Description : What is bigger a 5.1 km or a 5000 meters?
Last Answer : 5.1 km is 100 metres bigger
Description : How big is 200 meters in km?
Last Answer : It is: 200/1000 or 1/5 of a km
Description : Which is greater 40 meters or 4 km?
Last Answer : 4 km equals 4000 meters which is greater than 40 meters
Description : For a space wave transmission, the radio horizon distance of a receiving antenna with a height of 64 meters is approximately A. 8 km B. 32 km C. 64 km D. 256 km
Last Answer : B. 32 km
Description : A receiver is located 64 km from a space wave transmitting antenna that is 100 meters high. Find the required height of the receiving antenna. A. 36 meters high B. 64 meters high C. 100 meters high D. 182.25 meters high
Last Answer : A. 36 meters high
Description : If a transmitting antenna is 100 meters high and a separate receiving antenna is 64 meters high, what is the maximum space wave communication distance possible between them? A. 18 km B. 72 km C. 164 km D. 656 km
Last Answer : B. 72 km
Description : For a space wave transmission, the radio horizon distance of a transmitting antenna with a height of 100 meters is approximately: A. 10 km B. 40 km C. 100 km D. 400 km
Last Answer : B. 40 km
Description : Consider a source computer(S) transmitting a file of size 106 bits to a destination computer (D)over a network of two routers (R1 and R2) and three links(L1, L2, and L3). L1connects S to R1; L2 connects R1 to ... file from S to D? a. 1005 ms b. 1010 ms c. 3000 ms d. 3003 ms Answer: Option(a)
Last Answer : a. 1005 ms
Description : A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train? a) 120 meters b) 180 meters c) 324 meters d) 150 meters
Last Answer : d) 150 meters
Description : Two metro train 360 meters and 360 meters in length respectively and running in same directions, one at the rate of 116 km and other at the rate of 100 km an hours. What time will they be cross of each other? A) 100 sec B) 162sec C) 132sec D) 126sec
Last Answer : ANSWER: B Explanation: Length of the 1st metro train = 360m Length of the 2nd metro train = 360m Total length of the both metro train = 360 + 360 = 720 m speed of the 1st metro train = 116 km/hr ... Required time = distance / speed = (720/(40/9))sec = 720 * 9 /40 = 162sec.
Description : A shatabadi express takes 240 seconds to cover a distance of length 700 meters at a speed of 270 km/hr. What will be the time taken by the train to cross a standing pole? A) 160sec B) 465sec C) 310sec D) 231sec
Last Answer : ANSWER:D Explanation: Speed of the train = 270 km/hr. Converting the speed into m/sec Speed = 270 km/hr = 270 x 5/18 m/sec = 75 m/sec First, we have to find the length of the train Let ... a standing Pole at 75 m/s =( 17300/75)seconds = 231 seconds. Hence the answer is 231 sec(approx.)
Description : A train, 1800 meters long running at the rate of 204 km/hr will cross a platform in: A) 16 B) 32 C) 45 D) 64
Last Answer : ANSWER: B Explanation: Speed of the train = 204 km/hr. We have to find the time in seconds, so convert the speed in the unit of m/sec. Therefore 204 km/hr = 204 x 5/18 m/s = 1020/18 m/s Length ... m/sec Time = distance/speed = 1800/(1020/18)sec = (1800*18/1020)sec = 32 sec (approx.)
Description : Length of train is 510 meters and speed of train is 63 km/hour. This train can pass a pole in 90 seconds, then find the length of the pole? A) 575mts B) 2500mts C) 1065mts D) 876mts
Last Answer : ANSWER: C Explanation: Given speed of the train = 63 km/hr = 63*5/18 m/s =17.5m/s Let the length of the pole = x mts Given time taken to cover the distance of (510+ x)mts is 90 sec. We know speed = ... m/s 17. 5 = 510+x/90 1575 = 510+x x = 1065 Therefore the length of the pole is 1065 mts
Description : A cyclist moves due east at 8 km/h for half an hour and then turns exactly south-wards for another half an hour at 6 km/h. The average velocity of the cyclist for the period is (a) 5 km/h (b) 7 km/h (c) 10 km/h (d) 14 km/h
Last Answer : Ans:(a)
Description : Mr.Aneesh left for city 1 from city 2 at 3.00 pm. He travelled at the speed of 60km/hr for 1 and half hours. After that the speed was reduced to 15 km/hr. If the distance between two cities is 120 kms, at what time did Mr.Aneesh reach city 1 ? a) 6.30 pm. b) 5.30 pm. c) 7.30 pm. d) 8.30 pm.
Last Answer : A Mr.Aneesh travelled 60 km/hr for 1 1/2 hours (3/2 hours). Distance covered in 3/2 hours = 60 x 3/2 = 90 km. Therefore, remaining distance = 120 -90 = 30 km After 3/2 hours, the speed was ... village 2 at 3.00 pm + 3 hours 30 minutes = 6.30pm Hence the required answer is 6.30 pm.
Description : A train travelling at 36 kmph completely crosses another train having half its length and travelling in the opposite direction at 54 kmph, in 12 seconds. If it also passes a railway platform in 112 minutes, the length ... is : a) 560 metres b) 620 metres c) 700 meres d) 750 metres e) 720 meters
Last Answer : Answer: c)
Description : Two negative point charges are 2 meters apart and repel each other with a force of 2 newtons. When the distance between the charges is doubled, the force between them is w) one fourth as great x) one half as great y) twice as great z) four times as great
Last Answer : ANSWER: W -- ONE FOURTH AS GREAT
Description : A train covers the first half of the distance between two stations with a speed of 40 km/h and the other half with 60 km/h. Then its average speed is
Last Answer : A train covers the first half of the distance between two stations with a speed of 40 km/h and the other half with ... 48 km/h C. 52 km/h D. 100 km/h
Description : How many metres is half a km?
Last Answer : There are 500 metres in 1/2 of a km
Description : The Michaelis constant, Km is (A) Numerically equal to ½ Vmax (B) Dependent on the enzyme concentration (C) Independent of pH (D) Numerically equal to the substrate concentration that gives half maximal velocity
Last Answer : Answer : D
Description : When [s] is equal to Km, which of the following conditions exist? (A) Half the enzyme molecules are bound to substrate (B) The velocity of the reaction is equal to Vmax (C) The velocity of the reaction is independent of substrate concentration (D) Enzyme is completely saturated with substrate
Last Answer : Answer : A
Description : Velocity maximum for an enzyme at half the substrate concentration gives (A) The molecular weight of the enzyme (B) Km value (C) Isoelectric pH (D) Pk value
Last Answer : Answer : B
Description : When the velocity of an enzymatic reaction equals Vmax, substrate concentration is (A) Half of Km (B) Equal to Km (C) Twice the Km (D) Far above the Km
Description : In enzyme kinetics Km implies (A) The substrate concentration that gives one half Vmax (B) The dissocation constant for the enzyme substrate comples (C) Concentration of enzyme (D) Half of the substrate concentration required to achieve Vmax
Description : A train starts from Delhi and reaches Lucknow in 24.5 hours. If it travels the first half of journey at 30 kmph and second half at 40 kmph then what is the total distance it travelled? 1) 750 km 2) 800 km 3) 840 km 4) 900 km 5) 920 km
Last Answer : 3) 840 km
Description : A bus starts at bus stop and reaches a destination in 4 hours. If it travels first and second half at the speed of 40 km/hr and 50 km/hr respectively then the distance between bus stop and destination is a) 177.7 km b) 154.2 km c) 163.5 km d) 147.3 km
Last Answer : A Let the distance between bus stop and destination be X. The total time taken by the bus to cover X = 4 hours Since X/2 by 40km/hr and remaining X/2 by 50km/hr Then by Time = distance/speed, we have ... = 1600 9X = 1600 X = 1600/9 = 177.7 Hence 177.7 km is the required answer.
Description : Tharun has to cover a distance of 84 km in 40 minutes. If he covers one-half of the distance in one-fourth of the total time, to cover the remaining distance in the remaining time, what should be his speed in km/hr? a) 42 km/hr b) 64km/hr c) 84km/hr d)76km/hr
Last Answer : C Tharun needs to cover 84 km in 40minutes Given that he covers one-half of the distance in one-fourth of the total time ⇒ he covers half of 84km in one-fourth of 40 minutes ⇒ He covers 42 km in ¼ * ... Distance =42km Time =30minutes =1/2 hr Required Speed = Distance / Time =42/(1/2)=84 km/hr