZANNE (A) BUTAEEZ (B) SUZANNE (C) XYZABCD (D) ABCDXYZ

Last Answer : (A) BUTAEEZ

Let us assume that you construct ordered tree to represent the compound proposition (~(p˄q))↔(~p˅~q). Then, the prefix expression and post-fix expression determined using this ordered tree are given as ........... and ............. respectively. (A) ↔~˄pq˅ ~~pq, pq˄~p~q~˅↔ (B) ↔~˄pq˅ ~p~q, pq˄~p~q~˅↔ (C) ↔~˄pq˅ ~~pq, pq˄~p~ ~q˅↔ (D) ↔~˄pq˅ ~p~q, pq˄~p~~q˅↔

Description : Let us assume that you construct ordered tree to represent the compound proposition (~(p˄q))↔(~p˅~q). Then, the prefix expression and post-fix expression determined using this ordered tree are given as ........... and .......... ... ~p~q~˅↔ (C) ↔~˄pq˅ ~~pq, pq˄~p~ ~q˅↔ (D) ↔~˄pq˅ ~p~q, pq˄~p~~q˅↔

Last Answer : (B) ↔~˄pq˅ ~p~q, pq˄~p~q~˅↔

If the mean of P, Q,R is A and PQ + QR + RP =0, then the mean of p^2,Q^2,R^2 is. A) 2A^2 B) 4A^2 C) A^2 D) 3A^2

Description : If the mean of P, Q,R is A and PQ + QR + RP =0, then the mean of p^2,Q^2,R^2 is. A) 2A^2 B) 4A^2 C) A^2 D) 3A^2

Last Answer : D) We have (P + Q + R)/3 = A P+Q+R = 3A (P+Q+R)^2 = 9A^2 P^2+Q^2+R^2 + 2 (PQ + QR + PR) = 9A^2 P^2+Q^2+R^2 = 9A^2 Required mean = (P^2+Q^2+R^2)/3 = 9A^2/3= 3A^2

The line segment joining P(5, –2) and Q(9, 6) is divided in the ratio 3 : 1 by a point A -Maths 9th

Description : The line segment joining P(5, –2) and Q(9, 6) is divided in the ratio 3 : 1 by a point A -Maths 9th

Last Answer : Comparing y = 5\(x\) –7 with y = m\(x\) + c, the slope of given line = m = 5 ∴ Equation of a line parallel to y = 5\(x\) – 7 having y-intercept = –1 is y = 5\(x\) – 1.

Points P, Q, R and S divide a line segment joining A (2, 6) and B (7, -4) in five equal parts. Find the coordinates of P and R. -Maths 9th

Description : Points P, Q, R and S divide a line segment joining A (2, 6) and B (7, -4) in five equal parts. Find the coordinates of P and R. -Maths 9th

Last Answer : this is the ans hope its clear

An imaginary line joining the points of equal elevation on the surface of the earth, represents (A) Contour surface (B) Contour gradient (C) Contour line (D) Level line

Description : An imaginary line joining the points of equal elevation on the surface of the earth, represents (A) Contour surface (B) Contour gradient (C) Contour line (D) Level line

Last Answer : (C) Contour line

Which algorithm includes repeated addition of two predetermined values A and S to a product P and then performs a rightward arithmetic shift on P. 49 50. 51. 52. 53. 54. 55. a. Booth’s algorithm b. Usual algorithm c. Multiplication algorithm d. None of these

Description : Which algorithm includes repeated addition of two predetermined values A and S to a product P and then performs a rightward arithmetic shift on P. a. Booth’s algorithm b. Usual algorithm c. Multiplication algorithm d. None of these

Last Answer : a. Booth’s algorithm

ABCD is a square. P, Q, R, S are the mid-points of AB, BC, CD and DA respectively. By joining AR, BS, CP, DQ, we get a quadrilateral which is a -Maths 9th

Description : ABCD is a square. P, Q, R, S are the mid-points of AB, BC, CD and DA respectively. By joining AR, BS, CP, DQ, we get a quadrilateral which is a -Maths 9th

Last Answer : According to the given statement, the figure will be a shown alongside; using mid-point theorem: In △ABC,PQ∥AC and PQ=21 AC .......(1) In △ADC,SR∥AC and SR=21 AC .... ... are perpendicular to each other) ∴PQ⊥QR(angle between two lines = angle between their parallels) Hence PQRS is a rectangle.

Pick out the wrong statement. (A) The Reynolds analogy for mass transfer is given by Lewis relation and is applicable, when Schmidt number is one (B) Sherwood number for flow in pipes can be expressed as the ratio of the concentration gradient at wall to the overall concentration difference (C) According to film theory for equimolar counter diffusion, the mass transfer coefficient is given by DAB(B)P - 3, Q - 2 (D) The z-component of the total mass flux of a component A in binary mixture of A and B is given by - Dab'.dCA/dz

Description : Pick out the wrong statement. (A) The Reynolds analogy for mass transfer is given by Lewis relation and is applicable, when Schmidt number is one (B) Sherwood number for flow in pipes can be expressed ... flux of a component A in binary mixture of A and B is given by - Dab'.dCA/dz

Last Answer : (C) According to film theory for equimolar counter diffusion, the mass transfer coefficient is given by DAB(B)P - 3, Q - 2

P, Q and R have to share 52 apples among themselves such that P gets thrice as many applies as Q gets and Q gets thrice as many as R gets. Find the nu

Description : P, Q and R have to share 52 apples among themselves such that P gets thrice as many applies as Q gets and Q gets thrice as many as R gets. Find the nu

Last Answer : P, Q and R have to share 52 apples among themselves such that P gets thrice as many applies as Q ... R gets. Find the number of apples R must get.

Five persons M, N, O, P and Q request a bank for safety lockers. There are only 6 lockers available which are numbered from 52 to 57. The conditions are as follows: I. M’s locker number is 2 less than O’s lockers number. II. Lockers of N and P are next to each other. If N’s locker number is 52 then M’s locker number could be a) 52 or 53 only b) 53 or 54 only c) 54 or 55 only d) 53 or 55 only

Description : Five persons M, N, O, P and Q request a bank for safety lockers. There are only 6 lockers available which are numbered from 52 to 57. The conditions are as follows: I. M's locker number is 2 less than O's lockers ... could be a) 52 or 53 only b) 53 or 54 only c) 54 or 55 only d) 53 or 55 only

Last Answer : c) 54 or 55 only

Five persons M, N, O, P and Q request a bank for safety lockers. There are only 6 lockers available which are numbered from 52 to 57. The conditions are as follows: I. M’s locker number is 2 less than O’s lockers number. II. Lockers of N and P are next to each other. 14. If Q’s locker number is 54 and N’s locker number is greater than Q’s locker number, then which locker number is not allocated? a) locker 52 b) locker 53 c) locker 54 d)locker 56

Description : Five persons M, N, O, P and Q request a bank for safety lockers. There are only 6 lockers available which are numbered from 52 to 57. The conditions are as follows: I. M's locker number is 2 less ... , then which locker number is not allocated? a) locker 52 b) locker 53 c) locker 54 d)locker 56

Last Answer : a) locker 52

If the potential is given by, V = 10sin θ cosφ/r, find the density at the point P(2, π/2, 0) (in 10 -12 units) a) 13.25 b) 22.13 c) 26.31 d) 31.52

Description : If the potential is given by, V = 10sin θ cosφ/r, find the density at the point P(2, π/2, 0) (in 10 -12 units) a) 13.25 b) 22.13 c) 26.31 d) 31.52

Last Answer : b) 22.13

In the figure, PSDA is a parallelogram. Points Q and R are taken on PS such that PQ = QR= RS and PA || QB || RC. -Maths 9th

Description : In the figure, PSDA is a parallelogram. Points Q and R are taken on PS such that PQ = QR= RS and PA || QB || RC. -Maths 9th

Last Answer : Given In a parallelogram PSDA, points 0 and R are on PS such that PQ = QR = RS and PA || QB || RC. To prove ar (PQE) = ar (CFD) Proof In parallelogram PABQ, and PA||QB [given] So, ... = ΔDCF [by ASA congruence rule] ∴ ar (ΔPQE) = ar (ΔCFD) [since,congruent figures have equal area] Hence proved.

In the figure, PSDA is a parallelogram. Points Q and R are taken on PS such that PQ = QR= RS and PA || QB || RC. -Maths 9th

Description : In the figure, PSDA is a parallelogram. Points Q and R are taken on PS such that PQ = QR= RS and PA || QB || RC. -Maths 9th

Last Answer : Given In a parallelogram PSDA, points 0 and R are on PS such that PQ = QR = RS and PA || QB || RC. To prove ar (PQE) = ar (CFD) Proof In parallelogram PABQ, and PA||QB [given] So, ... = ΔDCF [by ASA congruence rule] ∴ ar (ΔPQE) = ar (ΔCFD) [since,congruent figures have equal area] Hence proved.

Point A(5, 1) is the centre of the circle with radius 13 units. AB ⊥ chord PQ. B is (2, –3). The length of chord PQ is -Maths 9th

Description : Point A(5, 1) is the centre of the circle with radius 13 units. AB ⊥ chord PQ. B is (2, –3). The length of chord PQ is -Maths 9th

Last Answer : (c) ParallelogramAB = \(\sqrt{(4-7)^2+(5-6)^2}\) = \(\sqrt{9+1}\) = \(\sqrt{10}\)BC = \(\sqrt{(7-4)^2+(6-3)^2}\) = \(\sqrt{9+9}\) = \(3\sqrt2\)CD =\(\sqrt{(4-1)^2+(3-2) ... = \(2\sqrt{13}\)AB = CD, BC = AD and AC ≠ BD ⇒ opposite sides are equal and diagonals are not equal. ⇒ ABCD is a parallelogram.

P and O are points on opposite sides AD and BC of a parallelogram ABCD such that PQ passes through the point of intersection O of its diagonals AC and BD. -Maths 9th

Description : P and O are points on opposite sides AD and BC of a parallelogram ABCD such that PQ passes through the point of intersection O of its diagonals AC and BD. -Maths 9th

Last Answer : According to question PQ passes through the point of intersection O of its diagonals AC and BD.

P and O are points on opposite sides AD and BC of a parallelogram ABCD such that PQ passes through the point of intersection O of its diagonals AC and BD. -Maths 9th

Description : P and O are points on opposite sides AD and BC of a parallelogram ABCD such that PQ passes through the point of intersection O of its diagonals AC and BD. -Maths 9th

Last Answer : According to question PQ passes through the point of intersection O of its diagonals AC and BD.

In the given figure, (not drawn to scale), P is a point on AB such that AP : PB = 4 : 3. PQ is parallel to AC and QD -Maths 9th

Description : In the given figure, (not drawn to scale), P is a point on AB such that AP : PB = 4 : 3. PQ is parallel to AC and QD -Maths 9th

Last Answer : answer:

`PQR` is a triangular park with `PQ=PR=200m`. A.T.V. tower stands at the mid-point of `QR`. If the angles of elevation of the top of the tower at `P`,

Description : `PQR` is a triangular park with `PQ=PR=200m`. A.T.V. tower stands at the mid-point of `QR`. If the angles of elevation of the top of the tower at `P`,

Last Answer : `PQR` is a triangular park with `PQ=PR=200m`. A.T.V. tower stands at the mid-point of `QR`. If the angles of ... (3)` B. `50sqrt(2)` C. `100` D. `50`

P, Q and R jointly thought of engaging themselves in a business venture. It was agreed that P would invest Rs. 3250 for 6 months, Q, Rs. 4200 for 5 months and R, Rs. 5,000 for 3 months. P wants to be the working member for which, he was to receive 10% of the profits. The profit earned was Rs. 3700. Calculate the share of Q in the profit. A) Rs. 1800 B) Rs. 1260 C) Rs. 1580 D) Rs. 1940

Description : P, Q and R jointly thought of engaging themselves in a business venture. It was agreed that P would invest Rs. 3250 for 6 months, Q, Rs. 4200 for 5 months and R, Rs. 5,000 for 3 months. P wants to be the ... Calculate the share of Q in the profit. A) Rs. 1800 B) Rs. 1260 C) Rs. 1580 D) Rs. 1940

Last Answer : Answer: B) For managing, P received = 10% of Rs. 3700 = Rs. 370. Balance = Rs. (3700 - 370) = Rs. 3330. Ratio of their investments = (3250 x 6) : (4200 x 5) : (5000 x 3)  = 19500 : 21000 : 15000  = 13 : 14 : 10 Q's share = Rs. 3330x 14 / 37 = Rs. 1260

In what ratio is the line joining the points A(4, 4) and B(7, 7) divided by P(–1, –1)? -Maths 9th

Description : In what ratio is the line joining the points A(4, 4) and B(7, 7) divided by P(–1, –1)? -Maths 9th

Last Answer : Let ABCD be the given square and let A ≡ (3, 4) and C ≡ (1, -1). Also let B ≡ (x, y). ABCD being a square,AB = BC ⇒ AB2 = BC2, ∠ABC = 90º⇒ \(\big(\sqrt{(x-3)^2+(y-4)^2}\big)^2\) = \(\big(\sqrt{(x-1)^2+(y+1 ... \(rac{9}{2}\),\(rac{1}{2}\)\(\bigg)\)and \(\bigg(\)\(-rac{1}{2}\), \(rac{5}{2}\)\(\bigg)\)

Points P (5, -3) is one of the two points of trisection of the line segment joining points A(7, -2) and B(1, -5) near to A. find the coordinates of the other point of trisection. -Maths 9th

Description : Points P (5, -3) is one of the two points of trisection of the line segment joining points A(7, -2) and B(1, -5) near to A. find the coordinates of the other point of trisection. -Maths 9th

Last Answer : answer:

The ratio in which P ( , B(2,-5) is : (a) 1:5 (b) 5:1 ) divides the line segment joining the points A ( , (c) 1:4 ) and (d) 4:1

Description : The ratio in which P ( , B(2,-5) is : (a) 1:5 (b) 5:1 ) divides the line segment joining the points A ( , (c) 1:4 ) and (d) 4:1

Last Answer : (a) 1:5

When (x^3 – 2x^2 + px – q) is divided by (x^2 – 2x – 3), the remainder is (x – 6), What are the values of p and q respectively ? -Maths 9th

Description : When (x^3 – 2x^2 + px – q) is divided by (x^2 – 2x – 3), the remainder is (x – 6), What are the values of p and q respectively ? -Maths 9th

Last Answer : answer:

If the expression (px^3 + x^2 – 2x – q) is divisible by (x – 1) and (x + 1), then the values of p and q respectively are ? -Maths 9th

Description : If the expression (px^3 + x^2 – 2x – q) is divisible by (x – 1) and (x + 1), then the values of p and q respectively are ? -Maths 9th

Last Answer : Let f(x)=px3+x2−2x−q Since f(x) is divisible by (x−1) and (x+1) so x=1 and −1 must make f(x)=0. Therefore, p+1−2−q=0, i.e., p−q=1; and −p+1+2−q=0, i.e., p+q=3 Thus p=2 and q=1

Calculate the average gradient along the two stations A and B, if the horizontal distance -SST 10th

Description : Calculate the average gradient along the two stations A and B, if the horizontal distance -SST 10th

Last Answer : Vertical interval/Horizontal equivalent = 240/1,200 = 1/5 or 1 : 5

Three pipes P, Q and R can fill a tank from empty to full in 40 minutes, 15 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. P, Q and R discharge chemical solutions X, Y and Z respectively. What is the proportion of the solution Y in the liquid in the tank after 5 minutes? a) 8 / 15 b) 7 / 15 c) 8 / 17 d) 6 / 13 e) 8 / 13

Description : Three pipes P, Q and R can fill a tank from empty to full in 40 minutes, 15 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. P, Q and R discharge chemical solutions X, Y and Z respectively. ... 5 minutes? a) 8 / 15 b) 7 / 15 c) 8 / 17 d) 6 / 13 e) 8 / 13

Last Answer : a Part of the tank filled by pipe P in 1 minute = 1 / 40 Part of the tank filled by pipe Q in 1 minute = 1 / 15 Part of the tank filled by pipe R in 1 minute = 1/ 30 Here we have to find the proportion of ... together in 5 minute = 5 1/8 = 5/ 8 Required proportion = (1/3) / ( 5/8) = 8 / 15

Using the RSA public key crypto system, if p=13, q=31 and d=7, then the value of e is (A) 101 (B) 105 (C) 103 (D) 107

Description : Using the RSA public key crypto system, if p=13, q=31 and d=7, then the value of e is (A) 101 (B) 105 (C) 103 (D) 107

Last Answer : (C) 103 Explanation: Basic RSA Algorithm: 1. Choose two primes, p & q. 2. Compute n=p*q and z=(p-1)*(q-1). 3. Choose a number relatively prime to z and call it d. 4. Find e such that e*d= ... each of these in turn by 7 to see which is divisible by 7, we find that 721/7 = 103, hence e = 103. 

Using p=3, q=13, d=7 and e=3 in the RSA algorithm, what is the value of ciphertext for a plain text 5? (A) 13 (B) 21 (C) 26 (D) 33

Description : Using p=3, q=13, d=7 and e=3 in the RSA algorithm, what is the value of ciphertext for a plain text 5? (A) 13 (B) 21 (C) 26 (D) 33

Last Answer : Answer: Marks to all Explanation: p=3, q=13, d=7, e=3, M=5, C=? C = Me mod n n = p*q  = 3*13 = 39 C = 53 mod 39 = 8 Answer is 8.

Taps P, Q and R can fill a tank in 3, 4 and 5 hours respectively. If all the taps are opened together and after 30 minutes taps Q and R are turned off, find the total time in which the tank is full. A) 2(3/8)hrs B) 1(1/7)hrs C) 2(13/40)hrs D) 3(13/43)hrs

Description : Taps P, Q and R can fill a tank in 3, 4 and 5 hours respectively. If all the taps are opened together and after 30 minutes taps Q and R are turned off, find the total time in which the tank is full. A) 2(3/8)hrs B) 1(1/7)hrs C) 2(13/40)hrs D) 3(13/43)hrs

Last Answer : C In 1 hr P, Q, R = 1/3+1/4+1/5 = 20+15+12/60 = 47/60 Filled in 30m = 47/120 Remaining = 1-47/120 =73/120 Tap P = 3*73/120= 219/120 Total = 219/120+1/2 =219+60 /120= 279/120= 2 13/40 hrs

P , Q, R hired a van for Rs. 640 and used it for 11,12,13 hours respectively. Hire changes paid by Q were. A) 213 B) 312 C) 123 D) 412

Description :  P , Q, R hired a van for Rs. 640 and used it for 11,12,13 hours respectively. Hire changes paid by Q were. A) 213 B) 312 C) 123 D) 412

Last Answer : Answer: A) P : Q : R = 11 : 12 : 13 Hire changes paid by Q = Rs.(640 * 12/36) = Rs. 7680 / 36 = Rs.213 (approx.)

The amounts of P, Q and R in the ratio 3:4:5 and their spending are in the ratio 4:5:6. If P saves 1/6th of his income then then savings of P, Q, R are in the ratio A) 18:11:3. B) 12:13:4. C) 4:11:18. D) None

Description : The amounts of P, Q and R in the ratio 3:4:5 and their spending are in the ratio 4:5:6. If P saves 1/6th of his income then then savings of P, Q, R are in the ratio A) 18:11:3. B) 12:13:4. C) 4:11:18. D) None

Last Answer : Answer: C)  Income of P,Q,R = 3x:4x:5x Expense of 4:5:6=4y:5y:6y.  Savings [income –expenditure]  =3x-4y :4x-5y :5x-6y------->1  Given 3x-4y=x/6  y=17x/24  Sub if (1) is,  =3x-4(17x/24) :4x-5(17x/24) :5x-6(17x/24)  =8x:22x:36x  = 4:11:18

Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 25.62 rad/sec B 20.78 rad/sec C 14.4 rad/sec D 15.33 rad/sec

Description : Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 25.62 rad/sec B 20.78 rad/sec C 14.4 rad/sec D 15.33 rad/sec

Last Answer : A 25.62 rad/sec