Is 0.02 greater than 0.0200?

Is 0.02 greater than 0.0200?
by

1 Answer

Answer :

No. Equal.
by

Related questions

Is 0.02 greater than 0.0200?

Description : Is 0.02 greater than 0.0200?

Last Answer : No. Equal.

Which of the following statements is an interpretation of the METAR? 00000KT 0200 R14/0800U R16/P1500U FZFG VV001 m03/m03 Q1022 BECMG 0800 = a. Meteorological visibility 200m, RVR for runway 16 1500m, temperature -3°C, vertical visibility 100m b. Meteorological visibility 200ft, RVR for runway 16 more than 1500m, vertical visibility 100ft, fog with hoar frost c. Meteorological visibility for runway 14 800m, fog with hoar frost, RVR for runway 16 more than 1500m d. RVR for runway 14 800m, vertical visibility 100ft, calm, meteorological visibility improving to 800m in the next 2 hours

Description : Which of the following statements is an interpretation of the METAR?   00000KT 0200 R14/0800U R16/P1500U FZFG VV001 m03/m03 Q1022 BECMG 0800 =  a. Meteorological visibility 200m, RVR for ... 800m, vertical visibility 100ft, calm, meteorological visibility  improving to 800m in the next 2 hours

Last Answer : d. RVR for runway 14 800m, vertical visibility 100ft, calm, meteorological visibility  improving to 800m in the next 2 hours

Which of the following statements is an interpretation of the METAR? 00000KT 0200 R14/0800U R16/P1500U FZFG VV001 m03/m03 Q1022 BECMG 0800 = a. Meteorological visibility 200m, RVR for runway 16 1500m, temperature -3°C, vertical visibility 100m b. Meteorological visibility 200ft, RVR for runway 16 more than 1500m, vertical visibility 100ft, fog with hoar frost c. Meteorological visibility for runway 14 800m, fog with hoar frost, RVR for runway 16 more than 1500m d. RVR for runway 14 800m, vertical visibility 100ft, calm, meteorological visibility improving to 800m in the next 2 hours

Description : Which of the following statements is an interpretation of the METAR? 00000KT 0200 R14/0800U R16/P1500U FZFG VV001 m03/m03 Q1022 BECMG 0800 = a. Meteorological visibility 200m, RVR for ... 14 800m, vertical visibility 100ft, calm, meteorological visibility improving to 800m in the next 2 hours

Last Answer : d. RVR for runway 14 800m, vertical visibility 100ft, calm, meteorological visibility improving to 800m in the next 2 hours

Which is greater 0.02 or 0.002?

Description : Which is greater 0.02 or 0.002?

Last Answer : Answers is the place to go to get the answers you need and to ask the questions you want

Is 1.02 greater than 1.22?

Description : Is 1.02 greater than 1.22?

Last Answer : No, it is smaller.1.02 is 0.20 less than 1.22

Is 1.02 greater than 1.22?

Description : Is 1.02 greater than 1.22?

Last Answer : No, it is smaller.1.02 is 0.20 less than 1.22

Is .003 seconds faster than 0.02 seconds?

Description : Is .003 seconds faster than 0.02 seconds?

Last Answer : .003 is faster than .005

Is .003 seconds faster than 0.02 seconds?

Description : Is .003 seconds faster than 0.02 seconds?

Last Answer : .003 is faster than .005

Stoke's law does not hold good if the size of particle is smaller than (A) 0.0002 mm (B) 0.002 mm (C) 0.02 mm (D) 0.2 mm

Description : Stoke's law does not hold good if the size of particle is smaller than (A) 0.0002 mm (B) 0.002 mm (C) 0.02 mm (D) 0.2 mm

Last Answer : (A) 0.0002 mm

Can you distinguish the difference of 0.2 and 0.02?

Description : Can you distinguish the difference of 0.2 and 0.02?

Last Answer : Pls answer!!!☹☹☹☹

Drinking of mineral water with very low levels of pesticides (about 0.02 ppm) for long periods may:

Description : Drinking of mineral water with very low levels of pesticides (about 0.02 ppm) for long periods may:

Last Answer : Drinking of mineral water with very low levels of pesticides (about 0.02 ppm) for long ... . cause leukaemia D. Produce immunity against mosquito.

The radius of a sphere is 8 cm and 0.02 cm is the error in its measurement. Find the approximate error in its volume.

Description : The radius of a sphere is 8 cm and 0.02 cm is the error in its measurement. Find the approximate error in its volume.

Last Answer : The radius of a sphere is 8 cm and 0.02 cm is the error in its measurement. Find the approximate error in its volume.

If mass of `KHC_(2)O_(4)` (potassium acid oxalate) required to reduce 100 mL of 0.02 M `KMnO_(4)` in acidic medium is x g and to neutralise 100 mL of

Description : If mass of `KHC_(2)O_(4)` (potassium acid oxalate) required to reduce 100 mL of 0.02 M `KMnO_(4)` in acidic medium is x g and to neutralise 100 mL of

Last Answer : If mass of `KHC_(2)O_(4)` (potassium acid oxalate) required to reduce 100 mL of 0.02 M `KMnO_(4)` in acidic ... y is 1g D. If x is 11g then y is 5.5g

At a given temperature \( PbI _{2} \) will be more soluble in(a) \( 0.4 M Pb \left( NO _{3}\right)_{2} \)(b) \( 0.02 M Na 1 \) when(c) \( 0.02 MKI \)(d) water \( PbI _{2} \rightleftharpoons Pb ^{+} \)

Description : At a given temperature \( PbI _{2} \) will be more soluble in(a) \( 0.4 M Pb \left( NO _{3}\right)_{2} \)(b) \( 0.02 M Na 1 \) when(c) \( 0.02 MKI \)(d) water \( PbI _{2} \rightleftharpoons Pb ^{+} \)

Last Answer : At a given temperature \( PbI _{2} \) will be more soluble in (a) \( 0.4 M Pb \left( NO _{3}\ ... (d) water \( PbI _{2} \rightleftharpoons Pb ^{+} \)

How would you find the product in 30.6 multiply 0.02?

Description : How would you find the product in 30.6 multiply 0.02?

Last Answer : 0.612

What is 0.02 x 0.7?

Description : What is 0.02 x 0.7?

Last Answer : 0.014

How much is 0.02 Percent Of 8000?

Description : How much is 0.02 Percent Of 8000?

Last Answer : 0.02% x 8000 = 1.6

What is 0.02 times 0.7?

Description : What is 0.02 times 0.7?

Last Answer : Need answer

What is 0.02 divided by 2.44?

Description : What is 0.02 divided by 2.44?

Last Answer : 0.0082

What number falls in the middle of 0.02 and 0.03?

Description : What number falls in the middle of 0.02 and 0.03?

Last Answer : It is: (0.02+0.03)/2 = 0.025

What is 0.02 in word form?

Description : What is 0.02 in word form?

Last Answer : I don’t know

Put these in decimal order 22.2,-0.2,2.02 staring with the smallest?

Description : Put these in decimal order 22.2,-0.2,2.02 staring with the smallest?

Last Answer : -0.2

A 0.22 M solution of lactic acid (pKa 3.9) was found to contain 0.20 M in the dissociated form and 0.02 M undissociated form, the pH of the solution is (A) 2.9 (B) 3.3 (C) 4.9 (D) 5.4

Description : A 0.22 M solution of lactic acid (pKa 3.9) was found to contain 0.20 M in the dissociated form and 0.02 M undissociated form, the pH of the solution is (A) 2.9 (B) 3.3 (C) 4.9 (D) 5.4

Last Answer : Answer : C

The percentage of fluoride present in dental enamel is (A) 0.01–0.02 (B) 0.05–0.10 (C) 0.15–0.20 (D) 0.20–0.40

Description : The percentage of fluoride present in dental enamel is (A) 0.01–0.02 (B) 0.05–0.10 (C) 0.15–0.20 (D) 0.20–0.40

Last Answer : Answer : A

Safe and adequate daily dietary intake of chromium in adults in mg is (A) 0.01–0.02 (B) 0.02–0.03 (C) 0.03–0.04 (D) 0.05–0.2

Description : Safe and adequate daily dietary intake of chromium in adults in mg is (A) 0.01–0.02 (B) 0.02–0.03 (C) 0.03–0.04 (D) 0.05–0.2

Last Answer : Answer : D

The percentage of Nitrogen in Air is - (1) 0.94 (2) 0.03 (3) 78.03 (4) 85.02

Description : The percentage of Nitrogen in Air is - (1) 0.94 (2) 0.03 (3) 78.03 (4) 85.02

Last Answer : (3) 78.03 Explanation: By volume, thy air contains 78.09% nitrogen, 20.95% oxygen, 0.93% argon, 0.039% carbon dioxide, and small amounts of other gases. Air also contains a variable amount of water vapor, on average around 1%.

A 30% (by volume) suspension of spherical sand particles in a viscous oil has a hindered settling velocity of 4.44 μm/s. If the Richardson Zaki hindered settling index is 4.5, then the terminal velocity of a sand grain is (A) 0.90 μm/s (B) 1 μm/s (C) 22.1 μm/s (D) 0.02 μm/s

Description : A 30% (by volume) suspension of spherical sand particles in a viscous oil has a hindered settling velocity of 4.44 μm/s. If the Richardson Zaki hindered settling index is 4.5, then the terminal velocity of a sand grain is (A) 0.90 μm/s (B) 1 μm/s (C) 22.1 μm/s (D) 0.02 μm/s

Last Answer : (B) 1 μm/s

Steel will respond to hardening by heat treatment processes, only when the minimum carbon content in it is __________ percent. (A) 0.02 (B) 0.2 (C) 0.35 (D) 0.5

Description : Steel will respond to hardening by heat treatment processes, only when the minimum carbon content in it is __________ percent. (A) 0.02 (B) 0.2 (C) 0.35 (D) 0.5

Last Answer : (B) 0.2

If 20 J of energy is trapped at producer level, then how much energy will be available to peacock as food in the following chain? Plant → Mice → Snake → Peacock (a) 0.02 J (b) 0.002 J (c) 0.2 J (d) 0.0002 J

Description : If 20 J of energy is trapped at producer level, then how much energy will be available to peacock as food in the following chain? Plant → Mice → Snake → Peacock (a) 0.02 J (b) 0.002 J (c) 0.2 J (d) 0.0002 J

Last Answer : (a) 0.02 J

The size of clay particles are— (A) 1•0 mm (B) 0•2 – 0•02 mm (C) < 0•02 mm (D) < 0•002 mm

Description : The size of clay particles are— (A) 1•0 mm (B) 0•2 – 0•02 mm (C) < 0•02 mm (D) < 0•002 mm

Last Answer : (D) < 0•002 mm

Calculate the phase constant of a dielectric with frequency 6 x 10 6 in air. a) 2 b) 0.2 c) 0.02 d) 0.002

Description : Calculate the phase constant of a dielectric with frequency 6 x 10 6 in air. a) 2 b) 0.2 c) 0.02 d) 0.002

Last Answer : c) 0.02

Calculate the phase constant of a conductor with attenuation constant given by 0.04 units. a) 0.02 b) 0.08 c) 0.0016 d) 0.04

Description : Calculate the phase constant of a conductor with attenuation constant given by 0.04 units. a) 0.02 b) 0.08 c) 0.0016 d) 0.04

Last Answer : d) 0.04

Calculate the conduction density of a material with resistivity of 0.02 units and electric intensity of 12 units. a) 300 b) 600 c) 50 d) 120

Description : Calculate the conduction density of a material with resistivity of 0.02 units and electric intensity of 12 units. a) 300 b) 600 c) 50 d) 120

Last Answer : b) 600

Find the susceptibility when the curie constant is 0.2 and the difference in critical temperature and paramagnetic curie temperature is 0.01. a) 2 b) 20 c) 0.02 d) 200

Description : Find the susceptibility when the curie constant is 0.2 and the difference in critical temperature and paramagnetic curie temperature is 0.01. a) 2 b) 20 c) 0.02 d) 200

Last Answer : b) 20

Calculate the polarisation vector of the material which has 100 dipoles per unit volume in a volume of 2 units. a) 200 b) 50 c) 400 d) 0.02

Description : Calculate the polarisation vector of the material which has 100 dipoles per unit volume in a volume of 2 units. a) 200 b) 50 c) 400 d) 0.02

Last Answer : a) 200

Calculate the dipole moment of a dipole with equal charges 2C and -2C separated by a distance of 2cm. a) 0.02 b) 0.04 c) 0.06 d) 0.08

Description : Calculate the dipole moment of a dipole with equal charges 2C and -2C separated by a distance of 2cm. a) 0.02 b) 0.04 c) 0.06 d) 0.08

Last Answer : b) 0.04

Find the curl of the vector and state its nature at (1,1,-0.2) F = 30 i + 2xy j + 5xz 2 k a) √4.01 b) √4.02 c) √4.03 d) √4.04

Description : Find the curl of the vector and state its nature at (1,1,-0.2) F = 30 i + 2xy j + 5xz 2 k a) √4.01 b) √4.02 c) √4.03 d) √4.04

Last Answer : d) √4.04

Cd for the orifice plate varies from (A) 0.58 to 0.8 (B) 0.93 to 0.98 (C) 0.2 to 0.3 (D) 0.02 to 0.03

Description : Cd for the orifice plate varies from (A) 0.58 to 0.8 (B) 0.93 to 0.98 (C) 0.2 to 0.3 (D) 0.02 to 0.03

Last Answer : (A) 0.58 to 0.8

Out of the following, TLV of __________ is the minimum (about 0.02 ppm). (A) Phosgene (B) Bromine (C) MIC (Methyl isocyanate) (D) Ozone

Description : Out of the following, TLV of __________ is the minimum (about 0.02 ppm). (A) Phosgene (B) Bromine (C) MIC (Methyl isocyanate) (D) Ozone

Last Answer : (C) MIC (Methyl isocyanate)

The alcoholic content of **** is approximately _____. a. 0.02 b. 0.04 c. 0.06 d. 0.08

Description : The alcoholic content of beer is approximately _____. a. 0.02 b. 0.04 c. 0.06 d. 0.08

Last Answer : b. 0.04

A dumpy level was set up at the midpoint between two pegs A and B, 50 m apart and the staff readings at and were 1.22 and 1.06. With the level set up at , the readings at and were 1.55 and 1.37. The collimation error per 100 m length of sight is (A) 0.02 m inclined upwards (B) 0.04 m inclined downwards (C) 0.04 m inclined upward (D) None of these

Description : A dumpy level was set up at the midpoint between two pegs A and B, 50 m apart and the staff  readings at and were 1.22 and 1.06. With the level set up at , the readings at  and were 1.55 and ... upwards  (B) 0.04 m inclined downwards  (C) 0.04 m inclined upward  (D) None of these

Last Answer : (B) 0.04 m inclined downwards 

While setting a plane table at a station it was found that the error in centering was 30 cm away from the ray of length 40 m drawn from the station. If the scale of the plan is 1 cm = 2 cm, the displacement of the end of the ray in plan from the true position will be (A) 0.02 cm (B) 0.15 cm (C) 0.2 cm (D) 0.1 cm

Description : While setting a plane table at a station it was found that the error in centering was 30 cm away from the ray of length 40 m drawn from the station. If the scale of the plan is 1 cm = 2 cm, the displacement of the end of ... true position will be (A) 0.02 cm (B) 0.15 cm (C) 0.2 cm (D) 0.1 cm

Last Answer : (B) 0.15 cm

The void ratio of a soil sample decreases from 1.50 to 1.25 when the pressure is increased from 25 tonnes/m2 to 50 tonnes/m2 , the coefficient of compressibility is (A) 0.01 (B) 0.02 (C) 0.05 (D) 0.001

Description : The void ratio of a soil sample decreases from 1.50 to 1.25 when the pressure is increased from 25 tonnes/m2 to 50 tonnes/m2 , the coefficient of compressibility is (A) 0.01 (B) 0.02 (C) 0.05 (D) 0.001

Last Answer : (A) 0.01

The difference in one unit of Rockwell hardness number corresponds to a difference in the depth of indentation of __________ mm. (A) 0.001 (B) 0.01 (C) 0.002 (D) 0.02

Description : The difference in one unit of Rockwell hardness number corresponds to a difference in the depth of indentation of __________ mm. (A) 0.001 (B) 0.01 (C) 0.002 (D) 0.02

Last Answer : Option C

If D is the degree of a curve, the percentage reduction of gradient, is (A) 0.01 D (B) 0.02 D (C) 0.03 D (D) 0.04 D

Description : If D is the degree of a curve, the percentage reduction of gradient, is (A) 0.01 D (B) 0.02 D (C) 0.03 D (D) 0.04 D

Last Answer : Answer: Option D

The volume is measured correct to the nearest (A) 0.01 cum (B) 0.02 cum (C) 0.03 cum (D) 0.04 cum

Description : The volume is measured correct to the nearest (A) 0.01 cum (B) 0.02 cum (C) 0.03 cum (D) 0.04 cum

Last Answer : (A) 0.01 cum

The area is measured correct to the nearest (A) 0.01 sqm (B) 0.02 sqm (C) 0.03 sqm (D) 0.04 sqm

Description : The area is measured correct to the nearest (A) 0.01 sqm (B) 0.02 sqm (C) 0.03 sqm (D) 0.04 sqm

Last Answer : (A) 0.01 sqm

Pick up the correct statement about silt soil from the following: (A) The silt soil has particle size from 0.02 mm to 0.06 mm (B) In organic fine grained silt soil possesses no plasticity (C) The least plastic type normally consists of more or less equidimensional grains of quartz (D) All the above

Description : Pick up the correct statement about silt soil from the following: (A) The silt soil has particle size from 0.02 mm to 0.06 mm (B) In organic fine grained silt soil possesses no ... The least plastic type normally consists of more or less equidimensional grains of quartz (D) All the above

Last Answer : Answer: Option D

The most common constituents of alkalinity in natural water are measured by titrating the water sample with 0.02 N H2SO4 using (a) Eriochrome Black T and Ferroin indicators (b) Ferroin and Phenolphthalein indicators (c) Phenolphthalein and Methyl Orange indicators (d) Methyl Orange and Ericochrome Black T indicators

Description : The most common constituents of alkalinity in natural water are measured by titrating the water sample with 0.02 N H2SO4 using (a) Eriochrome Black T and Ferroin indicators (b) Ferroin ... (c) Phenolphthalein and Methyl Orange indicators (d) Methyl Orange and Ericochrome Black T indicators

Last Answer : (c) Phenolphthalein and Methyl Orange indicators

Maximum area of compression reinforcement shall not exceed [ A ] 0.02 bd [ B ] 0.02 bD [ C ] 0.04 bd [ D ] 0.04 bD

Description : Maximum area of compression reinforcement shall not exceed [ A ] 0.02 bd [ B ] 0.02 bD [ C ] 0.04 bd [ D ] 0.04 bD

Last Answer : [ C ] 0.04 bd